To browser these website, it's necessary to store cookies on your computer.
The cookies contain no personal information, they are required for program control.
  the storage of cookies while browsing this website, on Login and Register.

Storing Cookies (See : ) help us to bring you our services at . If you use this website and our services you declare yourself okay with using cookies .More Infos here:
If you do not agree with storing cookies, please LEAVE this website now. From the 25th of May 2018, every existing user has to accept the GDPR agreement at first login. If a user is unwilling to accept the GDPR, he should email us and request to erase his account. Many thanks for your understanding

User Menu

Custom Search

Author Topic: HV Question...  (Read 3711 times)

Offline dieter

  • Hero Member
  • *****
  • Posts: 938
HV Question...
« on: February 17, 2017, 06:34:09 AM »
A simple question:

Imagine a weak HV source, such as a moskito killer that runs on 2x 1.5V AA cells and puts out a humming 1.2 kV DC.

The plus output may go over a sparkgap, then trough a diode to protect the HV generator, then trough a transformer that shifts the sparkgaps primitive AC to like 5kV. The back-emf may reach 20kV now.

Then, right next to this wire between diode and transformer is the unisolated, hot wire of the mains grid.

Imagine the voltage of the back emf is high enough to jump to the other wire, the hot mains wire (warning, this may or may not destroy electronics, connected with mains, including the watt meter etc. And your power company may even notice it)

So, any Idea what's going to happen?

Additionally, the same experiment, just with a car battery cable instead of the mains hot wire, what would happen?


Offline dieter

  • Hero Member
  • *****
  • Posts: 938
Re: HV Question...
« Reply #1 on: February 17, 2017, 08:05:24 PM »
Here's my guess of what could happen:

Let us assume the car battery experiment:

So the spark of +10kV jumps to the battery cable minus, and for a brief moment you have a huge potential diffrence between spark impact and battery negative. Theoreticly a current should flow, but how could it, if the positive of the battery is unconnected?