Language:
To browser these website, it's necessary to store cookies on your computer.
The cookies contain no personal information, they are required for program control.
the storage of cookies while browsing this website, on Login and Register.

### GDPR and DSGVO law

Storing Cookies (See : http://ec.europa.eu/ipg/basics/legal/cookies/index_en.htm ) help us to bring you our services at overunity.com . If you use this website and our services you declare yourself okay with using cookies .More Infos here:
https://overunity.com/5553/privacy-policy/
If you do not agree with storing cookies, please LEAVE this website now. From the 25th of May 2018, every existing user has to accept the GDPR agreement at first login. If a user is unwilling to accept the GDPR, he should email us and request to erase his account. Many thanks for your understanding.
Amazon Warehouse Deals ! Now even more Deep Discounts ! Check out these great prices on slightly used or just opened once only items.I always buy my gadgets via these great Warehouse deals ! Highly recommended ! Many thanks for supporting OverUnity.com this way.

Many thanks.

# New Book

Products

WaterMotor kit

### Statistics

• Total Members: 84255
• Latest: romeos69

• Total Posts: 898155
• Total Topics: 15837
• Online Today: 44
• Most Online: 103
(December 19, 2006, 11:27:19 PM)
• Users: 1
• Guests: 17
• Total: 18

### Author Topic: Basic physics questions  (Read 154 times)

#### Novus

• Newbie
• Posts: 1
##### Basic physics questions
« on: September 18, 2021, 08:10:40 PM »
Figure 1 – Weight ‘A’ equals weight ‘B’
‘C’ is a closed container with air at ambient pressure.
The system is in balanced with zero force exerted by weight ‘A’ on the air volume in container ‘C’.

Figure 2 – The centre of the balance has shifted towards weight ‘A1’.
A force is exerted by weight ‘A1’ equal to the opposite force of the compressed air volume of container ‘C1’.
The system is at equilibrium.

At each point between the trajectory from ‘A’ to ‘A1’ the system is at equilibrium.
The setup is close to ideal with low friction.
The system should be viewed as continuously oscillating between figure 1 and figure 2 and back to figure 1 with only a minimal force being applied to either ‘A’ or ‘B1’.

Figure 3 – Identical setup to figure 1 with the same volume of air in closed container ‘C’.
Mass ‘D’ has the same density/specific weight as the air volume in container ‘C’. (Or actually slightly higher in order to rest on the bottom of container ‘C’).

Figure 4 – Identical setup as figure 2 with compression of air volume in container ‘C’.
Mass ‘D’ will move upwards to position ‘D1’ as a result of the difference in air density.

The movement of ‘D’ to ‘D1’ does not change the pressure exerted by ‘C1’ on the bottom of ‘A1’?

The movement of ‘D’ to ‘D1’ constitutes ‘work’?

#### Free Energy | searching for free energy and discussing free energy

##### Basic physics questions
« on: September 18, 2021, 08:10:40 PM »