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Author Topic: The book is dedicated to self-propelled mechanical generating devices.  (Read 60554 times)

Offline rakarskiy

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Re: The book is dedicated to self-propelled mechanical generating devices.
« Reply #150 on: November 30, 2021, 02:03:49 PM »
Hello
OK I'll try. But in the video he only has a power regulator and a BLCD driver. One interrupter and two relays and throttle. I don't know what the transformer is for yet.
Greeting
Lota
https://www.youtube.com/watch?v=2_nj9m2UEBs&t=0s

My article on the device, https://rakarskiy.livejournal.com/16587.html    my video in the article. There is also a diagram of how the power limitation works. For example, a generator for 24-36-48 V at nominal rotation, a thyristor control is organized through a voltage regulator relay for a 14 V car.  As with two-phase diode bridges, I showed above. This is not the exact solution of how it works, this is my guess. Logic suggests exactly this solution.

Floor

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Offline rakarskiy

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Re: The book is dedicated to self-propelled mechanical generating devices.
« Reply #152 on: December 02, 2021, 10:03:48 PM »
In general, there is a small idea that of course requires verification, at least somehow explains the difference.
In any wire, when creating a field, there is a voltage drop, in principle, we calculate it U = E - (I *R +r) the drop coefficient kU = E / U
and take it into account in the formula: calculating the distance r :

r =μ₀*I*kU/(2π*Bm)

Then for 1 kW of mechanical to 1 kW of electric, we go out jewelry, you just need to check the fulfillment of this dependence.

********

Theoretically, based on the DED experiment of measuring the Ampere force in the gap between magnets with a clamp, I established a direct relationship of the Ampere force with the level of voltage drop in the conductor. Just as the voltage drops by orders of magnitude, so the point of resultant magnetic induction of the conductor grows.

It can be concluded that the basic condition of the formula of the magnetic induction module of the electromagnetic force: B = F / L*I is based without taking into account the conductor field based on the electrical voltage. And in fact, it just probably matters. Direct dependence is too clearly cutting the eye

The Mitkevich equation is not correct, since it takes into account the EMF of the conductor, and the magnetic induction of the magnetic field, and follows the voltage at the terminals of the generator under load and the resulting magnetic induction, taking into account the voltage drop in the conductor.

Constant: B = F/L*I is derived for full power or absolute voltage drop. It turns out that way, in any case, this is the only explanation for the results. Taking into account this information, the mechanical power and electrical power of an ideal generator are equal. The problem is solved.


Offline rakarskiy

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Re: The book is dedicated to self-propelled mechanical generating devices.
« Reply #153 on: December 06, 2021, 07:58:03 PM »
My material is about the possibilities of electro-mechanical (electromechanical) converters
Some will turn their brains upside down, some will not be able to finish reading the first part. Alas, there is no point in reading without basic knowledge.

The material in Russian / through a translator can be read
The first part: http://rakarskiy.narod.ru/publ/free_energy_systems/ehlektromekhanicheskij_preobrazovatel_sor_gt_1_raschet_cepi/3-1-0-139
The second part: http://rakarskiy.narod.ru/publ/free_energy_systems/generator_torque/3-1-0-138
The third part: http://rakarskiy.narod.ru/publ/free_energy_systems/calculation_generator_motor/3-1-0-140

Quote:
Still, ask "why does the motor have this result". Let's look at the peak ampere strength in the generator winding and the active motor winding:
Generator: peak Ampere force of 128.86 Newtons (excluding electromagnetic focal thrust) with a thickness/length of the rotor along the axis of 74 mm (1.5 kW of electrical power)
Motor: peak Ampere force of 271.55 Newtons with a thickness / length of the rotor along the axis of 158 mm (0.396 kW of electrical power). How did it happen?
Understand, everything is in the material, I think there is enough material to just think about whether we know everything about electromechanical converters.

Offline rakarskiy

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Re: The book is dedicated to self-propelled mechanical generating devices.
« Reply #154 on: December 07, 2021, 07:23:10 AM »

Offline rakarskiy

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Re: The book is dedicated to self-propelled mechanical generating devices.
« Reply #155 on: December 09, 2021, 08:17:01 PM »
A caring guy conducted a demonstration experiment for me with a simple generator. For which I am very grateful to him!

Video clip: https://www.youtube.com/watch?v=yOq1TN3lnIo

My updated theory is fully confirmed. My analysis is on the slide, if you can read the formulas, everything can be seen in the palm of your hand.

I have already been asked questions about the motor that I described in the article.  I will do a full analysis and methodology in the manual.


Offline rakarskiy

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Re: The book is dedicated to self-propelled mechanical generating devices.
« Reply #156 on: December 10, 2021, 11:40:20 AM »
I analyzed the experiment more deeply and found inaccuracies in determining the magnetic induction of a magnet in the wire area.
My method is very correct, I am very happy about it.
The magnetic induction of the magnet can be calculated on this page:

https://www.kjmagnetics.com/calculator.asp?calcType=block

PS: I haven't found anywhere else yet, a similar methodology for calculating the resulting ampere force



« Last Edit: December 10, 2021, 04:30:27 PM by rakarskiy »

Offline bistander

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Re: The book is dedicated to self-propelled mechanical generating devices.
« Reply #157 on: December 11, 2021, 02:35:53 AM »

Offline rakarskiy

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Re: The book is dedicated to self-propelled mechanical generating devices.
« Reply #158 on: December 16, 2021, 10:35:11 AM »
In general, I corrected my calculations a little, and everything came closer to equilibrium. The coefficient for the resulting magnetic induction in the calculation of the ampere force must be calculated more simply k' =U' / E, where - U' is the dimension of the voltage drop U' = I*∑R the product of the current by the total resistance of the circuit, including the reactance (in electrical engineering, the inductive resistance x = L * f). As a result, everything converges to the point of correctness of the table data (up to 20 turns). If there were no reactance, then the electrical and mechanical power of the generator would be equal. 

https://www.youtube.com/watch?v=yOq1TN3lnIo&t=77s


Having studied and worked out the ampere power system, I immediately identified the engine option: two-phase. control of electric valves with compensation of the reactance of the circuit during switching.
I do not know what will come of it, but the calculation is still beneficial to the prospect.
 *

http://rakarskiy.narod.ru/_pu/1/92585013.jpg
« Last Edit: December 16, 2021, 02:56:47 PM by rakarskiy »

Offline rakarskiy

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Re: The book is dedicated to self-propelled mechanical generating devices.
« Reply #159 on: December 24, 2021, 08:39:22 PM »

Have a good time, friends!
Caring guy Rich, made a clarifying experiment for magnetic induction from a magnet in the area of the wire of his generator.

https://www.youtube.com/watch?v=VAM9TLfUDkQ&t=30s

Unfortunately, his measurements are inaccurate. The reason is its data on the current strength, the resistance of the circuit with the load, the voltage at the terminals of the generator at 15 turns.
These data are sufficient to calculate the magnetic induction from the magnetic pole in the area of the generator winding wire.

To find out the voltage drop during current induction, it is enough to multiply the resistance of the circuit by the current strength in the circuit:  U'=R*Ig = 4 Ohm * 1.3 A = 5.4 V
Next, the voltage at the terminals of the generator connected to the load is added to the drop voltage and we get the EMF of the generator:  E = U'+Ug = 5.4 + 10.4 = 15.6 V
The rate of change of magnetic induction is determined by this formula: v = π*r*rpm/30  it will be: 11,52 m / s.
The length of one coil of the active wire is 0.66 meters * 15 turns: L = 9.90 meters

Now we are from the EMF formula [E = Bm*L*v]  we can find magnetic induction: Bm = E/v/L  = 15.6V / 9.9 m / 11.52 m/s  =  0.1369 T  [As you can see, its value is not equal to 0.082 T].

you can use a calculator to calculate the magnetic induction and force for a magnet at a distance: https://www.kjmagnetics.com/calculator.asp?calcType=block

Next, to determine the resulting ampere force, you need to calculate the resulting magnetic induction, for this I recommend using my method of multiplying the resulting magnetic induction by the voltage drop coefficient:  k' = Ug/E  =  10.4 / 15.6 = 0.67   
If you want, call this coefficient - the Rakarsky coefficient, but it will not change the essence.

Next, we find the value of the resulting magnetic induction from the value of the magnetic induction of the magnet:  B = Bm * k'  =   0.1369 T  * 0.67  =  0.091 T.

Next, we find the ampere force and the electromagnetic moment, which is 0.065 N * m (yellow row of the table)

If we take the electrical power of the generator under load: 10.4 V * 1.3 A = 13.52 W, we can calculate its electromagnetic moment by the formula: Mg=Рg*9,55/rpm   = 13,52*9,55/2000 = 0,065 Nm.

The electrical and mechanical power of the generator are equal, the problem is solved.

Rich, thank you for the experiments, write me an email.


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Re: The book is dedicated to self-propelled mechanical generating devices.
« Reply #160 on: December 26, 2021, 04:55:54 PM »
@ rakarskiy 

nice presentation

        thanks
             floor

Offline rakarskiy

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Re: The book is dedicated to self-propelled mechanical generating devices.
« Reply #161 on: December 30, 2021, 03:49:51 PM »
@ rakarskiy 

nice presentation

        thanks
             floor

I have summarized a little the materials on the Ampere Force and the resulting magnetic force. It turns out quite a position that the magnetic induction of the wire, and the voltage drop across the active section of the conductor (in fact, the dimensionality of the vortex electric field) is the main parameter for the resulting electromagnetic force. This moment is not depicted in any way in the physics textbooks of secondary and higher schools.

https://rakarskiy-narod-ru.translate.goog/publ/free_energy_systems/rezultirujushhaja_sila_ampera/3-1-0-146?_x_tr_sch=http&_x_tr_sl=ru&_x_tr_tl=en&_x_tr_hl=ru


Offline kolbacict

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Re: The book is dedicated to self-propelled mechanical generating devices.
« Reply #162 on: February 27, 2022, 08:37:49 PM »
And in Slobodyan's motor, is it important that the poles of the magnets be in two dimensions?
In the form of a long drum.