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### Author Topic: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?  (Read 184774 times)

#### George1

• Hero Member
• Posts: 884
##### Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #105 on: May 08, 2019, 01:39:53 PM »
Hi tinu,
You petrify me again, my friend! As if you are a highly-qualified expert in electrochemistry as well as in theoretical and applied mechanics too! You are genius!
(Please don't be angry again -- I am only joking! )
Looking forward to your calculations related to Fc and d.
Regards,
George

#### George1

• Hero Member
• Posts: 884
##### Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #106 on: May 09, 2019, 08:31:30 AM »
Hi guys,
Let us focus again on the zigzag design as described in the first post of this topic.
-----------------------------------
1) What will happen if:
a) the mass of the blue component is SMALLER than the mass of the black component;
b) the mass of the blue component is EQUAL to the mass of the black component;
c) the mass of the blue component is BIGGER than the mass of the black component.
-----------------------------------
2) And one modification of the main concept.
-----------------------------------
Let us assume that the black component is fixed motionless somewhere to some obstacle and is not able to move. In this case it is evident that after entering the zigzag channel section the blue component will decelerate. What will be the value of this deceleration d and how it will depend on the number of the zigzags? After how many zigzags for example the velocity of the blue component will be 3/4 its initial velocity Vo? Or, let's say, 1/2?
-----------------------------------
And one more question. It is evident that if the blue component enters the zigzag channel section, then the black component exerts force Fc on the obstacle, which does not allow the black component's linear motion. It is evident that the direction of Fc coincides with the direction of Vo. What will be the mean value of Fc for example? Or its maximum and minimum?
-----------------------------------
So can somebody calculate the values of the deceleration d and of the force Fc for all of us in this forum? It is evident that both d and Fc are bigger than zero ( d > 0 and Fc > 0), but it will be a nice job if some formulas are derived.
(Note. Friction is negligible and the shape of the zigzag channel could be for example an ordinary standard sinusoid. (Or any other curve, if more convenient.))
-----------------------------------
-----------------------------------
George

#### George1

• Hero Member
• Posts: 884
##### Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #107 on: May 09, 2019, 11:12:57 AM »
Hi tinu,
Waiting for your calculations related to the zigzag system.
Regards,
George

#### George1

• Hero Member
• Posts: 884
##### Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #108 on: May 10, 2019, 10:14:09 AM »
Hi guys,
Please have a look again at the first post of ours in this topic. Let us make the following comparison. (We will repeat some parts of our previous posts.)
============================
1) Please have a look at Fig. 4, Fig. 5, Fig. 5A and Fig. 6.
--------------------------------------------------
1A) THERE IS NO FRICTION. (Modern technologies allow to reduce practically as much as you want the experimental error, related to friction.)
--------------------------------------------------
1B) Let us assume that the black component is fixed motionless somewhere to some obstacle and is not able to move. In this case it is evident that after entering the zigzag channel section the blue component will decelerate. And it is also evident that the deceleration d (its absolute value and its mean value) will be bigger than zero, that is, d > 0.
--------------------------------------------------
1C) It is evident that if the blue component enters the zigzag channel section, then the black component exerts force Fc on the obstacle, which does not allow the black component's linear motion. It is evident that the direction of Fc coincides with the direction of Vo. It is also evident that the force Fc (its absolute value and its mean value) is bigger than zero, that is, Fc > 0.
============================
2) Please have a look at Fig. 1, Fig. 2, Fig. 2A and Fig. 3.
--------------------------------------------------
2A) THERE IS FRICTION in the linear channel s-segment section.
--------------------------------------------------
2B) Let us assume that the black component is fixed motionless somewhere to some obstacle and is not able to move. In this case it is evident that after entering the linear channel s-segment section the blue component will decelerate. And it is also evident that the deceleration d' (its absolute value and its mean value) will be bigger than zero, that is, d' > 0.
--------------------------------------------------
2C) It is evident that if the blue component enters the linear channel s-segment section, then the black component exerts force F'c on the obstacle, which does not allow the black component's linear motion. It is evident that the direction of F'c coincides with the direction of Vo. It is also evident that the force F'c (its absolute value and its mean value) is bigger than zero, that is, F'c > 0.
============================
3) Please compare item 1 with item 2. It is evident that we can always choose a suitable combination of (a) magnitude of force of friction, (b) length of segments s and (c) number and shape of zigzags, for which Fc = F'c, Fc > 0, F'c > 0, d = d', d > 0 and d' > 0. Therefore it is evident that zigzags successfully imitate resistance, which is identical to friction, but without generating heat. And if we use this simple fact in the experiments, described in Figs. 1 - 6, then we can conclude again that:
a) the law of conservation of linear momentum is not correct;
b) the law of conservation of mechanical energy is not correct;
c) both the law of conservation of linear momentum and the law of conservation of mechanical energy are not correct simultaneously.
============================
Let us stress upon the fact that IN GENERAL both the law of conservation of mechanical energy and the law of conservation of linear momentum are absolutely true and correct. There is no doubt about this. But any rule/law has its exceptions and there is nothing special, disturbing and tragic in this fact.
--------------------------------------------------
Regards,
George

#### George1

• Hero Member
• Posts: 884
##### Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #109 on: May 11, 2019, 01:11:59 PM »
George

#### George1

• Hero Member
• Posts: 884
##### Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #110 on: May 14, 2019, 01:38:36 PM »
Hi guys,
As if the theoretical conception in the first post of ours in this topic is most probably a small exception of the law of conservation of linear momentum. But please note -- I wrote "MOST PROBBALY" and NOT "SURELY". Please have a look again at item 3 of our penultimate post. Which one of its sub-items (a), (b) and (c) is correct? We hope that some colleagues here will help to clarify this question.
Regards,
George

#### tinu

• Hero Member
• Posts: 630
##### Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #111 on: May 14, 2019, 08:03:35 PM »
... most probably a small exception of the law of conservation of linear momentum

...But please note -- I wrote "MOST PROBBALY" and NOT "SURELY".
Noted. Most probably, like it's been said above.

Which one of its sub-items (a), (b) and (c) is correct?
Each and every of (a), (b) and (c) is wrong, also a brilliant sample of pure gibberish.

#### George1

• Hero Member
• Posts: 884
##### Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #112 on: May 15, 2019, 09:26:59 AM »
tinu,
Did you take your medicine this morning?
You are a pathological hater. You are a sick man. You really need a doctor. And I am absolutely sure that you are sending your posts from the psychiatry section of a hospital.

#### tinu

• Hero Member
• Posts: 630
##### Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #113 on: May 15, 2019, 09:54:03 AM »
No arguments on topic?

Being uneducated might be somewhat excusable but being rude is your best choice? Really, George? lol

#### George1

• Hero Member
• Posts: 884
##### Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #114 on: May 15, 2019, 11:42:59 AM »
Hi tinu,
Ok, ok, my friend! I will not argue with you. You are free to have your own opinion and protect it. It's ok!
Don't worry and be happy!
Regards,
George

#### George1

• Hero Member
• Posts: 884
##### Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #115 on: May 15, 2019, 12:04:08 PM »
Hi guys,
A friend from another OU forum gives an interesting idea. He suggests the zigzag rounded curves to be replaced with sharp zigzag forms similar to saw teeth.  In this case, he says, the possible violation-of-the-two-conservation-laws effect would be as if even much greater. What do you think about his suggestion?
Regards,
George

#### George1

• Hero Member
• Posts: 884
##### Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #116 on: May 15, 2019, 03:29:48 PM »
Any opinions related to the saw-teeth zigzag model suggested by the colleague from a similar to ours OU website? (Please have a look at our last post.) His suggestion seems to be interesting.
Regards,
George

#### George1

• Hero Member
• Posts: 884
##### Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #117 on: May 16, 2019, 09:35:12 AM »
Hi guys,
I am re-sending again our post of May 10, 2019, 10:14:09 AM. This post as if most clearly supports the validity of our basic concept.
============================
============================
Please have a look again at the first post of ours in this topic. Let us make the following comparison. (We will repeat some parts of our previous posts.)
============================
1) Please have a look at Fig. 4, Fig. 5, Fig. 5A and Fig. 6.
--------------------------------------------------
1A) THERE IS NO FRICTION. (Modern technologies allow to reduce practically as much as you want the experimental error, related to friction.)
--------------------------------------------------
1B) Let us assume that the black component is fixed motionless somewhere to some obstacle and is not able to move. In this case it is evident that after entering the zigzag channel section the blue component will decelerate. And it is also evident that the deceleration d (its absolute value and its mean value) will be bigger than zero, that is, d > 0.
--------------------------------------------------
1C) It is evident that if the blue component enters the zigzag channel section, then the black component exerts force Fc on the obstacle, which does not allow the black component's linear motion. It is evident that the direction of Fc coincides with the direction of Vo. It is also evident that the force Fc (its absolute value and its mean value) is bigger than zero, that is, Fc > 0.
============================
2) Please have a look at Fig. 1, Fig. 2, Fig. 2A and Fig. 3.
--------------------------------------------------
2A) THERE IS FRICTION in the linear channel s-segment section.
--------------------------------------------------
2B) Let us assume that the black component is fixed motionless somewhere to some obstacle and is not able to move. In this case it is evident that after entering the linear channel s-segment section the blue component will decelerate. And it is also evident that the deceleration d' (its absolute value and its mean value) will be bigger than zero, that is, d' > 0.
--------------------------------------------------
2C) It is evident that if the blue component enters the linear channel s-segment section, then the black component exerts force F'c on the obstacle, which does not allow the black component's linear motion. It is evident that the direction of F'c coincides with the direction of Vo. It is also evident that the force F'c (its absolute value and its mean value) is bigger than zero, that is, F'c > 0.
============================
3) Please compare item 1 with item 2. It is evident that we can always choose a suitable combination of (a) magnitude of force of friction, (b) length of segments s and (c) number and shape of zigzags, for which Fc = F'c, Fc > 0, F'c > 0, d = d', d > 0 and d' > 0. Therefore it is evident that zigzags successfully imitate resistance, which is identical to friction, but without generating heat. And if we use this simple fact in the experiments, described in Figs. 1 - 6, then we can conclude again that:
a) the law of conservation of linear momentum is not correct;
b) the law of conservation of mechanical energy is not correct;
c) both the law of conservation of linear momentum and the law of conservation of mechanical energy are not correct simultaneously.
============================
Let us stress upon the fact that IN GENERAL both the law of conservation of mechanical energy and the law of conservation of linear momentum are absolutely true and correct. There is no doubt about this. But any rule/law has its exceptions and there is nothing special, disturbing and tragic in this fact.
--------------------------------------------------
Regards,
George

#### tinu

• Hero Member
• Posts: 630
##### Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #118 on: May 16, 2019, 12:46:26 PM »
Please stop this crap already, will you? If you can't come with experimental results better stfu!
And stop spamming us again and again with your nonsense!
Can you understand this is a public forum or you're simply retard?

#### George1

• Hero Member
• Posts: 884
##### Re: IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?
« Reply #119 on: May 16, 2019, 01:37:10 PM »
tinu,
You did not take your medicine again this morning. I will talk to your doctor to forbid you to write in this forum and take away your computer. You are dangerous for you yourself and for the others.
May be you have to change the medicine? Because obviously the medicine you are taking is not effective enough.