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Author Topic: Pierre's 170W in 1600W out Looped Very impressive Build continued & moderated  (Read 228819 times)

Offline MichelM

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  • Posts: 28
Jeg, onielsen,

Pierre shows in his first video that all the outputs of the diodes converge towards the positive of the bank of capacitors (red wire).
So, if each diode has a utility, what is the good sense of the diodes? Or yes, half is useless.
Luc showed us his video with the flyback diode on an assembly with a single switch, and with a recovery that is discharged into a capacitor.
We need to know how to place the flyback diodes with another device, which has two switches - one underneath, and the other above the coil.
The idea is to put this energy back into the source.
Luc can you also give your opinion?

FR
Pierre montre dans sa première vidéo que toutes les sorties des diodes convergent vers le positif de la banque de condensateurs (fil rouge).
Donc, si chaque diode a une utilité, quelle est le bon sens des diodes ? Ou alors oui, la moitié est inutile.
Luc nous a montré sa vidéo avec la diode flyback sur un montage avec un seul interrupteur, et avec une récupération qui est déchargée dans un condensateur.
Nous avons besoin de savoir comment placer les diodes flyback avec un dispositif autre, qui dispose de deux interrupteurs - l'un en-dessous, et l'autre en dessus de la bobine. L'idée étant de remettre cette énergie dans la source.
Luc pouvez-vous aussi donner votre avis ?

Free Energy | searching for free energy and discussing free energy


Offline onielsen

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Hi MichelM,

Pierre's image:
http://overunity.com/17609/170-watts-in-1600-watts-out-looped-very-impressive-build-and-video/dlattach/attach/166918/image//

As the current through an inductor is always continuous (no sudden jumps) this makes the voltage doing the jumps or even changing sign to preserve the value of the current at any given moment. For capacitors the voltage is continuous while the current is discontinuous which is opposite to inductors. When disconnecting a coil the current continues to run through it which makes the voltage across it change sign. The coil changes from receiving energy (sink) to giving off the stored energy (source).
(http://zone.ni.com/images/reference/en-XX/help/370736U-01/loc_eps_quadrant.gif)
 This image is from here: http://zone.ni.com/reference/en-XX/help/370736U-01/ni_dc_power_supplies_help/sinking_sourcing/

Looking at Pierre's image the left hand side coil has the current going to the right when the top left and the center bottom switches are closed. The coil sinks power and stores it as magnetic energy. If opening one of the switches the current through the coil continues running but the voltage across the coil changes sign. The coil is now a source and gives off the stored magnetic energy. The voltage across it immediately adjusts to fit the current running. If the impedance the coil sees is high the insulation breaks down or a spark forms across the switch opening or the coil has enough capacitance between the winding to store the magnetic energy as electric energy.

Putting diodes to the supply rails prevents the destructive flyback voltages. The current instead takes the path through the diodes. The diode from the right hand side of the coil lets the current go to the positive supply rail. A diode from the negative supply rail across the bottom switch of the negative hand side is needed to close the circuit if the bottom switch is opened.

Regards
Ole

Offline Jeg

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L192
The maximum current that arduino 2560 can give across its outputs is 200mA in total. That means 200/30=7mA max per pin output. I tried to find how much current L298 board needs at its input but no luck. What do you think? Will arduino be able to drive 30 of such boards?

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Offline pmgr

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    • Stop organ harvesting from Falun Gong practitioners
L192
The maximum current that arduino 2560 can give across its outputs is 200mA in total. That means 200/30=7mA max per pin output. I tried to find how much current L298 board needs at its input but no luck. What do you think? Will arduino be able to drive 30 of such boards?
Hi Jeg, that should not be a problem. The inputs to the L298 board are digital CMOS/TTL compatible inputs so they consume no current, typically 10-30uA per input, see the datasheet:
https://www.sparkfun.com/datasheets/Robotics/L298_H_Bridge.pdf
PmgR

Offline seaad

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A 12 step simulation at 5Hz.

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Offline Jeg

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Hi Jeg, that should not be a problem. The inputs to the L298 board are digital CMOS/TTL compatible inputs so they consume no current, typically 10-30uA per input, see the datasheet:
https://www.sparkfun.com/datasheets/Robotics/L298_H_Bridge.pdf
PmgR

Thank you PMGR. Indeed 10-30uA is nothing. I was trying to find a good opto-isolator for the inputs when i realized this 200mA limit.
 

Offline stargate22

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  • Posts: 14
Don't forget options.. ;D as a relay replacement.  http://www.crydom.com/en/



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Offline TinselKoala

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  • Posts: 13968
Those Crydom SSRs seem to be selling for between about 12 and 20 dollars US each, depending on ratings and quantity purchased. So say you need 72 of them to replace Pierre's relays.... Well, nobody ever said Free Energy would be cheap, I guess.

Who is going to spend that kind of money on something where the original claims are still not verified?

For this application a jarfull of cheap SMD mosfets, mosfet drivers, and a custom-designed PCB could probably be built to handle all the switching for under a hundred bux (estimated of course). The major time consumer would be designing the PCB and sending the design off to a fab house in China.

Offline r2fpl

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  • Posts: 436
Those Crydom SSRs seem to be selling for between about 12 and 20 dollars US each, depending on ratings and quantity purchased. So say you need 72 of them to replace Pierre's relays.... Well, nobody ever said Free Energy would be cheap, I guess.

Who is going to spend that kind of money on something where the original claims are still not verified?

For this application a jarfull of cheap SMD mosfets, mosfet drivers, and a custom-designed PCB could probably be built to handle all the switching for under a hundred bux (estimated of course). The major time consumer would be designing the PCB and sending the design off to a fab house in China.

Why buy. You can do it cheaper 2$


For example: DIY
AC and DC version:

Free Energy | searching for free energy and discussing free energy


Offline seaad

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A 12 step simulation now at 52 Hz. N.b. wave  voltage drops suddenly!

Compared with the 5 Hz version the total Amperage draw don't decrease so much !

Offline pmgr

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    • Stop organ harvesting from Falun Gong practitioners
A 12 step simulation now at 52 Hz. N.b. wave  voltage drops suddenly!
That makes sense. The time constant of a coil is L/R, so maximum frequency is f=R/(2*pi*L). At 52Hz you are hitting the limit. If you decrease L, you will increase maximum frequency. Alternatively, you can increase the series resistance of the inductor.
PmgR

Free Energy | searching for free energy and discussing free energy


Offline seaad

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  • Posts: 311
That makes sense. The time constant of a coil is L/R, so maximum frequency is f=R/(2*pi*L). At 52Hz you are hitting the limit. If you decrease L, you will increase maximum frequency. Alternatively, you can increase the series resistance of the inductor.
PmgR

Here at 52 hz all coils 1mH and NO protection diodes at all. Nice curves!   I seems to be wrong about my prediction about high spikes.

N.b. Current draw! 6-7 Amp the same as at 5Hz!


N.b. 2 I can't simulate power suction from the secondary fixed core & coil here.
That can absolutely affect the cenario!

For switching I'm using Standard Transistors !!
« Last Edit: April 07, 2018, 03:45:20 PM by seaad »

Offline r2fpl

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  • Posts: 436
Test mosfet 2xirf540n; 1 coil in stator;

8Hz

5V@1.2A
6V@2.2A
6.5V@3.8A

20V@ ??? A ???



Offline seaad

  • Sr. Member
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  • Posts: 311
Test mosfet 2xirf540n; 1 coil in stator;   8Hz
5V@1.2A
6V@2.2A
6.5V@3.8A          20V@ ??? A ???

So help you God!  ;D ;D

Offline kEhYo77

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  • Posts: 241
New video guyz : how to wind the stator!
https://www.youtube.com/watch?v=cF2MHOouwG8

 

OneLink