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Author Topic: Partnered Output Coils - Free Energy  (Read 2735459 times)

Offline Polarisz

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Re: Partnered Output Coils - Free Energy
« Reply #6765 on: April 13, 2016, 03:19:20 PM »
ALL,

I have been a member here since 2010. You will not find any posts prior to this due to seeing too many personal attacks on this site.
Chris is trying to share something with all of you, and all he asks is that you replicate his experiment to see the effect that he has been studying for 15 years.
Typically a tank circuit will have a Q and as you load that circuit the Q will diminish.  By using Chris's method of bucking/partnered/mirrored coils, when you add a load to the tank circuit it still retains a high Q with the addition of the load. Utilizing the method of bucking/partnered/mirrored coils we currently are lighting a 12V light bulb and the circuit is retaining a Q of over 20.
I would hope that you are all open minded enough to replicate Chris' work and find out for yourself.  If you learn nothing else you will at least see an unexpected unique effect.

Free Energy | searching for free energy and discussing free energy

Re: Partnered Output Coils - Free Energy
« Reply #6765 on: April 13, 2016, 03:19:20 PM »

Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6766 on: April 13, 2016, 03:39:50 PM »

PW, Ramset,


PW, I fully understood, it is you that have entirely missed the Boat. I can not help with your Comprehension Problems, I am good but not that good - Sorry old mate!

Chet - I see words but its all a fuzzy mess... Did you go to the same school PW did? Incomprehensibly unintelligible contrivance. Some things to look at might be formatting, use of the Quote Tags... Sorry the rest is up to you. I dont have all day.


PW, you would not be in this mess if you spend 1 minute to read properly.





@ALL - There is actually a Very good reason I have spent so much time covering the information I have.

Many here, very much smarter than PW and Chet, will see the relationships I have shown and detailed with great detail are actually very important.

Tinman is in descovery now and will find some amazing things if he sticks at it and looks at the relationships without jumping to conclsions. Like PW and Chet.

You can see for sure here, that the relationships are very interesting from the Flux Phi, to the other Quantitys, Current and Voltage.

Its entirely a Reactive condition, and this condition has nothing what so ever to do with Faraday's law of Electromagnetic Induction!

Known as Complex Impedance and Circuit Analysis - Which you dont need to know inside out, but only be aware of.

How does adding a Capacitor to the Circuit change things so much?

   Chris Sykes
       hyiq.org

Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6767 on: April 14, 2016, 08:01:21 AM »
ALL,

I have been a member here since 2010. You will not find any posts prior to this due to seeing too many personal attacks on this site.
Chris is trying to share something with all of you, and all he asks is that you replicate his experiment to see the effect that he has been studying for 15 years.
Typically a tank circuit will have a Q and as you load that circuit the Q will diminish.  By using Chris's method of bucking/partnered/mirrored coils, when you add a load to the tank circuit it still retains a high Q with the addition of the load. Utilizing the method of bucking/partnered/mirrored coils we currently are lighting a 12V light bulb and the circuit is retaining a Q of over 20.
I would hope that you are all open minded enough to replicate Chris' work and find out for yourself.  If you learn nothing else you will at least see an unexpected unique effect.


Hear, hear - Mr Polarisz is exactly right!!!

The demonstration I put on YouTube back in Nov 2, 2014; Solid State Generator - How to Build and tune a Solid State Electrical Generator!!! - Low Level OU, was at the time, nearly 2 years old.

If the output is maximised and there is a tuned point, which I show you how to get to it, then once there, you can work on minimising the Input.

I clearly show you, there is no Lenz's Effects when tuned!

Once this frequency is determined, then Resonate the input at this frequency, it can give you a very good gain after some fiddling.

Come on, please Inventors, Study carefully, replicate carefully. It does work!!!

Below, an image of my 2013 experiment:

   Chris Sykes
       hyiq.org

« Last Edit: April 14, 2016, 10:26:34 AM by EMJunkie »

Free Energy | searching for free energy and discussing free energy

Re: Partnered Output Coils - Free Energy
« Reply #6767 on: April 14, 2016, 08:01:21 AM »
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Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6768 on: April 14, 2016, 09:43:11 AM »


Please remember what I have said, Look for the effects first, then make improvements.

In this picture, I have three identical coils, this was the discovery of the effect. As you can see, the Partnered Output Coils were two Identical Coils, one flipped over from the other and not CW / CCW.

It is the effects that led you to OU!!!

   Chris Sykes
       hyiq.org

Offline tinman

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Re: Partnered Output Coils - Free Energy
« Reply #6769 on: April 14, 2016, 05:02:08 PM »
 author=EMJunkie link=topic=15395.msg480507#msg480507 date=1460530559]





Quote
1: Tinman has nothing to do with the debate.

Actually i do Chris,as it was me that asked the question(that was aimed toward minnie ,after his comment toward me). My answer was /is the same as TK's,and i stand by it.

Quote
TK is still wrong in his statement:

TKs given answer is correct.

Quote
PW - You are still wrong.

I doubt that very much Chris.

Quote
Faradays Law does not PREDICT an angle of 90 Degrees, nor does it PREDICT Voltage to Current Phase Angles of any kind

It dose that exactly when there is no current flowing through the secondary coil.

Quote
Faraday's Law is entirely dependant on, and would not be valid without, the relationship of Electric to Magnetic Fields. You are so wrong!!! and will not admit it!

And the inverse is true,where it predicts changing magnetic fields giving rise to an EMF across an inductor.


Brad

Free Energy | searching for free energy and discussing free energy

Re: Partnered Output Coils - Free Energy
« Reply #6769 on: April 14, 2016, 05:02:08 PM »
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Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6770 on: April 14, 2016, 10:56:06 PM »
author=EMJunkie link=topic=15395.msg480507#msg480507 date=1460530559]





Actually i do Chris,as it was me that asked the question(that was aimed toward minnie ,after his comment toward me). My answer was /is the same as TK's,and i stand by it.

TKs given answer is correct.

I doubt that very much Chris.

It dose that exactly when there is no current flowing through the secondary coil.

And the inverse is true,where it predicts changing magnetic fields giving rise to an EMF across an inductor.


Brad


Brad, youre welcome to your opinion.

It doesnt make it any more correct than PW or TK - and if you keep on track, without being steered, then you will see this soon.

The Fundamental Electromagnetic Waves, are a Requirement for Faradays Law to exist, not the other way around.

   Chris Sykes
       hyiq.org

Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6771 on: April 14, 2016, 10:59:21 PM »


I mean, as an example - Just for giggles...

Read 1 Milion Papers on the Electromagnetic Spectrum.

How many times is Faraday's Law mentioned?

Yes, thats right - None!!!

Why?

Because the Fundamental, the very most basic requirement for existance, is where the race starts. This cant be changed, not by mere mortal men!!!

   Chris Sykes
       hyiq.org

Free Energy | searching for free energy and discussing free energy

Re: Partnered Output Coils - Free Energy
« Reply #6771 on: April 14, 2016, 10:59:21 PM »
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Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6772 on: April 14, 2016, 11:26:33 PM »


Brad, you have crossed wires:



Actually i do Chris,as it was me that asked the question(that was aimed toward minnie ,after his comment toward me). My answer was /is the same as TK's,and i stand by it.



This debate on Faraday's Law, is not about your question, it never was! This assumption has come from, Readers of the Forum, not reading properly.



TKs given answer is correct.



This debate on Faraday's Law, entirely stemms from TK's Answer and nothing else! Where I have proven to anyone reading, that TK and anyone that supports his statement, is wrong.


   Chris Sykes
       hyiq.org

Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6773 on: April 14, 2016, 11:57:26 PM »


Lets look at your question though: NONE have looked at this properly!!!

   1: You measure Current on the Input Stage.
   2: You measure Voltage on the Output Stage in a "No Load" Condition.

First, there is an assumption here, made by all, that the Input Current is in Phase with the Magnetising Force (ϕ) or Flux. However, under a "No Load" condition, this is ok to assume most of the time.

Right from the start, by comparing Input Current and Output Voltage, and then bringing Faraday's Law into the equation, was incorrect in its own right : Comparing Apples and Oranges!!!

FYI: One can use Faraday's Law to Calculate the EMF, then one can use Ohms Law to Calculate Current by the equation: I = V / R : Again, Apples and Oranges!!! This does not work in this situation simply because there are two different Circuits!!!

PW mostly now, TK and Tinman, you are wong on so many levels. Very clearly, if you look at the above Phasor Diagrams I posted, you will see, what you have said is totally wrong! So many assumptions made, and not a single shread of proof to support your wild assumptions!!!

   First: Faradays Law does not PREDICT Current!!!
   Second: Faradays Law does not PREDICT Flux (ϕ)!!!
   Third: Faradays Law does not PREDICT Phase Relationships between Voltage and Current!!!

   Fact: Faradays Law does PREDICT EMF and the Sign of it, Anti-Phase, or 180 Degrees to the Source.

The Fundamental Laws of the Electromagnetic Spectrum and System Design Determines the Flux (ϕ), Ohms Law Determines Current as long as the Voltage and Resistance is in the same Circuit.

   Chris Sykes
       hyiq.org

Free Energy | searching for free energy and discussing free energy

Re: Partnered Output Coils - Free Energy
« Reply #6773 on: April 14, 2016, 11:57:26 PM »
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Offline minnie

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Re: Partnered Output Coils - Free Energy
« Reply #6774 on: April 15, 2016, 12:11:28 AM »



  It comes as quite a shock to me to find that the old Koala's wrong,
  but come to think of it he must be a tad behind the times.
          John.

Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6775 on: April 15, 2016, 01:14:17 AM »


  It comes as quite a shock to me to find that the old Koala's wrong,
  but come to think of it he must be a tad behind the times.
          John.


Thank You John, you have read and cross checked the facts obviously!

   Chris Sykes
       hyiq.org

Free Energy | searching for free energy and discussing free energy

Re: Partnered Output Coils - Free Energy
« Reply #6775 on: April 15, 2016, 01:14:17 AM »
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Offline picowatt

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Re: Partnered Output Coils - Free Energy
« Reply #6776 on: April 15, 2016, 03:10:47 AM »

Lets look at your question though: NONE have looked at this properly!!!

   1: You measure Current on the Input Stage.
   2: You measure Voltage on the Output Stage in a "No Load" Condition.

First, there is an assumption here, made by all, that the Input Current is in Phase with the Magnetising Force (ϕ) or Flux. However, under a "No Load" condition, this is ok to assume most of the time.


This is all very true.  Just as the reference you yourself provided also states (caption to Fig. 10.14) and under the test conditions Tinman provided, it is quite reasonable to assume that the magnitude of the magnetic flux is very closely represented by the primary current trace.

Therefore, as per Faraday, we would expect the secondary voltage minimum amplitude to occur when the rate of change of the magnetic flux is also at a minimum (as represented by the primary current).

You want to keep quote mining one line from TK's post and claim it is wrong in isolation (which is very bad form by the way), but in his post, TK went on to explain just how he used Faraday's Law and even provided a graphic to further depict how he used it.

i will try to explain it to you one more time:

Given Tinman's test conditions, the primary current closely represents the magnetic flux.  Using Faraday's law, it is quite reasonable to predict that the induced voltage (secondary voltage) will be at a minimum when the rate of change of the magnetic flux (primary current) is also at a minimum.  TK explained this and also graphically indicated the time alignment of those two minimums in his annotated scope capture.

As this is the only point I have been trying to make you understand, I must assume you do not even agree with the references that you yourself provided.

One of your references, the Figure 10.14 caption, clearly states, to paraphrase, that the primary current is an excellent proxy for the magnetic flux.

Another of your references, from your post 1562 in the JT 101 thread, states:
Quote
Faraday's Law of Induction: the instantaneous emf induced in a circuit is directly proportional to the time rate of change of the magnetic flux through the circuit

Those two references fully support, agree with, and provide further clarification of TK's answer.

Are you also claiming that even your own references are in error?

PW

Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6777 on: April 15, 2016, 03:50:46 AM »



PW - You are still talking Apples and Oranges!

   Flux (ϕ) is a quantity, that must be measured and known well before Faraday's Law can be used. Thus part of the Electromagnetic Spectrum and also System Design.

It is very easy to calculate this: Flux (ϕ) = BA cos(θ)

Where:
       B is the Magnetic Field in Tesla (SI Units)
       A is the total Cross Sectional Area in Meters Squared.
       θ (Theta) is the angle to the Flux (ϕ) to the Plane

This is a Magnetic Spectrum/System defined quantity which must be known well before getting to Faraday's Law, once known then Faraday's Law can then Predict the EMF, which is Anti-Phase, or 180 degrees from the Source.
 

   Chris Sykes
       hyiq.org

Offline EMJunkie

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Re: Partnered Output Coils - Free Energy
« Reply #6778 on: April 15, 2016, 03:52:13 AM »



PW - Does what you say hold in the below image and if not why?


   Chris Sykes
       hyiq.org

Offline picowatt

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Re: Partnered Output Coils - Free Energy
« Reply #6779 on: April 15, 2016, 04:07:24 AM »


PW - You are still talking Apples and Oranges!

   Flux (ϕ) is a quantity, that must be measured and known well before Faraday's Law can be used. Thus part of the Electromagnetic Spectrum and also System Design.

Are you disagreeing with the Figure 10.14 caption you posted?

Are you saying that with the secondary open circuit, the primary current as measured in by Tinman did not accurately represent the magnetic flux?

You seem to be disagreeing with even your own references.

I suspect you are just being contrary...

PW

 

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