# Free Energy | searching for free energy and discussing free energy

## Mechanical free energy devices => mechanic => Topic started by: Gabriele on August 10, 2015, 08:11:24 PM

Post by: Gabriele on August 10, 2015, 08:11:24 PM
Hello. Here is a WM2d simulation. With electrostatics (or PERMANENT MAGNETS?). The costruction of the ring isn't very accurate. Left-half-thorus is 0,99998975 of right thorus.You can see. If somebody can build a draw 100% equivalent is better. Magnets (electrostatic objects) are polarized N S
S N

So when the array rounds gaining energy(?),when is rotated with the central gap to the center of the thorus,we can block it,catching work,moving it to the center again,and realligning to the start point repeating the game. Tell me what you think.

Gabriele
Post by: Gabriele on August 10, 2015, 11:16:09 PM
Perhaps I found a way. Unfortunatley i can't imagine a system to absorb energy from this method. Imagine a capillar can rise water for example 10 cm. Ok,now make it long 20cm. Anyway the water rise only for 10cm. Put it on water,water will rise 10cm. If you let sink capillar into water(imagining it very very thin,so Archimedes law could be trascurable) you obtain an energy due to force of surface tension of X for the distance defined by 10cm,and an X half for the rest. Energy we need to extract it from the water for 20 cm will be the same(X*15).Imagine now initial situation. Put a rod thiner than the capillar from top,inside the capillar. Liquid will rise for the rest of 10 cm emitting energy. Let sink capillar and the rod for 10cm(we gain X*15). Now let only the external capillar sink,gaining energy. Better up side down in Hg.

Nobel pls :D
Post by: Gabriele on August 17, 2015, 07:40:15 PM
Post by: Gabriele on August 18, 2015, 02:25:33 PM
What I need to underline is that if the system,could work,it not depends by gravity,but from surface tension only. If it works here on earth,it will work in space too. Is the concept clear? Can you help me with the question in the red drawing? Would be clearer if i draw entire process? Thanks
Post by: Gabriele on August 21, 2015, 02:29:55 AM
Should be possible. (About the red drawing: You can imagine let both thin glass walls escape from mercury,then reinsert only one. Energy you will obtain is minuscule,but positive)
Post by: Gabriele on August 22, 2015, 01:55:25 PM
I obtain an energetical surplus. Some one can consider to help me with the math? thank you
Post by: Gabriele on August 22, 2015, 06:56:33 PM
Math isn't hard.But i have a doubt. The following. If we have a capillar underwater for an example of 0.5 radius. Submerged for only an half of centimeter. I know force due from surface tension acting on external walls of capillar is the same of the max force reaceble by inside walls of capillar for the max "capillarity effect". So,if the capillar is only an half underwater,internal wall suffer by only a fraction of the max-force-capillar-effect. My doubt is the follow: if i insert a rod inside capillar for example 10cm,is obvious the skin of water will not drop for 10 centimeters. What appens? Does the skin of surface tension acts on rod like if we have the max-force-capillar-force-effect? I don't know. I'm oriented in NO.Orientation,like interpretetion is a fact of and due about things or substances like digressions can do.
__________________________________________________________________________________________________________________________________________________________

Gabriele
Post by: Gabriele on August 22, 2015, 06:58:56 PM
Post by: Gabriele on August 24, 2015, 11:13:49 AM
Math isn't hard.But i have a doubt. The following. If we have a capillar underwater for an example of 0.5 radius. Submerged for only an half of centimeter. I know force due from surface tension acting on external walls of capillar is the same of the max force reaceble by inside walls of capillar for the max "capillarity effect". So,if the capillar is only an half underwater,internal wall suffer by only a fraction of the max-force-capillar-effect. My doubt is the follow: if i insert a rod inside capillar for example 10cm,is obvious the skin of water will not drop for 10 centimeters. What appens? Does the skin of surface tension acts on rod like if we have the max-force-capillar-force-effect? I don't know. I'm oriented in NO.Orientation,like interpretetion is a fact of and due about things or substances like digressions can do.
__________________________________________________________________________________________________________________________________________________________

Gabriele

None?
Post by: Gabriele on August 27, 2015, 09:10:24 PM
Think I found. This expression is related to capillarity engine,considering the liquid as a magnet. Many wise italian friends told me it "could" be possible achieve overunity from a non-conservative field like a magnetic field. If you can imagine a rawer magnetic system about water (polar) and glass,you could build a way to grow a powerful system. I thought about use of paramagnetic and diamagnetic substances but had no reply.Anyway,i discriminated a solution if the
Quote
Math isn't hard.But i have a doubt. The following. If we have a capillar underwater for an example of 0.5 radius. Submerged for only an half of centimeter. I know force due from surface tension acting on external walls of capillar is the same of the max force reaceble by inside walls of capillar for the max "capillarity effect". So,if the capillar is only an half underwater,internal wall suffer by only a fraction of the max-force-capillar-effect. My doubt is the follow: if i insert a rod inside capillar for example 10cm,is obvious the skin of water will not drop for 10 centimeters. What appens? Does the skin of surface tension acts on rod like if we have the max-force-capillar-force-effect? I don't know
will don't appens.

Waiting for the nobel i wish you all the good (and somthing more).

Gabry
Post by: Gabriele on August 27, 2015, 09:12:21 PM
Post by: Gabriele on August 30, 2015, 11:00:16 AM
Post by: SoManyWires on August 31, 2015, 11:02:56 AM

by cutting the centre channel shown in the picture on one side,
it would increase transfer flow rate slightly, or reduce the flow rate depending on which of the 2 main chambers held more water in it,
also the pressure from more water at first, would gradually reduce the flow rate until equalibrium was achieved.

take an aquarium and silicon some glide slots for removable boards of different lengths to try in place or even just using tape instead of silicon to help get a more practical understanding of your project designs flow rate effects.
you want to harvest from the force of energy of a ferro-fluid being transferred past wire coils, or even just water, and possibly through rotating fins/turbines placed at the lower fluid transfer points, and more turbines placed on the inside walls of the chambers,
and maybe poured into another vessel that also collects energy like a regenerative braking system as that vessel lowers from its slow vertical fall / displacement?

it does seem maybe possible you could also include what you described for getting some energy from the raising of a float kept inside the center channel itself that maybe causes a shift in weight from a pushrod reaching a fixed angled rocking lever.

as for surface tension, the concept described was lost in translation for me, as much often is. and more often an idea seems to work better as just an idea until real tests are performed.

some sort of balance would have to trigger another action to make one side heavier that needs to be capable of repeating itself, borrowing from the electrical and mechanical energy created if you can keep developing it, there might be something there.