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### Author Topic: Partnered Output Coils - Free Energy  (Read 3374931 times)

#### MileHigh

• Hero Member
• Posts: 7600
##### Re: Partnered Output Coils - Free Energy
« Reply #3960 on: June 27, 2015, 04:17:14 AM »
Quote
Let me ask you, If we could take all the Energy out of a Magnetic Field instantly, what would happen?

Across two terminals, you get an energy pulse of infinite voltage, zero duration, finite current, and finite energy.

Quote
Mind blowing isn't it!!!

Not if you have been taking Spice and have blue eyes.

#### EMJunkie

• Hero Member
• Posts: 3322
##### Re: Partnered Output Coils - Free Energy
« Reply #3961 on: June 27, 2015, 04:22:34 AM »
If you take all the energy out of a magnetic field in one instant,then you would have less energy than what it took to create that field. you would also have a piece of material that in now as good as a bolt sitting in your parts tray.

Why would you want to remove that field?,why not let the field serve it's purpose within the device.
If we were to use say a PM,then would it not be better to neutralize that PM's field until such time as it is needed to provide a force?--both mechanical !and! electrically.

@Tinman - An extremely interesting answer!!!

I suggest you take some more time to think about the Magnetic Field. Break the Field down to the absolute Base Levels.

What is Entropy? System Equilibrium?

How is it that Earth's Magnetic Field has remained, through out its Cycles, for so long?

Chris Sykes
hyiq.org

#### tinman

• Hero Member
• Posts: 5365
##### Re: Partnered Output Coils - Free Energy
« Reply #3962 on: June 27, 2015, 04:23:55 AM »
The arrow in the symbol of the diode points to the direction of the conventional current (flow of + charge).

That is correct,and thus current cannot flow in the direction of the yellow arrow's(through coil A),but only in the direction of the red arrows(to the cap).

#### MarkE

• Hero Member
• Posts: 6830
##### Re: Partnered Output Coils - Free Energy
« Reply #3963 on: June 27, 2015, 04:38:11 AM »
That is correct,and thus current cannot flow in the direction of the yellow arrow's(through coil A),but only in the direction of the red arrows(to the cap).
Do you want to let on what that does to EMJ's most recent representation of what's in your shorting circuit box, or do you want to just let him continue to flounder?

#### MileHigh

• Hero Member
• Posts: 7600
##### Re: Partnered Output Coils - Free Energy
« Reply #3964 on: June 27, 2015, 04:39:24 AM »
I note that even with S1 open you have a conduction path between the shorting coil and the load.  It's just an observation and I am not getting involved in the analysis.

#### tinman

• Hero Member
• Posts: 5365
##### Re: Partnered Output Coils - Free Energy
« Reply #3965 on: June 27, 2015, 04:43:15 AM »
@Tinman - An extremely interesting answer!!!

I suggest you take some more time to think about the Magnetic Field. Break the Field down to the absolute Base Levels.

What is Entropy?

How is it that Earth's Magnetic Field has remained, through out its Cycles, for so long?

Chris Sykes
hyiq.org

What is there that could drain the energy that creates the earth's magnetic field's?

Why is it that the gravitational field travels faster than the speed of light?<-- you wont learn that in school.

As smart as we think we are,we still know so little<--or should i say,we are only allowed to know so little.

#### picowatt

• Hero Member
• Posts: 2039
##### Re: Partnered Output Coils - Free Energy
« Reply #3966 on: June 27, 2015, 04:43:36 AM »
That is correct,and thus current cannot flow in the direction of the yellow arrow's(through coil A),but only in the direction of the red arrows(to the cap).

Tinman,

From your previous explanations, I understood the only effective current flow between coil B and the output side of the circuit to be that caused by inductive coupling thru the rotor and stator when coil B is shorted.

Given no other non-disclosed connections between coil B and the output side of the circuit, the current flow you indicate with the red arrows must also flow thru the resistor feeding the shorting circuit.

Is the resistor connected to a high impedance node in the shorting circuit?

Please elaborate if you can...

PW

#### EMJunkie

• Hero Member
• Posts: 3322
##### Re: Partnered Output Coils - Free Energy
« Reply #3967 on: June 27, 2015, 04:46:02 AM »
Do you want to let on what that does to EMJ's most recent representation of what's in your shorting circuit box, or do you want to just let him continue to flounder?

@MarkE - This Thread must be one of your Favourites?

I need not implement any Guessing! I only question some explanations.

There in this above line contains more information than one may understand! But understand this and the rest is easy!

Chris Sykes
hyiq.org

#### EMJunkie

• Hero Member
• Posts: 3322
##### Re: Partnered Output Coils - Free Energy
« Reply #3968 on: June 27, 2015, 04:48:00 AM »
Tinman,

From your previous explanations, I understood the only effective current flow between coil B and the output side of the circuit to be that caused by inductive coupling thru the rotor and stator when coil B is shorted.

Given no other non-disclosed connections between coil B and the output side of the circuit, the current flow you indicate with the red arrows must also flow thru the resistor feeding the shorting circuit.

Is the resistor connected to a high impedance node in the shorting circuit?

Please elaborate if you can...

PW

Here in lies PW's admission of incorrect understanding what was thus so firmly held on to!

Thank You PW!!!

#### tinman

• Hero Member
• Posts: 5365
##### Re: Partnered Output Coils - Free Energy
« Reply #3969 on: June 27, 2015, 04:52:18 AM »
I note that even with S1 open you have a conduction path between the shorting coil and the load.  It's just an observation and I am not getting involved in the analysis.
Yes,there is a conduction path from coil B to the load,but no path from the load to coil B.
Coil B dose nothing until Coil A is producing a current flow,and thus S1 must be closed in order for coil B to provide current to follow that conduction path.

#### picowatt

• Hero Member
• Posts: 2039
##### Re: Partnered Output Coils - Free Energy
« Reply #3970 on: June 27, 2015, 05:03:36 AM »
Yes,there is a conduction path from coil B to the load,but no path from the load to coil B.
Coil B dose nothing until Coil A is producing a current flow,and thus S1 must be closed in order for coil B to provide current to follow that conduction path.

Tinman,

So now I am confused.  First of all, "Coil B" is the coil you short, correct?

Second, are you saying current flows from Coil B "electrically" to the output?  If so, is this current flow occurring when Coil B is not being shorted?

Again, from your video explanation I understood the only effective current flow between Coil B and the rest of the circuit to be inductive when Coil B is shorted.  You seemed to indicate that Coil B was not a "generator" coil per se' but rather was only used to provide an inductive kick at the proper time.

And again, if you can, is the resistor connected to a high impedance node?

PW

#### tinman

• Hero Member
• Posts: 5365
##### Re: Partnered Output Coils - Free Energy
« Reply #3971 on: June 27, 2015, 05:04:28 AM »
Tinman,

From your previous explanations, I understood the only effective current flow between coil B and the output side of the circuit to be that caused by inductive coupling thru the rotor and stator when coil B is shorted.

Given no other non-disclosed connections between coil B and the output side of the circuit, the current flow you indicate with the red arrows must also flow thru the resistor feeding the shorting circuit.

Is the resistor connected to a high impedance node in the shorting circuit?

Please elaborate if you can...

PW

First-i agree that the PM messaging here is crap. When i search sent items,it says 0 items,and yet i have sent many PM's.
I am sure i explained this to you in a PM PW,or it may have been here on the thread some where.
I stated that current dose flow through the resister,but is limited because of the resistor.

Hard to explain without giving too much away.

Anyway,it has warmed up a bit here,so im off to the workshop.

#### picowatt

• Hero Member
• Posts: 2039
##### Re: Partnered Output Coils - Free Energy
« Reply #3972 on: June 27, 2015, 05:13:33 AM »
First-i agree that the PM messaging here is crap. When i search sent items,it says 0 items,and yet i have sent many PM's.
I am sure i explained this to you in a PM PW,or it may have been here on the thread some where.
I stated that current dose flow through the resister,but is limited because of the resistor.

Hard to explain without giving too much away.

Anyway,it has warmed up a bit here,so im off to the workshop.

Tinman,

Are you saying that Coil B is used as both a generator coil AND as a shorting coil during different portions of the cycle?

PW

PS  No new PM's for some time.

#### tinman

• Hero Member
• Posts: 5365
##### Re: Partnered Output Coils - Free Energy
« Reply #3973 on: June 27, 2015, 05:14:43 AM »
Tinman,

So now I am confused.  First of all, "Coil B" is the coil you short, correct?

Second, are you saying current flows from Coil B "electrically" to the output?  If so, is this current flow occurring when Coil B is not being shorted?

And again, if you can, is the resistor connected to a high impedance node?

PW

Yes-coil B is the one that is shorted.
When coil B become's open,then a small amount of current can flow back to the cap via the resistor-->this current is negligible,but every bit help's. I shouldnt even call it a current flow,but that is the result when you need to pull down the Fet

Quote
Again, from your video explanation I understood the only effective current flow between Coil B and the rest of the circuit to be inductive when Coil B is shorted.  You seemed to indicate that Coil B was not a "generator" coil per se' but rather was only used to provide an inductive kick at the proper time.

That is correct. Coil B's main job is to provide torque and to buck the rotors field at the right time. As i also explained in the video,this bucking effects coil A through the inductive path of the stator core,and thus the two coils are inductively coupled to each other as well as to the rotor.

PW-You need to add in the bit's that i spoke to you about via PM-the bits of the device i had concerns with.

#### EMJunkie

• Hero Member
• Posts: 3322
##### Re: Partnered Output Coils - Free Energy
« Reply #3974 on: June 27, 2015, 05:18:25 AM »

What is there that could drain the energy that creates the earth's magnetic field's?

How much Energy in the Average Lightning Strike? What is the strength of the Earths Magnetic Field on average?

Why is it that the gravitational field travels faster than the speed of light?<-- you wont learn that in school.

Absolutely, Gravity Bends light! But what is Light? Do we really know what Light is, or Gravity for that matter? We might think we do...

As smart as we think we are,we still know so little<--or should i say,we are only allowed to know so little.

For everything we think we know, there is an infinite amount that we still have to learn!

For every Action, there is an equal and Opposite Reaction! Lenz's Law is one example!!! This is the most simple area to see this occur. At its absolute Base Level Magnetic Fields are Subatomic!

Chris Sykes
hyiq.org