Hi tinu,
1) Your idea sounds great, but could you be more specific?
2) About our leading researchers. (They are more than one.) Now they are preparing an answer related to your rejection of their COP > 1 concept. And for the present they would not like to be in the public eye.
Regards,
George     

Hi tinu,
While waiting for our experts to to prepare their sophisticated answer I considered carefully your yesterday posts.
There is something false and incorrect in your calculations.
Please answer the 6 questions below.
=====================
1) Vps = power supply voltage = 2 Volts. Is this correct?
--------------------------------------
2) Ips = current flowing through the electrolyte = 1 Ampere. Is this correct?
--------------------------------------
3) (Vps) x (Ips) = (2 Volts) x (1 Ampere) = 2 Watts = power, generated by the power supply. Is this correct?
--------------------------------------
4) R = 0.77 Ohm = ohmic resistance of the electrolyte. Is this correct?
--------------------------------------
5) Assume that Vps = 1 Volt. What will be in this case the value of Ips, that is, Ips = ? Ips = 0 Ampere?
--------------------------------------
6) Assume that Vps = 1.23 Volts. What will be in this case the value of Ips, that is, Ips = ?
--------------------------------------
Please answer the above 6 questions separately and clearly.
--------------------------------------
Next questions will asked in my next post.
Looking forward to your answer.
Regards,
George
   

 Hi George,
 
1. Yes
2. Yes
3. Yes
4. Yes, R=0.77 Ohm. This value is the equivalent resistance of liquid resistor DURING electrolysis only!
5. Vps=1V. No electrolysis is taking place. All power delivered by the power supply goes into Joule heating of electrolyte. Ips is unknown because R is unknown. In this regime R is not 0.77 Ohm but larger. Consequently, Ips=Vps/R. Surelly, 0<Ips<<1V/0.77Ohm. Ips can, of course, be easily measured.
6. Vps=1.23V. Still in Ohmic regime, while no electrolysis is taking place yet. All power delivered by the power supply goes into Joule heating of electrolyte. Ips is still unknown because R is unknown. Nonetheless, raising Vps further beyond 1.23V will start the electrolysis. This is a transient phenomenon, characterized by a relatively sharp increase in Ips because the equivalent resistance of liquid resistor (R) is dropping significantly due to an increase of ions concentration. However, it might be necessary to increase the voltage sufficiently high, until H2 and O2 will start forming bubbles, degassing out of the electrolyte and ensuring a stable regime for the electrodes. When full electrolysis kicks in, R is lowered to 0.77Ohm and Ips stabilizes at 1A.
 
Read carefully: I'm not here to answer your questions! Neither one of the members is. Now, having said that, the above small physics lesson is a favor I did for you. I won't do it again because on one hand, like I said, I'm on holiday and my vacation is rare and valuable and, on the other hand, this is basic knowledge and subject to bellow college-level class experiments. I'm well beyond that and you make me waste my time.
So, in conclusion:
(1). Please do your own experiments, publish the results here and then we can talk further, based on your actual data.
(2). Better yet, please bring in your leading scientist for further theoretical and practical discussions.
 
Again, please answer to the former question of mine:
(3). What is your formal training and expertise in the field?
(4). Where are you from?
 
We'll be hearing again when you fulfill (1)-(4).
In the meanwhile, please refrain yourself from posting invectives, fantasies and/or physical non-sense/absurdities, ok?


Regards.

 

Dear George1,I am very sorry but have to deny : I am not an expert in physics,  only an user.

I wish you fortune and success
wmbr
OCWL

                                           

Hey George1,
probably you and some team members read this works and results and discuss about it :

http://guns.connect.fi/innoplaza/energy/story/Kanarev/
                                       ------------------------------------
https://worldwide.espacenet.com/publicationDetails/biblio?CC=DE&NR=2733719A1&KC=A1&FT=D#
                 Compensation of magnetical ( attraction,repulsion)force                     

                                      -------------------------------------

https://worldwide.espacenet.com/publicationDetails/biblio?DB=EPODOC&II=1&ND=3&adjacent=true&locale=en_EP&FT=D&date=20121011&CC=US&NR=2012256422A1&KC=A1#
                           Above       [ 0092,0093,0094]. related :
For example : when a nominal 1000 W and 1000 RPM generator  by100 RPM only generates 1W,           

       100 RPM to 1000 RPM :                   ten times higher velocity ~ thousand times more power

             how many Watts consumes a coupled motor to achieve this 100 RPM ?!
   A. Continuous DC power motor B. Fractional AC pulse power motor

Hey again lancaIV,
And what about the link below?
https://overunity.com/16302/hho-as-real-uo-system/msg469903/#msg469903
Seems to be interesting and workable?
(Title "HHO as a real UO system", author John.K1, December 31, 2015. I wrote to this man many times, but he did not answer me.)
What do you think? What is your opinion about his suggestion?
Looking forward to your answer.
Regards,
George

Hi lancaIV,
Yes, an obvious disadvantage of John.K1's idea is that it is a "huge designed". Let us concentrate again then on the "small designed". We started considering already your penultimate post. Very interesting! I will write to you in the nearest future.
Regards,
George