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Solid States Devices => solid state devices => Topic started by: panyuming on April 27, 2018, 12:32:36 AM
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Antenna impedance Ohm 50
Transmitter power W 0.5 2 200
Antenna current A 0.1 0.2 2
Transmitter power consumption W 1 4 400
Groundwire current A 0.1 0.2 2
Critical output voltage V 10 20 200
Scheduled output voltage V 100 300 2000
Output Power W 10 60 4000
COP 10 15 10
Calculated COP=10 Active Antenna System
http://energysea.net/forum.php?mod=viewthread&tid=8447
Simplified Chinese
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in Simplified Chinese
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Oké......[size=78%]and how can we replicatie built this?[/size]
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Active antenna = antenna + amplifier.
Similarly, the "Power Loss Compensator". We apply 10 watts to the input, we get 100 watts at the output. Powered by a battery or car generator, 14.4 V.
Simplified russian:
https://izshop.by/assesories/kompensator-poter-kp-101-12-voronezh.html (https://izshop.by/assesories/kompensator-poter-kp-101-12-voronezh.html)
"Power Loss Compensator" - because it is forbidden to use without the permission a radio station of high power.
In many countries, you can not use a 100-watt radio station without permission. "Compensator power loss" or "Active antenna" such as it is possible to use, carefully.
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Active antenna = antenna + amplifier.
Similarly, the "Power Loss Compensator". We apply 10 watts to the input, we get 100 watts at the output. Powered by a battery or car generator, 14.4 V.
Simplified russian:
https://izshop.by/assesories/kompensator-poter-kp-101-12-voronezh.html (https://izshop.by/assesories/kompensator-poter-kp-101-12-voronezh.html)
"Power Loss Compensator" - because it is forbidden to use without the permission a radio station of high power.
In many countries, you can not use a 100-watt radio station without permission. "Compensator power loss" or "Active antenna" such as it is possible to use, carefully.
Thank you very much for joining the discussion.
This machine is a conventional high frequency power amplifier. The input power referred to is the input high frequency signal power. It still needs 13V about 15A DC power supply. Not an OVERUNITY device.
Thanks for Google translation.
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Yes of course:
https://en.wikipedia.org/wiki/Active_antenna (https://en.wikipedia.org/wiki/Active_antenna)
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Yes of course:
https://en.wikipedia.org/wiki/Active_antenna (https://en.wikipedia.org/wiki/Active_antenna)
hank you for your reply
Now I know that maybe I used the wrong word. Should use "Initiative Antenna"
The antenna system mentioned in the field of free energy is to say that many radios around the transmitting antenna of a radio can 'passively' receive the energy emitted by the radio. But every radio receives very little energy.
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Even with directional antennas, the energy received at the receiving end is much smaller.
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If every radiation of S is achieved by a certain current of a device, it is equivalent to this S-radiation-generating current charging capacitor C. This current is obviously not affected by the voltage on capacitor C.
According to the capacitor energy storage formula W=0.5CU^2
The voltage on C can increase without limit, and the energy in the capacitor is stored according to the square of the voltage, there is always a 'critical voltage'. Above the threshold voltage, the sum of the energy in the capacitor exceeds the sum of the current energy charged to it. Extra energy appears.
To repeat: Charging the capacitor directly with the power supply is energy conservation. With radiation, the energy can be increased.
To put it another way, we don't care where the waves from the antenna go. When the waves are sent out, there will be antenna currents. There is also a ground current. When the ground current is rectified, the DC voltage is obtained.
Instead of using an antenna to receive energy, we use an antenna to emit energy,
which means ' Initiative antenna'.
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Don't forget that the diode will kill the effect. Before opening it is a small serial capacitor with an inverse voltage eq to collector cap and after every step it will be harder to open it and the impedance will be high till the opening.
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Oké......[size=78%]and how can we replicatie built this?[/size]
Thank you kampen
I do not recommend testing this circuit because it may not meet CCIR regulations.
This is a OverUnity method that can be proved by conventional calculations to obtain energy from the earth.
I hope everyone will develop a more practical method based on the principle of "charge incentive."
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Don't forget that the diode will kill the effect. Before opening it is a small serial capacitor with an inverse voltage eq to collector cap and after every step it will be harder to open it and the impedance will be high till the opening.
In the past, there were many people using radio receivers and fewer people used radio transmitter. Now almost everyone uses a mobile phone, and they are all using radio transceivers.
Because the radio is receiving radiation energy from a broadcast station, receiving the program on the radio does not affect the radio energy received by the radio regardless of how much voltage is placed on the battery.
The same is true for radio transmitter. It emits radiated energy. No matter how the radio's ground wire, series battery or capacitor, or the voltage in the capacitor is high, it does not affect the radiation of the antenna.
Therefore, the diode's turn-on voltage (0.3V~1V) is insignificant for the 100V voltage accumulated in the capacitor.
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The energy of the transmitter's internal battery is converted by the transmitter to high-frequency energy to radiate from the antenna.
At this time, the antenna will have 'antenna high-frequency current'. Similarly, the corresponding, symmetrical, must have the same quantity 'ground high-frequency current'.
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The higher the frequency of the radio transmitter, the shorter the antenna, the shorter the ground wire, or the smaller the area of the ground metal plate.
If the principle of this post is used, the high-frequency power amplifier IC in the mobile phone can obtain the ground energy, and the mobile phone can become a self-powered OVERUNITY device.
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Find one Tesla GB patent (don't remember now the number) , and also his radiant energy famous patent and compare. You are right, except there is slight problem - the receiver should not load transmitter and that's what Tesla found.
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panyuming
COP 10 is quite a Bold statement
I do appreciate your sincerity, having spoken with some antennae builders here.. your explanations seem to need more clarity ?
Are you suggesting that it takes the transmitter to engage an "OU gain" which comes from the ground ?
seems a simple experiment can be modeled [By you ... so we get it correct ?]
example
what frequency
best Antennae
what type transmitter
good clear schematic
should ground be ??[treated or ?]
very qualified Builders here are ready to try this, but resources in the open source community are limited and spread quite thin ATM.
respectfully
Chet K
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Find one Tesla GB patent (don't remember now the number) , and also his radiant energy famous patent and compare. You are right, except there is slight problem - the receiver should not load transmitter and that's what Tesla found.
Yes, there are no receivers in this plan. Thank you!
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panyuming
COP 10 is quite a Bold statement
I do appreciate your sincerity, having spoken with some antennae builders here.. your explanations seem to need more clarity ?
Are you suggesting that it takes the transmitter to engage an "OU gain" which comes from the ground ?
seems a simple experiment can be modeled [By you ... so we get it correct ?]
example
what frequency
best Antennae
what type transmitter
good clear schematic
should ground be ??[treated or ?]
very qualified Builders here are ready to try this, but resources in the open source community are limited and spread quite thin ATM.
respectfully
Chet K
Chet K Thank you very much! And thank you very qualified Builders are willing to experiment with this plan.
I'm not suitable to post pictures in this forum.
So I will reply to your detailed content written in the Chinese website, please see the following website: Thank you!
http://energysea.net/forum.php?mod=viewthread&tid=8447&page=2&extra=#pid48874
Please tell me if there is a problem. Thank you!
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Sir
The good news is we have very skilled persons here who can verify this claim quite easily
However
I must ask
is this an actual result you have seen after building this ?
or is this something you "expect" should happen based on you calculations and method ?
The language barrier is a problem,however we do have friends here who can help with that.
But Clarity is important
Have YOU done Empirical testing or is this theory ?
respectfully
Chet K
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Sir
The good news is we have very skilled persons here who can verify this claim quite easily
However
I must ask
is this an actual result you have seen after building this ?
or is this something you "expect" should happen based on you calculations and method ?
The language barrier is a problem,however we do have friends here who can help with that.
But Clarity is important
Have YOU done Empirical testing or is this theory ?
respectfully
Chet K
Hello Chet K!
As you said,
“ you "expect" should happen based on you calculations and method ?”
Sorry, that's it. It's just my calculation.