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Author Topic: Kapanadze and other FE discussion  (Read 1147058 times)

Sergh

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Re: Kapanadze and other FE discussion
« Reply #2715 on: June 29, 2023, 09:08:10 AM »
Voltmeter on the generator terminals, shows U -10.4V; ammeter in the circuit of the generator winding and resistance shows: I -1.3A; R in the circuit -3 Ohm! Here you calculate, all other missing parameters of this combination: r -?; E -? Ui -?

Another simple problem: In order to get an active load current of one kilowatt, to the connected AC network 220V/50Hz what EMF should be in the phase of the generator, with a conventional resistance of the generator winding of 0 Ohm.
If the voltage of 10.4 volts is the open circuit voltage of the generator, then this must be reported so as not to be misleading.
If the voltmeter shows 10.4 volts and the 3 ohm resistor is disconnected, then this means that the current in the circuit is zero.
The output power in such a circuit is also zero.
To determine the power, it is necessary to measure the voltage and current at the same time, with the load connected.

Sergh

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Re: Kapanadze and other FE discussion
« Reply #2716 on: June 29, 2023, 09:30:32 AM »
BUNK 
It seems to me that honest people behave somehow differently. 

rakarskiy

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Re: Kapanadze and other FE discussion
« Reply #2717 on: June 29, 2023, 09:36:19 AM »
If the voltage of 10.4 volts is the open circuit voltage of the generator, then this must be reported so as not to be misleading.
If the voltmeter shows 10.4 volts and the 3 ohm resistor is disconnected, then this means that the current in the circuit is zero.
The output power in such a circuit is also zero.
To determine the power, it is necessary to measure the voltage and current at the same time, with the load connected.

Sadly, things are not going well at all for you.  The suitability of the profession, you could say zeroed out. The measurements were taken with the load connected. Simultaneous Ammeter and Voltmeter on the alternator creams. Doesn't the figure explain that. You have a problem with elementary knowledge, elementary power circuitry. You don't know how the current in a circuit is formed. For you as well as for most (radio masters) current is electrons. But Ohm's Law itself denies it by dividing the voltage and current into different components. Ask another question, if you turn off the load, open the circuit between the ammeter and the resistor, what voltage will show the voltmeter. I would simply condition the school principal to remove such a teacher from the school.

« Last Edit: June 29, 2023, 02:12:49 PM by rakarskiy »

Sergh

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Re: Kapanadze and other FE discussion
« Reply #2718 on: June 29, 2023, 09:45:57 AM »
The measurements were taken with the load connected. Simultaneous Ammeter and Voltmeter on the alternator creams. Doesn't the figure explain that. You have a problem with elementary knowledge, elementary power circuitry. You don't know how the current in a circuit is formed. For you as well as for most (radio masters) current is electrons. But Ohm's Law itself denies it by dividing the voltage and current into different components. Ask another question, if you turn off the load, open the circuit between the ammeter and the resistor, what voltage will show the voltmeter. I would simply condition the school principal to remove such a teacher from the school.
rakarskiy, please stop writing this. You disgrace yourself.
A voltmeter cannot show 10.4 volts across a 3 ohm resistor at a current of 1.3 amperes. Impossible. Since I have exhausted all efforts to help you, please consult your local physics teacher.

rakarskiy

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Re: Kapanadze and other FE discussion
« Reply #2719 on: June 29, 2023, 09:53:32 AM »
 ;)

The condition of effective power of the motor and the generator must be met: P=IU   

You take an ordinary generator with permanent magnets, with a 1 kW / 220V heater connected, you achieve at the generator terminals - 220V and current for 1 kW. Then open the circuit and watch the voltage on the terminals.

To get the appropriate current in the circuit, at the appropriate voltage in the circuit, the voltage drop across the load resistance must be taken into account. The EMF of the generator will always be greater by the value of the effective mains voltage. So when you measure 220V on the socket terminals and a current of 4.55A for a 1kW load, the EMF of the generator will be greater to the extent that the voltage drop on the load resistance and the circuit elements is greater.

The question is did you not know that?

This condition is mandatory, if you need to charge the battery your EMF voltage must be greater by the amount that will provide the appropriate charging current. Because if the operating voltage falls below the voltage of the battery, it will not be charging, but discharging, taking into account the resistance of the circuit. Then yourself, do radio engineers innovators, ohm's law for the circuit section, so that they do not work out.

Thaelin

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Re: Kapanadze and other FE discussion
« Reply #2720 on: June 29, 2023, 10:28:29 AM »
This is why I quit reading a lot of threads here. If you have discourse with something, discuss it like adults and bring your proof with you. Try this on Fermi Labs and see what happens.

kolbacict

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Re: Kapanadze and other FE discussion
« Reply #2721 on: June 29, 2023, 10:45:32 AM »
A voltmeter cannot show 10.4 volts across a 3 ohm resistor at a current of 1.3 amperes. Impossible.
Maybe he means that there is also reactance for AC that is added to these three ohms?
Which is about that  he silent.

bistander

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Re: Kapanadze and other FE discussion
« Reply #2722 on: June 29, 2023, 10:54:15 AM »
rakarskiy, ...
A voltmeter cannot show 10.4 volts across a 3 ohm resistor at a current of 1.3 amperes. Impossible. Since I have exhausted all efforts to help you, please consult your local physics teacher.

Hello Sergh,
Nice attempt. I also recommend consultation of local physics teacher long ago to rakarskiy. Sadly, he does not.

...
Rakarskiy,
A year or two ago I pointed out your error in applying Ampere's Force Law. But you persist, believing yourself smarter than all the engineers and scientists for the past couple centuries. ...

And there was this:

...
Energy is the derivative of power with respect to time, ...

Hi Rakarskiy,
You got that backwards.
bi

We tried.
bi

Sergh

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Re: Kapanadze and other FE discussion
« Reply #2723 on: June 29, 2023, 11:00:26 AM »
Maybe he means that there is also reactance for AC that is added to these three ohms?
He claims a mechanical generator that does not generate megahertz.
In this case, he should write that the 3 ohm load resistor is not an ordinary industrial resistor with a relatively small inductance, but a coil of 1000 turns (for example).

bistander

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Re: Kapanadze and other FE discussion
« Reply #2724 on: June 29, 2023, 11:14:37 AM »
Maybe he means that there is also reactance for AC that is added to these three ohms?
Which is about that  he silent.

He shows a purely resistive load of 3 Ohms.

The problem is rakarskiy just plugs numbers into any old equation without knowledge of meaning of the equation and physics fundamental to the analysis.

And then insults everyone.
bi

rakarskiy

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Re: Kapanadze and other FE discussion
« Reply #2725 on: June 29, 2023, 12:49:20 PM »
He shows a purely resistive load of 3 Ohms.

The problem is rakarskiy just plugs numbers into any old equation without knowledge of meaning of the equation and physics fundamental to the analysis.

And then insults everyone.
bi

Quote
Voltage drop is the gradual decrease in voltage along a conductor through which electric current flows, due to the fact that the conductor has an active resistance.   
The formula for calculating the voltage drop is   
dU = IR, where   
dU - voltage drop   
I - current strength   
R is the active resistance   

Quote
Calculating the alternator power to charge the battery.
To calculate the amount of power that the alternator will supply to the battery, you must calculate the amperage in the battery circuit.
According to Ohm's law:
I = U/R+r
Where:
I is the amperage;
U - difference between alternator voltage and battery voltage (U = Ug-Ub)
R + r - resistance of external circuit elements and current source.

Serg, you were right, my condition will be fulfilled at resistance of 8 ohms. But it does not change the essence of the EMF is always greater than the actual voltage in the network with the load. 


« Last Edit: June 29, 2023, 03:37:08 PM by rakarskiy »

pix

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Re: Kapanadze and other FE discussion
« Reply #2726 on: June 29, 2023, 12:54:47 PM »


Professor Michael Bank

Despite of what kind of value has his video channel  he is  giving us for free that what could be  turned to money.
So we are not talking about controversy here  but about willingness to share

Some information:
Jewish  speaking perfect Russian (educated in former Soviet Union)

https://www.youtube.com/watch?v=oHuDz29PT6w
Single Line Electrical (SLE) system of Prof. Bank.
 
https://www.youtube.com/watch?v=FscVyLtSk3k
One wire three phase system of Michael Bank.ru

This article is published and it is in close relation  to the subject  currently published in sequential parts
 in here :  https://overunity.com/18335/wireless-energy-transfer-experiments-builders-board/msg579484/#msg579484

Summary : all at the end will come back to Tesla Coil and energy
Wesley


In my opinion in this "single wire" system of Mr. Bank an earth connection is the second wire.
Even if they make "nullifier" by isolating part of the soil from the rest of the ground with insulating foil, as they showed in the experiment- they just created a capacitor.
And as we know capacitors will pass altarnating currents.
And last but not least- if you draw electric field lines from the "single line transmission" of Mr. Bank- they will go towards ground and Poynting vector is directed towards the load.
Without "ground connection" this system will not work.

pix

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Re: Kapanadze and other FE discussion
« Reply #2727 on: June 29, 2023, 01:17:01 PM »
I had conversation  with BUNK
Yes -the same Russian guy in the mask and the gloves who presented his device on YouTube some time ago.
He told me his last name too.
more  details later
Wesley
That will be very interesting Stivep.

dsquared18

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Re: Kapanadze and other FE discussion
« Reply #2728 on: June 29, 2023, 02:53:05 PM »
This is why I quit reading a lot of threads here. If you have discourse with something, discuss it like adults and bring your proof with you. Try this on Fermi Labs and see what happens.

So right!

D2

kolbacict

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Re: Kapanadze and other FE discussion
« Reply #2729 on: June 29, 2023, 07:16:17 PM »
Any electrician who will tune an electrical circuit from an alternator with permanent magnets in the rotor knows this.


Not Any. :D
« Last Edit: September 10, 2023, 07:55:09 PM by stivep »