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Author Topic: re: energy producing experiments  (Read 67815 times)

Offline Delburt Phend

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Re: re: energy producing experiments
« Reply #210 on: November 18, 2020, 03:50:39 AM »
Tie a string to a puck, at rest, on a frictionless plane; put the string through a small low friction tube.  Pull the puck toward the tube. Does the puck begin accelerating in a clockwise direction? What in the pull would cause the puck to rotate and then accelerate that rotation?

Nor would you lose velocity; the friction in the tube is not upon the puck; in is on the hand. The inward pull will have little whatever to do with the motion of the puck.

Yet the establishment goes nuts when you tell them angular momentum is not conserved.

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Re: re: energy producing experiments
« Reply #210 on: November 18, 2020, 03:50:39 AM »

Offline Delburt Phend

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Re: re: energy producing experiments
« Reply #211 on: January 13, 2021, 02:21:38 PM »
https://groups.spa.umn.edu/demo/mechanics/movies/1Q4020.mp4

At first the balls are far apart, and I measured the average rotational speed during this section to be 6.6 rad/sec (63 rpm).

Then he squeezes the handle and the balls are pulled nearer. During this section, I measured the the average rotational speed to be 17.5 rad/sec (167 rpm).
Finally, he released the handle and the balls resume their original distance. At this section, the average angular speed was 5.0 rad/sec (48 rpm).

So over the course of about 10 seconds, the speed dropped from 6.6 to 5.0 (24%). Hopefully, we can agree that is due to various losses - probably friction and aerodynamic drag.

But if we take a look at how the speed changes when the radius changes, we should get a good picture of how angular speed is related to radius.

Offline Delburt Phend

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Re: re: energy producing experiments
« Reply #212 on: January 13, 2021, 02:23:30 PM »
I should say that this is someone else that is doing this evaluation.

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Re: re: energy producing experiments
« Reply #212 on: January 13, 2021, 02:23:30 PM »
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Offline lancaIV

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Re: re: energy producing experiments
« Reply #213 on: January 13, 2021, 06:30:37 PM »
Hello,related #211 I reed yesterday in old threads in a discussion between Gustav Pese and Kator01 as given example by Kator/Mich(a)el a similar physical configuration !
Probably he,Kator01, can give good advices/links/help !

Sincere
OCWL

Offline helmut

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Re: re: energy producing experiments
« Reply #214 on: January 15, 2021, 11:02:14 AM »
Gustav Pese ... he should Rest in peace... he would love to see what Mr Zündel developed  regardimg  to gravity. Hello Mr de Lanca .. long time.


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Re: re: energy producing experiments
« Reply #214 on: January 15, 2021, 11:02:14 AM »
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Offline lancaIV

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Re: re: energy producing experiments
« Reply #215 on: January 15, 2021, 02:23:21 PM »
Hello,related #211 I reed yesterday in old threads in a discussion between Gustav Pese and Kator01 as given example by Kator/Mich(a)el a similar physical configuration !
Probably he,Kator01, can give good advices/links/help !

Sincere
OCWL
I refound it : https://overunity.com/30/extra-electric-power-power-amp/45/    #54 and meaning that translated does more sense  ::) :
A DESIGN FOR A PERFECT QUANTUM RESONANT PENDULUM

 http://www.unifiedtheory.org.uk/

 Here the principle of storing and retrieving centrifugal force is explained very well. Nobody had such an idea so far. However, it must be built differently than shown. Centrifugal forces, which are actually inertial forces (from the point of view of a co-rotating observer) take on enormous dimensions.

Here, too, the solution lies in moving away from the "rigid" concept towards a dynamic one so that the enormous potential can be decoupled.

Example: A weight of 100 grams generates a centrifugal force of approx. 1480 N [kg m / sec exp ^ 2) when rotated 20 cm from the axis at 3000 rpm.

First you have to temporarily store this force, if you let it run against a resistance for 1 second, for example (= impulse braking, the weight remains on the axis, it does not fly away tangentially) you get an impulse = F xt = force times time of 1480 kg meter / sec.
 If you let go of the weight (as every hammer thrower does), you get the impulse = F xt = M x V (mass times speed) = 0.1 kg times 47.12 meters / sec = 4.7 kg m / sec, i.e. only approx. 1/300 of the possible centrifugal force impulse (in SI units)

What a difference if done right.
 So far, nobody has thought of it because all circular systems are viewed rigidly.
 The author claims that he took a DC motor with a similar configuration to 3000 rpm, then switched off the DC input, after which the motor continued to run with a vibrating noise for 20 minutes (auto-resonance) before it switched off then had to brake violently.

Offline lancaIV

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Re: re: energy producing experiments
« Reply #216 on: January 15, 2021, 02:33:44 PM »
Gustav Pese ... he should Rest in peace... he would love to see what Mr Zündel developed  regardimg  to gravity. Hello Mr de Lanca .. long time.
??? Wer sind Sie ?  ???
 ;D Halloechen,helmut und Duisburg !? Oder Wohnort geaendert ? Immer noch politisch links von der Mitte ?  ::)

                              Oder nun doch "eingefleischter"  Merkelianer ? ;) ( An Sitzfleisch mangelt es dieser Person ja nicht ! :-\ )

                              Die oide "Ueber-Mutti der Nay-ssion" geht ja baldigst von Bord ! :'( Neuer bloeder Lotse gesucht !

                             Sie vielleicht ? 8) Erst Duisburg unter Sparkommissariat dann die ganze Nay-ssion ! Lock-out forever ! :o ;D


      Bei overunity.de war doch ein Frankfurter/Main( der mit dem Kaefer,nicht zwei-beinig,vier-raedrig) mit dem "Ei"      (Wasserstoff/bzw.HHO-Kata-/Elektro-lyse)
      anderes "Ei" https://www.weka.de/einkauf-logistik/das-wasserstoff-ei-des-kolumbus-revolution-in-der-energieversorgung/
      https://www.youtube.com/watch?v=kfYiQVzB3Cg

      individuelle pro/contra Meinung https://www.youtube.com/watch?v=PkbjkXTBsyw

Schon wieder Freitag , also schoenes geruhsames -home office - Wochenende wuenschend !

Bis dann mal
OCWL

p.s.: habe den Research nicht verlassen ,aber guenstige Technologie-Alternativen zu Imris/Ferreira Spulen
 da spielt ein hiesiger Ex-Phillips-Ingenieur, aktuell als Professor taetig, eine Rolle,wobei wir " uns technologisch" gegenseitig befruchten

Free Energy | searching for free energy and discussing free energy

Re: re: energy producing experiments
« Reply #216 on: January 15, 2021, 02:33:44 PM »
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Offline helmut

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Re: re: energy producing experiments
« Reply #217 on: January 23, 2021, 01:32:17 PM »
Hallo Hallo . Ja , wir kennen einander. Der Käfer aus Frankfurt rollt wohl nicht mehr. Leider hat der Schöpfer sich zurück gezogen. Andere werkeln nun weiter an HHO und meine eigenen Aktivitäten mit OLGA der Trennzelle ruhen noch eine Weile.  300 Tage bis zur Rente. Zwischenzeitlich hatte ich einen Abstecher in die Electromedizin getan und stecke noch fest , bis ich mir genug Wissen über die Frequenzerzeugung im Ghz Bereich angeeignet habe. Aus Duisburg komme ich erst raus , wenn ich die Hütte verkauft habe. Mutti und ihre Schergen giften uns mit ihrer hässlichen Fratze an. Oft denke ich über Auswandern nach. Ich grüsse Sie.


Offline Delburt Phend

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Re: re: energy producing experiments
« Reply #218 on: February 11, 2021, 02:56:20 AM »
You could construct a strong light wheel made of modern fiber that had a high quality center bearing. The wheel could be attached by a string to a 399 kilogram mass floating on dry ice. This same wheel could have a second string attached that had a 1 kg mass on the end.

The string for the one kilogram is arranged so that is can wrap around the wheel and the 399 kg is just pulled by the wrapping of the one kilogram.

What proponent of COAM are saying is that the one kilogram that is only moving twenty meters per second can wrap around the wheel and cause the 399 kilograms to achieve a velocity of 1 m/sec. The one kilogram only needs a string long enough to give the one kilogram a angular momentum sufficient for the 400 kg * 1 m/sec movement. This is ridiculous 20 units of momentum can not make 400 kg*m/sec.

Free Energy | searching for free energy and discussing free energy

Re: re: energy producing experiments
« Reply #218 on: February 11, 2021, 02:56:20 AM »
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Offline Delburt Phend

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Re: re: energy producing experiments
« Reply #219 on: February 23, 2021, 02:46:00 AM »
This is about an Atwood's machine with 199.5 kg on one side and 200.5 on the other.

Yes; the difference between M1 and M2 is 1 kg; and the sum is 400 kg. That means that the acceleration ‘a’ is 1/400 times 9.81 m/sec/sec.  a = .024525 m/sec²

Now the formula for time is used; d = ½ at²   With a drop distance of one meter and an acceleration of .024525 m/sec² we have a drop time of 9.03 seconds.

Doing the same for free fall we get a drop time of .4515 seconds.

9.03 sec / .4515 sec = 20

The force of 9.81 N is applied for 20 times as long in the (400 kg to 1 kg) Atwood’s machine.

The final velocity of the Atwood’s is found by this formula;  d = ½ v²/a;   this is just d = ½ at²  where v/a is substituted for t.

The final velocity for one meter of free fall is 4.429 m/sec; The final velocity for the 400 to one Atwood’s is .22147 m/sec.

This is 4.429 (1 kg * 4.429 m/sec) units of momentum for free fall and (400 kg * .22147 m/sec) 88.589 units of momentum for the Atwood’s. This is 20 times as much momentum produced; and 20 times as much time over which the force acts.

It takes 4.429 units of momentum to return the one kilogram of imbalance to the original position of the Atwood’s.  And you get 88.589 out.

Now this is the quantity of momentum that Newton said was conserved and you put 4.429 units in and you get 88.589 units out. Every cycle; 4.429 in 88.589 out.

All that is needed is to transfer the motion of the 400 kilograms into the one kilogram: and that can be done with a cylinder and spheres machine.

There is also a modified Atwood’s that eliminate the up and down motion; if that bother some.

Offline Delburt Phend

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Re: re: energy producing experiments
« Reply #220 on: March 01, 2021, 07:17:38 PM »
https://pisrv1.am14.uni-tuebingen.de/~hehl/Drehimpuls.pdf

The last two are of interest; and the labrat disproves his own theory.

You have to click on the graph to make the video play.

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Re: re: energy producing experiments
« Reply #220 on: March 01, 2021, 07:17:38 PM »
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Offline Delburt Phend

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Re: re: energy producing experiments
« Reply #221 on: March 03, 2021, 11:34:27 PM »
This is about a discussion on the cylinder and spheres experiments.

If you were to shoot a 1 kilogram mass moving 20 m into a 399 kilogram block; the block will not start moving 1 m/sec. This is the conservation of energy and it will not happen; as you know. But you are proposing that you put the one kilogram on a string and then it will happen; but it won’t, the string will not make it happen.

You lose it all to heat; right. That is what the theory says, so stick with it.

It takes four frames to cross the black square at the start and four frames after the spheres return the motion. The spheres are much smaller than the cylinder and they can not return the energy to the cylinder. The spheres return the momentum to the cylinder, which means they received the momentum from the cylinder.

The Paul Nord experiment proves that angular momentum conservation does not work in the lab. That leaves you with only linear Newtonian momentum. And if Newton is correct this leaves us with free energy.

Circular Motion - YouTube

https://www.youtube.com/watch?v=zww3IIMRo4U

Offline telecom

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Re: re: energy producing experiments
« Reply #222 on: March 05, 2021, 12:16:32 PM »
This is about an Atwood's machine with 199.5 kg on one side and 200.5 on the other.

Yes; the difference between M1 and M2 is 1 kg; and the sum is 400 kg. That means that the acceleration ‘a’ is 1/400 times 9.81 m/sec/sec.  a = .024525 m/sec²

Now the formula for time is used; d = ½ at²   With a drop distance of one meter and an acceleration of .024525 m/sec² we have a drop time of 9.03 seconds.

Doing the same for free fall we get a drop time of .4515 seconds.

9.03 sec / .4515 sec = 20

The force of 9.81 N is applied for 20 times as long in the (400 kg to 1 kg) Atwood’s machine.

The final velocity of the Atwood’s is found by this formula;  d = ½ v²/a;   this is just d = ½ at²  where v/a is substituted for t.

The final velocity for one meter of free fall is 4.429 m/sec; The final velocity for the 400 to one Atwood’s is .22147 m/sec.

This is 4.429 (1 kg * 4.429 m/sec) units of momentum for free fall and (400 kg * .22147 m/sec) 88.589 units of momentum for the Atwood’s. This is 20 times as much momentum produced; and 20 times as much time over which the force acts.

It takes 4.429 units of momentum to return the one kilogram of imbalance to the original position of the Atwood’s.  And you get 88.589 out.

Now this is the quantity of momentum that Newton said was conserved and you put 4.429 units in and you get 88.589 units out. Every cycle; 4.429 in 88.589 out.

All that is needed is to transfer the motion of the 400 kilograms into the one kilogram: and that can be done with a cylinder and spheres machine.

There is also a modified Atwood’s that eliminate the up and down motion; if that bother some.

Can this transfer be done by the different means?
For example using m * v = F * dt
In your case for the t= 1 sec F is equal 80 N
The piston of the hydraulic cylinder can be pressed with 80 N for 1 sec, which can be used to turn the generator...
I can be wrong, though.
Tnx

Offline Delburt Phend

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Re: re: energy producing experiments
« Reply #223 on: March 11, 2021, 10:12:46 PM »
I did an air table experiment today were I used the center pin of the air table to interrupt the string on a puck with a 108 cm radius. After the string hit the pin; the new radius was 14.9 cm. This is a radius change of 108 cm to 14.9 cm = 7.25.   108 cm is 7.25 times larger than 14.9 cm.

Therefore if angular momentum is to remain the same the linear velocity of the puck will have to increase by a factor of 7.25.

I did a video and I placed this video on my computer; I put the video in a frame by frame mode and counted the frames needed to cross a distance of 2.86 cm on the puck. It took 21 frames to cross this distance on the puck when the radius was 108 cm and when the radius was 14.9 cm.   At 240 frames per second this is a speed of .327 m/sec for both the small circle and the large circle. There is no change in velocity when you go from the large circle to the small circle.

I did it in the opposite direction as well; going from the small 14.9 cm circle to the 108 cm circle.  There is no change in velocity when you go from the small circle to the large circle.

Now I will try to post the video.

Offline Delburt Phend

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