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Author Topic: RANT CAFFE ASYLUM  (Read 23721 times)

Offline picowatt

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Re: RANT CAFFE ASYLUM
« Reply #345 on: September 23, 2020, 04:11:06 PM »
CaptainLoz,

What prompted my initial post to EMJ was with regard to your video #5:

 https://www.youtube.com/watch?v=Tk9uSOdj-hE

At around 7:30 in that video, we see the two incandescent lamps, apparently in series, being used as a load.  At that point, the DC supply is providing a total of around 17 watts.  It does not seem probable that those two incandescent lamps could be dissipating 17 watts, let alone more than that, as indicated by the scope.

Thanks to your reply, we now know that the lamps will draw .2 amps when driven by 14VDC.  Therefore, when driven to their rated brightness, each lamp will dissipate 2.8 watts.  The series connected pair, will therefore dissipate 5.6 watts when connected across 28VDC.

The waveform driving the lamps is not DC, but the thermal mass of the lamps tends to do a good job smoothing/averaging a complex AC waveform driving the lamps. 

I suggested that you connect the two lamps directly to the DC supply and adjust the supply's voltage until the lamps are illuminated as bright as they are at 7:30 in the video and compare the watts drawn from the supply to the watts driving the POC circuit at 7:30 in the video.  Although a judgement as to what is "similarly bright" is rather subjective, such a test will, at the least, provide a ballpark number to compare to the scope reading.

Its a fairly simple test and should not have set off a firestorm of insulting replies from EMJ (which he then deletes).

So, to repeat, in video 5, at around 7:30, we see 17watts from the supply being used to light a pair of 2.8 watt rated incandescent lamps.  Even if the lamps were being overdriven to almost three times their rating, the circuit would be less than unity and way more inefficient than what the scope is indicating.

If the scope math is not set correctly, you could be measuring reactive power circulating in the circuit and not real power driving the load.  Performing a quick test with the two lamps, driven to comparable brightness by the DC supply, would provide an "in the ballpark" verification of the scope's measurements.

PW     

       

Free Energy | searching for free energy and discussing free energy

Re: RANT CAFFE ASYLUM
« Reply #345 on: September 23, 2020, 04:11:06 PM »

Offline partzman

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Re: RANT CAFFE ASYLUM
« Reply #346 on: September 23, 2020, 04:33:42 PM »
CaptainLoz,

Respectively, I would recommend you try what Picowatt has suggested and if you find that his test shows you could not be producing the level of output your scope indicates, I have a suggestion.

Remove all the floating grounds.  These are not necessary due to the inherent isolation provided by the transformer windings.  IOW, place the common ground from your signal generating source on the the same ground connection of your circuitry, on the same ground of your scope and ground each secondary at this same point.  Now take your measurements as let's see what the result is.

Regards,
Pm

Offline picowatt

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Re: RANT CAFFE ASYLUM
« Reply #347 on: September 23, 2020, 04:49:00 PM »
Partzman,

A comment to his video #9 suggested he feed two zero to 5 VDC "in phase" 50% duty cycle square waves into the two scope channels for a simulated 25 watts during the square wave on times.

If the scope math is correct, that should read an average of 12.5 watts (25 watts for 50% of the time).  One of the square waves is then phase shifted 180 degrees and the scope should then read close to zero watts.

I think the above is an excellent suggestion as well.

PW

Free Energy | searching for free energy and discussing free energy

Re: RANT CAFFE ASYLUM
« Reply #347 on: September 23, 2020, 04:49:00 PM »
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Offline picowatt

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Re: RANT CAFFE ASYLUM
« Reply #348 on: September 24, 2020, 01:58:48 AM »
EMJ,

Apparently you do not grasp the logic of this suggestion.  It is a simple method of verifying that the scope math is programmed and reading correctly.

A function generator is used to simulate a voltage and current signal of known amplitude and duty cycle and fed directly into the two scope channels.

Various amplitudes, waveforms, duty cycles, and phase relationships can be used, but the suggested pair of "in phase", 0-5VDC @50% square waves makes for easy math.

When the pair of square waves are "in phase", the scope should read 12.5 watts (5V X 5A= 25W for 50% of the time = 12.5W).

The phase of one of the square waves is then shifted 180 degrees.  The scope should now read very close to zero watts.  If the scope does not read zero watts, the math is not properly programmed and is not measuring "real power".

Feel free to ask additional questions if you or CaptainLoz do not fully understand this suggestion.

PW

 
Is anyone reading these moronical Assumptions?

50%? last I checked Loz used 35% or less. What is wrong with these people? Cant they get simple figures right?

How many times do you have to be told the simple stuff?

Why do they all rush in, from years of Slumber, to act like children, when we have a measurement that shows something special?

It is obvious to me!

Best wishes, stay safe and well in these Dire Times,
   Chris Sykes

Offline partzman

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Re: RANT CAFFE ASYLUM
« Reply #349 on: September 24, 2020, 02:37:54 AM »
--

Free Energy | searching for free energy and discussing free energy

Re: RANT CAFFE ASYLUM
« Reply #349 on: September 24, 2020, 02:37:54 AM »
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Offline picowatt

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Re: RANT CAFFE ASYLUM
« Reply #350 on: September 24, 2020, 02:49:55 AM »
EMJ,

No one is making "wild claims".  I watched the videos.  Nothing in those videos verifies the scope math when measuring complex waveforms with large amounts of reactive power. 

CaptainLoz is measuring a very complex AC waveform that likely has a large reactive current component.

The simple test previously suggested is quick verification that the scope is measuring real power and not VARS or some other weird possibilities that can happen if the math channel is not programmed correctly.

When the two 0-5VDC square waves @50% are in phase, the expected math output would be 12.5 watts (5V X 5A = 25W for 50% of the time = 12.5 watts).

Shifting one of the square waves 180 degrees simulates a current and voltage that are exactly 180 degrees out of phase, so the scope should now read zero watts (5V X 0A = 0W, 0V X 5A = 0W).

This quick verification ensures the scope is reading real power and not VARS or some other weird values that can occur if the math is not programmed correctly.  It would take less time to perform than it took to make this reply.

PW

Some make wild claims: "the math is not properly programmed" on the scope.

Honestly, this is so absolutely stupid to suggest! Desperate, COMPLETELY desperate attempts to sweep this major problem they have away!

TWO Scopes, both A x B Both Calibrated, both tested using Standard DC Methods with Equipment. How do we test our equipment?

Here:
   1: Test the Scope using Known DC Load: https://youtu.be/x17HQCiVHW0
   2: Test Equipment again after Scope Calibration: https://youtu.be/ol-3VZJaqys


DAMN! Some people are silly idiots and have no logic what so ever in their minds! This is the absolute dumbest suggestion I have ever heard! It is IMPOSSIBLE to have the Scope Math wrong, if its been tested under DC Conditions and found to be Correct!

Some, are completely wrong, talking from an uncontrollable hole in the middle their your head. Use commonsense, stop talking RUBBISH! Illogical, nonsensical rubbish! Stop with all the Diabolical Stupid! Tell your uneducated Numptys to go and educate! They make you look even dumber when they come and make dumb idiot Posts!

Best wishes, stay safe and well in these Dire Times,
   Chris Sykes

Offline picowatt

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Re: RANT CAFFE ASYLUM
« Reply #351 on: September 24, 2020, 03:05:12 AM »
EMJ,

I am not making any assumptions.  I am merely pointing out an observation.

In video #5 @ 7:30, the DC power supply is feeding 17 watts into a circuit that is lighting two small incandescent lamps that appear to be series connected.  Thanks to CaptainLoz's response, we know these lamps draw .2 amps at 14VDC, or 2.8 watts, at their rated output.  The series connected pair would therefore draw 5.6 watts when connected across 28VDC. 

The lamps in the video do not appear to be overdriven to any large extent, but even if the pair of lamps were being overdriven by a factor of three times their rating (i.e., 16.8 watts), the circuit would still not be 100% efficient.

It would take very little time to connect the series connected pair of lamps directly to the DC supply to confirm their power draw at similar brightness.

PW

These people, are, automatically basing their assumptions, entirely, on the Oscilloscope readings being incorrect!
...

Logic and Reason does not exist here!


P.S: I will continue Deleting Idiots!

Free Energy | searching for free energy and discussing free energy

Re: RANT CAFFE ASYLUM
« Reply #351 on: September 24, 2020, 03:05:12 AM »
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Offline picowatt

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Re: RANT CAFFE ASYLUM
« Reply #352 on: September 24, 2020, 03:44:46 AM »
EMJ,

You can't be serious.  I think you need to step back and look at this with much less emotional investment. 

A string of pulses is being fed into circuit having both inductive and capacitive reactances, with some apparent tuning using a variable capacitor, and you do not believe there will be a reactive current component flowing in the circuit?

I don't even know how to respond to that.  Hopefully CaptainLoz is a bit smarter and will understand the logic of the suggested square wave test.  The point of the test is to ensure that any current out of phase with the measured voltage is not counted as real power.  Its a very simple test. 

By the way, the square wave used to simulate the current input can be reduced to 500 millivolts if the scope's current input channel is set for use with a 0.1 ohm CSR (as opposed to a 1 ohm CSR). 

If you still don't understand, please feel free to ask...

PW


WHAT ARE YOU SMOKING!!!

Voltage and Current Phase is almost purely IN PHASE! Pure, Real Power! Power Factor of pretty much: 1.0

There is no Reactive Power in there! What are you SMOKING! Do you have any idea how Stupid your post sounds? Man Alive, go and retire or something, you are so far off the mark its not funny!

What Non-Sense you keep writing Picowatt!

Best wishes, stay safe and well in these Dire Times,
   Chris Sykes

Offline hartiberlin

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Re: RANT CAFFE ASYLUM
« Reply #353 on: September 24, 2020, 04:43:33 AM »
Hello All,User WhatIsItis on moderation, cause he has slandered permanently Chris...
Sorry, I am very busy with other things and can not moderate much... but with the function moderation single users,I can better see, what they post, before the postings go online...
If there is a claim, that someone runs a scam on his own website, I guess there would be comingother users forward, that feel being scammed... so are there any victims yet ??

Regards, Stefan.

Free Energy | searching for free energy and discussing free energy

Re: RANT CAFFE ASYLUM
« Reply #353 on: September 24, 2020, 04:43:33 AM »
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Offline EMJunkie

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Re: RANT CAFFE ASYLUM
« Reply #354 on: September 24, 2020, 05:08:23 AM »
Hello All,User WhatIsItis on moderation, cause he has slandered permanently Chris...
Sorry, I am very busy with other things and can not moderate much... but with the function moderation single users,I can better see, what they post, before the postings go online...
If there is a claim, that someone runs a scam on his own website, I guess there would be comingother users forward, that feel being scammed... so are there any victims yet ??

Regards, Stefan.






Thank You Stefan!

There is no Scam, that was a false accusation! Some kind people, through free will, can make a donation if they wish, to help support the costs of my website, other than that, I receive no financial incentive to do what I am doing. I do not run ads or anything! I do this for Free! I do this for Love!

We have a replication of My Work, CaptainLoz has shared his work publically and we are trying to come to a conclusion. With brand new, calibrated equipment, we can not find an error. Many are trying, as yet unsuccessfully.

Best wishes, stay safe and well in these Dire Times,
   Chris Sykes

Offline picowatt

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Re: RANT CAFFE ASYLUM
« Reply #355 on: September 24, 2020, 05:43:19 AM »
EMJ,

I would think you would welcome any suggestions, and the opportunity they provide, to silence the naysayers and prove your claims.

What data can we glean from video #5 at around 7:30?

https://www.youtube.com/watch?v=Tk9uSOdj-hE

A DC power supply is feeding a circuit drawing 17 watts of power as indicated by the DC supply.  The load being driven is a series string of two small incandescent lamps that are rated at 14VDC @.2amps.  Therefore, when the series string is connected across 28VDC, the lamps will draw 5.6 watts at their rated brightness.  There is also an oscilloscope connected to measure the power consumed by the load (the two small incandescent lamps) that is indicating that the lamps are consuming 20 watts.

DC supply indicates 17watts
Scope indicates 20 watts
Lamps indicate 5.6 watts

A good researcher would look at those three indications and want to verify, confirm, and sort out those three indications to either find a measurement error or be proudly able to verify the circuit's claimed operation. 

Consider the two incandescent lamps, a good researcher would stand back, look at those indications, and ask themselves "are those two small lamps actually consuming 20 watts as the scope indicates, or even the 17 watts the supply indicates"?  "Can those two small 2.8 watt rated lamps even handle that much power"? 

That researcher would want to connect the series string of two lamps directly to the DC power supply and adjust that DC supply until the lamps lit with similar brightness as observed during the POC test.  That researcher would note the power draw indicated by the DC supply and compare that indication to the 17 watts and 20 watts indicated during the POC test.  A very simple 5 minute test.

If it really does take 20 watts from the DC supply to make the lamps illuminate as bright as they were in the video, congratulations, that confirms the scope readings, and the circuit may indeed be operating above unity.

However, if the lamps draw less than 20 watts, or even less than 17 watts, when driven to similar brightness by the DC power supply, that researcher would want to continue sorting it all out.

Regarding the scope indication, a simple test has been suggested that ensures the scope math is programmed to indicate real power using two square waves.

A researcher should welcome any such suggestions, particularly if the tests proposed use equipment the researcher already has and requires little time to perform.

If the scope reads zero power when the two square waves are out of phase, another step has been made toward confirming above unity operation.  If the scope does not read zero power, that would indicate the scope math is incorrect and efforts should be made to sort that out.

Surely you can see the logic in the above discussion.

PW

Free Energy | searching for free energy and discussing free energy

Re: RANT CAFFE ASYLUM
« Reply #355 on: September 24, 2020, 05:43:19 AM »
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Offline FriskyFritz

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Re: RANT CAFFE ASYLUM
« Reply #356 on: September 24, 2020, 10:05:41 AM »
thank you Stefan  ;)
I warned Die silly boy
I told him he was breaking rules
we will eat sausages now
Fritz

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Offline lancaIV

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Re: RANT CAFFE ASYLUM
« Reply #357 on: September 24, 2020, 11:38:17 AM »
What is the logic and target from this circuit ?
The efficiency from lamps as indicator :
                                                        lumen per Watt
lamps rated Watt : 2,8 Watt

2 lamps = 5,6 Watt

Charging with by  some assumed 17,8 Watt ' pure power" ~ 17,8 Wh hourly consume !
                                         
                                               5,6 Watt lamps lumen output / 17,8 Watt
                                                            lumen/Watt circuit  ratio ?


battery + lamps       versus battery + circuit + lamps   ' dura-cell like' teste for comparison !

Duration before and after !

Sincerely

p.s: ramset his heatbox teste configuration is well mind ,but :

between industrial same rated Watt-age devices are physical-technical output differences
Reference : terrarium hobbiists their heat bulbs comparison study

between lamp rated Volt-age/tension and used upper/lower Volt-age is a non-linear output as lumen and heat relationship

Offline picowatt

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Re: RANT CAFFE ASYLUM
« Reply #358 on: September 24, 2020, 02:41:20 PM »
Quote from: EMJunkie on Today at 07:28:17 AM
Quote
Well, to accurately measure the Power in the Circuit, we must Average the Instantaneous Voltage over time, and Average the Instantaneous Current over Time, this product is the Total Power during this time Period in this Circuit. Right? Do we agree?

This is incorrect.  If you program the scope to the above math, the scope will not indicate real power to the load.

You should instead multiply the instantaneous voltage by the instantaneous current, and then average that product.

Programmed as you describe, the scope would not read zero watts in the suggested "two square wave test" when the square waves are out of phase.  That is why that two square wave test was suggested as a quick test of the scope's math programming.  Programmed as I suggest, the scope will read zero watts when the two square waves are out of phase.

Perhaps CaptainLoz will perform the POC test again using the two series incandescent lamps as the load, note the supply and scope readings, and then drive the lamps to comparable brightness directly from the DC supply and note the power draw from the supply.  If the scope measurements do not agree with the "directly driven from the DC supply" measurements, consider reprogramming the scope math.

PW

Offline picowatt

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Re: RANT CAFFE ASYLUM
« Reply #359 on: September 24, 2020, 02:43:07 PM »
Quote from: EMJunkie on Today at 07:55:39 AM
Quote
Oh Picowatt, come on!

You are saying EXACTLY the same as I said!

That is not true.  You said:

"Well, to accurately measure the Power in the Circuit, we must Average the Instantaneous Voltage over time, and Average the Instantaneous Current over Time, this product is the Total Power during this time Period in this Circuit. Right? Do we agree?"

You appear to be stating that you should average the voltage, average the current, and then multiply those two averages together.

I said:

"You should instead multiply the instantaneous voltage by the instantaneous current, and then average that product."


PW

 

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