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Author Topic: The secret to Overunity  (Read 32016 times)

Offline sm0ky2

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Re: The secret to Overunity
« Reply #60 on: December 20, 2017, 03:20:08 AM »
An inductor is the closest thing we have to using all of our energy


During the time that our electric field is converted into magnetism.


Both halves of the field participate in this action


You want an “over unity” device?
Go to a junkyard and ask the old man to show you his 250v /50amp
Electromagnet


Then ask him to lift 13000 Joules worth of truck
Using 10000 Joules of electricity.


Then ask him to drop it,


Now you have witnessed 26000 Joules of energy
16000 of them were “free”.


Energy is not imprisoned
It is our minds that need to be freed

Free Energy | searching for free energy and discussing free energy

Re: The secret to Overunity
« Reply #60 on: December 20, 2017, 03:20:08 AM »

Offline blueplanet

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Re: The secret to Overunity
« Reply #61 on: December 20, 2017, 04:27:45 AM »
Let me do some calculation on this circuit.
V <> 0
I = 0
P = V*I = V*0 = 0
Conclusion: There should not be any energy output at all. My high school teacher would be very happy to see my answer.


I have tamed the static.

Some of it anyway.   8)

http://www.youtube.com/watch?v=f-aP7sk48jw

Offline sm0ky2

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Re: The secret to Overunity
« Reply #62 on: December 20, 2017, 05:58:41 AM »
1+(-1)= (sqrt)-1^2

Free Energy | searching for free energy and discussing free energy

Re: The secret to Overunity
« Reply #62 on: December 20, 2017, 05:58:41 AM »
Sponsored links:




Offline sm0ky2

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Re: The secret to Overunity
« Reply #63 on: December 20, 2017, 06:02:00 AM »
We have both a positive and negative current




Offline sm0ky2

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Re: The secret to Overunity
« Reply #64 on: December 20, 2017, 06:07:58 AM »
After the electron meets the positron,
The voltage And amperage =0
Because 100% of their energy exploded into the environment


13.6eV + (-13.6eV) = sqrt(-184.96)


Using the height of the ball in the video
And it’s angular velocity
we could determine the electron and positron
output of the (I’m sorry is that a rubber band?)

Free Energy | searching for free energy and discussing free energy

Re: The secret to Overunity
« Reply #64 on: December 20, 2017, 06:07:58 AM »
Sponsored links:




Offline sm0ky2

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Re: The secret to Overunity
« Reply #65 on: December 20, 2017, 06:35:09 AM »
18.2(X10^-31)x(300(x10^6)^2x1.6(x10^-19) =5.1^5Coulombs


That is what is released in the collision








Offline forest

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Re: The secret to Overunity
« Reply #66 on: December 20, 2017, 09:01:08 AM »
STOP
unless you want another thread with 10000 posts !


All you want to do is use your capacitor to produce magnetic field.
This is the begin of journey

Free Energy | searching for free energy and discussing free energy

Re: The secret to Overunity
« Reply #66 on: December 20, 2017, 09:01:08 AM »
Sponsored links:




Offline AlienGrey

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Re: The secret to Overunity
« Reply #67 on: December 20, 2017, 09:12:20 AM »
AG,

My post was based on over 50 years of experience with caps.  I retired from a career of working in electronics.  There are no "plates" in a normal capacitor.  There are layers of foil wrapped around each other with the dielectric material in between.  When I was a kid my dad had a TV repair shop.  He would let us have the bad condensers as they were called then.  They were coated in wax.  We peeled that wax off and unrolled the foil across the yard.  So I know first hand what they are.  And the rest of your post doesn't appear to have anything to do with what I posted.

Smokey2,

You can't have it both ways.  You're claiming the spark gap will limit the voltage and I agree.  But Tajarek is claiming he can go over voltage to charge the cap faster.  You can't go over voltage if the spark gap is limiting the voltage.  So I still maintain that you will blow some caps and possibly be injured if you insist on trying to charge them with over voltage.  I have seen what they do when they explode.

And the comments about me from Void are entirely correct.  I am actively searching for OU because I have seen enough to convince me it may very well be possible.  But I also try to correct mistaken ideas when I see them.  I don't want people wasting their time on false ideas.  Now if a person is doing research and experimenting to try and learn that is a great thing to do.  But when a person claims to have solved OU and they haven't even built anything yet to demonstrate their claims then I am very skeptical.

Thank you Void for your kind comments.

Respectfully,
Carroll
Wax capacitors  sure Ive seen them when a kid and the older folk use to slung them out the old radio that looked like church doors from the 20s  ;D or an old Phillco  radio from the 50s but lets get more up to date on the plates thing they are used in led acid battery's, E V Gray used his spark tube to regulate and dissipate surplus energy while charging a battery by boiling a small section of acid known as de-sulphating at the same time a capacitor is i different kettle of fish oil  ;D but where is the formula for this kind of work (out of the window). All this Tesla stuff was around  in the 1920s none of it is new just different materials. But what is so called free in the free energy malarkey you asked and i say to you look at the Townsend electron avalanche principle it's a fact you will be luck to find any formula for or teachings on yet exists, even if some like to get up set over on these pages or threads, and they do  ;D ;D ;D ;D ;D ;D ;D

As a youth I can remember asking a college lecturer about Tesla work his reply was it's more than my jobs worth to devote time on that kind of material with a huge grin on his face!

Allen

Offline blueplanet

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Re: The secret to Overunity
« Reply #68 on: December 20, 2017, 12:23:35 PM »
This one is another example of laughing stock which could illustrate the point:

https://en.wikipedia.org/wiki/Oxford_Electric_Bell

This bell has been ringing for more than a century. Based on the ball movement, the power output should be around 0.2mW. To make things simple, I am not going to consider the power of ringing sounds and the heat as a result of collision.

The voltage column of the drypile is about 1200volts. This yields a current of 0.16 microamp. I seriously doubt if it has any measurable current at all.

However, the ball moves more violently when the humidity is low. Lower humidity means higher resistance, which in turns is equivalent to a lower current. Lower current means lower power output. This power output probably has little to do with the dynamic of the ball movement.

Free Energy | searching for free energy and discussing free energy

Re: The secret to Overunity
« Reply #68 on: December 20, 2017, 12:23:35 PM »
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Offline AlienGrey

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Re: The secret to Overunity
« Reply #69 on: December 20, 2017, 01:22:51 PM »
This one is another example of laughing stock which could illustrate the point:

https://en.wikipedia.org/wiki/Oxford_Electric_Bell

was it worth the floor space, seen it before thought it was a wast of space then.

Allen

Offline sm0ky2

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Re: The secret to Overunity
« Reply #70 on: December 21, 2017, 02:58:52 PM »
rolled condensers are the same as a flat plate.
(when using them for their capacitance factor)



Anything other than parallel, includes angular equations.


Within the pi function:
Starting from the center, induction decreases with increasing radius.
They are truncated at some outer radius where the changes in induction
respective to each next outer wrapping become negligible, and it is sealed off.


We also have the convenience of a large surface area packed into a small space.


For the purposes of discussion, there is no real difference between the forms.
Just trivial changes to the formula to maintain perspective accuracy.


The difference comes into play when we use the inductive relationship to charge
one of the plates for free, by charging only one plate. (Or layer)


Remember, that each layer is still the same plate.
If we ignore the angular inductive aspect of it being rolled
It is the same as if we placed two parallel plates of equal area
the same distance apart.


We can engineer capacitors and condensers of infinite shape and design
That perform exactly the same. (under most conditions)


Where their differences come into play is in the changes to the induced charge.


There’s only one important question to ask yourselves.


What is the current of charge induction?
i.e.: when we charge a plate (or later) how much “current” moves to induce
an equal and opposite charge on the other plate (or layer)?
[ignore the modern technique of grounding the opposite plate]


And how does this numerical value apply to the “current” drawn from discharging
the capacitor/condenser?






Free Energy | searching for free energy and discussing free energy

Re: The secret to Overunity
« Reply #70 on: December 21, 2017, 02:58:52 PM »
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Offline Tajerek

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Re: The secret to Overunity
« Reply #71 on: December 21, 2017, 09:27:49 PM »



There’s only one important question to ask yourselves.


What is the current of charge induction?
i.e.: when we charge a plate (or later) how much “current” moves to induce
an equal and opposite charge on the other plate (or layer)?
[ignore the modern technique of grounding the opposite plate]


And how does this numerical value apply to the “current” drawn from discharging
the capacitor/condenser?

charging current across a capacitor is  I=V/R * Exponential (-t/RC)
It is ONLY the combined resistance of the circuit that consumes current, which is equivalent to R+ESR . The cap itself needs only voltage to charge.
In practice you cannot really remove resistance but you can lower it to a very small value where virtually just high voltage with very small current is able to charge up the cap.
The charge on the cap is Q=C*V

some people argue that cap takes long time to charge , that's probably because some caps have bleeding resistor (such as microwave oven caps) or high ESR. That resistive part is the one that slows the charging and consumes power P=I*V. not the charging of cap.

Those who argue should really know the science and understand the formulas otherwise y'all be shooting darts in the dark with only 'practice' wishing for overunity because there are infinite ways to experiment.  And if by any luck you get it you won't be able to reproduce it, prove it, or explain it.

Offline Tajerek

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Re: The secret to Overunity
« Reply #72 on: December 21, 2017, 10:00:10 PM »
There is a huge difference between debunkers who dismiss everything related to OU out of hand,
and healthy skepticism where one neither dismisses nor believes unless something can be proven
by proper bench testing. IMO, the OU research area needs much more healthy skepticism and a lot less people
just making claims without being able to demonstrate anything to support what they are saying.

I don't need to prove textbook formulas. Unfortunately many people want to debunk known textbook formulas as wrong and their lab tests as more correct. it is astonishing to me how people see the formula that says charge on a capacitor Q=CV and still want to convince me that it depends on current.
with that being said, I have tested what I am saying and confirmed it. But I thought sharing the basic formulas is more valuable than showing a working OU that no one knows how it work and why. Understanding the theory of OU can make 1000 experimenters come up with their own applications of it with their own OU devices.

EV gray, Don Smith, Kapanadze...etc showed OU working devices but people can't replicate them. Why? because no one know HOW they work and what's the theory behind . I just revealed the theory and it is up to anyone who wants to apply it or not.

Offline peper10

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Re: The secret to Overunity
« Reply #73 on: December 21, 2017, 10:04:14 PM »

charging current across a capacitor is  I=V/R * Exponential (-t/RC)
It is ONLY the combined resistance of the circuit that consumes current, which is equivalent to R+ESR . The cap itself needs only voltage to charge.
In practice you cannot really remove resistance but you can lower it to a very small value where virtually just high voltage with very small current is able to charge up the cap.
The charge on the cap is Q=C*V

some people argue that cap takes long time to charge , that's probably because some caps have bleeding resistor (such as microwave oven caps) or high ESR. That resistive part is the one that slows the charging and consumes power P=I*V. not the charging of cap.

Those who argue should really know the science and understand the formulas otherwise y'all be shooting darts in the dark with only 'practice' wishing for overunity because there are infinite ways to experiment.  And if by any luck you get it you won't be able to reproduce it, prove it, or explain it.


That can be observed with a simple joule thief loading a cap and discharging it manually...  As the voltage raise in the cap, the joule thief raise in frequency due to the LESS RESISTIVE CHARGE of the cap..  Good point Tajarek

Offline Void

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Re: The secret to Overunity
« Reply #74 on: December 22, 2017, 12:39:23 AM »
I don't need to prove textbook formulas. Unfortunately many people want to debunk known textbook formulas as wrong and their lab tests as more correct.
it is astonishing to me how people see the formula that says charge on a capacitor Q=CV and still want to convince me that it depends on current.

Hi Tajerek. It has already been pointed out to you that you are making major mistakes in
your assumptions and interpretations. The total charge on a capacitor at a given point in time
is equal to C x V, yes, but that in no way means or implies that to build up that charge on
the capacitor that no current has to flow. :) You are showing that you have no understanding
of what the formulas represent.


with that being said, I have tested what I am saying and confirmed it.

There is no possible way that you have tested this, because if you did do some actual testing
you would quickly realize that what you have been saying here is false. :) To charge a capacitor
requires a flow of current (flow of charges). The formula which you yourself have posted for the capacitor
charge current clearly shows that the higher the applied voltage, the higher the initial capacitor charging current will be.

For you to keep saying that when you apply a high voltage to the capacitor there will be little or no capacitor
charge current is not only obviously completely at odds with the formula which you posted, but it shows that
you have not even the most basic understanding of simple electric circuits and how capacitors work. If you did,
you would not be making such obvious errors.

I won't waste further time on this, as anyone with even just a very basic understanding of capacitors will be
able to see that what you are saying makes no sense.

All the best...




 

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