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Author Topic: Partnered Output Coils - Free Energy  (Read 2052052 times)

Offline Magluvin

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Re: Partnered Output Coils - Free Energy
« Reply #7080 on: July 23, 2016, 04:54:18 AM »


What does a Moving Magnetic Field Create?


   Chris Sykes
       hyiq.org


Listen Very Carefully:

Hey Chris

Listened to the mp3.    Had discussed this with Poynt a while back.

Are there demonstrations that show the E field of a moving magnet that prove this vs field cutting the conductors to produce currents?

Its all easy to say and hear. But how can we visually show it in a sense that we can say, ok, I get it?

Mags

Free Energy | searching for free energy and discussing free energy

Re: Partnered Output Coils - Free Energy
« Reply #7080 on: July 23, 2016, 04:54:18 AM »

Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7081 on: July 23, 2016, 05:03:26 AM »

I have said it, I told you so, this would not last forever...

You, the people of the world are now about to be bound by Patent protection, for a Technology that does not belong to.




I have been comtemplating the release of this for some time now.

Its not fair to limit the importance of this to a select few.

I show the real importance of Coil Polarity on a single Core: What does a Coil really do on the core? - hyiq.org

Study this closely, there is MUCH more going on here than you might imagine. [Protational Field, Mass Current, Lense-Thirring Effect, Spin Wave, Atomic Polarisation]


   Chris Sykes
       hyiq.org


P.S: the door will not stay open for ever, YOU NEED to take advantage of this before its too late!!!


Isnt it ironic, that the threat YOU face(Patent protection), stems directly from the very People that Funded Floyd Sparky Sweet from day one!!! Seems a Link is obvious to those that do their homework!!!


At the same time, Grahams work showing this, Partnered Output Coils as I have shown them, really has proven to many that what I have been saying here for the last few years is true and correct.






Well, there you have it, the Murakmi Army and the Patenting of all the Free Energy Devices of the People: Your Dollars for DVD's Books and all the Marketing BS has paid for your Intellectual Imprisonment!!! You have locked yourselves out...

You, the people are no longer Free!!!


   Chris Sykes
       hyiq.org


Offline Magluvin

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Re: Partnered Output Coils - Free Energy
« Reply #7082 on: July 23, 2016, 06:16:15 AM »


What does a Moving Magnetic Field Create?


   Chris Sykes
       hyiq.org


Listen Very Carefully:



Hey Chris

Listened to the mp3.    Had discussed this with Poynt a while back.

Are there demonstrations that show the E field of a moving magnet that prove this vs field cutting the conductors to produce currents?

Its all easy to say and hear. But how can we visually show it in a sense that we can say, ok, I get it?

Mags

Free Energy | searching for free energy and discussing free energy

Re: Partnered Output Coils - Free Energy
« Reply #7082 on: July 23, 2016, 06:16:15 AM »
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Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7083 on: July 23, 2016, 12:08:17 PM »


Hey Chris

Listened to the mp3.    Had discussed this with Poynt a while back.

Are there demonstrations that show the E field of a moving magnet that prove this vs field cutting the conductors to produce currents?

Its all easy to say and hear. But how can we visually show it in a sense that we can say, ok, I get it?

Mags



Really good question Mags!!!

Try the below picture, I have used this before for different task and it works fine.

Detecting Electric Fields is normally the task of an Electrometer, or an Electrostatic Field Detector, but many are probe dependant and measure Terminal Potential Difference Voltages.

Below is an example of an Electrostatic Field Detector, Handheld that does not require Probes.

Hope this Helps Mags.

   Chris Sykes
       hyiq.org


P.S: I dont know of a way to detect Electric Fields without using some kind of Conductors. I have heard of Chemical methods, where a reaction is exhibited in the presence of Electric Fields, but never seen or been able to find relivant data on it.
 
« Last Edit: July 23, 2016, 11:47:55 PM by EMJunkie »

Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7084 on: July 24, 2016, 04:40:55 AM »



In a Resonant System, LC, LRC Tank Circuit, we will see a Phase Angle between Voltage (V) and Current (I), this we have been through many times before.

The Active Power in the System is Calculated by the following forumla:

   Power (P) = Volts (V) * Amps (A) * Cos(Φ)

Where Phi (Φ) is the Phase Angle between Voltage (V), normally Leading, and Current (I), normally Lagging, in a LC Resonant Circuit.

But what happens if the Input you are measuring appears to be returning more Energy back to the Source than is Supplied? We have been through this with MarkE (In Respect of him), a long way back.

When a Magnetic Field, external to a System, but applied to the System, moves in the System, there is normally a sudden shift, over Time (t). The Density of the Magnetic Field can be calculated with the following equation:

   Flux (B) = Permeability (μ) * Turns (N) * Current (I)

The Energy (E) Stored in the Magnetic Field (B) can be calculated as follows:

    Energy (E) = ( 1/2 * ( Inductance (L) * Current (I) ) )2

Lets say, a Device Under Test (DUT) has the following Parameters:

   Turns: 2x 300 Turns 0.45mm
   Connected: Series
   Inductance: 2.40 Henrys
   Capacitance: 15uF
   DC Resistance: 11.2 Ohms

The following Wave form is achieved:

   Chris Sykes
       hyiq.org
« Last Edit: July 24, 2016, 10:32:45 AM by EMJunkie »

Free Energy | searching for free energy and discussing free energy

Re: Partnered Output Coils - Free Energy
« Reply #7084 on: July 24, 2016, 04:40:55 AM »
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Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7085 on: July 24, 2016, 05:41:18 AM »


Please correct me if I am wrong!!!

In the below Analysis you can see there is two parts to the Input Cycle. Two Portions of Active, real Power, marked in Blue. Also two Portion's of Reactive, or Negative Power, thats Power returning back to the Source. Marked in Orange.

The Yellow Lines are marked as Peak Power for each Part of the Power Cycle, for one Cycle. The following, is based on AC Sine Waves, that are not distorted, because of some degree of distortion, there will be some degree of Inaccuracy in some of these figures.

   Peak Power (Real) :
       DC: V * I = 2.37 * 0.0225 = 0.053325
       Phase Angle: 90
       Active Watts: 0
       Apparent Power:  0.053325
       Reactive Power: 0.053325
       Power Factor: 0

   Peak Power (Negative) :
       DC: V * I = 11.75 * 0.075 = 0.88125
       Phase Angle: 261.8
       Active Watts: -0.125691718125
       Apparent Power:  0.88125
       Reactive Power: -0.87224027625
       Power Factor: -0.1426289


Realising, this is not best practice, measuring and calculating Power at peak Values and also from Wave Forms that are not symetrical. Full Wave Integration needs to be applied to this to get an accurate idea. However, it is fairly easy to see, the Total Area, Positive Active Power (Marked in Blue), is far less that the Total Area of the Negative Power (Marked in Orange).


So, whats the Energy here? Lets look:

   EnergyPositive (E) = ( 1/2  * ( Inductance (L) * Current (I) ) )2 = 1/2 * 2.40 * 0.0225 2 = 2.125764E-06 Joules.

   EnergyNegative (E) = ( 1/2 * ( Inductance (L) * Current (I) ) )2 = 1/2 * 2.40 * -0.075 2 = 0.00026244 Joules.

Please check my Math. You can see this is a massive difference!!! From: 0.000002125764 Supplied, Positive Joules, to 0.00026244 Returned, Negative Joules. Thats more than 2 Orders of Magnitude, more Joules Returning to the Source than was supplied, at each of the Peaks in one Cycle...


Again, If I have this wrong, please correct me.

You can see, an external Magnetic Field added to a System, and Moving this Magnetic Field, in the System, can, and does, add energy to the System. Thus the "Generation" of electrical Energy.

   Chris Sykes
       hyiq.org
« Last Edit: July 24, 2016, 10:52:39 AM by EMJunkie »

Offline Magluvin

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Re: Partnered Output Coils - Free Energy
« Reply #7086 on: July 24, 2016, 06:05:14 AM »


Really good question Mags!!!

Try the below picture, I have used this before for different task and it works fine.

Detecting Electric Fields is normally the task of an Electrometer, or an Electrostatic Field Detector, but many are probe dependant and measure Terminal Potential Difference Voltages.

Below is an example of an Electrostatic Field Detector, Handheld that does not require Probes.

Hope this Helps Mags.

   Chris Sykes
       hyiq.org


P.S: I dont know of a way to detect Electric Fields without using some kind of Conductors. I have heard of Chemical methods, where a reaction is exhibited in the presence of Electric Fields, but never seen or been able to find relivant data on it.

The question was, back then, is if we have a toroid transformer, pri on left and sec on right, is there magnetic flux that crosses over the hole in the toroid in order to have that flux cut the secondary to induce the secondary, or, there is no flux that escapes the core material and the sec would only be induced by the E field around the core produced by the primary. I think you were in that thread at the time.

In this link    http://overunity.com/8597/solid-state-orbo-system/msg224747/#msg224747
shows a pic of a flux gate type setup. Notice the 4 small coils in the outer perimeter of the core with through holes in the core. In the other thread we were in we discussed trying that outer perimeter setup shown in the link and also doing the same on the inner perimeter. The funny thing is, in the link provided, the reason for putting those control coils as show is for a lenz less effect when the output coil becomes active. As in the output doesnt affect the input.

So my argument was, if we did the experiment of having a toroid core, with a primary on the left, and 1 sec on the right of the inner perimeter of the core, and another secondary on the outside perimeter, as shown in the link, would the inner perimeter sec be induced by the primary? And also test the outer sec for induction from the primary.
For me, if the inner perimeter sec is induced by the primary, but the outer sec is not, then I have to think that it is the flux crossing the hole that induces the sec and not the E field. Otherwise if it is the E field inducing the inner sec, then why would it not induce the outer sec, if this E field is circling the radius of the core?

To my original question, are we saying that if we have a wheel of magnets spinning, we can measure an E field, and only when it rotates? Or is the detector being induced by flux cutting of the device? What if one of those devices does detect the moving magnet, then we would have to test it the other way around. Put the detector on the wheel and the mag stationary. If the E field is produced only if the magnet is moving, then this second test should show no detection as compared to the first test. I couldnt live with the first test being conclusive without test 2.

Mags

Free Energy | searching for free energy and discussing free energy

Re: Partnered Output Coils - Free Energy
« Reply #7086 on: July 24, 2016, 06:05:14 AM »
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Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7087 on: July 24, 2016, 07:12:14 AM »



Hi Mags, yes I remember the topic.

The idea of a Core, is to make the Path for the Flux as easy as possible to travel. This is called Magnetic Peameability and relates to the Magnetic Reluctance, there is a good article here: Calculating the strength of a magnet

Also some good data: Magnetic Reluctance

A really good Transformer will have very little Flux Leakage, a badly designed Transformer will have more Flux Leakage.

So, I guess, this is a "Depends on Design" sort of question. Generally, the more Flux Leakage the worse the performance the Power Transformation will be.

Some Transformers have a Magnetic Shunt, there will be a jump of Flux at a certian point, where the Forward Current and Reverse Current, Lenz's Law, will oppose, and the Reluctance is not great enough to keep the Flux in the Main Core. See Below Image. This creates dual paths for the Flux.

If Magnetic Flux finds an easier path other than the Core, then it will leak out and Close Loop, from North to South pole.

Allthough this is "Best Practice" in Transformer theory, if its the case that there is more than one Source of Magnetif Flux and especially if the geometry allows for it, then this Leakage can be of benefit!!!

See: Self Assisted Oscillation or Field Effect Amplification of an Induced Rotating Magnetic Field - this particular design is not efficent, but it does show how Flux Leakage can increase by adding another Source of Magnetic Field.


   Chris Sykes
       hyiq.org

Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7088 on: July 25, 2016, 02:38:38 AM »



Power is the Product of Voltage times Current, averaged over time and this power is called the Mean, or Average Power.

How does this work, and what does area have to do with it?

To Integrate the Wave Forms means to take as many small Rectangles under each of the Wave Form's, and get the value of this very small Rectangle, it is really good to watch this video: What Is an Integral? - Thus Integrating the Wave Forms gives us a Value over time of the Power. Thats why Area of the Rectangles are important.

The Mean or Average Power over Time, which is in its own right, Watts, Energy over Time, or Joules Per-Second.

This is done for Current (I) and at the same time for Voltage (V) and each Rectangle is thus the Product, Voltage (V) * Current (I) over Time = Watts.

As an example, at the Peaks shown above, on the Yellow Lines, each Yellow Line could represent a small rectangle. This Area was calculated and the Figures for an Instantaneous value of Power:

   Peak Power (Real) :
       Instantaneous: V * I = 2.37 * 0.0225 = 0.053325

   Peak Power (Negative) :
       Instantaneous: V * I = 11.75 * 0.075 = 0.88125


So, the more area the more the Average or Mean Power will be. Either Input or Output... No one has pointed out any mistakes, and I have made some, to see if anyone was paying attention...

EG: Voltage should have been: -11.75 and not 11.75 also, the Phase angle was not 90 on the input, but in fact closer to 82 Degrees. Its not important any way as this was irrelevant.

   Peak Power (Negative) :
       Instantaneous: V * I = -11.75 * 0.075 = -0.88125

Below, the Red Boxes are Current, to be Integrated from the Zero Graticle Line to the Wave Peak, Negative or Positive, the Blue Boxes are Voltage, to be Integrated from the Zero Graticle Line to the Wave Peak, Negative or Positive - The Product, is Voltage times Current, and these Values are averaged over time.

We are going to have to be smart and cross all our t's and dot all our i's if we are going to get anywhere with this. Once a grasp is obtained, it gets so much easier.


   Chris Sykes
       hyiq.org


P.S: Just maybe, the assumed knowledge of, or lack of, the Scope, was slightly under appreciated...

P.P.S: I should be Clear, this is Input Only Analysis, on a LC Tank Circuit with Permanent Magnets added to the System, no Output has been looked at yet.

« Last Edit: July 25, 2016, 05:01:25 AM by EMJunkie »

Free Energy | searching for free energy and discussing free energy

Re: Partnered Output Coils - Free Energy
« Reply #7088 on: July 25, 2016, 02:38:38 AM »
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Offline Magluvin

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Re: Partnered Output Coils - Free Energy
« Reply #7089 on: July 25, 2016, 08:23:19 AM »


Hi Mags, yes I remember the topic.

The idea of a Core, is to make the Path for the Flux as easy as possible to travel. This is called Magnetic Peameability and relates to the Magnetic Reluctance, there is a good article here: Calculating the strength of a magnet

Also some good data: Magnetic Reluctance

A really good Transformer will have very little Flux Leakage, a badly designed Transformer will have more Flux Leakage.

So, I guess, this is a "Depends on Design" sort of question. Generally, the more Flux Leakage the worse the performance the Power Transformation will be.

Some Transformers have a Magnetic Shunt, there will be a jump of Flux at a certian point, where the Forward Current and Reverse Current, Lenz's Law, will oppose, and the Reluctance is not great enough to keep the Flux in the Main Core. See Below Image. This creates dual paths for the Flux.

If Magnetic Flux finds an easier path other than the Core, then it will leak out and Close Loop, from North to South pole.

Allthough this is "Best Practice" in Transformer theory, if its the case that there is more than one Source of Magnetif Flux and especially if the geometry allows for it, then this Leakage can be of benefit!!!

See: Self Assisted Oscillation or Field Effect Amplification of an Induced Rotating Magnetic Field - this particular design is not efficent, but it does show how Flux Leakage can increase by adding another Source of Magnetic Field.


   Chris Sykes
       hyiq.org


Hmm. I get all that.  What I want to know is if you believe in flux cutting in order to induce current in a secondary conductor, or do you believe that it is an E field that produces current in the secondary conductor.   

The pdf below explains my argument. Its not a long read.

Mags

Offline forest

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Re: Partnered Output Coils - Free Energy
« Reply #7090 on: July 25, 2016, 09:20:16 AM »
Mags


I think there is one thing to consider about your pdf. If core is ring and you put a additional path of high permeability into a center of it with a very slight air gap and you drive it with sinewave power at very low frequency then I imagine the flux lines in air are impossible to reach the opposite site of ring core.

Free Energy | searching for free energy and discussing free energy

Re: Partnered Output Coils - Free Energy
« Reply #7090 on: July 25, 2016, 09:20:16 AM »
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Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7091 on: July 25, 2016, 09:51:59 AM »

Hmm. I get all that.  What I want to know is if you believe in flux cutting in order to induce current in a secondary conductor, or do you believe that it is an E field that produces current in the secondary conductor.   

The pdf below explains my argument. Its not a long read.

Mags



Hey Mags, yes of Course, EMF = Bvl, for sure Flux Cutting would induce an EMF, but the efficency would be poor, in the particular configuration.

Yes, have seen the work of Mr Distinti B.S. E.E. - They seriously need to change the B.S. bit in Science!!!

It is easy enough to throw a few coils on a core and test, I did many years back, it was very poor efficency! Can you tell me why it would be poor efficency?


   Chris Sykes
       hyiq.org


P.S: I am coming from the Transformer Point of View. Like was shown in the pdf you posted. This is a generalisation and is how this question might be viewed as a Industry point of view, but in practice, this is not always the case, so dont let my answer change your mind, merely look at my posts as a generalisation as not all Configurations are true of the same problems. 1.6 Tesla is a common B Field Maximum in some Core Materials. Please remember, Magnetic Flux will always try to take the Shortest Path with the least Reluctance...


Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #7092 on: July 25, 2016, 10:36:27 AM »


Power is the Product of Voltage times Current, averaged over time and this power is called the Mean, or Average Power.

How does this work, and what does area have to do with it?

To Integrate the Wave Forms means to take as many small Rectangles under each of the Wave Form's, and get the value of this very small Rectangle, it is really good to watch this video: What Is an Integral? - Thus Integrating the Wave Forms gives us a Value over time of the Power. Thats why Area of the Rectangles are important.

The Mean or Average Power over Time, which is in its own right, Watts, Energy over Time, or Joules Per-Second.

This is done for Current (I) and at the same time for Voltage (V) and each Rectangle is thus the Product, Voltage (V) * Current (I) over Time = Watts.

As an example, at the Peaks shown above, on the Yellow Lines, each Yellow Line could represent a small rectangle. This Area was calculated and the Figures for an Instantaneous value of Power:

   Peak Power (Real) :
       Instantaneous: V * I = 2.37 * 0.0225 = 0.053325

   Peak Power (Negative) :
       Instantaneous: V * I = 11.75 * 0.075 = 0.88125


So, the more area the more the Average or Mean Power will be. Either Input or Output... No one has pointed out any mistakes, and I have made some, to see if anyone was paying attention...

EG: Voltage should have been: -11.75 and not 11.75 also, the Phase angle was not 90 on the input, but in fact closer to 82 Degrees. Its not important any way as this was irrelevant.

   Peak Power (Negative) :
       Instantaneous: V * I = -11.75 * 0.075 = -0.88125

Below, the Red Boxes are Current, to be Integrated from the Zero Graticle Line to the Wave Peak, Negative or Positive, the Blue Boxes are Voltage, to be Integrated from the Zero Graticle Line to the Wave Peak, Negative or Positive - The Product, is Voltage times Current, and these Values are averaged over time.

We are going to have to be smart and cross all our t's and dot all our i's if we are going to get anywhere with this. Once a grasp is obtained, it gets so much easier.


   Chris Sykes
       hyiq.org


P.S: Just maybe, the assumed knowledge of, or lack of, the Scope, was slightly under appreciated...

P.P.S: I should be Clear, this is Input Only Analysis, on a LC Tank Circuit with Permanent Magnets added to the System, no Output has been looked at yet.


It should now be obvious to all reading, that did not already know, that the Power Into/out of a Circuit can be Positive (+) or Negative (-). For example:

   Power (P) = -Voltage (V) * Current (I) = - P

or

   Power (P) = Voltage (V) * -Current (I) = - P

but, the Positive Power into a Circuit will always be Positive:

   Power (P) = Voltage (V) * Current (I) = P


I will let you think on this for a bit, as it does have consequences...

   Chris Sykes
       hyiq.org


Offline Magluvin

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Re: Partnered Output Coils - Free Energy
« Reply #7093 on: July 25, 2016, 06:32:51 PM »
Hey Chris

Do you have a link to that transformer depiction?

Mags


 

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