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Author Topic: Zoltan Szili overunity circuit  (Read 4039 times)

Offline sidneysomes

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Zoltan Szili overunity circuit
« on: February 10, 2008, 06:00:30 AM »
Has anyone information on this circuit in public domain since 2005?  I find nothing on it in a search of Naudin's website even though the Rex Research article references Naudin.    Link:http://www.rexresearch.com/szili/szili.htm

Free Energy | searching for free energy and discussing free energy

Zoltan Szili overunity circuit
« on: February 10, 2008, 06:00:30 AM »

Offline Paul-R

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Re: Zoltan Szili overunity circuit
« Reply #1 on: January 09, 2018, 03:55:08 PM »
Has anybody any news on this apparently fairly simple-to-build circuit?

Offline AlienGrey

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Re: Zoltan Szili overunity circuit
« Reply #2 on: January 09, 2018, 05:33:43 PM »
Do you mean this http://www.rexresearch.com/szili/szili.htm

Nice try : it's hardly going to light a suspension bridge at night !

it's barley a couple of milliamps !

Allen

Free Energy | searching for free energy and discussing free energy

Re: Zoltan Szili overunity circuit
« Reply #2 on: January 09, 2018, 05:33:43 PM »
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Offline conradelektro

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Re: Zoltan Szili overunity circuit
« Reply #3 on: January 09, 2018, 11:45:54 PM »
If you look at the attached circuit diagram of the Zoltan Szili contraption, you will see that the Gate goes higher than the Drain of the IRF510 transistor. The power supply for the Drain-Source is only 1.5 Volt, but the signal driving the Base of the transistor goes up to 5 Volt.

This is a bad way to use a IRF510 transistor, the Gate should never go higher than the Drain. And it can well happen that the Gate leeks current through the transistor into the Drain-Source part of the circuit if the Gate has higher potential than the Source. The IRF510 is a very robust transistor and withstands the maltreatment, but not without non-standard outcome.

So, the alleged OU comes from the signal generator or whatever drives the Gate. The alleged OU is only about 0.12 Watt, which is not a problem for a run of the mill signal generator and no problem for the robust IRF510.

The circuit is also very simple. Do you really think that nobody would have noticed OU till now?

One should put a measuring resistor of 1 Ohm (shunt) in front of the gate in order to see where the OU comes from.

Greetings, Conrad

 

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