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Author Topic: Tommey Reed’s new Clem Engine Build.  (Read 16486 times)

TommeyLReed

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Re: Tommey Reed’s new Clem Engine Build.
« Reply #15 on: May 20, 2019, 12:41:46 AM »
Hi all,


It’s getting big.

TommeyLReed

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Re: Tommey Reed’s new Clem Engine Build.
« Reply #16 on: October 19, 2019, 04:04:48 AM »
Hello All,
I have been very busy building this new version of the Clem engine I call a hydraulic implosion motor.
I have a few short videos to show off now of the build.
https://www.youtube.com/watch?v=6ITWZ20Gj6w
I will add that it's not completed yet because of testing the speed of rotation.
I will try to answer your question and some specs information.
Tom

TommeyLReed

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Re: Tommey Reed’s new Clem Engine Build.
« Reply #17 on: October 19, 2019, 04:16:19 AM »
I have a lot of short videos of the build.


https://www.youtube.com/watch?v=4Q7vfucSq_8
Tom.

Blackhawk

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  • Posts: 1
Re: Tommey Reed’s new Clem Engine Build.
« Reply #18 on: February 07, 2020, 08:45:15 AM »
Hi Tommey,

Can you tell me why you are building this build so large ??

Just curious.

Graeme

myover

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Re: Tommey Reed’s new Clem Engine Build.
« Reply #19 on: October 13, 2020, 11:37:49 AM »
Did you ever finish this build?  Any more videos you can post directly here, all your YouTube videos are down.

Sterlingsilverpound

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Re: Tommey Reed’s new Clem Engine Build.
« Reply #20 on: November 23, 2020, 11:33:33 PM »
https://www.youtube.com/watch?v=Ji0GAt-q2EM
Your going to get a kick out of this.

Sterlingsilverpound

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Re: Tommey Reed’s new Clem Engine Build.
« Reply #21 on: November 23, 2020, 11:46:29 PM »
When your ready with the external combustion engine I want to work with you on it. I have a way of increasing it's efficiency with magnetic repulsion.  No bologna.

Sterlingsilverpound

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Re: Tommey Reed’s new Clem Engine Build.
« Reply #22 on: December 05, 2020, 08:44:46 PM »
The experiment for R&D on James Roney's Contour Magnetic Runway Plate
Calculations
Joules of work = force x distance
Gravity 9.8m/sec ^2
1 netwon / 1 meter = .7376 ft/lbs per second is wattage
- unit of power is Watt, defined as joule per second. or .7376 ft/lbs

For example we have a 6.2 gram magnet and a distance of 10 centimeters
10 centimeters is .1 meter to find netwon we multiply magnet weight by gravity
distance second squared.
.0062 x 9.8 = 0.0608 newton
now multiply the newton by meter to get Joules
0.0608 x .1 meter = .00608 Joules
Work is measured in Joules but lets get the foot pounds
.00608 x .7376 = 0.04484608 ft/lbs

lets now do some more calculations of kinetic Wattages and real Work  wattage using the
example.

0.0608 newton x .1m = 0.0608 Joules

formula "Joules to Watts"
the power P in watts (W) is equal to the energy E in Joules (J), divided by the time period T in seconds
(S)... so the problem is  E(J)/T(S) = P(W)

Magnet rolling down
.00608 Joules / .47 seconds = 0.01293617 watts(Kinetic)
----
Magnet rolling up
.00608 Joules / .52 seconds = 0.011692308 watts(Work)

so if you take the difference of the watts you see gravity adds
0.001243862

We can see here magnet rolling up is basically free energy since it is
going against gravity with magnetic attraction/repulsion and only a slight loss in watts

Now if we apply this to a real world working engine, you can calculate the
boost by the speed / distance the rotor travels and have a fixed magnet.
or have a magnet rotating and a fixed metal plate. either way you can
calculate the boost.

Now the above calculations might not seem like much until you realize a 6 gram magnet is very small. If you use a 100 gram magnet now your getting 1 joule of power or 1 watt
and 300 gram would be 3 watt etc.. and we start getting into the 10s and 100s and 1000s of watts the heavier the magnet gets with gravity and velocity.
I am including a picture of a 100 gram magnet rolling up, 1 watt of "free energy"

Sterlingsilverpound

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Re: Tommey Reed’s new Clem Engine Build.
« Reply #23 on: February 21, 2021, 03:46:06 PM »