Author Topic: Is this the Smith/Kapanadze secret ? (Read 48588 times)

Belfior · « **Reply #45 on:** July 05, 2018, 04:22:18 PM »

A capacitor is not a magnetic device. You only need voltage to charge it and some amps to take care of the internal resistance.

Then you use the charge in the caps by what ever means to power a load. Like if you got 9000V in the cap bank you pulse it through a spark gap to a trafo and get it down to 230V. Or if the freq is off then down to 12V and DC with a FWBR.

Why do you need a schematic for this?

AlienGrey · « **Reply #46 on:** July 06, 2018, 02:15:35 AM »

Quote from: Belfior on July 05, 2018, 04:22:18 PM

A capacitor is not a magnetic device. You only need voltage to charge it and some amps to take care of the internal resistance.

Then you use the charge in the caps by what ever means to power a load. Like if you got 9000V in the cap bank you pulse it through a spark gap to a trafo and get it down to 230V. Or if the freq is off then down to 12V and DC with a FWBR.

Why do you need a schematic for this?

is it a secret ? if a cap is charging it's got inductance by nature of it's construction and also resistance so it creates a magnetic field as pulse as it charges!

Belfior · « **Reply #47 on:** July 06, 2018, 10:36:50 AM »

it seems to be an open secret and the only way to hide it. Voltage we can create and voltage is what the cap takes in, but then it can output charge which is amperage when it is spent over time.

Resistance is always a problem and other ways we lose charge like a spark gap. We need to work around these problems.

Impedance disappears with reactance if the pickup coil and the cap are in resonance. You could also AV plug into the cap so the cap only sees DC.

https://www.youtube.com/watch?v=TI5XWz8aZvo

If all that fails then we move on. How about using the L2's lower end to a cap leg and high end to another caps leg? Then you got the coil's potential stored in a cap with potential difference between them

I think the whole point of all these kachers and grenade coils is to fool people to think it is something mystical. Energy stored in a cap is (CV^2)/2. Farads and volts. No current there in the equation.

apecore · « **Reply #48 on:** July 06, 2018, 06:30:55 PM »

Quote from: Belfior on July 06, 2018, 10:36:50 AM

it seems to be an open secret and the only way to hide it. Voltage we can create and voltage is what the cap takes in, but then it can output charge which is amperage when it is spent over time.

Resistance is always a problem and other ways we lose charge like a spark gap. We need to work around these problems.

Impedance disappears with reactance if the pickup coil and the cap are in resonance. You could also AV plug into the cap so the cap only sees DC.

https://www.youtube.com/watch?v=TI5XWz8aZvo

If all that fails then we move on. How about using the L2's lower end to a cap leg and high end to another caps leg? Then you got the coil's potential stored in a cap with potential difference between them

I think the whole point of all these kachers and grenade coils is to fool people to think it is something mystical. Energy stored in a cap is (CV^2)/2. Farads and volts. No current there in the equation.

Belfior,
I like your approach...real eye opener... very usefull comment.
In fact two caps..each side of the grenade... sounds good.

Greetings

Belfior · « **Reply #49 on:** July 07, 2018, 01:22:48 PM »

I do not claim that I am right. I am just saying that we need new ways of looking into this stuff. You are not going to find anything useful by reading something published by jpmorgans and what ever to energy industry is lobbying. They pay for books and education, but they control what is taught in the schools.

Darsonval had a transformer that produced low volts and more amperage. The guy was hard to find, because he has been almost wiped from history. Attaching a pic of his coil system.

Interestingly Darsonval also used caps there.

There is like 20 lines on the guy https://en.wikipedia.org/wiki/Jacques-Ars%C3%A8ne_d%27Arsonval

So one approach would be to create high potential difference with HV that will excite electrons not already in the circuit. The stuff that scientists say is there. The ambient energy. Then provide easy access to a pool of electrons like the ground. Put the load in between or store the energy in caps.

I feel that the answer is something simple. Something overlooked. We are just being misguided by people that try to pull us towards theory and complex devices

Belfior · « **Reply #50 on:** July 07, 2018, 02:15:54 PM »

I am trying to modify this charge pump http://tinyurl.com/yc2pyl5h so that the mosfet is replaced by a transistor in reverse avalance mode. I am hoping to replace my SG in that setup with just a transistor as a switch. Got some transistor that will reverse avalance with a 9V battery.

Then I can control the voltage on the cap with a spark gap like the one in that darsonval trafo picture. 1cm gap I get 1000V and so on. The charging cap and the spark gap will be my oscillator & HV source. Hopefully all this with a 9V battery and transistor

Freq can be controlled by the circuitry on the reverse ava switch and spark gap.

Not even sure if it will work, but just an idea I had to get a controllable simple HV source. I know I could use flybacks and what not, but this is my idea

AlienGrey · « **Reply #51 on:** July 07, 2018, 11:28:36 PM »

Belfor
if your interested I have a 555 circuit that works and generates a narrow pulse For 'TEST and EXPERIMENTS' you can play about with
Its easy to build your self on some bread board or vero if your clever and test it as you go, but it's at your own
risk and expense . I take no responsibility for errors or your errors or what you connect it into or any electronics
you might damage with the narrow pulse generated it's entirely at your risk!!

stivep · « **Reply #52 on:** July 08, 2018, 07:40:28 PM »

https://youtu.be/qdJ1V_yDv-c
Wesley

Belfior · « **Reply #53 on:** July 08, 2018, 11:04:38 PM »

Quote from: stivep on July 08, 2018, 07:40:28 PM

https://youtu.be/qdJ1V_yDv-c
Wesley

Yes. Answered in the other thread.

Void · « **Reply #54 on:** July 09, 2018, 02:04:59 AM »

Quote from: Belfior on July 05, 2018, 04:22:18 PM

A capacitor is not a magnetic device. You only need voltage to charge it and some amps to take care of the internal resistance.

Hi Belfior. To say that "You only need voltage to charge it and some amps to take care of the internal resistance."
is not correct. It takes a current (a flow of charge) to charge a capacitor. A voltage (potential difference) is applied
across a capacitor's plates, and this causes a current to flow (a flow of charges) from one capacitor plate to the other.

When a DC voltage is applied, the charging current falls off following an exponential curve. This applied voltage
and subsequent charging current represents an expenditure of power. Real power is consumed when charging a capacitor.
It does not 'magically' charge up in a closed loop circuit. Unless your circuit setup can somehow pull in energy
from elsewhere (the environment, the vacuum) you will always have less power out than in.
Some simple bench tests will quickly prove this.

NerzhDishual · « **Reply #55 on:** July 14, 2018, 12:59:49 AM »

Salve OU dot com fellows,

IMO#1, Belflior is a creative experimenter and a worth-to-be-read poster.

Few others members seem, IMO#2, less creative but more sermonizers.

Anyway :
What about charging a (few uf range indeed), capacitor with an Avramenko plug, a short
kinda "antenna" near a Slayer Exciter ? See attached picture.
I have tested this contraption. It works.

Absolutely no OU claimed here.
Just, perhaps, a sort of proof of (some) concept and any food for thought ?

If electrons were needed to charge this capacitor, where do they come from?
Are they traveling through the air?

Avec mes salutations les plus distinguées,
Jean

forest · « **Reply #56 on:** July 14, 2018, 11:59:16 AM »

NerzhDishual

If you have it working then please test various obstacles between the Slayer exciter and the Av plug section. Then for the last part test some metal plate and metal sheet grounded and tell us the effect.

Belfior · « **Reply #57 on:** July 19, 2018, 09:27:09 PM »

Quote from: NerzhDishual on July 14, 2018, 12:59:49 AM

Salve OU dot com fellows,

IMO#1, Belflior is a creative experimenter and a worth-to-be-read poster.

Few others members seem, IMO#2, less creative but more sermonizers.

Thank you for your kind words. I can't see any reason there can't be OU or like I see it "creating movement in the ambient energy and harvesting it". We just need to take a fresh look at this stuff and not just repeat stuff that was already said 100 years ago and was wrong even then. I feel some people are just like priests and just bable the old ceremony. There reason OU is hiding is because we are asking the wrong questions. People try to guide is into wrong directions and if you keep building&using your circuits like they teach you in school you can never find it. That is why the school is there.

There is no current in the equation for charge in a capacitor. This tells me that it is a function of capacitance and voltage. If it takes some amps then it is for internal resistances.

https://www.youtube.com/watch?v=atlnVNy0IDE

the text at the end of the video indicates, that there is no raise in current when the cap charges. So input to the system is not tied to the output/load

AlienGrey · « **Reply #58 on:** July 20, 2018, 07:42:43 PM »

Quote from: Belfior on July 19, 2018, 09:27:09 PM

Thank you for your kind words. I can't see any reason there can't be OU or like I see it "creating movement in the ambient energy and harvesting it". We just need to take a fresh look at this stuff and not just repeat stuff that was already said 100 years ago and was wrong even then. I feel some people are just like priests and just bable the old ceremony. There reason OU is hiding is because we are asking the wrong questions. People try to guide is into wrong directions and if you keep building&using your circuits like they teach you in school you can never find it. That is why the school is there.

There is no current in the equation for charge in a capacitor. This tells me that it is a function of capacitance and voltage. If it takes some amps then it is for internal resistances.

https://www.youtube.com/watch?v=atlnVNy0IDE

the text at the end of the video indicates, that there is no raise in current when the cap charges. So input to the system is not tied to the output/load

If the current is constant as in a TV display picture then the slope would be linear.

The Tesla coil: the bigger the diameter the more current

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Author Topic: Is this the Smith/Kapanadze secret ? (Read 48588 times)

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