Author Topic: The book is dedicated to self-propelled mechanical generating devices. (Read 83449 times)

rakarskiy · « **Reply #135 on:** November 22, 2021, 09:03:38 PM »

Quote from: Floor on November 22, 2021, 02:50:44 PM

@ Mr. Rakarskiy

First, I wish you success in your free energy explorations.

Second, it is up to you (the presenter) to prove or show experimentally
any O.U. results you might claim.

Third, It is not up to others (i.e. bistander) to disprove O.U. claims. It is reasonable
that the burden of proof rest upon any claimant of what is extra ordinary, to demonstrate
and CLEARLY AND PLAINLY describe their method or device,

and

to show measurements along with the methods of how those measurements were taken.

best wishes
floor

Floor, Thank you!

We are conducting research! I hope it will be useful to someone. My goal is to create transparent technologies available for creating devices for generating energy without fuel in a closed cycle.

Unfortunately, the technology that we are "discussing" here is really very expensive, though. The main thing is that the pattern I described is logical.

All the best!

rakarskiy · « **Reply #136 on:** November 25, 2021, 02:35:37 PM »

I calculated the electromagnetic moment of the simplest generator and the Ampere force. Yes, indeed, the peak: electrical power is equal to mechanical power.

Something very interesting showed up, with variations in ampere-strength. Discoveries are ruled by chance!

We will consider how to make a generator in the area of research of Adams and Tewari.

https://rakarskiy-narod-ru.translate.goog/publ/free_energy_systems/generator_torque/3-1-0-138?_x_tr_sch=http&_x_tr_sl=ru&_x_tr_tl=en&_x_tr_hl=ru&_x_tr_pto=nui

rakarskiy · « **Reply #137 on:** November 26, 2021, 08:41:42 AM »

Later, the author apologized for the mistake, telling in the first video about the orientation of the magnets in the yoke. Its installation option is the same as in the first picture. This is confirmed by constant physics, according to which the higher the density of the magnetic flux (magnetic induction), the more effective the Ampere force. It remains unclear why science claims that mechanical and electrical power are equal, when in the case of the simplest electric machine at the point of maximum EMF and current in the circuit, mechanical power is twice as much as electric, in an ideal machine without cores. The condition of an ideal flow that permeates a conductor with a current, if the conductor or the field move one side to each other, only the condition of the resulting force = 1/2 Ampere of force is fulfilled.
The opening didn't work out!

) In any case, we are moving on to complex systems.

We need to look for a solution for the generator design that would have an efficiency coefficient greater than 1. This is what we will do on the pages of my manual. Today there is a variant of such a machine with pronounced poles, which excludes the complete closure of the magnetic flux in the magnetic circuit - the rotor-stator, painted and implemented in the theory of Robert Adams with a vivid illustration in the patent of Karl Latmmer 1983-86 (Australia). Also consider a system with an inertial drive flywheel. The flywheel has an interesting feature in the overclocked state, when the operation of the system is organized in the overclocking-eat mode. Acceleration is carried out from the point when the application of force for acceleration is minimal, and removal is carried out by braking the inertia of the flywheel, through the control of the removed power, to the point of acceleration. It is on this principle that the installation of the autonomous generator "Earth Engine" is built by Соmpany IE, USA. And yet, at the request of readers, we will consider in more detail, and find the optimal variant of the machine described in my book "A-Generator"

rakarskiy · « **Reply #138 on:** November 26, 2021, 05:27:25 PM »

I recently received a letter from my long-time reader, a clear supporter of the Law of Conservation of Energy.
I think he won't be offended if I publish it!

Quote

Good time!
Have you solved this problem yet? Are there any other unresolved issues?
You yourself have hastened to make sudden conclusions, my restless friend, and haste is a bad companion on a journey.
You have found the grain of how a wire interacts with a current in a magnetic field. You have very little left.
Your efforts with your friend are very commendable. You just need to be able to set yourself the right tasks to conduct practical tests.
Traditionally, thrust force measurements are carried out!
In fact, when testing a laboratory sample, this condition has just been met. The wire with the current stuck to the magnetic pole with a force corresponding to the gap between the wire and the magnetic pole, the magnetic induction of the magnet at this point and the current strength in the wire along the entire length of the attraction zone. The force of attraction was determined by the distance between the sources of the magnetic field. Have you really not heard anything about such an element of the magnetic field force as lines of force, which, as I will point out to you, are capable of contracting and stretching. In the drawings they are called isolines. Their densest manifestation will be at the pole. You should also make an imitation of a wire with a current with a gap, without shifting to the edges of the poles of the magnet. In my last post, I recommended that you use an incompressible non-magnetic material superimposed on the poles of a magnet. In the generator, this distance does not change to establish the truth, it cannot be changed in the experiment. In addition, it is necessary to eliminate the friction force of the movable element. I recommend making such an element with the possibility of changing the gap. The magnetic clamp must have a cross-section equal to the cross-section of the magnet, the magnetic resistance in the magnetic circuit has not been canceled.
I have given you a drawing, you have the opportunity to depict it in a more visual form using electronic means. The red color indicates only the condition of the gasket at a constant distance when measuring magnetic thrust. It is impossible to apply the ampere force constant without taking into account many factors. I hope that you will do everything right and make sure that the Law of Conservation of Energy does not need to be ignored.

https://youtu.be/EaJQ3igxD_U

I have a clear excess of two times the mechanical power over the electrical.

A perfect calculation indicates a mismatch. I calculated the ideal generator circuit for 1 kW, if we take into account the length of the active wire and the current in the circuit with the condition that the EMF voltage drops to the mains voltage level according to the formula I = E-U / R+r, just the resulting electrical power is two times less than the mechanical power on the shaft.

I have a clear calculation for today.
The power of the electric machine is "considered" from the maximum EMF, then 440V * 4.55 A = 2002 W (2 kW), which is confirmed by the calculation through the Ampere Force and the electromagnetic moment.
The power of the load is 1 kW at 220 V, (1000/220 = 4.55 A). In
order to obtain a current in the circuit for the load at the appropriate voltage, an appropriate no-load EMF is required.

It still remains to find out the correctness of the calculation of the ampere force / electromagnetic force.

PS: my mistake was just in the incorrect application of the value of r in the formula: B=μ₀*I/2nr. I took it for the distance to the magnetic pole - 1 mm. It was necessary to specify the distance when the opposite magnetic inductions are equal, that's the thing. I was instructed to perform a balance, which actually determines the Law of Conservation of Energy.

rakarskiy · « **Reply #139 on:** November 27, 2021, 02:42:53 PM »

Just a basic calculation. In the statement of the constant: 1 Tesla = 1 Newton / 1 Ampere * 1 meter, the dimensionality of the distance of the field boundary of the wire for equilibrium with the external field is equal to the minimum, in fact, the surface of the conductor. I calculated both conditions. In reality, based on the experiments conducted, there was not a single case that the distance was equivalent to the surface of the conductor.

rakarskiy · « **Reply #140 on:** November 28, 2021, 05:23:59 PM »

In any case, in the simplest generator, at ideal values, the mechanical power on the shaft is twice the electrical power of the load.

That's where the discrepancy is so far! We decide further.

An interesting parallel between ampere power and two wires with current. In both cases, the length is 1 m, and the current is 1 A.
The distance of a wire with a current of 1 A, when its induction is 1 Tl, is at a distance of 0.0000002 m (seventh decimal place). It is at this boundary of the field that the wires and the external flow interact with each other, and the external field cannot compress the wire field further.
If we consider two conductors with a length of 1 m, with a current of 1 A, then the distance of 0.0000002 m between the wires with magnetic induction circuits of 1 Tl, the force of attraction of the wires will be 9.86 Newtons (gravitational constant 9.81).
If we assume that the second conductor is an external magnetic field, then to calculate the power of the amplifier as a result of the attraction force of 1 N, the current in it will correspond to 0.1 A.
It can be concluded about the ratio of the current to the magnetic induction of the field, who is the helmsman, in the condition of the "Ampere Force".

bistander · « **Reply #141 on:** November 28, 2021, 11:56:19 PM »

Quote from: rakarskiy on November 27, 2021, 02:42:53 PM

Just a basic calculation. In the statement of the constant: 1 Tesla = 1 Newton / 1 Ampere * 1 meter, the dimensionality of the distance of the field boundary of the wire for equilibrium with the external field is equal to the minimum, in fact, the surface of the conductor. I calculated both conditions. In reality, based on the experiments conducted, there was not a single case that the distance was equivalent to the surface of the conductor.

Mr. Rakarskiy,
I mentioned previously you misapply Ampere's Force Law. Now you use a units definition as a method to calculate a variable. It is not an equation intended for such use.
bi

(edit) excuse me please. I have lost the URL where I copied the graphic used. Similar can be easily found by search for "physics units of tesla".

rakarskiy · « **Reply #142 on:** November 29, 2021, 12:11:02 PM »

Quote from: bistander on November 28, 2021, 11:56:19 PM

Mr. Rakarskiy,
I mentioned previously you misapply Ampere's Force Law. Now you use a units definition as a method to calculate a variable. It is not an equation intended for such use.
bi

(edit) excuse me please. I have lost the URL where I copied the graphic used. Similar can be easily found by search for "physics units of tesla".

Listen, "the expert who failed the test", what Tesla and Gauss are ( probably heard about such a dimensionality of the magnetic field), I have charmingly known since the 80s of the last century. I can count very well, even better than many.

Quote

Tesla as a unit of measurement:
Tesla is a unit of measurement of magnetic flux density, magnetic field strength and induction in the International System of Units (SI), named after the inventor Nikola Tesla.

Tesla as a unit of measurement has the Russian designation - Tлl and the international designation - T.

1 tesla is equal to the induction of such a homogeneous magnetic field in which a force of 1 newton acts on 1 meter of the length of a straight conductor perpendicular to the magnetic induction vector with a current of 1 ampere. In other words, one Tesla is equal to the field strength acting on a conductor with a force of one newton per meter of conductor at a current strength for each ampere of current.

Similarly, one Tesla represents a magnetic flux density of one weber per square meter of area.

T = kg / (c² · A) = N / (A · m) = Wb / m².

1 T = 1 kg / (1 s² · 1 A) = 1 N / (1 A · 1 m) = 1 Wb / 1 m².

Tesla was introduced into the International System of Units by the decision of the XI General Conference on Weights and Measures in 1960, simultaneously with the adoption of the SI system as a whole. In accordance with the SI rules concerning derived units named after scientists, the name of the Tesla unit is written with a lowercase letter, and its designation is capitalized (Tl). This spelling of the designation is also preserved in the designations of derived units formed using Tesla.

I suggest you do your calculation! If you can't, then it's better to just be a spectator. Otherwise, the employer is uneven, read your conclusions

bistander · « **Reply #143 on:** November 29, 2021, 01:33:20 PM »

Rather cumbersome isn't it? And in the end will prove nothing due to circular reasoning. Why not just build your toy simplest generator and test it? 1700% efficiency published in your book. And that wasn't worth building the simplest generator and a test.
bi

Floor · « **Reply #144 on:** November 29, 2021, 01:58:16 PM »

@ rakarskiy

Build and test your principle in a simple experiment.

floor

rakarskiy · « **Reply #145 on:** November 29, 2021, 02:29:54 PM »

Quote from: Floor on November 29, 2021, 01:58:16 PM

@ rakarskiy

Build and test your principle in a simple experiment.

floor

What's the point of building it when I found a bug.

In the calculations of the magnetic induction of the wire, I set the distance from the wire to the pole equal to 1 mm (the gap distance between the wire and the pole). With the help of my friend, this error was proved experimentally. This distance should be taken into account in an ideal state according to the formula:(r = μ₀*(2π*Bm / I) ), where Bm is the magnetic induction of the external field. this distance will indicate where the inductions of the external field and the conductor are equal.
The algorithm for calculating the generator and the circuit with the generator is absolutely correct.

Your friend is just a little crazy. I don't take anyone's word for it, just calculation. And our friend is very slow to think. If you want to have a dialogue with me, you need to process information faster.

If initially the constant that in an ideal engine and generator their power - electrical and mechanical, are equal, was questioned. The possibility of creating a simple generator with a СОР>1 was considered.
Now, if we calculate the power of the maximum EMF point and the torque, the mechanical power is always twice as much as the electrical one. And here's another catch, due to the reversibility of machines, the possibility of creating an electric motor with a conversion efficiency greater than 1, which cannot be.

They have already tried to prove to me that it is necessary to take into account the voltage drop in the generator circuit, I do not agree with this, since the moment is calculated from the current strength. No one has solved this problem yet. The constant is not executed.

Floor · « **Reply #146 on:** November 30, 2021, 06:53:25 AM »

Quote from: rakarskiy on November 29, 2021, 02:29:54 PM

What's the point of building it when I found a bug.

No point... since you found a bug... unless more / other insights comes from a build.

best wishes
floor

lota · « **Reply #147 on:** November 30, 2021, 07:54:15 AM »

Hello
now you have calculated so much. Whether everything is right or not? But how should the generator for TOYIR Kamolov bike be? It is four poles. The diameter approx. 160mm the width approx. 80mm. With neodymium magnets. Wire approx. 0.5mm. Can you do the math?? I built the engine with flywheel but the generator is the problem.
Greeting
Lota

rakarskiy · « **Reply #148 on:** November 30, 2021, 10:02:44 AM »

Quote from: lota on November 30, 2021, 07:54:15 AM

Hello
now you have calculated so much. Whether everything is right or not? But how should the generator for TOYIR Kamolov bike be? It is four poles. The diameter approx. 160mm the width approx. 80mm. With neodymium magnets. Wire approx. 0.5mm. Can you do the math?? I built the engine with flywheel but the generator is the problem.
Greeting
Lota

If such as that of TOYIR (Uzbekistan), the generator should be controlled by the power of the phase (the simplest power regulator). At the output of the generator phase, put a bridge and a regulator with a thyristor in front of it, find the position when the flywheel and the motor are working, and the generator does not slow it down more than necessary. This is the only correct solution for a traditional generator with an inertial drive. So it was decided in all successful projects, including the American "Earth Engine"https://rakarskiy.livejournal.com/12789.html .

Each phase has its own power regulator

lota · « **Reply #149 on:** November 30, 2021, 01:07:29 PM »

Hello
OK I'll try. But in the video he only has a power regulator and a BLCD driver. One interrupter and two relays and throttle. I don't know what the transformer is for yet.
Greeting
Lota
https://www.youtube.com/watch?v=2_nj9m2UEBs&t=0s

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Author Topic: The book is dedicated to self-propelled mechanical generating devices. (Read 83449 times)

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