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Author Topic: Partnered Output Coils - Free Energy  (Read 3501703 times)

Meta

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Re: Partnered Output Coils - Free Energy
« Reply #7530 on: December 04, 2016, 10:39:05 AM »
There are still some unknowns, there is a relationship between the Turns of the Coils that I just cant put my finger on.

Anywhere from about 5:1 to 1:3 seems to be an open door but this is not always the case. I don't know why.

Chris Sykes

_____________________________________________

Notice 5 and 3.

3, 5, 7, 9, 11, 13 are all odd number: 3rds, 5ths, 7ths etc., of an enharmonic octave, used by John Worrell Keely and others.


Meta

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Re: Partnered Output Coils - Free Energy
« Reply #7531 on: December 04, 2016, 11:03:59 AM »

EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7532 on: December 04, 2016, 08:52:06 PM »
There are still some unknowns, there is a relationship between the Turns of the Coils that I just cant put my finger on.

Anywhere from about 5:1 to 1:3 seems to be an open door but this is not always the case. I don't know why.

Chris Sykes

_____________________________________________

Notice 5 and 3.

3, 5, 7, 9, 11, 13 are all odd number: 3rds, 5ths, 7ths etc., of an enharmonic octave, used by John Worrell Keely and others.



Hi Meta - Yes, that's a good point. I was thinking the 1/4 Wave Length as Don Smith pointed out, but I cant be sure on this either. Interestingly, Floyd Sweet also talks about the same thing:

Quote


Resonance frequencies may be maintained quite constant at high power levels so long as the load remains constant. We are all familiar with AM and FM propagation, where in the case as AM, the voltage amplitude varies, and with FM, the frequency is modulated.

However, the output power sees a constant load impedance, that of the matched antenna system. If this changes, the input to the antenna is mismatched, and standing waves are generated resulting in a loss of power. The frequency is a forced response and remains constant. Power is lost and efficiency becomes less and less, depending on the degree of mismatch.




   Chris Sykes
       hyiq.org


E_man

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Re: Partnered Output Coils - Free Energy
« Reply #7533 on: December 04, 2016, 09:55:01 PM »
To Chris (and may be to others)
Thanks to YOU, I make my own research. My big problem is, that loss of ferrite material I am using is too big. It is more then 30% of energy in 1/2 period(of resonant circuit) without load.
I believe to lower this loss under 10%, it could be possible self sustain.
At once thanks for Your effort to keep us In (forgive my "english").
E_man

EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7534 on: December 04, 2016, 10:38:07 PM »
To Chris (and may be to others)
Thanks to YOU, I make my own research. My big problem is, that loss of ferrite material I am using is too big. It is more then 30% of energy in 1/2 period(of resonant circuit) without load.
I believe to lower this loss under 10%, it could be possible self sustain.
At once thanks for Your effort to keep us In (forgive my "english").
E_man



Hi E_Man - Your English is very good, perfectly understandable.

You're quite right, the more "Losses" a System has, the more Energy needs to be made up. So a reasonable efficiency is needed. The Average Transformer is about 80% give or take some. I like to think that's a pretty good baseline to start.

I agree 100% - Everyone needs to make their own way with their own Research! In my path of Research I found it very beneficial to learn key concepts from those before me, the Greats, Floyd Sweet, Lester Hendershot, Don Smith and so many more. I have seen it before so many times, many make fantastic experiments, but really do not grasp the simple concepts of How Energy is Pumped in the first place which only leaves sheer luck for the end result.

If there is direction, then this narrows the "Result by Chance" and a more accurate, better experimental direction can be taken.

I used to think to myself: Many have done it, with only "Resonance" in Coils and Capacitors. E.G: Lester Hendershot. - Now I know the basic concepts to allow that to happen. So do you all.

   Chris Sykes
       hyiq.org

EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7535 on: December 06, 2016, 06:50:01 AM »



I am really surprised that no one has posted any replications at all of the MrPreva Circuit that John.K1 posted!

I have pointed out so many times that there is a massive amount to learn from those experiments! Then when you think you're finished, there is more to Learn! and More! My experiments that I posted some pages back only scratch the surface!


   Chris Sykes
       hyiq.org



E_man

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Re: Partnered Output Coils - Free Energy
« Reply #7536 on: December 06, 2016, 08:09:01 PM »
Do not be surprised. For instance I am just so busy (from private reasons), and conviced of my good (right) way, that frankly have not time to divide my effort to another searching. Be sure, not forget it!

EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7537 on: December 10, 2016, 05:10:09 AM »



@E_man - Thanks!


@All - I would like to share some more work from another successful experiment: Partnered coils - proof of overunity - by Marc Belanger from Advanced Electronics - About 1 Year old now!

Marc has done a fantastic job of showing and sharing his work! Thanks Marc and well done!


   Chris Sykes
       hyiq.org


EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7538 on: December 16, 2016, 12:40:07 AM »



Two Coils: "13 year old Invents Free Energy Device for 14 bucks!"


This kid obviously pays attention!


   Chris Sykes
       hyiq.org



EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7539 on: December 16, 2016, 12:46:10 AM »



Floyd Sweet wrote a letter, in it he describes a common Transformer Equation:


   Chris Sykes
       hyiq.org
« Last Edit: December 16, 2016, 09:10:18 AM by EMJunkie »

EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7540 on: December 16, 2016, 09:21:06 PM »


Walt Rosenthal shared a similar diagram:

   Chris Sykes
       hyiq.org

EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7541 on: December 16, 2016, 09:29:17 PM »







The Arrow (Vector) is the direction of the Thumb when the Fingers are curled in the direction of the Current (The Right Hand Grip Rule), in their own Vector Space.

Each Coil is a Singular, individual Coil in its own Vector Space, each having its own Magnetic Field (The Arrow, or Vector)

Quote

Consider for a moment the construction of the triode which includes the bifilar coils located within the fields of the two conditioned magnets.

When the current in one half of the conductors in the coils (i.e., one of the bifilar elements in each coil) of the device is moving up, both the current and the magnetic field follow the right-hand rule.

The resultant motional E-field would be vertical to both and inwardly directed.

At the same time the current in the other half of the conductors in the coils is moving down and both the current and magnetic field follow the right-hand rule.

The resulting motional E-field is again vertical to both and inwardly directed.

Thus, the resultant field intensity is double the intensity attributable to either one of the set of coil conductors taken singularly.



Which can be seen Mathematically as:


   I = + da+/dt + da-/dt


Quote


Current is deemed as a quantity or number of charged particles moving from P1 to P2 in time t, or as the charge transferred in one second by a current of one ampere. The coulomb is the charge on 6.24 x 1018 electrons. Electric fields are due to the presence of charges. Magnetic field effects are due to the motion of charges. Current is the net rate of flow of positive charges. This is a scalar quantity.


In the specific case of positive charges moving to the right and negative charges to the left, the effect of both actions is positive charge moving to the right. Current to the right is: I = + da+/dt + da-/dt. Negative electrons flowing to the left contribute to the current flowing to the right.



Which is Why Floyd Sweet did not agree with Millikan's Oil Drop Experiment:

Quote

Note: This writer does not agree in respect to method regarding Millikan’s oil drop experiment determining charge of a single electron. A flaw in the derivation will affect a change in the concept.

...

The underlying principal (forget Millikan’s experiment) has been derived in that magnetic effects vary on the square of the current. As the load on the machine increases, the volt-ampere product increases. The rate of flow of charges increases.



Which we have already seen how this is accomplished. Current gains are possible, in orders of Magnitude greater than is input. This is SO IMPORTANT and so simple!

Voltage is Potential and is very easily Stepped up at no Cost.


   Chris Sykes
       hyiq.org


EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7542 on: December 19, 2016, 12:24:10 AM »



What is a Wire, an Insulated, piece of Electrical Wire?

Comprises of two basic components:

An Insulator
   An Electrical Barrier, an attempt to stop the Conduction of Electricity, with a break down rating.

A Conductor
   A Metallic, Conductive, element of the Wire, where an Open Path for the Movement of Charged Particles can be Invoked. Where a Magnetic moment occurs, a Magnetic Field can exist, or bee seen as the Source of the Magnetic Field, also being susceptible to External Magnetic Fields (sometimes referred to as a Parasitic Inductance).


But, if one wanted to build an Electromagnetic "Generator", using the principles of Faradays Law of Induction, then all one would need to do, is, swipe a Permanent Magnet at 90 degrees to the above Wire, and a Voltage Potential (EMF) would be Induced!

This, apparently from nowhere!

The Source, Charged Particles, the Atomic Structure, the Metallic Structure of the Conducting Element! - (Electrons/Ions) - Charge Separation! The fundamental basis for this lays in the Lorentz Force:

   Chris Sykes
       hyiq.org


Dog-One

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Re: Partnered Output Coils - Free Energy
« Reply #7543 on: December 19, 2016, 12:35:32 AM »
Chris, can I ask you something?   I'm hoping this isn't a redundant question--I haven't been keeping up on everything.

The bucking coil or partnered output coils...

Have you tried any intensives tests with these coils slightly asymmetric?

I have reason to believe if these coils are nearly perfectly identical, it may actually reduce the intended effect.
The reason I say this is outlined in a post I made here:
http://overunity.com/12736/kapanadze-cousin-dally-free-energy/msg497316/#msg497316

Curiouser and curiouser...

EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7544 on: December 19, 2016, 01:22:52 AM »
Chris, can I ask you something?   I'm hoping this isn't a redundant question--I haven't been keeping up on everything.

The bucking coil or partnered output coils...

Have you tried any intensives tests with these coils slightly asymmetric?

I have reason to believe if these coils are nearly perfectly identical, it may actually reduce the intended effect.
The reason I say this is outlined in a post I made here:
http://overunity.com/12736/kapanadze-cousin-dally-free-energy/msg497316/#msg497316

Curiouser and curiouser...





Hi Dog-One - "can I ask you something"? - Yes of Course!

I have lost count of the experiments I have done, I try to document all I do, as its so easy to forget some of it.

I will do the best I can to answer, but, please remember, many different configurations give different results. Inductance changes with the Magnetic Field, also with Core Permeability and also other variables as you know. So to always give an accurate answer is sometimes hard. I hope all reading can see this.

let me start with your link:


Lots of good information there conico.

Here's an interesting little nugget:

Quote

Symmetrical coil is wound from the center in opposite directions an equal number of turns.
If several turns add to one half of the coil and remove a few turns on the other half, we obtain an additional magnetic field H3 created inductance - LD .

As a result: a coil with a large number of turns will act as the inductance and the coil with fewer turns to act as a capacitor. It is a well known fact (read the book). Full voltage across the coil will be less than its half.




Note: What you have found is documented in a very good PDF by other researchers: A Novel Transformer with Compensating Coil Image attached Below:


You are right! There does appear to be a "Capacity" to these Coils!


Its really important to keep in mind that I have found two Configurations that work, one better than the other, but that there may be other configurations I have not found, that work equally well or better. Both Configurations can be read about in my pdf (Guidelines to Bucking Coils - hyiq.org)

You are right, there can be a benefit, sometimes, to a difference in Turn Count. This can create a Magnetic Offset and this can help in the: "Getting it working" - But worth noting, this can also reduce the output efficiency too.

The Magnetic Field is a function of the Current through the Number of Turns, so reducing the turns is not always the best way to go. Certainly its a good place to investigate to get a device working however!

I wish I had the perfect analogy, its hard to explain so everyone can grasp.

First, Partnered Output Coils dont have to be CW/CCW, they can be CW/CW - the Only requirement is that one must have Two Separate Output Coils! This is critical and Most Important - Why?

Picture a One Ton Concrete Block, you want to move it. You have another One Ton Block and a lot of very strong Steel Cable with a big Hook. We can use the Notion of Counter Balance, to move the One Ton Concrete Block with very little force required by us using Counter Balance. See the below Image of a Crane with a Counter Balance.

So, we have our Input Magnetic Field 1/100th of a Ton, lifting our Object, One Ton (Our Secondary Magnetic Field), by using another One Ton Counter Balance, which is Our Tertiary Magnetic Field.

This is Newtons Laws of Motion: Action, Reaction and Counter-Reaction we have Counter Balanced the Magnetic Forces!


NOTE: Conventionally, Bucking Coils are known to cancel the Magnetic Fields, no output Voltage, and thus Current, can be "Generated" as a result! (Unless a very Sharp Voltage Gradient is injected into the Coil (Kapanadze) ) - Partnered Output Coils, the Magnetic Fields Oppose, but we get Voltage and Current! I have shown recently how where and why in my MrPreva experiment that John.K1 shared with us. We don't want to reduce Electromagnetic Induction Effects, we want to Increase them!!!


Floyd Sweet called this a Feed Back Loop:

Quote

The feedback loop: Previously mentioned, you will more clearly see how the loop functions at the time you see the physical construction of the stationary armature of stator assembly. The underlying principal (forget Millikan’s experiment) has been derived in that magnetic effects vary on the square of the current. As the load on the machine increases, the volt-ampere product increases. The rate of flow of charges increases. Quantum mechanics state not all electrons in copper are free to carry charges. Then it’s time to set the wheels in motion to free them from binding magnetic forces. Once this is done, conductivity will improve and resistance decrease as we are dealing only with electrons. Copper will not change to another metal as atoms which are mostly empty space would have many electrons to spare anyway.




I hope this all makes sense! I hope it answers your question?


   Chris Sykes
       hyiq.org


« Last Edit: December 19, 2016, 05:22:49 AM by EMJunkie »