revised calculations 3 (there were bad calculations in versions 1 and 2)
the energy density is, as should be expected very low, because gravity is
a weak force.
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assume:
float = 3 meters length by 0.33 meters radius.
approximate 10 feet by 1 foot
cylinder of 0.33 meters diameter or
0.165 meters radius by 3 meters length
= 0.25669285714285694 cubic meters of water.
0.2566 cu meters of water = 256.6 kilograms of weight or
565.7062 pounds of weight.
256.6 kilograms = 2516.3864 newtons.
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assume :
float chamber interior is 10.5 meters height, by 10.5 meters width,
by 0.5 meters depth into the page.
this means that the height of the lifting of the float
= 10.5 meters minus 1 float cylinder diameter.
this is = 10.5 m - 0.33 m = 10.17 m
the float is lifted to a total of twice this distance
10.17 m x 2 = 20.34 m total height of the float rise
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2516.3864 newtons x 20.34 meters = 5214.899376 joules of energy stored
as weight of the float external to the fluid chamber. OUTPUT
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assume:
it requires 25 kilograms of force or 245.1663 newtons, over a displacement
of 3 meters to INSERT the float.
245.1663 newtons x 3 meters = 735.4989 joules of work
it requires 25 kilograms of force or 245.1663 newtons, over a displacement
of 3 meters to REMOVE the float.
245.1663 newtons x 3 meters = 735.4989 joules of work
735.4989 newtons x 2 = 1470.9978 joules input work / energy. INPUT
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assume:
it requires 25 kilograms of force over a distance of 0.33 meters to initiate
/ accomplish a 180 degree rotation of the device.
25 kilograms = 245.1663 newtons
245.1663 newtons x 0.33m = 80.9048 joules of work
there are two 180 degree rotations during each complete cycle.
80.9048 joules x 2 = 161.8097 joules INPUT
...........................................................................
1470.99 joules input + 161.8097 joules input = 1632.7997 joules
(previously in error)
...........................................................................
5214.89 joules of energy stored as weight of the lifted float, while
external to the fluid chamber.
5214.899376 joules of energy stored - 1632.7997 joules total input
= 3582.0996 joules ENERGY YIELD
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assume:
a slow operation time to store that energy (not to use it) of 2 minutes
3582.0996 joules per every 2 minutes = 1791.0498 joules per minute.
1791.0498 joules per minute = 29.85083 joules per second or in other
words 29.85083 watts
(1791.0498 joules / 60 seconds = 29.85083 joules per second)
conservatively arrived at, this is 29.85083 continuous watts gained as
output power
or
29.85083 continuous watts if used for 1 hour = 29.85083 watt hours
and this is
716.41992 watt hours if continuously used for 24 hours
and this is
5.0149 kilowatt hours if continuously used for one week
and this is
20.0597 kilowatt hours if continuously used for one month
and this is
240.717 kilowatt hours if continuously used for one year
probably actually about 3 times this amount of energy.