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Mechanical free energy devices => mechanic => Topic started by: nix85 on August 25, 2020, 11:56:51 PM

Title: Water Inertial Drive
Post by: nix85 on August 25, 2020, 11:56:51 PM
i shared this on other thread but i think it deserves it's own.

principle is simple. imagine a circular pipe, bottom half 4 times the diameter of the upper, there is a pump inside the system,

in short, centrifugal force will be 4 x greater in upper part despite the fact that volume of water is 4 times less.

this is due to venturi effect (continuity principle), water in narrower part speeds up proportionally to how much narrower pipe is (https://youtu.be/UJ3-Zm1wbIQ?t=97 ) and centrifugal force is proportional to velocity squared.

let's say 5 liters is enclosed in the tube, since upper half is 1/4 diameter, there are 4 liters in bottom half and 1 liter in upper half.

let's say pump is pushing bottom part water at 1m/s, this means water in upper part moves at 4m/s.

let's say radius of the circle is 0.5m

let's calculate the centrifugal force http://www.calctool.org/CALC/phys/newtonian/centrifugal

for 4 liters at 1m/s force is 8N or 0.8kg.

for 1 liter at 4m/s force is 32N or 3.2kg.

or constant 2.4kg, but since only at the center force is pure y component it is 1/2 or 1.2kg average up


and

for 4 liters at 2.5m/s force is 50N or 5kg.

for 1 liter at 10m/s force is 200N or 20kg.

or constant 1/2 x 15kg = 7.5kg up


etc

of course increase of velocity means more friction and very low friction tube must be used, like electropolished stainless steel, but principle is clear and should be tested.

Title: Re: Water Inertial Drive
Post by: nix85 on August 26, 2020, 12:26:04 AM
how i imagine it is a propeller in the center of the bottom part, i know such axial pumps are not good for creating static pressure, but seems most optimal for this
Title: Re: Water Inertial Drive
Post by: lupacexi on September 01, 2020, 09:52:59 AM
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Title: Re: Water Inertial Drive
Post by: sm0ky2 on September 01, 2020, 03:38:07 PM
Tangential forces on either side of the center cancel each other out
We are left with a small portion in the center of the smaller tube
which has an effective force remaining to apply to the system as a whole:
Its’ magnitude is proportional to a tiny volume of water in the smaller tube’s center.
not enough to overpower the moment of inertia of the entire volume of water:
Title: Re: Water Inertial Drive
Post by: nix85 on September 02, 2020, 02:03:33 AM
Tangential forces on either side of the center cancel each other out

wrong, y component of all centrifugal force in the narrow part counts, nothing cancels out