New theories about free energy systems > Understanding OverUnity

A very easy method for overunity and its the real deal as they say.

(1/19) > >>

 Its all about the ram pumps, if you dont know what they are then do a search on youtube or google. This was known about back in the day but somehow was forgotten, wonder how that happened. Anyway a ram pump works like this. Water from a reservoir flowing down hill a little ways then goes to a ram pump. The ram pump uses that little water pressure from the down hill flow and then pushes water up hill to a great distance far higher then your reservoir. And it does it all mechanically with no needed power source of any kind since a ram pump is powered by gravity itself. Now you can use many ram pumps that get water up hill fast and it can all come from one reservoir and you can have them all working at once as well. Then you allow that water to fall down hill through electric turbines that generate electricity just like how hydroelectricity is made. And you direct that water that is now falling down hill back into the same reservoir that you used to get the water from in the first place. That keeps it full of water, and you have free electricity generated in the process of it all. So yeah totally free electricity can easily be made. And this was known about long ago, just some how mysteriously forgotten, misplaced, and turned into hydroelectric dams of today that supply the power most pay for.

The flow you can raise is always less than the flow that provides the energy, so the system cannot be looped.

It's like a transformer, just because you have a small voltage in primary and a large one in secondary doesn't mean you can supply the former with the latter. Always the same confusion between potential (voltage or water level) and energy!

And posted in "Understanding OverUnity" when the basics of elementary school physics are not even mastered, what a pretentiousness!  ::)


The following is from a web site about ram pumps.

A ram pump uses the downhill flow of water to pump a portion of it uphill. You can pump up to 25 percent of your supply water, depending on the drop and the lift. Ram pumps will work on sites with 3 to 50 feet (0.9–15 m) of head (vertical drop) and can deliver to elevated sites far from the pump and source.

The formula for calculating the amount of water a ram pump can pump.
Water Delivered = Available Water x Source Fall x 0.5 ÷ Delivery Height           

We can see from the formula and information that 75% of the water goes on past the ram pump.  It has to in order for the pump to work.  We also can see that the amount of water a ram pump can pump depends on the source fall or head pressure getting to the pump.  So you can't put more of them in series because the lower ones won't have any head pressure.  And putting several of them in parallel will only work if you have a very large volume of water flowing downhill.  But even then each pump is only going to pump at most 25% of the water that is getting to that pump.  So you can't make a looping system where you keep pumping the same water back to the top.

And ram pumps have not been forgotten.  There are webs sites where you can buy them today.

You must see the "Thai pump" !
It's not a Heron fountain.

Take a tank full of water. Use the weight of the water, and force the water to go in one direction only.
In the top of the tank, you get the entry. In the bottom, it go out.
Entry is connected to the source, and the source is lower than the output, but the weight and the no return are running like a syringe (see the deformity on some tank).
Understand the potential.

Working solutions :

See also the Tesla valve, here :


--- Quote from: Xavier on January 16, 2019, 05:26:58 PM ---You must see the "Thai pump" !

--- End quote ---

It's not particularly Thai, it's the "siphon" principle!
"The word refers particularly to a tube in an inverted 'U' shape, which causes a liquid to flow upward, above the surface of a reservoir, with no pump, but powered by the fall of the liquid as it flows down the tube under the pull of gravity, then discharging at a level lower than the surface of the reservoir from which it came." (therefore no energy gain)


[0] Message Index

[#] Next page

Go to full version