Dear Sm0ky2 sir,
As per my calculations it must work.if there is something wrong then please clarify it.
The scale length is 2 meter.
There is a 2 or 4 meter long tube.
Let's take tube length 2 meter.
This 2 meter long tube is mounted on left arm of seesaw in middle so it's 1 meter part is above fulcrum and 1 meter is below fulcrum.
A 10 kg.ball is resting at the bottom of the tube.
Now counterweight.
After calculating distance from fulcrum the counterweight will be 14.4 kg.to balance the seesaw as the distance of ball is 1.44 meter from fulcrum as the ball is in rest position in the tube.
Now the seesaw is in balanced position.
But I will take counterweight 20 kg.due to this excess counterweight the seesaw will be in tilting position at 90 degree angle.
Now when I lift up the seesaw then I will not have to calculate the input energy of the 1 meter distance of tube which is mounted below fulcrum as I have added mass in counterweight.
Now calculate input using mgh formula
Mgh=10*10*1=100 Joule
But calculate output as ball will fall down from 2 meter height
Mgh= 10*10*2=200 Joule
Ball will again fall down from 2 meter height at the time of reversing
Mgh=10*10*2=200 Joule
So total output is 400 Joule but input is 100 Joule.
The very interesting point is that it is not important that the device must complete one cycle as ball has completed one cycle.
See the link.you can see momentum in the video.
https://youtu.be/TQr-MR2yj_U