This is some data on producing  using rim jet turbine.
 
 1hp = 33,000lb raise one foot in one minute.
 33,000/60sec= 550lb second.
 1 gallon of water = 8.33lb or 1cubic foot = 7.48gal@62.31lb
 
 Foot head pressure = 0.434psi or one foot head.
 10 feet head pressure = 4.34psi.
 
My mathematical formula design to produce 20 hp.
 
 D= Diameter of water flowing out of a hole.
 
 Rim jet thrust pounds = 1.57 * psi * D* D
 
                                   _______________
 Rim jet flow rate = \/32+32 * (psi/0.434) = ft/per/sec
 
 Each Rim Jet  is ½ or 0.5 diameter
 
 At 250 psi:
 
 1.57*250psi * 0.5 * 0.5 = 98.125 pounds of thrust at a constant @10GPM.
 
 Thrust flow rate \/32+32* (250psi/0.434) = 192ft/sec
 
 Rim Jet diameter is 24” with a circumference of  (24*pi)= 75.4 in or 6.28ft. This allow thrust of  98.125 pound to be converted to foot pounds at a constant.
 
 Top speed  no load would be 192*60sec = 11520/6.28 = 1834 rpm.
 
 Full load at 917rpm @ 49ft/lb /5252 =  8.55hp @10 GPM because of loading down the rpm and loss in rotational speed.
 25.65 hp@30GPM would work just fine with a low rpm generator.
 
 8 pole generator 900rpm 10kw would be needed.
 
 Rim jet at 900 rpm *100ft/lb / 5252 = 17hp@20GPM. Gpm would have to be tested due to exit at the rim jet.
 
 17hp*85% efficiency = 14.45 hp
 
 14.45hp * 746watt =10.7 kw
 
 Testing the engine using low pressure and gpm.
https://www.youtube.com/watch?v=HYIWPMJwxoE


Tommey Reed

I believe the Lords Pump Project also is in Africa trying to do the same thing, do you work for them?

I have a system but I already have a investor involved.

I get 250+ psi with my system, can't say anymore then that..

https://www.youtube.com/watch?v=Gkj4w-CnXi0

Yes it works!




Tom