To Floor.
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Prof. S. L. Srivastava's solution is given below.
Prof. S. L. Srivastava's solution consists of two lines only.
LINE 1. Current through the electrolyte is given by I = (m)/(Z x t).
LINE 2. Power consumed = (I) x (I) x (R) =  ((m)/(Z x t)) x ((m)/(Z x t)) x (R) = 31.86 W.
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I am asking you (PERSONALLY!) my question for the 22nd time: Is Prof. S. L. Srivastava's solution correct? Yes or no? Only one word -- either "yes" or "no"!
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All members of this forum are waiting for your PERSONAL(!) answer for the 22nd time. Only one word -- either "yes" or "no"!

To those members of good will in this forum, who are searching honestly for the truth.
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Ok, let us start from the very beginning. Please read carefully and thoroughly the text below.
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1) Let us consider a standard SOLID conductor. This could be for example a standard copper wire.
1A) A standard SOLID conductor is connected to a standard DC source thus forming a circuit.
1B) The circuit is equipped with a standard DC ammeter and with a standard DC ohmmeter.
1C) The ammeter registers a direct current, which is equal to 1A.
1D) The ohmmeter registers an Ohmic resistance, which is equal to 1Ohm.
1E) Each second the standard SOLID conductor consumes electric energy, which is equal to 1J, that is, (1A) x (1A) x (1Ohm) = 1J/s.
1F) Each second the standard SOLID conductor generates Joule's heat, which is equal to 1J, that is, (1A) x (1A) x (1Ohm) = 1J/s.
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2) Let us consider a standard LIQUID conductor (a standard electrolyte). This could be for example a zinc or copper sulphate solution or a sodium chloride (NaCl) solution (ordinary salty water) or whatever electrolyte you want. There are hundreds of standard ordinary electrolytes (LIQUID conductors).
2A) A standard LIQUID conductor is connected to a standard DC source thus forming a circuit.
2B) The circuit is equipped with a standard DC ammeter and with a standard DC ohmmeter.
2C) The ammeter registers a direct current, which is equal to 1A.
2D) The ohmmeter registers an Ohmic resistance, which is equal to 1Ohm.
2E) Each second the standard LIQUID conductor consumes electric energy, which is equal to 1J, that is, (1A) x (1A) x (1Ohm) = 1J/s.
2F) Each second the standard LIQUID conductor generates Joule's heat, which is equal to 1J, that is, (1A) x (1A) x (1Ohm) = 1J/s.
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3) In one word, the above two items 1 and 2 are an illustration of one of the basic axioms of electric engineering, which is given by the equality
A = I x I x R = B,
where
A = electric energy, which is consumed each second by the conductor
I = direct current, which flows through the conductor
R = Ohmic resistance of the conductor
B = Joule's heat, which is generated each second by the conductor
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4) Equality A = I x I x R = B is valid for any standard conductor (no matter solid, liquid or gaseous).
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5) Equality A = I x I x R = B can be found in any electric engineering beginner's guide/manual/textbook.
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6) But if the above mentioned axiom of electric engineering is not correct, then it's OK! Let us start creating then a new revolutionary branch of electric engineering with another basic axioms.
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Everything seems to be clear now, doesn't it? (But please ask questions, if any.)
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(to be continued)

To those members of good will in this forum, who are searching honestly for the truth.
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No questions as far as I can see -- an indication that everything is clear from our post of January 27, 2021, 03:51:29 PM. This is good. 
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So let us proceed further with our explanations, which we started in our previous post of January 27, 2021, 03:51:29 PM .
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1) Another basic axiom of electric engineering states that all LIQUID conductors (electrolytes) generate a great variety of additional effects (while direct current flows through them, i.e. while electrolysis takes place). Most frequently occurring and most important of these additional effects are as follows.
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1A) Additional effect 1. Transferring of metals from one electrode to the other. Examples of such metals are silver, zinc, copper, aluminium, nickel, chrome, gold, iron, sodium and magnesium.
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1B) Additional effect 2. Generation of chlorine.
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1C) Additional effect 3. Generation of oxygen.
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1D) Additional effect 4. Generation of hydrogen.
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1E) Additional effect 5. Some combination of the above four.
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2) Let us consider additional effect 1. Having in mind our previous post of January 27, 2021, 03:51:29 PM, we can write down that:
A) Each second the standard LIQUID conductor consumes electric energy, which is equal to 1J, that is, (1A) x (1A) x (1Ohm) = 1J/s.
B) Each second the standard LIQUID conductor generates Joule's heat, which is equal to 1J, that is, (1A) x (1A) x (1Ohm) = 1J/s.
C) Each second the standard LIQUID conductor transfers copper (or any of the above mentioned metals) from one electrode to the other.
Question: Can we burn/explode in some way the transferred copper in order to generate each second some additional portion of heat?
Answer: No, we can't. Metals are not inflammable under normal conditions.
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3) Let us consider now additional effect 2. Having in mind our previous post January 27, 2021, 03:51:29 PM, we can write down that:
A) Each second the standard LIQUID conductor consumes electric energy, which is equal to 1J, that is, (1A) x (1A) x (1Ohm) = 1J/s.
B) Each second the standard LIQUID conductor generates Joule's heat, which is equal to 1J, that is, (1A) x (1A) x (1Ohm) = 1J/s.
C) Each second the standard LIQUID conductor generates a certain amount of chlorine.
Question: Can we burn/explode in some way the generated chlorine in order to generate each second some additional portion of heat?
Answer: No, we can't. Chlorine is aggressive and dangerous for human health, but it is not inflammable under normal conditions.
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4) Let us consider additional effect 3. Having in mind our previous post of January 27, 2021, 03:51:29 PM, we can write down that:
A) Each second the standard LIQUID conductor consumes electric energy, which is equal to 1J, that is, (1A) x (1A) x (1Ohm) = 1J/s.
B) Each second the standard LIQUID conductor generates Joule's heat, which is equal to 1J, that is, (1A) x (1A) x (1Ohm) = 1J/s.
C) Each second the standard LIQUID conductor generates a certain amount of oxygen.
Question: Can we burn/explode in some way the generated oxygen in order to generate each second some additional portion of heat?
Answer: No, we can't. Oxygen supports the process of burning, but it is not inflammable by itself under normal conditions.
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5) Let us consider additional effect 4. Having in mind our previous post of January 27, 2021, 03:51:29 PM, we can write down that:
A) Each second the standard LIQUID conductor consumes electric energy, which is equal to 1J, that is, (1A) x (1A) x (1Ohm) = 1J/s.
B) Each second the standard LIQUID conductor generates Joule's heat, which is equal to 1J, that is, (1A) x (1A) x (1Ohm) = 1J/s.
C) Each second the standard LIQUID conductor generates a certain amount of hydrogen.
Question: Can we burn/explode in some way the generated hydrogen in order to generate each second some additional portion of heat?
Answer: Yes, we can. And here is the exception. If we burn/explode hydrogen immediately after its releasing, then we could generate each second 0.35J of additional heat.
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5-1) Therefore, having in mind the text above, we can write down that:
A) Each second the standard LIQUID conductor consumes electric energy, which is equal to 1J, that is, (1A) x (1A) x (1Ohm) = 1J/s.
B) Each second the standard LIQUID conductor generates Joule's heat, which is equal to 1J, that is, (1A) x (1A) x (1Ohm) = 1J/s.
C) Each second the standard LIQUID conductor generates a certain amount of hydrogen.
D) Each second the released hydrogen is burned/exploded immediately after its releasing.
E) Each second the burning/exploding released hydrogen generates 0.35J of additional heat, that is, 0.35J/s.
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5-2) In one word:
5-2A) The inlet electric energy, consumed each second, is equal to 1J/s.
5-2B) The outlet heat, generated each second, is equal to 1J/s + 0.35J/s = 1.35J/s.
5-2C) Efficiency = (1.35J/s.)/(1J/s) = 1.35 <=> Efficiency > 1.
5-2D) The latter is in perfect accordance with our further development of Prof. S. L. Srivastava's solution. (Please refer to our previous posts.)
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Everything seems to be clear now, doesn't it? Please ask questions, if any. We'll be glad to answer.

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