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Author Topic: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?  (Read 212801 times)

lltfdaniel1

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George1

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Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #391 on: March 01, 2021, 03:35:45 PM »
Let us shorten our previous explanations (of February 26, 2021, 04:01:00 PM) by jumping directly to PART 3 (and having a brief glimpse at a small section of PART 2).
----------------------------------------
So let us start our shorter explanations.
----------------------------------------
1) Firstly, please have a look for a while at PART 2 and at the related link https://youtu.be/aVOfWLDrYwA from 00:00 to 00:03. This is only for getting a notion about the limits of the segment "s", that is, how this segment "s" is situated in relation to (relative to) the zigzag section.
----------------------------------------
2) Now let us focus on PART 3 and on the related link https://youtu.be/pPGPktU_kpo . The experiment is carried out in a space station under weightlessness conditions. Friction is negligible as the only exception is the friction inside the two straight-line channels of the segment "s". (The inside surfaces of the straight-line channels of the segment "s" are made rough thus able to generate friction (and heat, respectively).)
----------------------------------------
3) The mass of each blue component is Ma.
-----------------------------------------
4) The mass of each black component is Mb.
-----------------------------------------
5) There are four couples blue ball/blue rod. Each blue ball is firmly attached to the related blue rod thus forming one united whole.
-----------------------------------------
5A) The mass of each blue ball is negligible (if compared to Ma or to Mb), but not equal to zero.
-----------------------------------------
5B) The mass of each blue rod is negligible (if compared to Ma or to Mb), but not equal to zero.
-----------------------------------------
6) From 00:00 to 00:03 the two blue components move simultaneously and uniformly. Each blue component's linear velocity is V' as V' = const. The two black components are at rest.
------------------------------------------
7) At 00:03 the four blue balls enter simultaneously (a) the "upper" black component's smooth zigzag channels and (b) the "lower" black component's rough straight-line channels of the segment "s", respectively.
------------------------------------------
8) From 00:03 to 00:15 the four blue balls move (a) inside the "upper" black component's smooth zigzag channels and (b) inside the "lower" black component's rough straight-line channels of the segment "s", respectively.
-------------------------------------------
9) At 00:15 the four blue balls exit simultaneously (a) the "upper" black component's smooth zigzag channels and (b) the "lower" black component's rough straight-line channels of the segment "s", respectively.
-------------------------------------------
10) The force of friction inside the two rough channels of the segment "s" is chosen in such a manner (we could use for example a variable roughness and the related variable force of friction, respectively) that:
-------------------------------------------
a) the blue components decelerate in one and same manner, that is, their decelerations are one and same and equal one to another;
-------------------------------------------
b) the black components accelerate in one and same manner, that is, their accelerations are one and same and equal one to another.
-------------------------------------------
11) From 00:15 to 00:17 the two blue components move simultaneously and uniformly. Each blue component's velocity is V" as V" = const.
-------------------------------------------
12) From 00:15 to 00:17 the two black components also move simultaneously and uniformly. Each black component's velocity is V"' as V"' = const.
-------------------------------------------
13) Therefore for the "upper" zigzag modification we can write down that
(Ma) x (V') = ((Ma) x (V'')) + ((Mb) x (V''')) (1)
(1/2) x (Ma) x (V') x (V') = ((1/2) x (Ma) x (V'') x (V'')) + ((1/2) x (Mb) x (V''') x (V''')) (2)
-------------------------------------------
14) And for the "lower" straight-line modification we can write down that
(Ma) x (V') = ((Ma) x (V'')) + ((Mb) x (V''')) (1)
(1/2) x (Ma) x (V') x (V') = ((1/2) x (Ma) x (V'') x (V'')) + ((1/2) x (Mb) x (V''') x (V''')) + Q (3),
where Q is the heat, which is generated while the two blue balls move inside the two rough channels of the segment "s" in the "lower" modification.
------------------------------------------
15) It is evident that (a) the system of equations in item 13 and (b) the system of equations in item 14 cannot be true simultaneously.
------------------------------------------
16) And it directly follows from the previous item 15 that either (a) the law of conservation of linear momentum is not correct or (b) the law of conservation of mechanical energy is not correct or (c) both the law of conservation of linear momentum and the law of conservation of mechanical energy are not correct simultaneously.
------------------------------------------
17) Please refer, if necessary, to our first post of Sat Jul 28, 2018 12:41 and to the two related links
https://mypicxbg.files.wordpress.com/2018/04/pages_01-12.pdf
https://mypicxbg.files.wordpress.com/2018/05/figs01-08.pdf
------------------------------------------
Looking forward to your answer.


George1

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Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #392 on: March 01, 2021, 03:46:18 PM »
In our last post because of some defect of the system some stupid yellow head with black spectacles replaced number eight. So the  yellow head with the black spectacles to be read as/to be replaced with number eight (item eight).   

George1

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Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #393 on: March 01, 2021, 03:51:59 PM »
To lltfdaniel1.
--------------------------------
Very, very interesting links! Congratulations! Welcome to our team! :) We need enthusiasts like! :)

George1

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Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #394 on: March 02, 2021, 03:38:18 PM »
Some comments, opinions or recommendations, related to our post of March 01, 2021 03:35:45 PM?

George1

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Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #395 on: March 02, 2021, 03:41:12 PM »
To lltfdaniel1.
-------------------------------------------
And what about the link https://endalldisease.com/hyperdrive-free-energy-gerard-morin/
Really amazing! Does this machine really work? How to build it? Some more information?
Welcome to our team! :) We need enthusiasts like you! :)

lltfdaniel1

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Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #396 on: March 02, 2021, 05:30:52 PM »
Yes that website has interesting devices,


No idea if it works, as for how to build it i know they sell kits


They sell kits for hyper drive here > https://www.hyper-drive-hv.com/


Also you can ask any question here > https://www.hyper-drive-hv.com/contact-us/

You could ask them for plans and how it is meant to work but i am willing to consider buying parts so you can put them together and with your knowledge determine if it works or not.

Always a risk if you don't know and maybe scams but i am optimistic but a little sceptical because i believe in free energy.

I am willing to buy what you need and be out of my way but it is best to know exactly how this works before i buy anything or if you need parts or you do all the parts yourself.

I know that you studied physics and taking a proper look at it and then started questioning it but you will need every detail as to how this hyper drive works which is sensible in my opinion (this is where some people start)

I don't know where to get every detail claimed and explanation for this hyper drive.

despite that there are videos to explain it but we need professional know how as to how this is supposed to work > https://www.youtube.com/results?search_query=Hyper+Drive+-+Gerard+Morin

Anyways... you could study about bedini motor here > https://thingiverse-production-new.s3.amazonaws.com/assets/93/06/22/d6/ec/Instructions.pdf and image of the 3 books here > https://i.ibb.co/PhLBdqh/Screenshot-2021-02-13-at-18-41-05.png

I recommend study bedini generator motor because he gives the explanations as to how it is meant to work well enough and then decide if it is bunk or not but i remember looking at a university page for the bedini generator motor and it achieved a cop over 1 for sure.

Another link about bedini > http://www.panaceatech.org/John%20Bedini%20Technology.pdf


Dan.

George1

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Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #397 on: March 04, 2021, 03:10:42 PM »
Hi Dan,
Hi dear colleague,
Thanks a lot for your reply. It is always a great pleasure for me to correspond with you! :)
Your last post contains again a very interesting information. I will consider it very carefully. But meanwhile I would like to ask a question: Is it possible to buy directly this device from somewhere and then put it in your basement for example thus satisfying all energy needs of your household? Are there any households in the world which satisfy their energy needs by using this machine?
Looking forward to your answer.
Regards,   

lltfdaniel1

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Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #398 on: March 04, 2021, 07:40:12 PM »
I have looked everywhere and no i cannot find a fully assembled device.


Instead i sent the inventor an email asking for a assembled device.


Dan.

George1

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Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #399 on: March 05, 2021, 02:40:52 PM »
Hi Dan,
Hi dear colleague,
1) Yes, you are absolutely right! The best approach is to get firstly an assembled device! And to test this assembled device for a certain period of time.
2) And what is the inventor's answer? When will he send to you an assembled device?
Looking forward to your answer.
Regards,
---------------------------------
P.S. I will follow your path and will also send the inventor an email asking for an assembled device.
 
 

lltfdaniel1

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Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #400 on: March 05, 2021, 04:12:25 PM »
To George,


I am still waiting for an email from the inventor, i hope he is not too busy and responds.


Dan

George1

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Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #401 on: March 08, 2021, 02:35:07 PM »
To Dan.
-------------------------------
The same for me. Waiting for an email from the inventor.
Regards,

George1

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Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #402 on: March 08, 2021, 02:46:17 PM »
Please look again at our post of March 01, 2021, 03:35:45 PM. Any comments, questions, recommendations, related to this post?

George1

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Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #403 on: March 09, 2021, 02:30:51 PM »
Please look again at our post of February 26, 2021, 04:01:00 PM. A copy of this post is given below.
=========================
Our simulation/animation is given below.
=========================
Firstly, please always keep in mind and please always refer to our first post of July 21, 2018, 02:11:37 PM and to the related two links
https://mypicxbg.files.wordpress.com/2018/04/pages_01-12.pdf
https://mypicxbg.files.wordpress.com/2018/05/figs01-08.pdf
--------------------------------------------
Secondly, our simulation/animation presentation is subdivided into three consecutive separate parts for an easier understanding.
=========================
PART 1. Please look at the link https://youtu.be/9cBGurYSryw
1) The zigzag device and the straight-line device are put together vertically one to another and are fixed motionless to a horizontal motionless plane.
2) The two blue T-shaped components start free falling together and simultaneously. Friction is negligible.
3) In the straight-line case the T-shaped blue component falls freely without any interruptions and obstacles.
4) In the zigzag case however after the blue balls enter the zigzag channel the blue T-shaped component slows down its vertical downward motion and decreases its downward vertical velocity.
5) In one word, the straight-line modification blue T-shaped component covers the distance between the highest position and the lowest position much faster than the zigzag modification blue T-shaped component.
==========================
PART 2. Please look at the link https://youtu.be/aVOfWLDrYwA
1) How to slow down the vertical downward motion (that is, how to decrease the vertical downward velocity) of the straight-line modification blue T-shaped component?
2) The answer is simple. The straight-line segment "s" is made rough (inside the channels) as the related force of friction is chosen in such a manner so that in the lowest position the linear downward velocities of the two blue T-shaped components are one and same and equal one to another.
3) In one word, the zigzags generate mechanical resistance, (a) which is absolutely identical and equivalent to friction and (b) which does not generate heat.
===========================
PART 3. Please look at the link https://youtu.be/pPGPktU_kpo
The last link simply repeats the experiment, described in our first post of Sat Jul 28, 2018 12:41 pm and in the related two links
https://mypicxbg.files.wordpress.com/2018/04/pages_01-12.pdf
https://mypicxbg.files.wordpress.com/2018/05/figs01-08.pdf
The zigzags generate again mechanical resistance, (a) which is absolutely identical and equivalent to friction and (b) which does not generate heat.
===========================
In one word, the text above and the related links above unambiguouly show that (a) either the law of conservation of linear momentum is not correct or (b) the law of conservation of mechanical energy is not correct or (c) both the law of conservation of linear momentum and the law of conservation of mechanical energy are not correct simultaneously.
===========================

George1

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Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #404 on: March 09, 2021, 02:34:55 PM »
Please look again at our post of March 01, 2021, 03:35:45 PM. A copy of this post is given below.
======================
Let us shorten our previous explanations (of February 26, 2021, 04:01:00 PM) by jumping directly to PART 3 (and having a brief glimpse at a small section of PART 2).
----------------------------------------
So let us start our shorter explanations.
----------------------------------------
1) Firstly, please have a look for a while at PART 2 and at the related link https://youtu.be/aVOfWLDrYwA from 00:00 to 00:03. This is only for getting a notion about the limits of the segment "s", that is, how this segment "s" is situated in relation to (relative to) the zigzag section.
----------------------------------------
2) Now let us focus on PART 3 and on the related link https://youtu.be/pPGPktU_kpo . The experiment is carried out in a space station under weightlessness conditions. Friction is negligible as the only exception is the friction inside the two straight-line channels of the segment "s". (The inside surfaces of the straight-line channels of the segment "s" are made rough thus able to generate friction (and heat, respectively).)
----------------------------------------
3) The mass of each blue component is Ma.
-----------------------------------------
4) The mass of each black component is Mb.
-----------------------------------------
5) There are four couples blue ball/blue rod. Each blue ball is firmly attached to the related blue rod thus forming one united whole.
-----------------------------------------
5A) The mass of each blue ball is negligible (if compared to Ma or to Mb), but not equal to zero.
-----------------------------------------
5B) The mass of each blue rod is negligible (if compared to Ma or to Mb), but not equal to zero.
-----------------------------------------
6) From 00:00 to 00:03 the two blue components move simultaneously and uniformly. Each blue component's linear velocity is V' as V' = const. The two black components are at rest.
------------------------------------------
7) At 00:03 the four blue balls enter simultaneously (a) the "upper" black component's smooth zigzag channels and (b) the "lower" black component's rough straight-line channels of the segment "s", respectively.
------------------------------------------
8) From 00:03 to 00:15 the four blue balls move (a) inside the "upper" black component's smooth zigzag channels and (b) inside the "lower" black component's rough straight-line channels of the segment "s", respectively.
-------------------------------------------
9) At 00:15 the four blue balls exit simultaneously (a) the "upper" black component's smooth zigzag channels and (b) the "lower" black component's rough straight-line channels of the segment "s", respectively.
-------------------------------------------
10) The force of friction inside the two rough channels of the segment "s" is chosen in such a manner (we could use for example a variable roughness and the related variable force of friction, respectively) that:
-------------------------------------------
a) the blue components decelerate in one and same manner, that is, their decelerations are one and same and equal one to another;
-------------------------------------------
b) the black components accelerate in one and same manner, that is, their accelerations are one and same and equal one to another.
-------------------------------------------
11) From 00:15 to 00:17 the two blue components move simultaneously and uniformly. Each blue component's velocity is V" as V" = const.
-------------------------------------------
12) From 00:15 to 00:17 the two black components also move simultaneously and uniformly. Each black component's velocity is V"' as V"' = const.
-------------------------------------------
13) Therefore for the "upper" zigzag modification we can write down that
(Ma) x (V') = ((Ma) x (V'')) + ((Mb) x (V''')) (1)
(1/2) x (Ma) x (V') x (V') = ((1/2) x (Ma) x (V'') x (V'')) + ((1/2) x (Mb) x (V''') x (V''')) (2)
-------------------------------------------
14) And for the "lower" straight-line modification we can write down that
(Ma) x (V') = ((Ma) x (V'')) + ((Mb) x (V''')) (1)
(1/2) x (Ma) x (V') x (V') = ((1/2) x (Ma) x (V'') x (V'')) + ((1/2) x (Mb) x (V''') x (V''')) + Q (3),
where Q is the heat, which is generated while the two blue balls move inside the two rough channels of the segment "s" in the "lower" modification.
------------------------------------------
15) It is evident that (a) the system of equations in item 13 and (b) the system of equations in item 14 cannot be true simultaneously.
------------------------------------------
16) And it directly follows from the previous item 15 that either (a) the law of conservation of linear momentum is not correct or (b) the law of conservation of mechanical energy is not correct or (c) both the law of conservation of linear momentum and the law of conservation of mechanical energy are not correct simultaneously.
------------------------------------------
NOTE. Please refer, if necessary, to our first post of Sat Jul 28, 2018 12:41 and to the two related links
https://mypicxbg.files.wordpress.com/2018/04/pages_01-12.pdf
https://mypicxbg.files.wordpress.com/2018/05/figs01-08.pdf
------------------------------------------