Language: 
To browser these website, it's necessary to store cookies on your computer.
The cookies contain no personal information, they are required for program control.
  the storage of cookies while browsing this website, on Login and Register.

GDPR and DSGVO law

Storing Cookies (See : http://ec.europa.eu/ipg/basics/legal/cookies/index_en.htm ) help us to bring you our services at overunity.com . If you use this website and our services you declare yourself okay with using cookies .More Infos here:
https://overunity.com/5553/privacy-policy/
If you do not agree with storing cookies, please LEAVE this website now. From the 25th of May 2018, every existing user has to accept the GDPR agreement at first login. If a user is unwilling to accept the GDPR, he should email us and request to erase his account. Many thanks for your understanding.
Amazon Warehouse Deals ! Now even more Deep Discounts ! Check out these great prices on slightly used or just opened once only items.I always buy my gadgets via these great Warehouse deals ! Highly recommended ! Many thanks for supporting OverUnity.com this way.

User Menu

Tesla Paper

Free Energy Book

Get paid

Donations

Please Donate for the Forum.
Many thanks.
Regards, Stefan.(Admin)

A-Ads

Powerbox

Smartbox

3D Solar

3D Solar Panels

DC2DC converter

Micro JouleThief

FireMatch

FireMatch

CCKnife

CCKnife

CCTool

CCTool

Magpi Magazine

Magpi Magazine Free Rasberry Pi Magazine

Battery Recondition

Battery Recondition

Arduino

Ultracaps

YT Subscribe

Gravity Machines

Tesla-Ebook

Magnet Secrets

Lindemann Video

Navigation

Products

Products

WaterMotor kit

Statistics

  • *Total Members: 84193
  • *Latest: eirik

  • *Total Posts: 897202
  • *Total Topics: 15809
  • *Online Today: 44
  • *Most Online: 103
(December 19, 2006, 11:27:19 PM)
  • *Users: 3
  • *Guests: 11
  • *Total: 14

Author Topic: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?  (Read 152793 times)

Offline Jerry Volland

  • Sr. Member
  • ****
  • Posts: 305
Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #780 on: June 19, 2021, 10:33:42 PM »
I'm not going to focus on some designated part of your klick bait presentation.  You do not have a space drive, and you do not have a perpetual motion system.  Continuing to rewind and repeat without end will cost you underserved attention.  You have to step back and look from a different perspective.

Free Energy | searching for free energy and discussing free energy


Offline Jerry Volland

  • Sr. Member
  • ****
  • Posts: 305
Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #781 on: June 19, 2021, 11:38:18 PM »
Now imagine it's on a Plumb Bob and SEE the Plumb Bob vibrating.  What amount of coasting velocity does it have?

Offline Jerry Volland

  • Sr. Member
  • ****
  • Posts: 305
Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #782 on: June 19, 2021, 11:59:48 PM »
"He who has the greatest potential to produce Change will attract the greatest opposition."  And that isn't George[size=78%]1.[/size]

Free Energy | searching for free energy and discussing free energy

Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #782 on: June 19, 2021, 11:59:48 PM »
Sponsored links:




Offline George1

  • Hero Member
  • *****
  • Posts: 877
Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #783 on: June 21, 2021, 02:06:31 PM »
To JerryVolland.
======================
But you are not reading my posts at all! This is not a dialogue! This is your monologue!
======================
Please read carefully the text below and please answer the question at the end of the text below. Please!
======================
1) Please look again at PART 3 of the link https://www.youtube.com/watch?v=xX14NK8GrDY&t=24s  . Please focus on the “upper” zigzag case.
2) Ma = 1 kg.
3) Mb = 4 kg.
------------------------------------
4) Va’ = pre-zig-zag velocity of the blue component = 1 m/s = const.
5) Vb’ = pre-zig-zag velocity of the black component = 0 m/s; the black component is motionless.
------------------------------------
6) Va” = during-zig-zag velocity of the blue component = variable and comparatively difficult (but not impossible) to calculate.
7) Vb” = during-zig-zag velocity of the black component = variable and comparatively difficult (but not impossible) to calculate.
8/ Vy = during-zig-zag velocity of each couple blue rod-blue ball along the Y-axis = variable and comparatively difficult (but not impossible) to calculate.
------------------------------------
9) Va”’ = post-zig-zag velocity of the blue component = 0.6 m/s = const.
10) Vb”’ = post-zig-zag velocity of the black component = 0.1 m/s = const.
------------------------------------
11) According to the third Newton’s law and to the related law of conservation of linear momentum we can write down the equalities
((Ma) x (Va’)) +  ((Mb) x (Vb’)) =  ((Ma) x (Va”’)) +  ((Mb) x (Vb”’))      <=>
<=>  ((Ma) x (Va’)) + 0 =  ((Ma) x (Va”’)) +  ((Mb) x (Vb”’))       <=>
<=>  (Ma) x (Va’) =  ((Ma) x (Va”’)) +  ((Mb) x (Vb”’))       <=>
<=>  (1 kg) x (1 m/s) = ((1 kg) x (0.6 m/s)) +  ((4 kg) x (0.1 m/s))     <=>
<=>  1 kg.m/s = 1 kg.m/s.
12) In one word, the values of Va”, Vb” and Vy are actually of no interest to us.  Actually only the values of Va’, Va”’ and Vb”’ are of interest to us as these three values determine the validity of the third Newton’s law and the related law of conservation of linear momentum.
13) The mass of each couple blue rod-blue ball is much smaller than the mass of the blue T-shaped component. For example if Ma=1kg, then the mass of each couple blue rod-blue ball must be equal to, let’s say, 0.0001 kg (and even smaller).
14) In our numerous real experiments we strongly reduce friction and the mean experimental values of  Va”’ and Vb”’ are equal to 0.5999992 m/s and to 0.0999997 m/s, respectively, that is, Va”’ = 0.5999992 m/s and  Vb”’ =  0.0999997 m/s. The latter clearly shows that the experimental error (due to friction) is much smaller than 1 % and this experimental error is perfectly acceptable.
15) Let me remind only again (it is written in the explanatory text of the link https://www.youtube.com/watch?v=xX14NK8GrDY  ) that the zigzags generate a mechanical effect (let us call this mechanical effect the "X effect"), (a) which is absolutely identical and equivalent to friction and (b) which does not generate heat. (We take gravity and friction out of equation and consideration.) And really even if the mean experimental value of force of friction inside the zigzag channels is equal to 0.0000001 N (our last experimental result), then the "X effect" still remains and can be clearly observed as in PART 3 of the link above.
============================
DO YOU HAVE ANY OBJECTIONS AGAINST ANY OF THE ABOVE ITEMS 1 - 15? YES OR NO? ONLY ONE WORD -- EITHER "YES" OR "NO"!

Offline Jerry Volland

  • Sr. Member
  • ****
  • Posts: 305
Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #784 on: June 21, 2021, 07:57:51 PM »
Answering your question requires three words:
No sustainable velocity.


*****
Jerry Volland has left the room.
What a waist of discussion time..

Free Energy | searching for free energy and discussing free energy

Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #784 on: June 21, 2021, 07:57:51 PM »
Sponsored links:




Offline George1

  • Hero Member
  • *****
  • Posts: 877
Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #785 on: June 22, 2021, 12:00:13 PM »
To JerryVolland.
=======================
You are simply afraid of truth. You are simply rejecting obvious physical reality.
Consider carefully and thoroughly again our post of June 21, 2021, 02:06:31 PM.
I am asking you my direct and clear question for the 2nd time: DO YOU HAVE ANY OBJECTIONS AGAINST ANY OF ITEMS 1 - 15? YES OR NO?
Looking forward to your answer for the 2nd time. (ONLY ONE WORD -- EITHER "YES" OR "NO"!) 

Offline George1

  • Hero Member
  • *****
  • Posts: 877
Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #786 on: June 23, 2021, 02:40:22 PM »
To all sceptics :) here in this forum.
======================
Please always keep in mind our post of June 21, 2021, 02:06:31 PM.
Asking my direct and clear question for the 3rd time: Do you have any objections against any of items 1 - 15? Yes or no?
Looking forward to your answer for the 3rd time. (Only one word -- either "yes" or "no"!)

Free Energy | searching for free energy and discussing free energy

Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #786 on: June 23, 2021, 02:40:22 PM »
Sponsored links:




Offline George1

  • Hero Member
  • *****
  • Posts: 877
Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #787 on: June 25, 2021, 02:32:53 PM »
Please always keep in mind our post of June 21, 2021, 02:06:31 PM.
Asking my direct and clear question for the 4th consecutive time: Do you have any objections against any of items 1 - 15? Yes or no?
Looking forward to your answer for the 4th consecutive time. (Only one word -- either "yes" or "no"!)

Offline Jerry Volland

  • Sr. Member
  • ****
  • Posts: 305
Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #788 on: June 25, 2021, 08:04:02 PM »
Popping in one last time: I still think my suggestion to maximize the torque is a valid idea.  Of course, this would also maximize motor coil heating.  Driving torque produces a lot of waste heat, somewhere or else.


@George1: don't count yourself into Oblivion.  If you even read what I said, trying to impart understanding to a Robot brain, you can see how foolish you act, having to ask if I object to some part of your premise.


Over and Out.

Free Energy | searching for free energy and discussing free energy

Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #788 on: June 25, 2021, 08:04:02 PM »
3D Solar Panels

Offline Floor

  • Hero Member
  • *****
  • Posts: 1997
Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #789 on: June 26, 2021, 06:42:15 AM »
                             click bait
si !

Offline George1

  • Hero Member
  • *****
  • Posts: 877
Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #790 on: June 26, 2021, 09:44:03 AM »
To JerryyVolland and Floor.
---------------------------------------
You are both either stubborn ignoramuses or paid agents of the official science mafia, who try to manipulate the audience in a clumsy and unskillful manner by using only one absurd and insane arguement, whose essence is "This is impossible, because it is impossible and that's all!" Congratulations! An iron-made argument! You both are among the next Nobel prize winners for sure! In one word, it is evident for all members of this forum that you are simply two unworthy persons! Shame on you!
============================
============================
Asking my direct and clear question for the 5th consecutive time: Do you have any objections against any of items 1 - 15 below? Yes or no? (If yes, then specify exactly which item you do not agree with and why.)
Looking forward to your answer for the 5th consecutive time. (Only one word -- either "yes" or "no"!)
============================
============================
1) Look again at PART 3 of the link https://www.youtube.com/watch?v=xX14NK8GrDY&t=24s  . Focus on the “upper” zigzag case.
2) Ma = 1 kg.
3) Mb = 4 kg.
------------------------------------
4) Va’ = pre-zig-zag velocity of the blue component = 1 m/s = const.
5) Vb’ = pre-zig-zag velocity of the black component = 0 m/s; the black component is motionless.
------------------------------------
6) Va” = during-zig-zag velocity of the blue component = variable and comparatively difficult (but not impossible) to calculate.
7) Vb” = during-zig-zag velocity of the black component = variable and comparatively difficult (but not impossible) to calculate.
8/ Vy = during-zig-zag velocity of each couple blue rod-blue ball along the Y-axis = variable and comparatively difficult (but not impossible) to calculate.
------------------------------------
9) Va”’ = post-zig-zag velocity of the blue component = 0.6 m/s = const.
10) Vb”’ = post-zig-zag velocity of the black component = 0.1 m/s = const.
------------------------------------
11) According to the third Newton’s law and to the related law of conservation of linear momentum we can write down the equalities
((Ma) x (Va’)) +  ((Mb) x (Vb’)) =  ((Ma) x (Va”’)) +  ((Mb) x (Vb”’))      <=>
<=>  ((Ma) x (Va’)) + 0 =  ((Ma) x (Va”’)) +  ((Mb) x (Vb”’))       <=>
<=>  (Ma) x (Va’) =  ((Ma) x (Va”’)) +  ((Mb) x (Vb”’))       <=>
<=>  (1 kg) x (1 m/s) = ((1 kg) x (0.6 m/s)) +  ((4 kg) x (0.1 m/s))     <=>
<=>  1 kg.m/s = 1 kg.m/s.
12) In one word, the values of Va”, Vb” and Vy are actually of no interest to us.  Actually only the values of Va’, Va”’ and Vb”’ are of interest to us as these three values determine the validity of the third Newton’s law and the related law of conservation of linear momentum.
13) The mass of each couple blue rod-blue ball is much smaller than the mass of the blue T-shaped component. For example if Ma=1kg, then the mass of each couple blue rod-blue ball must be equal to, let’s say, 0.0001 kg (and even smaller).
14) In our numerous real experiments we strongly reduce friction and the mean experimental values of  Va”’ and Vb”’ are equal to 0.5999992 m/s and to 0.0999997 m/s, respectively, that is, Va”’ = 0.5999992 m/s and  Vb”’ =  0.0999997 m/s. The latter clearly shows that the experimental error (due to friction) is much smaller than 1 % and this experimental error is perfectly acceptable.
15) Let me remind only again (it is written in the explanatory text of the link https://www.youtube.com/watch?v=xX14NK8GrDY  ) that the zigzags generate a mechanical effect (let us call this mechanical effect the "X effect"), (a) which is absolutely identical and equivalent to friction and (b) which does not generate heat. (We take gravity and friction out of equation and consideration.) And really even if the mean experimental value of force of friction inside the zigzag channels is equal to 0.0000001 N (our last experimental result), then the "X effect" still remains and can be clearly observed as in PART 3 of the link above.
============================
============================
Asking my direct and clear question for the 5th consecutive time: Do you have any objections against any of the above items 1 - 15? Yes or no? (If yes, then specify exactly which item you do not agree with and why.)
Looking forward to your answer for the 5th consecutive time. (Only one word -- either "yes" or "no"!)

 




Free Energy | searching for free energy and discussing free energy

Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #790 on: June 26, 2021, 09:44:03 AM »
3D Solar Panels

Offline Floor

  • Hero Member
  • *****
  • Posts: 1997
Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #791 on: June 26, 2021, 11:44:20 PM »
Second and final warning George2
or I'm telling my mom on you !

Offline George1

  • Hero Member
  • *****
  • Posts: 877
Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #792 on: June 28, 2021, 09:48:53 AM »
To Floor.
---------------------------------------
It is more than evident already for any honest member of good will in this forum that you are simply a paid agent of the official science mafia! How much do they pay you?   Shame on you!
============================
============================
Asking my direct and clear question for the 6th consecutive time: Do you have any objections against any of items 1 - 16 below? Yes or no? (If yes, then specify exactly which item you do not agree with and why.)
Looking forward to your answer for the 6th consecutive time. (Only one word -- either "yes" or "no"!)
============================
============================
1) Look again at PART 3 of the link https://www.youtube.com/watch?v=xX14NK8GrDY&t=24s  . Focus on the “upper” zigzag case.
2) Ma = 1 kg.
3) Mb = 4 kg.
------------------------------------
4) Va’ = pre-zig-zag velocity of the blue component = 1 m/s = const.
5) Vb’ = pre-zig-zag velocity of the black component = 0 m/s; the black component is motionless.
------------------------------------
6) Va” = during-zig-zag velocity of the blue component = variable and comparatively difficult (but not impossible) to calculate.
7) Vb” = during-zig-zag velocity of the black component = variable and comparatively difficult (but not impossible) to calculate.
8/ Vy = during-zig-zag velocity of each couple blue rod-blue ball along the Y-axis = variable and comparatively difficult (but not impossible) to calculate.
------------------------------------
9) Va”’ = post-zig-zag velocity of the blue component = 0.6 m/s = const.
10) Vb”’ = post-zig-zag velocity of the black component = 0.1 m/s = const.
------------------------------------
11) According to the third Newton’s law and to the related law of conservation of linear momentum we can write down the equalities
((Ma) x (Va’)) +  ((Mb) x (Vb’)) =  ((Ma) x (Va”’)) +  ((Mb) x (Vb”’))      <=>
<=>  ((Ma) x (Va’)) + 0 =  ((Ma) x (Va”’)) +  ((Mb) x (Vb”’))       <=>
<=>  (Ma) x (Va’) =  ((Ma) x (Va”’)) +  ((Mb) x (Vb”’))       <=>
<=>  (1 kg) x (1 m/s) = ((1 kg) x (0.6 m/s)) +  ((4 kg) x (0.1 m/s))     <=>
<=>  1 kg.m/s = 1 kg.m/s.
12) In one word, the values of Va”, Vb” and Vy are actually of no interest to us.  Actually only the values of Va’, Va”’ and Vb”’ are of interest to us as these three values determine the validity of the third Newton’s law and the related law of conservation of linear momentum.
13) The mass of each couple blue rod-blue ball is much smaller than the mass of the blue T-shaped component. For example if Ma=1kg, then the mass of each couple blue rod-blue ball must be equal to, let’s say, 0.0001 kg (and even smaller).
14) In our numerous real experiments we strongly reduce friction and the mean experimental values of  Va”’ and Vb”’ are equal to 0.5999992 m/s and to 0.0999997 m/s, respectively, that is, Va”’ = 0.5999992 m/s and  Vb”’ =  0.0999997 m/s. The latter clearly shows that the experimental error (due to friction) is much smaller than 1 % and this experimental error is perfectly acceptable.
15) Let me remind only again (it is written in the explanatory text of the link https://www.youtube.com/watch?v=xX14NK8GrDY  ) that the zigzags generate a mechanical effect (let us call this mechanical effect the "X effect"), (a) which is absolutely identical and equivalent to friction and (b) which does not generate heat. (We take gravity and friction out of equation and consideration.) And really even if the mean experimental value of force of friction inside the zigzag channels is equal to 0.0000001 N (our last experimental result), then the "X effect" still remains and can be clearly observed as in PART 3 of the link above.
16) And now we can easily calculate the pre-zig-zag and post-zig-zag kinetic energies of the bodies, taking part in the experiment. That is, we can write down the inequalities
(0.5) x (Ma) x (Va’) x (Va’) >  ((0.5) x (Ma) x (Va”’) x (Va”’)) +  ((0.5) x (Mb) x (Vb”’) x (Vb”’))       <=> 
<=>  (0.5) x (1 kg) x (1 m/s) x (1 m/s) > ((0.5) x (1 kg) x (0.6 m/s)x (0.6 m/s)) +  ((0.5) x (4 kg) x (0.1 m/s) x (0.1 m/s))     <=>   0.5 J > 0.2 J
The last three inequalities unambiguously show a severe violation of the law of conservation of mechanical energy.
============================
============================
Asking my direct and clear question for the 6th consecutive time: Do you have any objections against any of the above items 1 - 16? Yes or no? (If yes, then specify exactly which item you do not agree with and why.)
Looking forward to your answer for the 6th consecutive time. (Only one word -- either "yes" or "no"!)
« Last Edit: June 28, 2021, 01:29:23 PM by George1 »

Offline Jerry Volland

  • Sr. Member
  • ****
  • Posts: 305
Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #793 on: June 29, 2021, 01:36:58 AM »
This is starting to look like the forum is being attacked by a worm virus. It seems more than just spam

Offline George1

  • Hero Member
  • *****
  • Posts: 877
Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #794 on: June 29, 2021, 10:02:47 AM »
To JerryVolland.
===================
NO, THIS IS NEITHER A WORM VIRUS NOR A SPAM! YOU ARE SIMPLY A PAID AGENT OF THE OFFICIAL SCIENCE MAFIA, WHO TRIES TO MANIPULATE THE AUDIENCE  AGAIN IN A CLUMSY AND UNSKILLFUL MANNER! TAKE SOME BEGINNER'S MANIPULATION TECHNIQUES GUIDE AND STUDY IT CAREFULLY! BECAUSE OTHERWISE YOU SIMPLY RESEMBLE A CLOWN!
===================
Asking my direct and clear question for the 7th consecutive time: Do you have any objections against any of items 1 - 16 below? Yes or no? (If yes, then specify exactly which item you do not agree with and why.)
Looking forward to your answer for the 7th consecutive time. (Only one word -- either "yes" or "no"!)
============================
============================
1) Look again at PART 3 of the link https://www.youtube.com/watch?v=xX14NK8GrDY&t=24s  . Focus on the “upper” zigzag case.
2) Ma = 1 kg.
3) Mb = 4 kg.
------------------------------------
4) Va’ = pre-zig-zag velocity of the blue component = 1 m/s = const.; Va’ = V1.
5) Vb’ = pre-zig-zag velocity of the black component = 0 m/s; the black component is motionless.
------------------------------------
6) Va” = during-zig-zag velocity of the blue component = variable and comparatively difficult (but not impossible) to calculate.
7) Vb” = during-zig-zag velocity of the black component = variable and comparatively difficult (but not impossible) to calculate.
8/ Vy = during-zig-zag velocity of each couple blue rod-blue ball along the Y-axis = variable and comparatively difficult (but not impossible) to calculate.
------------------------------------
9) Va”’ = post-zig-zag velocity of the blue component = 0.6 m/s = const.; Va”’ = V2.
10) Vb”’ = post-zig-zag velocity of the black component = 0.1 m/s = const.; Vb”’ = V3.
------------------------------------
11) According to the third Newton’s law and to the related law of conservation of linear momentum we can write down the equalities
((Ma) x (Va’)) +  ((Mb) x (Vb’)) =  ((Ma) x (Va”’)) +  ((Mb) x (Vb”’))      <=>
<=>  ((Ma) x (Va’)) + 0 =  ((Ma) x (Va”’)) +  ((Mb) x (Vb”’))       <=>
<=>  (Ma) x (Va’) =  ((Ma) x (Va”’)) +  ((Mb) x (Vb”’))       <=>
<=>  (1 kg) x (1 m/s) = ((1 kg) x (0.6 m/s)) +  ((4 kg) x (0.1 m/s))     <=>
<=>  1 kg.m/s = 1 kg.m/s.
12) In one word, the values of Va”, Vb” and Vy are actually of no interest to us.  Actually only the values of Va’, Va”’ and Vb”’ are of interest to us as these three values determine the validity of the third Newton’s law and the related law of conservation of linear momentum.
13) The mass of each couple blue rod-blue ball is much smaller than the mass of the blue T-shaped component. For example if Ma=1kg, then the mass of each couple blue rod-blue ball must be equal to, let’s say, 0.0001 kg (and even smaller).
14) In our numerous real experiments we strongly reduce friction and the mean experimental values of  Va”’ and Vb”’ are equal to 0.5999992 m/s and to 0.0999997 m/s, respectively, that is, Va”’ = 0.5999992 m/s and  Vb”’ =  0.0999997 m/s. The latter clearly shows that the experimental error (due to friction) is much smaller than 1 % and this experimental error is perfectly acceptable.
15) Let me remind only again (it is written in the explanatory text of the link https://www.youtube.com/watch?v=xX14NK8GrDY  ) that the zigzags generate a mechanical effect (let us call this mechanical effect the "X effect"), (a) which is absolutely identical and equivalent to friction and (b) which does not generate heat. (We take gravity and friction out of equation and consideration.) And really even if the mean experimental value of force of friction inside the zigzag channels is equal to 0.0000001 N (our last experimental result), then the "X effect" still remains and can be clearly observed as in PART 3 of the link above.
16) And now we can easily calculate the pre-zig-zag and post-zig-zag kinetic energies of the bodies, taking part in the experiment. That is, we can write down the inequalities
(0.5) x (Ma) x (Va’) x (Va’) >  ((0.5) x (Ma) x (Va”’) x (Va”’)) +  ((0.5) x (Mb) x (Vb”’) x (Vb”’))       <=>
<=>  (0.5) x (1 kg) x (1 m/s) x (1 m/s) > ((0.5) x (1 kg) x (0.6 m/s)x (0.6 m/s)) +  ((0.5) x (4 kg) x (0.1 m/s) x (0.1 m/s))     <=>   0.5 J > 0.2 J
The last three inequalities unambiguously show a severe violation of the law of conservation of mechanical energy.
============================
============================
Asking my direct and clear question for the 7th consecutive time: Do you have any objections against any of the above items 1 - 16? Yes or no? (If yes, then specify exactly which item you do not agree with and why.)
Looking forward to your answer for the 7th consecutive time. (Only one word -- either "yes" or "no"!)

 

OneLink