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Author Topic: Bozidar Lisac  (Read 4823 times)

antimony

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Bozidar Lisac
« on: December 16, 2016, 03:17:54 PM »
Hi, I printed out a few pages of Patrick Kellys chapter 5, because i have trouble reading on a screen.
Anyway I printed out the patent documentation of a guy called Bozidar Lisac, which i found interesting.
I don't know if you have heard about this guy, but I just wanted to ask if there was someone who had.
I googled, and i didn't find anything from this forum or any other.

Patent application nr: US20080030165


Paul-R

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Re: Bozidar Lisac
« Reply #1 on: December 16, 2016, 05:29:40 PM »

Low-Q

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Re: Bozidar Lisac
« Reply #2 on: December 17, 2016, 11:40:39 AM »
I'm a little confused where the inventor is heading with this, but I think he is wrong about the work from the capacitors.
When in parallell, the capacitors C will be charged with the same voltage within time T. The capacitance is 2xC at a given voltage 1xV, and the charging time is 2xT.
When the switches turns the capacitors into series, the total voltage V is 2xV, but the total capacitance C is C/2. So the discharge time is reduced to T/2, enabelig the capacitors to discharge fully and not partially.


Vidar

antimony

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Re: Bozidar Lisac
« Reply #3 on: December 17, 2016, 12:19:50 PM »
As I understand it is not a "real" patent, but an patent application so it may not be anything. If
But has anyone any experience with these circuits or if anything it would be easy to throw them together.  I am going to give it a try but I am new to electronics as you may know if you have already read some of my earlier posts. :)

citfta

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Re: Bozidar Lisac
« Reply #4 on: December 17, 2016, 12:58:01 PM »
That patent application is simply a cheap attempt to copy someone else's work and profit from it.  The idea of recycling the energy by charging and discharging caps goes back to 1989 when Ray Nelson demonstrated his scalar battery charger to John Bedini.  The idea has evolved for those of us working on it into the Basic Free Energy Device found on the Energetic Forum and also found here in a thread called David Bowling's Continuous Charging Device.  Here is a link to a thread discussing the original device:

http://www.energyscienceforum.com/showthread.php?t=70

I hope this helps to clear up some of the confusion.

TinselKoala

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Re: Bozidar Lisac
« Reply #5 on: December 18, 2016, 12:08:53 AM »
Energy (Joules) on a capacitor is given by E = (CV2)/2.

Charge two 1 F capacitors in parallel to 1 V.  Energy contained in the system is E = (2*12)/2 = 1 Joule.

Now connect the two caps in series. Voltage of the system is now 2 V, but capacitance has decreased to 0.5 F.
So energy contained in the system is E = (0.5*22)/2 = 1 Joule.

So no cheezburger today, sorry.   :'(

citfta

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Re: Bozidar Lisac
« Reply #6 on: December 18, 2016, 01:17:33 AM »
What you said TK is true but consider this. The 1 Joule of energy would have gone to ground if not used to charge the caps.  So we now have 1 Joule of energy that can be returned back to the source.  Well not quite because the 2 caps in series can only discharge to close to the same level as the battery voltage so the caps never really return all that was put into them.  But by returning almost half of the energy put into them they do make the system much more efficient.  We are powering a load and charging some caps at the same time with the current leaving the load.  Then depending on the circuit we can power the load again as we send half of the cap energy back to the source or just send it directly back to the source.  Anyone that understands the charge and discharge actions of caps will see there is no extra energy here, just a simple way to reuse some of the energy and make a more efficient circuit.

Carroll

Low-Q

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Re: Bozidar Lisac
« Reply #7 on: December 18, 2016, 09:32:24 PM »
What you said TK is true but consider this. The 1 Joule of energy would have gone to ground if not used to charge the caps.  So we now have 1 Joule of energy that can be returned back to the source.  Well not quite because the 2 caps in series can only discharge to close to the same level as the battery voltage so the caps never really return all that was put into them.  But by returning almost half of the energy put into them they do make the system much more efficient.  We are powering a load and charging some caps at the same time with the current leaving the load.  Then depending on the circuit we can power the load again as we send half of the cap energy back to the source or just send it directly back to the source.  Anyone that understands the charge and discharge actions of caps will see there is no extra energy here, just a simple way to reuse some of the energy and make a more efficient circuit.

Carroll
The capacitors can't discharge 100%, but not 100% charged either. The energy you put in is the excact energy you can get out - which make sense.