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Author Topic: Negative Inductance and measure of Magnetic force.  (Read 165509 times)


synchro1

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Re: Negative Inductance and measure of Magnetic force.
« Reply #346 on: October 17, 2018, 05:41:41 PM »
Here's a video of exclusive BEMF illuminating a small bank of four LED's in series parallel:

https://youtu.be/pZ21536Jogo


Evacuating the BEMF causes the oscillator to speed up; A "Reverse Lenz" effect we've seen demonstrated many times.
« Last Edit: October 17, 2018, 08:06:11 PM by synchro1 »


F6FLT

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Re: Negative Inductance and measure of Magnetic force.
« Reply #348 on: October 18, 2018, 11:35:58 AM »
32 3v LED's at full brightness should consume around 30 ma apiece. That's 960 milli amps all totaled. The D.C. wall transformer only generates 1000 ma (1 Amp), so the 32 LED's lit to full brightness would confirm that the output is equal to the input.
...

The coil is outputting nearly six volts. A coil with twice the turns should generate close to twelve. That would allow for a closed loop.
...

There is no surprise at all to see LEDs lit by a power supply connected to the mains.
I wonder why so many alleged inventors provide youtube videos without any measurement but with a lot of blah-blah, rather than going directly to the "closed loop" of which they dishonestly hint at the possibility.


synchro1

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Re: Negative Inductance and measure of Magnetic force.
« Reply #349 on: October 18, 2018, 02:40:57 PM »
Here's the schematic with the output switch closed:

F6FLT

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Re: Negative Inductance and measure of Magnetic force.
« Reply #350 on: October 18, 2018, 03:46:06 PM »
Why not connect the LEDs directly to the battery?
That would be much more efficient!   :D

synchro1

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Re: Negative Inductance and measure of Magnetic force.
« Reply #351 on: October 18, 2018, 04:17:28 PM »
Why not connect the LEDs directly to the battery?
That would be much more efficient!   :D


The solenoid piston can turn a flywheel for free and light the LED's too.



synchro1

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Re: Negative Inductance and measure of Magnetic force.
« Reply #354 on: October 21, 2018, 12:03:11 PM »
Increasing the copper mass and magnet strength will increase the foot pounds of torque in the solenoid piston. An attraction oscillator the size of Joe Neman's "Big Eureka" would drive a train locamotive and run for free just like the big Newman motor. People routinely replicate the Newman spinner but they can't re-create the commutator, that's why we never see any self running Newman motors.   


The solenoid magnet piston beats the switch spring to the top, and the inductive kickback is dissipated during this delay. Tapping back spike from the coil electrodes kills the induction; The current is traveling in the opposite direction!


Joe Newman's commutator had a section that sidetracked the back spike to a separate destination. The spring pressure switch simply looses it in a hysteresis loop so the output is unadulterated BEMF. Flyback kills induction.

synchro1

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Re: Negative Inductance and measure of Magnetic force.
« Reply #355 on: October 21, 2018, 02:57:39 PM »
It"s easy to see how a Newman motor would loop the same way as the attraction oscillator, with a cam lobe and an SPDT micro roller spring pressure switch. The cam lobe would have to be shaped to close the output gates at 17 degrees past TDC to allow time for the inductive kickback to discharge. The remainder of the output would be current traveling in a reverse direction. The back spike we skipped with the connection delay. If you don't detour the back spike, the Newman motor will fail to work because the flyback cancels the induction.

The spring release time is equal to or greater then the inductive kickback discharge time in the attraction oscillator. The entire attraction stroke is a pure D.C. pulse. That's all we need to catch. This is free power and in no way effects the torque on piston.

synchro1

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Re: Negative Inductance and measure of Magnetic force.
« Reply #356 on: October 21, 2018, 08:44:23 PM »
Halbach levitation rings like these can suspend a very heavy solenoid magnet cylinder on it's side:

https://i.pinimg.com/236x/2e/40/69/2e40694fc87d151245e6bf738fb0e5f7--eddy-current-magnetic-levitation.jpg


A very large attraction oscillator could ideally pressurize a hydraulic fluid system and drive a piston like a steam engine. The pressure on the power stroke would be directly proportional to the mass in copper and magnet strength. Let's say we add ten times the copper wire and a ten times stronger magnet. We develop ten times the pressure on the solenoid piston, but the power in and power out remain about even!

synchro1

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Re: Negative Inductance and measure of Magnetic force.
« Reply #357 on: October 22, 2018, 06:38:38 PM »
The Mendocino levitator applies pressure to the tip of the axle. Placing a repulsion coil and an electrode on the axle may get it to trigger an SPDT relay with a small battery in the circuit. A resistor would need to be connected between the contacts and the relay to delay the pulse enough to permit discharge of the inductive kickback.


Two of these power looping Mendocino oscillators running reciprocally, face to face could oscillate a third larger solenoid magnet cylinder in the center perhaps levitated by Halbach rings inside an output coil.

synchro1

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Re: Negative Inductance and measure of Magnetic force.
« Reply #358 on: October 22, 2018, 08:09:37 PM »

all axially magnetized rings; two coils; one hybrid power at the wall, and a second strictly output for the outside magnet.


this generator would be over unity by exactly the amount of bemf it recovered.

plev.isofront.png

synchro1

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Re: Negative Inductance and measure of Magnetic force.
« Reply #359 on: October 23, 2018, 03:39:16 PM »
The trick to running the "Mendocino levitator attraction oscillator" would simply be to position the SPDT pressure switch with a backing magnet strong enough to depress the switch spring with the attraction force from the axle magnet. The levitator base magnets would need to be extended to cover the throw. Two coils would nest between them, one on each end, the far side exclusively output.