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Author Topic: This old enemy the capillarity :)  (Read 15136 times)

Gabriele

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This old enemy the capillarity :)
« on: January 07, 2015, 11:46:11 PM »
Look on drawings to understand my question. Thanks

telecom

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Re: This old enemy the capillarity :)
« Reply #1 on: January 08, 2015, 04:46:15 AM »
I think smaller capillary should go down because it
doesn't have enough force to support the weight.

telecom

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Re: This old enemy the capillarity :)
« Reply #2 on: January 08, 2015, 04:46:38 AM »
I think smaller capillary should go down because it
doesn't have enough force to support the weight.

Gabriele

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Re: This old enemy the capillarity :)
« Reply #3 on: January 08, 2015, 06:18:50 AM »
You mean it shoulds empty?

telecom

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Re: This old enemy the capillarity :)
« Reply #4 on: January 08, 2015, 09:40:04 AM »
Yes

Gabriele

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Re: This old enemy the capillarity :)
« Reply #5 on: January 08, 2015, 06:18:19 PM »
Is there a formula to know if it is possible do so to empty a capillar?

telecom

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Re: This old enemy the capillarity :)
« Reply #6 on: January 08, 2015, 06:28:17 PM »
not 100% sure, may be as you suggested, to apply  pressure by a small piston?

Gabriele

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Re: This old enemy the capillarity :)
« Reply #7 on: January 08, 2015, 09:13:56 PM »
I followed some lessons about adhesion forces from an indian teacher...you will find on YT. It seeams only way to know the force needed to break that bond is by a sperimental way... i don't think there are formulas...but it seem strange. I tried to empty a container full of water with down below a capillar tube. All liquid flow down till it reaches the top of the capillar.

I supponse if we divide a capillar like i drew up,we don't have to win the surface tension,but only the adhesion forces inside the capillar...and how i have just written it works. Better show this sistem to a phisycist or an engineer to have some clarifications...

It is clear that when we have emptied the short capillar,we have to move it and link on the top of the bigger and the water will rise again because longer is now  on the surface of the water contained in the tank.

It's a lot i don't write in english so please forget my mistakes in the way i write!

Gabriele

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Re: This old enemy the capillarity :)
« Reply #8 on: January 08, 2015, 09:26:18 PM »
Nobel pls  :D

telecom

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Re: This old enemy the capillarity :)
« Reply #9 on: January 08, 2015, 11:38:12 PM »
I followed some lessons about adhesion forces from an indian teacher...you will find on YT. It seeams only way to know the force needed to break that bond is by a sperimental way... i don't think there are formulas...but it seem strange. I tried to empty a container full of water with down below a capillar tube. All liquid flow down till it reaches the top of the capillar.

I supponse if we divide a capillar like i drew up,we don't have to win the surface tension,but only the adhesion forces inside the capillar...and how i have just written it works. Better show this sistem to a phisycist or an engineer to have some clarifications...

It is clear that when we have emptied the short capillar,we have to move it and link on the top of the bigger and the water will rise again because longer is now  on the surface of the water contained in the tank.

It's a lot i don't write in english so please forget my mistakes in the way i write!
It sounds interesting.
Can you make a picture?

Gabriele

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Re: This old enemy the capillarity :)
« Reply #10 on: January 09, 2015, 12:34:26 AM »

telecom

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Re: This old enemy the capillarity :)
« Reply #11 on: January 09, 2015, 03:30:03 AM »
Can you shed some light on your system?

Gabriele

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Re: This old enemy the capillarity :)
« Reply #12 on: January 09, 2015, 10:49:26 AM »
I didn't build nothing working jet... only theory

Gabriele

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Re: This old enemy the capillarity :)
« Reply #13 on: January 10, 2015, 02:45:51 AM »
Then i thought this ...  :)

profitis

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Re: This old enemy the capillarity :)
« Reply #14 on: January 10, 2015, 06:53:09 AM »
I don't think it will go down with piston-engine because width of bottom capillar capable of lifting up to certain hydrostatic height-pressure