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Simple Overunity Method With Capacitors

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trevstar:
Hello all.
Has anyone tried the following method or are there any threads on this? I first saw this years ago.
"Make yourself a test set up. Use 2 large low voltage capacitors. Make sure one is about 1/2 the capacity of the other. Charge the smaller one fully and discharge it into the larger one. Take measurements on both before and after discharging them together to see how much power is transferred.
Now do the same with a small bulb in series as you discharge the small cap into the larger one. Measure the power levels in both caps. You will have some light produced and some heat, but the WHOLE charge is transferred to the other capacitor!!"
those paragraphs are quoted from the following site
www.linux-host.org/energy/sgcarter.html


The guy insists that it worked for him. There is some question about if the original charge remains in the smaller cap.    Has this been discussed here already?
Thanks,Trevor

poynt99:
Yes,


This "new idea" has been beaten to death a few times. There is no gain or OU, or Free Energy of any sort with this.


I did a detailed analysis of cap-to-cap energy transfer years ago. The file is still here.


https://overunity.com/downloads/sa/view/down/209/

trevstar:
Thanks,I appreciate the link.That answers the question.This has been discussed
Also, there is no overunity.
On to the next topic!
Trevor

shylo:
Hi Trevstar,
You can transfer a charged bank to an identical bank and preform work in the process.
You will lose some but not 50%.(with the right circuit)

The work I'm trying to do is running a generator/pulsemotor that adds charge to the banks so they don't deplete.
artv

Jeg:

--- Quote from: shylo on August 12, 2019, 10:41:19 AM ---Hi Trevstar,
You can transfer a charged bank to an identical bank and preform work in the process.
You will lose some but not 50%.(with the right circuit)

The work I'm trying to do is running a generator/pulsemotor that adds charge to the banks so they don't deplete.
artv

--- End quote ---

I agree with artv. I do the same and i have only 14% losses instead of 50%. I find it possible to reach even higher levels of efficiency.

ps. It is more appropriate to calculate energy than charges. https://www.electronics2000.co.uk/calc/capacitor-charge-calculator.php

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