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Author Topic: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1  (Read 210400 times)

Offline George1

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Re: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1
« Reply #645 on: June 14, 2021, 02:51:56 PM »
Still no comments? Nobody here in this forum wants to save some electric energy in his/her household? :)

Offline George1

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Re: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1
« Reply #646 on: June 15, 2021, 11:41:07 AM »
Where is the brave pioneer spirit here in this forum? :) Looking forward to your comments.:)

Offline George1

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Re: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1
« Reply #647 on: June 17, 2021, 03:03:29 PM »
The text below is a copy of our post of April 24, 12:50:36 PM. (The text below has been published many times in this forum topic.)   
----------------------------
Have a look again at the book "Solved Problems in Physics", 2004, Volume 2, p. 876, solved problem 12.97. The author of this book is Prof. S. L. Srivastava (Ph.D.)
The same book can be found at the link https://books.google.bg/books?id=rrKFzLB9KQ8C&pg=PA876&lpg=PA876&dq=%22electrochemical+equivalent+of+hydrogen%22&source=bl&ots=tQ8PSMLet3&sig=ACfU3U2HOLB78XHl2o3q-JanapzSK-McJA&hl=bg&sa=X&ved=2ahUKEwjDpp2-zZXhAhWT5OAKHUfuBzUQ6AEwBHoECAkQAQ#v=onepage&q=%22electrochemical%20equivalent%20of%20hydrogen%22&f=false
--------------------------
For your convenience I am giving below the text of the problem and its solution.
--------------------------
12.97. In the electrolysis of sulphuric acid solution, 100 mg of hydrogen is liberated in a period of 20 minutes. The resistance of the electrolyte is 0.5 Ohm. Calculate the power consumed. Electrochemical equivalent of hydrogen is 1.044 x 10 -8 kg/C.
SOLUTION.
Prof. S. L. Srivastava's solution is given below.
Prof. S. L. Srivastava's solution consists of two lines only.
LINE 1. Current through the electrolyte is given by I = (m)/(Z x t).
LINE 2. Power consumed = (I) x (I) x (R) =  ((m)/(Z x t)) x ((m)/(Z x t)) x (R) = 31.86 W.
---------------------------
Prof. S. L. Srivastava stops here his calculations.
(The related solution's set of equations is not given here in order to save time and space. This set of equations however can be found in the book or in the link above.)
--------------------------
WE DEVELOPED FURTHER PROF. SRIVASTAVA'S SOLVED PROBLEM IN A NON-STANDARD MANNER.
OUR FURTHER DEVELOPMENT OF PROF. SRIVASTAVA'S SOLVED PROBLEM LED TO COP > 1.
HERE IS THE ESSENCE OF OUR APPROACH.
--------------------------
1) Let us calculate the inlet energy, that is, inlet energy = (31.86 W) x (1200 s) = 38232 Ws = 38232 J.
2) The Joule's heat, generated in the process of electrolysis is given by
Q = (I) x (I) x (R) x (t) =  ((m)/(Z x t)) x ((m)/(Z x t)) x (R) x (t) = (31.86 W) x (1200 s) = 38232 Ws = 38232 J = outlet energy 1.
3) HHV of hydrogen is 142 000 000 J/kg. Therefore the heat H, generated by burning/exploding of 0.0001 kg of hydrogen, is given by
H = (HHV) x (m) = (142 000 000) x (0.0001) = 14200 J = outlet energy 2,
where
m = mass of the released hydrogen
HHV = higher heating value oh hydrogen
4) Therefore we can write down the equalities:
4A) outlet energy 1 + outlet energy 2 = 38232 J + 14200 J = 52432 J
4B) inlet energy = 38232 J.
5) Therefore COP is given by
COP = 52432 J/38232 J = 1.37 <=> COP = 1.37 <=> COP > 1.
------------------------------
IMPORTANT NOTE. Constant pure water and cooling agent supply could keep constant the electrolyte's temperature, heat exchange, mass and ohmic resistance, respectively. Besides 0.0001 kg of hydrogen (and the related amount of the already split pure water) is small enough and can be neglected as a factor influencing the electrolyte's temperature, mass and ohmic resisitance.
-----------------------------
And one more interesting fact.
Literally the same solved problem can be found in an old Russian (still from the Soviet times) book "Сборник задач и вопросов по физике", 1986, p. 130, solved example problem 71. The authors of this book are Р. А. Гладкова and Н. И. Кутиловская. In the Russian version the data is a little different, that is, time is 25 minutes, the amount of generated hydrogen is 150 mg, Ohmic resisitance is 0.4 Ohm and the calculated power is 37 W.
Russians also stopped their calculations at 37 W.
Our further development of the Russian version led to the same COP = 1.37, that is, we have again the same COP > 1.
-----------------------------
IMPORTANT NOTE. The text above must be evaluated (SOLELY AND ONLY!) by highly qualified experts (Ph.D.) in electric engineering. Otherwise nothing will come out of it.
-----------------------------
Looking forward to your comments.

Offline George1

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Re: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1
« Reply #648 on: June 18, 2021, 02:09:03 PM »
COP = 1.37 <=> COP > 1. Looking forward to your comments.

Offline George1

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Re: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1
« Reply #649 on: June 19, 2021, 10:57:58 AM »
COP = 1.37 <=> COP > 1. Still no comments? No one here in this forum wants to save some small amount of electric energy? :)

Offline George1

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Re: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1
« Reply #650 on: June 21, 2021, 02:08:58 PM »
COP = 1.37 <=> COP > 1. Still no positive comments? :)

Offline George1

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Re: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1
« Reply #651 on: June 22, 2021, 12:06:49 PM »
Where is the brave pioneer spirit here in this forum? :) Where is the brave pioneer spirit, dedicated to new technologies? :)

Offline George1

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Re: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1
« Reply #652 on: June 23, 2021, 02:43:20 PM »
Waiting for your comments.

Offline George1

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Re: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1
« Reply #653 on: June 25, 2021, 02:35:58 PM »
COP = 1.37 <=> COP > 1. You could put a standard water-splitting electrolyzer in your basement and save a lot of money while heating your home during winter season. :)

Offline George1

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Re: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1
« Reply #654 on: June 26, 2021, 09:46:40 AM »
COP = 1.37 <=> COP > 1. Nothing can be done against the truth. :)

Floor

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Re: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1
« Reply #655 on: June 27, 2021, 09:10:32 AM »
The truth is your topic in just an attempted scam and click bait.

Floor

  • Guest
Re: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1
« Reply #656 on: June 27, 2021, 09:29:12 AM »
Your original stupid George1 scam attempt.

This is your original statement and attempt to get money. It is from the
first page of your topic here.
   @
https://mypicxbg.files.wordpress.com/2019/01/pages_1-6.pdf

Last page of that PDF is shown below as "George1 stupid scam"

So if you can't get $10,000,000 then what?
You'll  take the chump change from monetized hits here instead ?
How much does 138222 Views pay ?

You don't know nothing do you ?

One word answer only.
    Yes or No

Floor

  • Guest
Re: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1
« Reply #657 on: June 27, 2021, 04:20:32 PM »
@George1

Do you George1, believe this simple electric heater has efficiency
greater than 1 ?

Answer is NO, isn't it ?

Personally I think a person has some right to challenge
the proofs of science, its dogmas and so on.
If only that were the purpose for which you started
this topic, I would have not objections ?

Are you still trying to sell your "secret" technology ?




Offline George1

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Re: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1
« Reply #658 on: June 28, 2021, 09:44:18 AM »
To Floor.
----------------------------
Hi old cheater,:)
1) You again try to manipulate the audience in a clumsy and unskillful manner. Obviously you are not familiar enough with the art of successful manipulation. Your masters will not pay you your month's salary and will beat you. You have to run quickly!:)
2) Look again at my post of March 01, 2021, 03:58:45 PM. Let us proceed further with our previous questions as written in our post of March 01, 2021, 03:58:45 PM.
----------------------------
Prof. S. L. Srivastava's solution is given below.
Prof. S. L. Srivastava's solution consists of two lines only.
LINE 1. Current through the electrolyte is given by I = (m)/(Z x t).
LINE 2. Power consumed = (I) x (I) x (R) =  ((m)/(Z x t)) x ((m)/(Z x t)) x (R) = 31.86 W.
---------------------------------------
I am asking you (PERSONALLY!) my question for the 27th time: Is Prof. S. L. Srivastava's solution correct? Yes or no? Only one word -- either "yes" or "no"!
----------------------------------------
All members of this forum are waiting for your PERSONAL(!) answer for the 27th time. Only one word -- either "yes" or "no"!

Floor

  • Guest
Re: A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1
« Reply #659 on: June 28, 2021, 08:18:39 PM »
@ George1
 I repeat my simple question again.

You don't know nothing do you ?

One word answer only.
    Yes or No

 :)
 floor