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Author Topic: Getting energy from asymmetry of the magnetic field experiment  (Read 40359 times)

telecom

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Re: Getting energy from asymmetry of the magnetic field experiment
« Reply #105 on: February 14, 2020, 02:40:56 AM »
Great.

You can get cameras from ebay or ali express, for $2, something. I have these cameras, so i never have a problem that i have no camera. But then, these cameras are not very good. Also the camera that i used for my video was not very good.
So far I haven't gotten the scale, even though was supposed getting them within a week. May be it has to do with a flu scare? Still waiting.

telecom

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Re: Getting energy from asymmetry of the magnetic field experiment
« Reply #106 on: February 27, 2020, 07:30:32 PM »
This is my third attempt to post, basically starting testing the setup, they block images

Raycathode

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Re: Getting energy from asymmetry of the magnetic field experiment
« Reply #107 on: February 27, 2020, 07:49:57 PM »
This is my third attempt to post, basically starting testing the setup, they block images
have you got MSpaint on your machine
If so load it, save the 'what ever it is' in your pictures or dowload file then load it into ms paint
check it for size then save it to where ever you want to back into picyures ect
but before you save it change its format *.png  file. easy

raymondo

ayeaye

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Re: Getting energy from asymmetry of the magnetic field experiment
« Reply #108 on: February 27, 2020, 09:12:37 PM »
they block images

I don't know what is the problem, maybe someone here can help, like sm0ky2, i'm not impartial, like email images to someone, and one will post them here.

I use gimp, also inkscape and dia for drawings, one may use paint.net or pinta, and the accepted formats here are yes png and jpg. There are also some image posting sites like postimage, but the problem with these is that the images may not stay there for long, here they stay as long as the forum exists. Other than that, archive.org would be better i think for all images and videos.


telecom

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Re: Getting energy from asymmetry of the magnetic field experiment
« Reply #109 on: February 27, 2020, 09:32:27 PM »
this is the  setup

telecom

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Re: Getting energy from asymmetry of the magnetic field experiment
« Reply #110 on: February 27, 2020, 09:36:00 PM »
the forces in kg x distance in cm are like that
from the left:
0 - .16
1 - 0.06
2 - 0.08
3 - 0.08
4 - 0
5 - 0

from the right:
0 - 0.08
1 - 0.10
2 - 0.12
3 - 0
4 - 0
5 - 0

telecom

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Re: Getting energy from asymmetry of the magnetic field experiment
« Reply #111 on: February 27, 2020, 09:51:52 PM »
Next week will try doing more measurements.
Can someone analyze the data?

telecom

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Re: Getting energy from asymmetry of the magnetic field experiment
« Reply #112 on: February 27, 2020, 09:53:34 PM »
At the end of the  ravel to the right there is a very strong perpendicular force pushing the magnet away from the setup

ayeaye

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Re: Getting energy from asymmetry of the magnetic field experiment
« Reply #113 on: February 27, 2020, 10:04:54 PM »
the forces in kg x distance in cm are like that
from the left:
0 - .16
1 - 0.06
2 - 0.08
3 - 0.08
4 - 0
5 - 0

from the right:
0 - 0.08
1 - 0.10
2 - 0.12
3 - 0
4 - 0
5 - 0

Looks nice.

By fast calculation it is 0.38 kg * cm at left and 0.3 kg * cm at right (just add all numbers at left and at right side), better to convert it to Newton * mm or milli Joules.

This confirms my results.

More energy at the left side than at the right side. Also there is a significant force a longer distance at the left side than at the right side. Though the difference of energy is less.


ayeaye

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Re: Getting energy from asymmetry of the magnetic field experiment
« Reply #114 on: February 29, 2020, 12:56:39 PM »
I notice that your small moving magnet is rather wide, i used a much narrower small magnet. I'm not sure whether it's true, but how i see it by now, any irregularity of the field there may be, a wide moving magnet may make it all more even, something. If you have only one kind of magnets, these with poles on the wider sides, if you have them too many, and if they are ceramic magnets, maybe split some to half in the middle, sorry to recommend that... What i can say by now.

Should not be difficult to replicate the way Telecom did it. Like if you have an aluminum or a plastic ruler, make it stand 90 degrees on the side, should not be too difficult for these who have done things with their hands.


ayeaye

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Re: Getting energy from asymmetry of the magnetic field experiment
« Reply #115 on: February 29, 2020, 08:24:28 PM »
Maybe i was not clear enough about friction.

When an object moves by whatever force, the force of friction is always against the force that makes the object to move. That is, on dry slippery smooth surfaces when the object stands, the friction force is equal to the summary force to the object, until that summary force increases the maximum friction force. Then the object starts to move, and the friction force remains the same. When talking about the friction force below here, we mean that maximum friction force at the particular location. Friction force is an electromagnetic force between molecules or atoms of two surfaces against each other.

Thus, when we put the magnet somewhere and measure the force, the measured force is likely the real force to the magnet minus friction. Because the force to be measured, requires a slight movement towards the measured force, even if the movement is very slight. For any such movement, the force to the magnet must overcome the friction force. And the friction force does not disappear when the movement ends and the magnet stands still.

At any point, we can measure two forces. One is just before the magnet starts to move in the direction where we pull, this is the real force plus friction. The other is just before the magnet starts to move in the direction opposite to where we pull. This is the real force minus friction. Because for any movement to happen, the difference between the force to the magnet and the pulling force, must be greater than the friction force.

The real force is the average of these two forces. And the friction force is difference between these two forces, divided by two.

Also as i said before, adding the energies does not increase the error. This is because the scales don't always err to one side. The error is thus the difference between the greatest energy (of the energies added) calculated with the measured force plus the error of the scales, and the same energy calculated with the measured force minus the error of the scales.

Approximately, to convert kg to Newtons, multiply with 9.8, to convert kg * cm to milli Joules, multiply with 98. Like you had 37 milli Joules at the left side, and 29 milli Joules at the right side.

« Last Edit: March 01, 2020, 03:37:53 AM by ayeaye »

telecom

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Re: Getting energy from asymmetry of the magnetic field experiment
« Reply #116 on: February 29, 2020, 08:59:08 PM »
I notice that your small moving magnet is rather wide, i used a much narrower small magnet. I'm not sure whether it's true, but how i see it by now, any irregularity of the field there may be, a wide moving magnet may make it all more even, something. If you have only one kind of magnets, these with poles on the wider sides, if you have them too many, and if they are ceramic magnets, maybe split some to half in the middle, sorry to recommend that... What i can say by now.

Good point, the easiest probably would be just getting a small magnet somewhere. I will work on it.

telecom

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Re: Getting energy from asymmetry of the magnetic field experiment
« Reply #117 on: March 03, 2020, 07:59:33 PM »
done some more measurements w the same setup:
this time my friend was holding a plastic ruler on top to prevent it from jumping out.
left:
.24, 0.6, .30,.20
right:
.36, .08, .10, 0
reading taken each centimeter

telecom

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Re: Getting energy from asymmetry of the magnetic field experiment
« Reply #118 on: March 03, 2020, 08:05:12 PM »
Then I placed stack of the magnets horizontal, out of curiocity

telecom

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Re: Getting energy from asymmetry of the magnetic field experiment
« Reply #119 on: March 03, 2020, 08:07:38 PM »
The readings Re like that:
left:
.20, .16, .14, .32, .10

right:
.20, .08, .32, .16, 0

at the end of right travel there is a very strong vertical attraction force, will try measuring as well. which equals .30 kg
and at the end of the left travel there is a very big repelling force more than .4

all the readings are in kg