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Author Topic: questions and ideas that need input  (Read 1488 times)

Offline Belfior

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questions and ideas that need input
« on: February 11, 2019, 11:26:58 PM »
Had a hard time finding a category where to ask this, but I guess this is it.

I have a couple of questions/ideas that I have pondered upon and I hope you could correct me or confirm my thoughts. I will replace Ether with "quantum foam" so people do not foam. Now after writing the questions it seems there were more than I expected, but I feel I cannot proceed with any experiments, if the actual "causes" are eluding me

Some of these items are 'basic knowledge' for educated people and could be checked from a book, but what I am looking for is 'actual' knowledge that came from bench testing. I could also do all this bench testing on my own, but I think the purpose of these forums is to share knowledge and save years from other people. The reason I am asking is that I have seen multiple explanations for some effects and to me it means that the cause is unknown. How can I do any testing of my own, if all I can see is the effects and the cause is what ever my most recent 'educator' thinks it is? So wikipedia links I can go google on my own, but I  would like to hear from actual experience, if that is ok for you guys?

1. Electricity is manifested when quantum foam is stressed into movement (change) by a moving magnetic field and there is a conductor in the area of this movement. Doesn't need to be a coil. Can be hot gas even ie. a conductor

2. Electricity going through a coil starts slow and then blows out from the end. Like water in a bucket at the end of a string that is spun in a circle. When you cut the power that string is cut and the bucket flies outwards. You see this when a diode and a cap is after the coil. You get battery voltage + what ever was in the bucket in the cap. More than battery voltage anyway. That "blowing" or stretching in the coil now snaps back, because it was stretched further than where the coil was. The quantum foam that is the invisible spring being stretched here snaps back and cause the backEMF. This is larger than battery voltage and this is what strings do.

3. Positive and negative voltages depend on the agreed 0-level that is called ground. You can arbitrarely decide where this ground is. If your ground is at the positive end of 2x 9V batteries in series, then between the batteries is -9V and at the negative and you got -18V. More common example would be ground in the middle for 9V, 0V and -9V or just 18V and 0V when ground is at the negative end.

4. Now lets say you are standing in the actual circuit and looking along the wire. Positive voltage (to you) means positive pressure towards where you are looking at and charges move that way. If you are measuring negative voltage that means negative pressure (suction) and that means charges coming at you.

5. In an AC circuit there is no positive or negative terminal and you can swap your power plug which ever way you wasn't in the wall socket. When you are looking along the wire you see charges going and coming at you 50 times a second. The light bulb does not care which way the charges are going.

6. In the previous item the amount of electricity you are "using" is the what ever the bulb can turn to light and heat. Like two of your friends on your left and right side both pulling on a rope that goes around your wrist. They each pull 60 times a second and you get a nice rope burn on your wrist. The rope experiences a slight wear and tear from your wrist, but in Finland you pay rent for the whole rope in kW per hour. This is measured from either terminal. In Canada with the new smart meters they started to measure from both ends, so they now charge double.

7. I now put a diode between myself and my positive friend so that positive charge (rope) can come from my positive friend towards my wrist. This is now called a half-bridge and it is supposed to cut negative half waves off, but that negative half wave is rope coming towards my positive friend?!? Isn't that diode supposed to pass negative voltage from that direction towards my positive friend? What was cut off by the diode and what are the measuring points to achieve this? If I reverse the diode does my wrist get anything from my positive friend and does my negative friends rope now pass my wrist and somehow go against the reversed diode?!?

8. I just read that capacitor has one charge and on which plate this charge is located depends on the voltage applied. What happens if I connect a cap to positive 9V DC and leave the other leg disconnected? What happens if I do this with 9V AC?

10. What happens to charges if I connect both legs to 9V DC battery? Cap now has 9V, but what supplied the actual charges?

11. What happens in I use 9V AC? Both plates are continuously being charged with positive and negative charges? Where do the charges come from?

12. My cap now has 9V potential difference between the legs and that is charge depending on farads. Do I have positive charge on positive plate and none on the negative plate or do I have positive charge on positive plate and negative charge on negative plate?

13. If I ground the negative leg, the ground will change the plate potential to zero. I see no other way than the ground supplying the plate with positive charges. Do I now have a cap with both plates charged with positive charge?

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questions and ideas that need input
« on: February 11, 2019, 11:26:58 PM »

Offline Low-Q

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Re: questions and ideas that need input
« Reply #1 on: March 13, 2019, 06:52:25 PM »
Heard about step up converters (Or buck-converter as many call them)? They use the coil and switching DC to generate higher voltage. But to your surprize, these converters pulls a little more power at the input than you get out on the output. If you have 10V input at 2 Ampère, you got 20V output at less than 1 Ampére. The increased voltage comes from the collaps of magnetic field, just as ignition coils works.


Vidar



Offline Belfior

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Re: questions and ideas that need input
« Reply #2 on: March 14, 2019, 11:54:34 PM »
Heard about step up converters (Or buck-converter as many call them)? They use the coil and switching DC to generate higher voltage. But to your surprize, these converters pulls a little more power at the input than you get out on the output. If you have 10V input at 2 Ampère, you got 20V output at less than 1 Ampére. The increased voltage comes from the collaps of magnetic field, just as ignition coils works.


Vidar

Thank you very much. Actually I have found all the answers that I need.

Free Energy | searching for free energy and discussing free energy

Re: questions and ideas that need input
« Reply #2 on: March 14, 2019, 11:54:34 PM »
Sponsored links:




Offline F6FLT

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Re: questions and ideas that need input
« Reply #3 on: March 15, 2019, 11:49:24 AM »
...
3. ...You can arbitrarely decide where this ground is. If your ground is at the positive end of 2x 9V batteries in series, then between the batteries is -9V and at the negative and you got -18V. More common example would be ground in the middle for 9V, 0V and -9V or just 18V and 0V when ground is at the negative end.
...
There is no absolute potential, your reference is only an arbitrary choice. This is known as "gauge invariance".

Quote
8. I just read that capacitor has one charge and on which plate this charge is located depends on the voltage applied. What happens if I connect a cap to positive 9V DC and leave the other leg disconnected? What happens if I do this with 9V AC?
Answer in point 3: nothing happens. When you speak about "9v", what is your potential reference? The capacitor "doesn't know" which potential is your reference.

However, in "real life", things are not that simple. A capacitor as a whole constitutes the "plate" of another capacitor relative to the environment and the ground. Of course, it is very low (< pF) but nevertheless a very small current will flow when you change its potential. It is so small that people repairing high voltage lines over 100 KV are not endangered when, suspended in the air from the wire by insulating cords and constituting themselves a "capacitor plate", they connect themselves electrically to the line's potential.

This same principle explains single-wire transmission: the termination of the wire constitutes, with the ground and the environment, a capacitor allowing the current to pass through, especially with a high voltage and a high frequency for which the impedance of this capacitor is thus smaller and allows the current to pass better.


Quote
10. What happens to charges if I connect both legs to 9V DC battery? Cap now has 9V, but what supplied the actual charges?
The battery! In fact, it doesn't provides charges, it separate positive and negative charges.

Quote
11. What happens in I use 9V AC? Both plates are continuously being charged with positive and negative charges? Where do the charges come from?

The circuit is globally neutral. The electrons move from one plate to the other one, you just separate charges. There is no moving positive charges. In a capacitor, a "positive charge" is only a lack of electron, the real positive charges of the atomic nuclei are no longer neutralized by electrons.

Quote
12. My cap now has 9V potential difference between the legs and that is charge depending on farads. Do I have positive charge on positive plate and none on the negative plate or do I have positive charge on positive plate and negative charge on negative plate?

You have an excess of electrons on the negative plate and a lack of electrons on the positive plate. They just have moved.

Quote
13. If I ground the negative leg, the ground will change the plate potential to zero. I see no other way than the ground supplying the plate with positive charges. Do I now have a cap with both plates charged with positive charge?

The ground doesn't change anything inside the capacitor, you have just changed your potential reference. See points 3 / 8.


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