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Author Topic: Simple Overunity Method With Capacitors  (Read 4998 times)

Offline trevstar

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Simple Overunity Method With Capacitors
« on: August 11, 2019, 05:24:48 PM »
Hello all.
Has anyone tried the following method or are there any threads on this? I first saw this years ago.
"Make yourself a test set up. Use 2 large low voltage capacitors. Make sure one is about 1/2 the capacity of the other. Charge the smaller one fully and discharge it into the larger one. Take measurements on both before and after discharging them together to see how much power is transferred.
Now do the same with a small bulb in series as you discharge the small cap into the larger one. Measure the power levels in both caps. You will have some light produced and some heat, but the WHOLE charge is transferred to the other capacitor!!"
those paragraphs are quoted from the following site
www.linux-host.org/energy/sgcarter.html


The guy insists that it worked for him. There is some question about if the original charge remains in the smaller cap.    Has this been discussed here already?
Thanks,Trevor

Offline poynt99

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Re: Simple Overunity Method With Capacitors
« Reply #1 on: August 11, 2019, 08:44:30 PM »
Yes,


This "new idea" has been beaten to death a few times. There is no gain or OU, or Free Energy of any sort with this.


I did a detailed analysis of cap-to-cap energy transfer years ago. The file is still here.


https://overunity.com/downloads/sa/view/down/209/

Offline trevstar

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Re: Simple Overunity Method With Capacitors
« Reply #2 on: August 11, 2019, 09:26:06 PM »
Thanks,I appreciate the link.That answers the question.This has been discussed
Also, there is no overunity.
On to the next topic!
Trevor

Offline shylo

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Re: Simple Overunity Method With Capacitors
« Reply #3 on: August 12, 2019, 10:41:19 AM »
Hi Trevstar,
You can transfer a charged bank to an identical bank and preform work in the process.
You will lose some but not 50%.(with the right circuit)

The work I'm trying to do is running a generator/pulsemotor that adds charge to the banks so they don't deplete.
artv

Offline Jeg

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Re: Simple Overunity Method With Capacitors
« Reply #4 on: August 12, 2019, 12:44:09 PM »
Hi Trevstar,
You can transfer a charged bank to an identical bank and preform work in the process.
You will lose some but not 50%.(with the right circuit)

The work I'm trying to do is running a generator/pulsemotor that adds charge to the banks so they don't deplete.
artv

I agree with artv. I do the same and i have only 14% losses instead of 50%. I find it possible to reach even higher levels of efficiency.

ps. It is more appropriate to calculate energy than charges. https://www.electronics2000.co.uk/calc/capacitor-charge-calculator.php

Offline trevstar

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Re: Simple Overunity Method With Capacitors
« Reply #5 on: August 12, 2019, 04:28:22 PM »
Well that is INTERESTING
Thanks Artv and Jeg. So I can discharge one cap into the other and run a load and only loose  14% of the charge.  That is promising.  Certainly worth looking into.

Offline Jeg

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Re: Simple Overunity Method With Capacitors
« Reply #6 on: August 12, 2019, 04:40:00 PM »
.... and only loose  14% of the charge. 

Hi
You should better look at the attached calculator above. Total charges are the same after discharge. Losses take place at the stored energy, because energy depends on the square of the voltage. :)

Offline trevstar

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Re: Simple Overunity Method With Capacitors
« Reply #7 on: August 12, 2019, 10:00:12 PM »
The work I'm trying to do is running a generator/pulsemotor that adds charge to the banks so they don't deplete.
artv

Do you have more info on this?  I have only basic electronics knowledge so please give the simplified version if you could.
Thanks,Trevor

Offline LazerBolts

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Re: Simple Overunity Method With Capacitors
« Reply #8 on: August 25, 2019, 06:42:52 AM »
The circuit seems far too elaborate to work which then would consume effort it appears to be published without providing adequate measurements.

Offline mmm4free

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Re: Simple Overunity Method With Capacitors
« Reply #9 on: June 20, 2022, 12:34:45 AM »
Hello all.
Has anyone tried the following method or are there any threads on this? I first saw this years ago.
"Make yourself a test set up. Use 2 large low voltage capacitors. Make sure one is about 1/2 the capacity of the other. Charge the smaller one fully and discharge it into the larger one. Take measurements on both before and after discharging them together to see how much power is transferred.
Now do the same with a small bulb in series as you discharge the small cap into the larger one. Measure the power levels in both caps. You will have some light produced and some heat, but the WHOLE charge is transferred to the other capacitor!!"
those paragraphs are quoted from the following site
www.linux-host.org/energy/sgcarter.html


The guy insists that it worked for him. There is some question about if the original charge remains in the smaller cap.    Has this been discussed here already?
Thanks,Trevor


Link is offline, take one of this snapshots.
https://web.archive.org/web/20140501000000*/http://www.linux-host.org/energy/sgcarter.html

Offline stivep

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Re: Simple Overunity Method With Capacitors
« Reply #10 on: June 20, 2022, 01:46:06 AM »
Yes,
This "new idea" has been beaten to death a few times. There is no gain or OU, or Free Energy of any sort with this.
I did a detailed analysis of cap-to-cap energy transfer years ago. The file is still here.
https://overunity.com/downloads/sa/view/down/209/
I absolutely agree.
OU doesn't exist, 
Perpetual motion doesn't exist,

Free Energy is just the energy that does not have to be paid for but it must come from somewhere
In other words if nature pays for this energy then this is Free Energy.
you may have free food at home. if you're Father pays for it too.

There is no gain nor OU nor any Free Energy or any sort of this in such  capacitor based configuration.
Thank you for your job, as you spend a lot of time to make PDF.

The only what I didn't see there is word impedance.
Resistance is only the property of DC , however it applies to AC only as purely resistive in it's nature <component.>*
Impedance is only the property of  AC characterized by
–XL inductive reactance
–XC capacitive reactance
whenever we are dealing with discharging capacitor we are dealing with AC and impedance- not with the resistance alone.
The same  is with e.g rectangular impulses were leading-edge and trailing edge are AC
and top of an impulse (the highest amplitude) is DC.


note:by word <component.>* we understand purely resistive resistor that does not have any reactive XL  and XC
        Coil in DC, is only resistive and is not  reactive.(no XL)
        Capacitor in DC acts as an open circuit and after is charged or discharged is no longer reactive. (no XC)
Wesley.

Offline nix85

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Offline norman6538

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Re: Simple Overunity Method With Capacitors
« Reply #12 on: June 22, 2022, 03:40:49 PM »
Stivep said "I absolutely agree.
OU doesn't exist, 
Perpetual motion doesn't exist,

Free Energy is just the energy that does not have to be paid for but it must come from somewhere
In other words if nature pays for this energy then this is Free Energy.
you may have free food at home. if you're Father pays for it too."

But that does not explain the Finsrud machine nor my pendulum that is dropped from 2pm and travels up to noon and falls back to 6pm....
The pendulum secret is in the magnetic spin. When mag polarity is flipped it does not work.

Norman

Offline kolbacict

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Re: Simple Overunity Method With Capacitors
« Reply #13 on: June 22, 2022, 05:00:39 PM »
my pendulum that is dropped from 2pm and travels up to noon and falls back to 6pm....
Norman
Not only did you succeed.
Here a friend writes that he also achieved something.
https://overunity.com/19160/overunity-phisics-experiment/msg568232/#msg568232
only to me nothing doesn't work . But I need it more than anyone...

Offline alan

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Re: Simple Overunity Method With Capacitors
« Reply #14 on: June 22, 2022, 05:31:53 PM »
The energy of capacitors is comparable to elastic compression. 

OU is possible, take a magnet, bring an iron ball to its field, and when it starts accelerating, the kinetic energy of the ball increases without energy input, W=F.s work is done. The energy input is EFTV.