Hi everybody, it has been a while since I last wrote something on this Forum.


But of course I was still thinking about ways to Free Energy. At some point I was realizing that there is a tremendous  contradiction, a very irritating fact about the Back-EMF. I was also surprised that seemingly noone ever wrote or spoke about it, at least not that I've heared of.




So, what is it then? Well, glad you ask...


Back-EMF Manifesto


By Dieter Marfurt.


Any electrician and many people in general know, that a device that consumes a high wattage has a low electrical resistance. It is one of those fundamentals:


The lower the resistance of the load, the more energy "consumed". And the higher the resistance, the less energy it will "consume".



Actually, this is just the amount of current the device does let flow trough itself to the Minus pole of the supply.


Now Imagine a coil that has a big Back-EMF spike. You pulse it with a pulse-lenght that is just enough to "load" or saturate the coil. This way most of the energy that went into the coil as pulses, will flow back to the supply. No matter how many Amps are bouncing back and forth here, power consumption will be near zero, very comparable to a transformer with no load attached to the secondary. (Assuming our supply is able to utilize the Back-EMF, of course, by caps, or a chargable battery etc.)




So basicly, we are using the voltage of the supply to lure the current into the magnetic field of the coil. We do not allow the current to reach the negative pole of the supply. At least most of it won't reach it.


And yet, we have a pulsed high power cirquit here, indeed current flow.


Now here's the deal:


If we attach a Load between the coil and the supply positive side so that it shall be energized by our cirquit, then the following becomes true:


The higher the resistance of the load, the more Energy will be "consumed".
And the lower the resistance of the load, the less energy is "consumed".



This is, because with a low resistance of the load, more of the Back-EMF will finally reach back to the power supply or battery.


So, theoreticly, two heaters in parallel will consume less energy than only one.




There is a reason why we have seen so many "Anomalies" with Back-EMFs involved.


So there it is,the key in plain sight.


Furthermore, instead of a power supply, an other coil could be used as the "supply", this would reduce losses by battery/cap charging/uncharging greatly (lead acid batteries lose half of the energy in that cycle, just like caps, most other batteries are even worse). A coil could be an interesting energy storage device, efficiency-wise.


I hope these of my thoughts are useful for any good folks out there and I wish you a pleasent journey.


Dieter

Hi Forest.


Of course, the load sits in a separated back EMF path. Even tho, it may also work in the forward path if the load is not inductive, not capacitive and pf extremly low resistance. But, yes, it's better in the back path, so the coil can load unhindered..


Thanks for reading btw.

Now, that really is some inductance...

Please draw schematic, because if you place load along the coil in series connection then it is the same as ordinary one, I think you mean : place load at the back-emf spike path ?

Where is the "back-emf spike path"? Do you mean parallel to the coil?

Didn't anyone notice this howler?But of course we know that this isn't true at all, and conventional electrical theory conforms with the results of experiments in this matter (agrees with past and correctly predicts future experimental results). So there is something terribly wrong with your "theory".

[/font]Something? Something. Funny.But I am not here to talk to little minds nor to play with puppies..Great minds may read my words and understand, silently.

As far as I see, this has been confirmed to some degree eg. by Gotoluc and Woopyjump, even tho they did not draw this fundamental conclusion.

 author=dieter link=topic=17611.msg516959#msg516959 date=1519264733]
 

When the Pulse ends, the current reverses direction.

Wrong.
The current continues to flow in the same direction through the coil during the inductive kickback part of the cycle/when the source current is disconnected..

Only the voltage inverts across the coil when the source is disconnected.

the coil charges the supply for a brief moment.

No it dose not,as the current flow will be in the wrong direction through the coil,when the coil is disconnected from the current source.

You can use Diodes to make this reverse current flow over a different path.

There is no reverse current.


Brad.

 author=Magluvin link=topic=17611.msg516966#msg516966 date=1519270261]

When the pulse current is applied, the field of the coil is building outwards, and that field cuts the windings of the coil causing a reverse influence of the input current, CEMF, which causes the delay in the coil to reach max current from the input.

What is the reverse influence Mags?

The higher the inductance, the longer it takes to get to max current/max field. Now when the pulse current is taken away, that field that was built collapses inward of the coil, opposite to when it was building. So now the collapsing field is cutting the windings inward causing the current in the coil to be in the same direction as was the input pulse.

Are you sure it's a magnetic field?

If we take a toroid core inductor for example-->is not the magnetic field contained within the core?
If so,then what field is collapsing inward around the wire ?

The 'back emf' statements can confuse us into thinking as you are, as did it me, back then.

EMF is measured in volts--has nothing to do with current.

Brad