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Author Topic: Partnered Output Coils - Free Energy  (Read 3501708 times)

EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6915 on: April 28, 2016, 03:35:47 AM »

I think there is one thing we can prove in all this, there is a missing component to all Science, "The Aether" or "Dark Matter" is required to fill gaps that we currently have.

Gravity and Light Interact, both travel in a medium, it appears to us as if Light sees a Resistance, thus the speed of light appears to be fixed to us.

Or could it be that the very Gravitational  Field we are bathed in, is setting the Light Speed Constant, for our Observation?

Gravity Waves, mentioned above travel in a Medium, Light travels in a Medium, this medium is clearly present, currently we call it Space, but it could be much more than that!

    Chris Sykes
        hyiq.org

tinman

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Re: Partnered Output Coils - Free Energy
« Reply #6916 on: April 28, 2016, 11:20:36 AM »
I think there is one thing we can prove in all this, there is a missing component to all Science, "The Aether" or "Dark Matter" is required to fill gaps that we currently have.

Gravity and Light Interact, both travel in a medium, it appears to us as if Light sees a Resistance, thus the speed of light appears to be fixed to us.

Or could it be that the very Gravitational  Field we are bathed in, is setting the Light Speed Constant, for our Observation?

Gravity Waves, mentioned above travel in a Medium, Light travels in a Medium, this medium is clearly present, currently we call it Space, but it could be much more than that!

    Chris Sykes
        hyiq.org

Light.gravity,and magnetic fields all act on one another.
What can we learn from this?

And what about my question 1 in my previous post?


Brad

EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6917 on: April 28, 2016, 01:01:41 PM »
Light.gravity,and magnetic fields all act on one another.
What can we learn from this?

And what about my question 1 in my previous post?


Brad


Have been pondering on that.

Only Thing I can think of is Spin Up/Spin Down.

Electron Spin - Diamagnetic vs Paramagnetic & Ferromagnetic Stuff but I am not sure this is what you were talking about?


    Chris Sykes
        hyiq.org


EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6918 on: April 28, 2016, 01:52:14 PM »



Erfinder, hahahahaha Clearly youre as Dumb as a Bag of Hammers!!!

You clearly do not understand what youve posted - Hahahaha - Dumb as a Bag of Hammers!!!

Now, whats B Induced?

Whats B?

What is it called when B is Moving in the Proximity to a Conductor?

Yes, E.M.F   -   What a Dummy!!!

Well, it looks like MileHigh's Boss has promoted Marry Poppins, here, to second in charge!!! To bad youre as Dumb as a Bag of Hammers Erfinder!!!

I think everyone should take note of Erfinders brilliant observation and his post on this observation, this is how one makes a total FOOL of himself infront of the entire world!!!

    Chris Sykes
        hyiq.org

tinman

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Re: Partnered Output Coils - Free Energy
« Reply #6919 on: April 28, 2016, 01:55:51 PM »

Have been pondering on that.

Only Thing I can think of is Spin Up/Spin Down.

Electron Spin - Diamagnetic vs Paramagnetic & Ferromagnetic Stuff but I am not sure this is what you were talking about?


    Chris Sykes
        hyiq.org

No
Forget all that bullshit--pointing arrows,and flow spin direction crap around PMs-they guy has no idea what he is talking about--or anyone else that thinks that crap is right.

Lets try paramagnetic electrons,and diamagnetic electrons.
What is the difference between the two?.

What could attract one,but repel the other?--and dont say magnetic field lol.
Why dose a magnetic field exert a force on light?--is that force a repelling force,or an attracting force?-->will light be pushed away from- or draw to a magnetic field ?.
What is all this adding up to?


Brad

EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6920 on: April 28, 2016, 02:10:25 PM »


Hey Brad,

Well we have Spin Up +1/2 and Spin Down -1/2.

Like Lenz's Law, we see the Spin in the direction of the Sign.

So Diamegnetic Objects have spin in the other direction, Spin Down, this is the High Energy State.

But, again, this is not what youre looking for, I see youre looking for something else...

    Chris Sykes
        hyiq.org

 

EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6921 on: April 28, 2016, 02:24:28 PM »


Hahahahaha - Erfinder, your games are just so funny, they always back fire on you, and you always come out brusied from the little battles you start.

Unfortunately, youre in with no chance, ever!!!

    Chris Sykes
        hyiq.org


tinman

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Re: Partnered Output Coils - Free Energy
« Reply #6922 on: April 28, 2016, 02:37:38 PM »

Hey Brad,

Well we have Spin Up +1/2 and Spin Down -1/2.

Like Lenz's Law, we see the Spin in the direction of the Sign.

So Diamegnetic Objects have spin in the other direction, Spin Down, this is the High Energy State.

But, again, this is not what youre looking for, I see youre looking for something else...

    Chris Sykes
        hyiq.org

Yes Chris
Looking for something else.
But not to worry,some one will pay attention sooner or later.


Brad

EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6923 on: April 28, 2016, 02:48:13 PM »
Yes Chris
Looking for something else.
But not to worry,some one will pay attention sooner or later.


Brad


At what level Brad?

Field, Quantum, Hard to read your mind! Trying but not getting anthing right now. Hahaha just kidding.

Well, at a field level, in Diamagnetic Materials, the Fields Oppose. Ferromagnetic they Attract.

Electrons have different Energy States, as in last post. The Fields are back the other way around.

Still not sure what you are looking for?

    Chris Sykes
        hyiq.org

EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6924 on: April 28, 2016, 03:03:29 PM »



Paired vs Un-Paired Electrons?

    Chris Sykes
        hyiq.org

tinman

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Re: Partnered Output Coils - Free Energy
« Reply #6925 on: April 28, 2016, 04:11:45 PM »


Paired vs Un-Paired Electrons?

    Chris Sykes
        hyiq.org

Ah ha  ;)
Paired and unpaired electrons in Atoms.
Diamagnetic atoms repel magnetic fields.
Paramagnetic Atoms are attracted to magnetic fields.

Now we are getting some where.
What(and i do not mean the generic term- magnetic field)will push against(repel) a diamagnetic Atom?
And what (and i do not mean the generic term- magnetic field) will attract a Paramagnetic Atom?

This is where we dismiss that rubbish shown in the video you posted a couple of post back,as !both! end's of the magnet act upon the diamagnetic and paramagnetic Atom in the same way.
If this spin theory was correct,then each end of the magnet would have the opposite effect against that Atom. Here lies the problem--we(well most) believe in only two charge states-->negative charge,and positive charge,and where a neutral charge is an even amount of both charge states.

So now a bit of research for you.
Find out what charge state the paramagnetic Atom is,and what charge state the diamagnetic Atom is.


If you are happy to discuss/discover this here on your thread,we will continue. If not,we can open a new thread on the magnetic charge--i mean field/force.  :D


Brad

picowatt

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Re: Partnered Output Coils - Free Energy
« Reply #6926 on: April 28, 2016, 04:59:45 PM »

This is where we dismiss that rubbish shown in the video you posted a couple of post back,as !both! end's of the magnet act upon the diamagnetic and paramagnetic Atom in the same way.
If this spin theory was correct,then each end of the magnet would have the opposite effect against that Atom.

Tinman,

Would you please expand on what you mean to say above?

With either polarity of applied field:

paramagnetic materials align opposite to the applied field and are therefore attracted to the applied field

diamagnetic materials align with the applied field and are therefore repelled from the applied field

In both types of materials, the alignment typically returns to a random state (due to thermal motion) when
the applied field is removed (the "para" or "dia" magnetism is not retained). 

Since either material assumes an alignment which is determined by the polarity of the applied field, I fail to
see how this disproves electron spin.

Do you believe that "spin" (or several spins) cannot be flipped (or otherwise manipulated)? 

PW

picowatt

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Bob Smith

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Re: Partnered Output Coils - Free Energy
« Reply #6928 on: April 28, 2016, 07:14:15 PM »
Chris
Maybe someone's already mentioned this but fwiw...
Considering Spin Theory, if we get 2 spin waves travelling toward each other along oppositely wound coils on a shared same core, are we not going to get a standing wave where they meet?

It would seem to me that if we put a pickup coil at this particular point where the standing wave manifests, we can draw excess energy from the standing wave without taking anything away from what's being produced in the individual sets of windings. In this sense, we would effectively have a cop>1, would we not?
Bob

Edit: Just noticed a little bit of Spin Theory chat above - no time to read, back to work. Hope I didn't duplicate what's already been said.

EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6929 on: April 28, 2016, 10:38:47 PM »
Ah ha  ;)
Paired and unpaired electrons in Atoms.
Diamagnetic atoms repel magnetic fields.
Paramagnetic Atoms are attracted to magnetic fields.

Now we are getting some where.
What(and i do not mean the generic term- magnetic field)will push against(repel) a diamagnetic Atom?
And what (and i do not mean the generic term- magnetic field) will attract a Paramagnetic Atom?

This is where we dismiss that rubbish shown in the video you posted a couple of post back,as !both! end's of the magnet act upon the diamagnetic and paramagnetic Atom in the same way.
If this spin theory was correct,then each end of the magnet would have the opposite effect against that Atom. Here lies the problem--we(well most) believe in only two charge states-->negative charge,and positive charge,and where a neutral charge is an even amount of both charge states.

So now a bit of research for you.
Find out what charge state the paramagnetic Atom is,and what charge state the diamagnetic Atom is.


If you are happy to discuss/discover this here on your thread,we will continue. If not,we can open a new thread on the magnetic charge--i mean field/force.  :D


Brad



Hey Brad - Yes happy to discuss, its a valid and sensible topic.

When you say:


So now a bit of research for you.
Find out what charge state the paramagnetic Atom is,and what charge state the diamagnetic Atom is.


If you are happy to discuss/discover this here on your thread,we will continue. If not,we can open a new thread on the magnetic charge--i mean field/force.  :D



Havent I already done this?

Paramagnetic:
   Possessing Un-Paired Electrons (E-) - In attraction to an external Magnetic Field - Spin +1/2 (Low Energy State)

Diamagnetic:
   Lacking Un-Paired Electrons (E-) - In repulsion to an external Magnetic Field - Spin -1/2 (High Energy State)

The actual Charge Value of the Electrons depend on:
   1: The Element in the Periodic Table
   2: The Orbital of that Electron
   3: The state of the Electron

E.G:

Tungsten (Paramagnetic), 74 Electrons, 6 different States.

Bismuth (Diamagnetic), 83 Electrons, 6 different States.

However, the Formal Charge:

Quote from: https://en.wikipedia.org/wiki/Formal_charge

In chemistry, a formal charge (FC) is the charge assigned to an atom in a molecule, assuming that electrons in all chemical bonds are shared equally between atoms, regardless of relative electronegativity.[1] When determining the best Lewis structure (or predominant resonance structure) for a molecule, the structure is chosen such that the formal charge on each of the atoms is as close to zero as possible.

The formal charge of any atom in a molecule can be calculated by the following equation:

FC = V - N - B/2

where V is the number of valence electrons of the neutral atom in isolation (in its ground state); N is the number of non-bonding valence electrons on this atom in the molecule; and B is the total number of electrons shared in bonds with other atoms in the molecule.


Quote from: https://en.wikipedia.org/wiki/Elementary_charge

This charge has a measured value of approximately 1.6021766208(98)×10−19 coulombs.



    Chris Sykes
        hyiq.org
« Last Edit: April 29, 2016, 01:26:41 AM by EMJunkie »