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Author Topic: Single circuit converts reactive to active power  (Read 5216 times)

Offline Jose Netra

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  • Posts: 2
Single circuit converts reactive to active power
« on: September 08, 2019, 05:03:59 AM »

Let's think in an AC circuit consist in a resistor R in series with a capacitor C connected to the power grid, inverter or any AC voltage power source of Amplitude V and frequency w

 But the resistor is not common, it changes his resistance according to this:

R(i)= k/i

As R dont can get negative values we can use the absolute value of i

R(i)= k/abs(i)

So resistance increases if current decrease and resistance decrease if current increases

Then the equation of the circuit is:

V*sen(w*t)= R*i + 1/C*q

V*sen(w*t)= k + 1/C*q

Where q is the charge in the capacitor

Solving this single equation for get the current:

i= dq/dt=C*V*w*cos(w*t)

Is the same solution for the case the voltage in the resistor is -k when current value is negative

So we can see current is at 90 degrees of phase shift from voltage, the power source see reactive pure power , the power source dont see the resistor, it vanishes because in the resistor there is a DC voltage
 This explain how some free energy devices  works as the "scalar charger" is a capacitor in series with a diode bridge has the battery connected to the positive and negative terminals of the bridge, this series circuit is connected direct to the power grid. A resistive load can be connected in parallel to the battery to make measurements of input and output power

Offline Bear

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  • Posts: 1
Re: Single circuit converts reactive to active power
« Reply #1 on: December 16, 2020, 03:30:09 PM »
There is a book on Amazon that addresses your issues with reactive power.  See the book named NIKOLA TESLA WIRELESS POWER SECRETS REVEALED. It goes into great detail about reactive power transfer and various receivers.