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Author Topic: Gravity assisted power project- GRAM  (Read 47655 times)

Offline burnit0017

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Re: Gravity assisted power project- GRAM
« Reply #75 on: October 09, 2016, 07:24:01 PM »

Offline burnit0017

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Re: Gravity assisted power project- GRAM
« Reply #76 on: October 09, 2016, 11:08:02 PM »

Offline burnit0017

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Re: Gravity assisted power project- GRAM
« Reply #77 on: October 11, 2016, 03:46:55 PM »
Last configuration failed.
New configuration attempt.

https://youtu.be/S3MokDKLgH8

Free Energy | searching for free energy and discussing free energy

Re: Gravity assisted power project- GRAM
« Reply #77 on: October 11, 2016, 03:46:55 PM »
Sponsored links:




Offline FreeEnergy

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Re: Gravity assisted power project- GRAM
« Reply #78 on: October 12, 2016, 12:36:17 AM »

Can you post the file as well please?

Thank you.

Offline burnit0017

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Re: Gravity assisted power project- GRAM
« Reply #79 on: October 12, 2016, 02:58:48 AM »
Hi, the lever  is 8 feet, the fall weight is 10 pounds rotating on 1 foot crank.

Free Energy | searching for free energy and discussing free energy

Re: Gravity assisted power project- GRAM
« Reply #79 on: October 12, 2016, 02:58:48 AM »
Sponsored links:




Offline burnit0017

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Re: Gravity assisted power project- GRAM
« Reply #80 on: October 16, 2016, 05:05:40 PM »
https://youtu.be/YWdlyuVDJu4

nice, possible up grade 8)

Offline Low-Q

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Re: Gravity assisted power project- GRAM
« Reply #81 on: October 17, 2016, 02:58:46 PM »
https://youtu.be/YWdlyuVDJu4

nice, possible up grade 8)
An oscillator, or pendulum like this does not operate very much different from a rotary solution, because both principles are based on the very same sinusiodal fuction. At the moment you load the output coil, the magnet will feel resistance because the coil will resist induction when it is loaded. This resistance will add a delay on the pendulum that will drain the kinetic energy of it, so the pendulum will stop sooner than if it was not loaded. Using big heavy weights, will not make any othe difference than sustaining oscillation longer because higher weight at a given angular velocity has more kinetic energy than a light weight at the same angular velocity.
This kind of resistive electromechanism will apply to any form of generators that is loaded. A rotary solution will keep rotating as long there is no energy output, just like the pendulum will continue to oscillate as long there is no energy output, but both will be drained if you load them.
I can see that the bicycle frame is wobbling like a seesaw. If you take energy out of this seesaw, the very same happens. When you load it with resistance, you basicly are counterforcing the seesaw with a given delay that will cause the pendulum to stop. No free energy in this one.


Vidar

Free Energy | searching for free energy and discussing free energy

Re: Gravity assisted power project- GRAM
« Reply #81 on: October 17, 2016, 02:58:46 PM »
Sponsored links:




Offline burnit0017

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Re: Gravity assisted power project- GRAM
« Reply #82 on: October 17, 2016, 11:14:03 PM »
Thanks for the info.

Offline burnit0017

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Re: Gravity assisted power project- GRAM
« Reply #83 on: October 17, 2016, 11:27:55 PM »
https://youtu.be/Y1cKWIAFT0I

will the same happen

Offline Low-Q

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Re: Gravity assisted power project- GRAM
« Reply #84 on: October 18, 2016, 07:38:30 AM »
https://youtu.be/Y1cKWIAFT0I

will the same happen
The same will happen here if it wasn't for the energy input from the pneumatically piston.
The misconception is that a pendulum that is arranged like this will provide energy output with little or no energy input. However, the energy output is a direct consequence of the energy input.
It is both mathematically and practically provable, but the inventors often overlook this because of the construction principle plays mind tricks.
It's difficult, if not impossible, to observe the machine behavior in detail. The counterforce from the energy output is allways slightly ahead of the mechanical oscillation. This is harder to observe the less energy output there is.


However, it has been built water wells with hand powered pumps that is based on this principle. These pumps are more efficient because the loss in the human body is less when operating such a pump compared to the continuous external pressure directly on a pump lever. Try to press your hands hard together for a while. No work is done because the hands are stationary, but you consume lots of energy. The pendulum require a short burst of energy input that in turn does not require much energy from your body, but the energy input is not less than the energy required to pump the water.


Vidar

Offline burnit0017

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Re: Gravity assisted power project- GRAM
« Reply #85 on: October 18, 2016, 11:52:45 AM »
Hi, thanks again. My project is a attempt to find a configuration that will combine a small amount of electricity with mechanical advantage and gravity at the input that will produce a max torque at the output shaft.  The output shaft will drive a PMA. I plan to use Buck converter with a variable duty cycle  at the output of the PMA. The electricity generated at the output will be less then 50% of the max torque of the output shaft.
I will post results when available.  Thanks again.

Offline Low-Q

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Re: Gravity assisted power project- GRAM
« Reply #86 on: October 18, 2016, 05:19:40 PM »
Just a tip for your project:
If you want to calculate energy, you must multiply torque with displacement. Torque is usually measured in punds pr feet or Newton per meter radius.


A buck converter is useful. These small devices increase voltage output on expense on current input. If you want to power a 10W load that runs on 20V @ 0.5 Ampére, and the input voltage is 10V, then the buck conveter will draw 1 Ampére from the input. So a buck converter does not increase energy output. The more expensive ones have an efficiency of approx 90-95%, which means for each watt output, it draws 1.05 - 1.1W at the input. Think of a inverted pulley with ropes. You must displace 1 meter of rope at 2kg force to lift a 1kg weight 2 meters up.


Good luck :-)


Vidar

Offline burnit0017

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Re: Gravity assisted power project- GRAM
« Reply #87 on: October 19, 2016, 04:20:12 PM »
DC to DC step down converter = Buck converter

https://youtu.be/B3dLzZZ5jKQ

Offline Low-Q

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Re: Gravity assisted power project- GRAM
« Reply #88 on: October 19, 2016, 09:06:08 PM »
You can also buy them as DC to DC step UP converters. Amazingly how stable the output voltage is when you load them. I use such a converter to power my DIY aux head lights on my car. From the 12V car battery, this converter outputs 30V @ 3.2A, and if I hook off the load, the voltage is still 30V. I had to hook it directly on to the battery with a 10A fuse, and a relay, because the converter draws 9A from the battery, and the fuse in the car will blow if I power the converter directly from the head lights.
My LED aux lights are 2 x 5 LEDs at approx 10W each. Mine can deliver approx 160W max. Bought on DX.com.


Vidar

Offline burnit0017

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Re: Gravity assisted power project- GRAM
« Reply #89 on: October 22, 2016, 03:37:57 PM »
https://youtu.be/uWsDc0oMrmI

proceeding to fabricate  Milkovic 2 stage oscillator  configuration

 

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