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Hi thereHere is my take on the issue.In order to try to address your question, the question should be properly defined. 1, If your question is based on the Maxwell displacement current then “Maxwell displacement current” either in vacuum or in dielectrics, neither generate magnetic field nor are sensitive to external magnetic fields. In other words current in dielectrics “The polarization current” does not act with potential forces on other currents and “external magnetic field” does not react with kinetic forces to the action of other currents.2, Displacement current is a quantity appearing in Maxwell's equations that is defined in terms of the rate of change of electric displacement field. Displacement current has the units of electric current density, and it has an associated magnetic field just as actual currents do. However it is not an electric current of moving charges, but a time-varying electric field. To conclude the above I quote from “Harry McLaughlin” https://www.quora.com/profile/Harry-McLaughlina. A "changing" electric field CANNOT create a magnetic fieldb. A "changing" magnetic field CANNOT create an electric field “end of quote”3, The so-called "displacement current" term(1/4π) ∂E/∂t is not some current density generating magnetic field, as Maxwell supposed. This term gives information about the conduction currents which have been interrupted in the neighborhood of the reference point.4, For what it worth, we cannot measure magnetic field produced by displacement currents but we can measure exactly the field of the interrupted conduction currents. Even if the details are not so obvious and require a skill to understand but what the equations imply is that the electric and magnetic fields depend only on the source charges. It is our orientation relative to the source charges and their motions that give rise to the details of the fields we measure.From Maxwell basic equations the only sensible is the existence of ε0 and µ0 ∂E/∂x=-Z0 ϵ0 ∂E/∂t∂H/∂x=-μ0/Z0 ∂H/∂tAnd they express that the E field causes the E Filed and The H field causes the H fieldWAW what a discovery!!!! The Equations only express that E and H fields are co-existent, co-substantial, and co-eternal like any two perpendicular sides of a brick neither the length affects the width or the other way around. Hope it helps jj
F.Y.I.Or even more simply:Electric charges or Potential Differences can be "exchanged or transferred" either by direct contact (e.g. wire conductor) or by {close} proximity (electrostatic influence). Current is generally associated with electron "flow" through a conductor and occurs when an electric charge is exchanged between potential charge differences (e.g. a wire circuit with resistance and a battery or oscillatory generator). Within the conductor, electrons "flow" [current] while external to the conductor, magnetic fields "flow." Electrostatic influence potential difference (charge) transfer does not use a conductor to facilitate "electron flow" therefore no current appears and thus there is no magnetic field. This assumes dry air or a pure dielectric. Arc discharges are beyond the scope here.The conundrum with Maxwell's equations occurs when a capacitor is considered since there is no direct connection (conductor) to facilitate current "flow" so, it appears, to preserve the "logic" a fudge factor was created. This has come to be known by many names including "Displacement Current". So the question might become; "Does a capacitor have a magnetic field?"However, if you consider the missing "scalar" part of Maxwell's equations or refer to the original complete equations initially created by Maxwell, there is no anomaly. But this would create another problem (?); that being the likely existence of the illusive {forbidden} aether and the existence of light as both a particle and a wave! Have faith however, there are work-arounds - not too elegant, but, break the problem into both Electromagnetics and Particle Physics!Also see: http://agni.phys.iit.edu/~vpa/information.htmlFIN