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Author Topic: Kapanadze and other FE discussion  (Read 1147260 times)

bistander

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Re: Kapanadze and other FE discussion
« Reply #2700 on: June 26, 2023, 09:45:05 PM »
Wow! So you don't even know basic things? 
10.4 volts is the voltage on the voltmeter or the effective voltage of the circuit. 
3 ohms - resistor + 1 ohm winding and circuit = 4 ohms;
1.3A is the ammeter reading.
1.3A*4 Ohms = 5.2V is the level of Voltage Drop; 
10.4V + 5.2V = 15.6V is the effective value of EMF under electromagnetic induction.


I = (E-U)/(R+r) = (15.6V-10.4V)/(3+1)=  1.3A

 ;) Don't embarrass yourself.

I rest my case.

rakarskiy

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Re: Kapanadze and other FE discussion
« Reply #2701 on: June 26, 2023, 10:27:17 PM »
According to Ohm's law, in the section of the conductor with active res istance R, the current I creates a voltage drop Ui = IR.
 ;) ;D

PS
the voltage drop level - [Ui], can be determined from the difference of the EMF -[E] and  the effective voltage in the network;  which is shown by the voltmeter - [Ui = E - U]


In blue I added a post on how to check the voltage drop level in the circuit
 
« Last Edit: June 27, 2023, 07:36:12 AM by rakarskiy »

bistander

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Re: Kapanadze and other FE discussion
« Reply #2702 on: June 26, 2023, 10:34:19 PM »
According to Ohm's law, in the section of the conductor with active res istance R, the current I creates a voltage drop U = IR.
 ;) ;D

And that is not what is shown. You show 10.4V.
bi

*assuming ammeter shunt is a typical 0.1-0.01 milliohm and therefore negligible.

rakarskiy

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Re: Kapanadze and other FE discussion
« Reply #2703 on: June 26, 2023, 10:46:22 PM »
The question is, what kind of education do you have? God forbid such a teacher would teach physics to my grandchildren, I would have made a scandal and demanded an aptitude test.


Sergh

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Re: Kapanadze and other FE discussion
« Reply #2704 on: June 27, 2023, 09:28:29 AM »
About:
https://rakatskiy.blogspot.com/p/ampere-force.html
Looks like a measurement error.

Reading Wiki:

https://en.wikipedia.org/wiki/Amplitude

Rakarskiy probably measured the peak-to-peak amplitude with an oscilloscope. This is (2) "Peak-to-peak amplitude" at the Wiki link.
And it was necessary to divide it by 2 to get parameter (1) "Peak amplitude". Then parameter (1)"Peak amplitude" must be divided by the root of 2 to get parameter (3) "Root mean square amplitude".
Use parameter (3)"Root mean square amplitude" for your further calculations and conclusions. This is true only for sinusoidal voltage!

Wrong measurements lead to wrong conclusions.

The question is, what kind of education do you have?

<facepalm>

rakarskiy

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Re: Kapanadze and other FE discussion
« Reply #2705 on: June 27, 2023, 09:54:07 AM »
In the experiment, measurements were made with an ammeter, a voltmeter for alternating current circuits.  This is enough to estimate the voltage and amperage of an AC circuit, in which there is nothing but the alternator winding, connecting wires and load resistance.
I am always wary of the "radiologist in power." Never listen to a "radiologist" who cannot calculate an AC circuit.

Second, I suggested above that Wesley solve the circuit calculation problem.
Serga solve it, and then yap! Because your "proffesional correctness" is also highly questionable.

Sergh

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Re: Kapanadze and other FE discussion
« Reply #2706 on: June 27, 2023, 10:24:51 AM »
In the experiment, measurements were made with an ammeter, a voltmeter for alternating current circuits. 
Then there are no options.
Your voltmeter or ammeter or resistor is defective.
Replace with a new one that is known to be good.

Serga solve it, and then yap! Because your "proffesional correctness" is also highly questionable.

I communicate with you absolutely correctly. Why are you using insulting phrases about me and other forum members?

rakarskiy

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Re: Kapanadze and other FE discussion
« Reply #2707 on: June 27, 2023, 10:41:34 AM »
Then there are no options.
Your voltmeter or ammeter or resistor is defective.
Replace with a new one that is known to be good.

I communicate with you absolutely correctly. Why are you using insulting phrases about me and other forum members?

I'm not insulting anyone, that's the first thing.
 
If you don't know how to calculate a generator circuit under load, and don't know where the amperage in it comes from, it shows you are educated on the subject. That's what I'm explicitly saying, and I doubt your ability to judge these matters. If that offends you, learn the basics of electrodynamics, electrical engineering. Any electrician who will tune an electrical circuit from an alternator with permanent magnets in the rotor knows this. At any rate, he knows the difference in no-load EMF and voltage under load.
If you measure the drop on the 3 Ohm resistor you will have between 3.8-3.9V. But this is not the voltage network into which this resistor is included in series, because there is also an ammeter with its own resistor and diode bridge, connecting wires and alternator phase winding.


220V or 110V in the AC mains, this is what figure and how it is held. 

https://rakatskiy.blogspot.com/p/ampere-force.html 
In the material all the details and correctly displayed, what, how and why, conclusions are made.

Sergh

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Re: Kapanadze and other FE discussion
« Reply #2708 on: June 27, 2023, 10:48:03 AM »
In this case, we are not interested in your generator.

You measure current and voltage across a resistor.
And you claim something like this:
2 + 2 = 10.4
Other forum members assure you that usually:
2 + 2 = 4
You scold them. This is fine?

rakarskiy

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Re: Kapanadze and other FE discussion
« Reply #2709 on: June 27, 2023, 10:57:30 AM »
In this case, we are not interested in your generator.

You measure current and voltage across a resistor.
And you claim something like this:
2 + 2 = 10.4
Other forum members assure you that usually:
2 + 2 = 4
You scold them. This is fine?

You can imagine as you like, but the phase of the generator is included in the circuit and forms the current in the circuit.  Even if the source of the battery, the missing volts physicists explain the missing volts by the external action of EMF. Since the current in the circuit cannot form without the absorption of the electric field.

All I can say is that you do not work with real power circuits, and if you do, you are far from understanding what is going on in them.

rakarskiy

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Re: Kapanadze and other FE discussion
« Reply #2710 on: June 27, 2023, 02:45:30 PM »
Ohm's formula for a complete circuit: I = E / (R + r)
(!!!! this expression is true for the full conversion of EMF to Current Force)
This formula cannot be applied in its pure form, it does not take the voltage drop into account.
The voltage drop is: Ui = I (R + r)
The amperage will be:  I = Ui / (R + r).
The voltage drop can still be determined by the formula: Ui = E - U, where U is the effective voltage in the circuit or at the terminals of the generator with the load connected. 
The formula for calculating the current in a circuit with a load is: I = (E - U) / (R + r).

SAR
If you work in the energy field, you need to know such elementary things.


« Last Edit: June 27, 2023, 08:08:52 PM by rakarskiy »

rakarskiy

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Re: Kapanadze and other FE discussion
« Reply #2711 on: June 27, 2023, 10:27:13 PM »
Я можу оперувати українською майже так само, як ви, я припускаю, що ви радіоаматор коротковольник
Одного я не розумію . Чому ви не можете розрахувати свою претензію на "надмірне єднання"?
- Вибачте, я думаю, що в українській мові немає  слова, яке б описувало "єдність," (вище)  >1

 Wesley

 ;)

Over Unity  - Понад Єдність

Тлумачення "Єдність"
https://slovnyk.ua/index.php?swrd=%D1%94%D0%B4%D0%BD%D1%96%D1%81%D1%82%D1%8C

Тлумачення "Понад"
https://slovnyk.ua/index.php?swrd=%D0%BF%D0%BE%D0%BD%D0%B0%D0%B4

"Відношення кількості і міри
5. із знах. в. Уживається при вказуванні на перевищення якої-небудь кількості."

ПС
Мова "таємної масонської ложи" давньоруська (ні російська, бо російську мову придумав Ломоносов)
україньська мова це на 80% та сама давньоруська.

Sergh

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Re: Kapanadze and other FE discussion
« Reply #2712 on: June 28, 2023, 10:53:22 AM »
The formula for calculating the current in a circuit with a load is: I = (E - U) / (R + r).

 I = (E - U) / (R + r);

(E - U) = I *  (R + r);
I = 1.3 A; R = 3 Ohm; r -> 0;

(E - U) = 1.3 * ( 3 + 0 ) = 3.9 V

This voltage should show a voltmeter. If it shows 10.4 volts, then something in the circuit is faulty or the parameters are not as specified.
If there are difficulties in acquiring good measuring instruments and components, you can use the calorimetric method of measuring energy and power.
All that is needed is a load resistance, a thermally insulated glass jar, a medical thermometer, water and a watch.
https://www.youtube.com/watch?v=EAgbknIDKNo
https://www.youtube.com/watch?v=be50rl-bsMk


rakarskiy

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Re: Kapanadze and other FE discussion
« Reply #2713 on: June 28, 2023, 12:40:42 PM »
I = (E - U) / (R + r);

(E - U) = I *  (R + r);
I = 1.3 A; R = 3 Ohm; r -> 0;

(E - U) = 1.3 * ( 3 + 0 ) = 3.9 V


Voltmeter on the generator terminals, shows U -10.4V; ammeter in the circuit of the generator winding and resistance shows: I -1.3A; R in the circuit -3 Ohm! Here you calculate, all other missing parameters of this combination: r -?; E -? Ui -?

Another simple problem: In order to get an active load current of one kilowatt, to the connected AC network 220V/50Hz what EMF should be in the phase of the generator, with a conventional resistance of the generator winding of 0 Ohm.

(when you plug the heater into a 220v outlet how does the voltage change in the outlet, why does this happen?)

This question puzzles many engineers, it is one of the reasons why many engineers cannot get jobs in electric machine design offices.




stivep

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Re: Kapanadze and other FE discussion
« Reply #2714 on: June 28, 2023, 01:39:36 PM »


________________________________________

Professor Michael Bank

Despite of what kind of value has his video channel  he is  giving us for free that what could be  turned to money.
So we are not talking about controversy here  but about willingness to share

Some information:
https://www.youtube.com/watch?v=oHuDz29PT6w
Single Line Electrical (SLE) system of Prof. Bank.
 
https://www.youtube.com/watch?v=FscVyLtSk3k
One wire three phase system of Michael Bank.ru

This article is published and it is in close relation  to the subject  currently published in sequential parts
 in here :  https://overunity.com/18335/wireless-energy-transfer-experiments-builders-board/msg579484/#msg579484

Summary : all at the end will come back to Tesla Coil and energy
Wesley
« Last Edit: July 27, 2023, 04:30:51 PM by stivep »