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Author Topic: 3rd working machine you gandmother could make _2nd Law crushed  (Read 47944 times)

Offline The Eskimo Quinn

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3rd working machine you gandmother could make _2nd Law crushed
« on: November 26, 2014, 08:46:58 PM »
Being validated as we speak, no human can "Not" do this at home with a small glass jar in a bucket of water. It is over. and this is the third machine all different physics, number 4 is one its way with another physics application.

NO ONE ON EARTH CANNOT DO THIS AT HOME

as per usual will be no comments read or written by the author except the validation note from the engineers not that this needs it

Free Energy | searching for free energy and discussing free energy


Offline Madeo

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #1 on: November 26, 2014, 09:10:27 PM »
as usual,  extraordinary claims requires extraordinary evidence...

Offline The Eskimo Quinn

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #2 on: November 27, 2014, 09:19:43 AM »
Being validated as we speak, no human can "Not" do this at home with a small glass jar in a bucket of water. It is over. and this is the third machine all different physics, number 4 is one its way with another physics application.

NO ONE ON EARTH CANNOT DO THIS AT HOME

as per usual will be no comments read or written by the author except the validation note from the engineers not that this needs it

 NB: Engineer Validated 28th Nov 2014 – “Looks good”
Notes: this machine is more viable than a combustion engine that can run out of fuel or fail in spark – for Buoyant objects will always rise to the surface no matter the depth, falling Objects will always create energy – Nothing can alter these facts :
At less than 10 percent lift cost on the described height, there is a minimum 90 percent output for free – estimated fall time 60 second driving the generator @10,000KG (not including bonus encasement weight) 10,000 falling 1 Metre x 9.81 = 98100 joules x 100m = 9,810,000 joules  divided by the 60 second fall time = 163,500 watts x 60 mins per hour =9,810,000 watts per hour, less lift cost of 10 percent, = 8,829,000 watts. However the cycle time for rise is not accommodated even with multiple blocks in play, so it may add up to 5 minutes to the cycle. This one such unit would be then calculated at producing =8,829,000 divided by 6 =1,471,500 watts per hour clean free energy per tower unit. Or 1471.5 kilowatts per hour= 1.4 megawatts or min 75 houses assuming massive 20kw usage per day.
 

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #2 on: November 27, 2014, 09:19:43 AM »
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Offline Panul

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #3 on: November 27, 2014, 12:30:54 PM »
upload it in another form. it is impossible for me to open this odt

ok i opened it through this site zamzar.com

Offline tinman

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #4 on: November 27, 2014, 03:04:26 PM »
Buoyancy is something i know very well,having owned my own boat building firm,and i was also one of the builders ;).
Because of this,I too have an OU buoyancy device that i designed many years ago -but where to get the money to fund such a device or project.
No broken laws of physics,and the complete math to boot to back up said OU device. The opperation is so simple--.increasing and decreasing mass density/surface area. This is where the !buoyant force! comes into play.If the object’s weight is less than the buoyant force, the object will float.  If the object’s weight is greater than the buoyant force, the object will sink.The buoyant force is the force that pushes against the bottom and top surface areas of the object in the body of water,as the side ways forces cancel each other out.Because the bottom of the object has a greater depth than that of the top of the object(as the object will have hight/thickness),the object will feel slightly lighter under water,as the water pressure under the object will be slightly higher than it is on top of the object-and this depends on many factors in regards to the object. So all you need to do is increase the objects buoyant surface area without increasing it's weight,and the object will float. We then decrease the objects buoyant surface area,and the object will sink.

So here is the kicker. Once the object begins to sink,it will keep sinking with the same downward force until it hits the bottom-ocean floor. And when it begins to float,it will rise with the same force until it reaches the surface. So if it takes say 10000 joules of energy to get the object to sink say 10 feet,it takes the same amount of energy to get the object to sink 1 000 000 feet-->and this is done by decreasing the objects buoyant surface area,while maintaining the object weight.

They say that it takes x amount of energy to lift y amount of weight a set distance. Well using buoyancy as a tool,this is where that law dose not apply.This is one case it takes x amount of energy to lift y amount of weight to any hight,and return it back to it's starting point. 8)

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #4 on: November 27, 2014, 03:04:26 PM »
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Offline MarkE

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #5 on: November 27, 2014, 04:23:57 PM »
Buoyancy is something i know very well,having owned my own boat building firm,and i was also one of the builders ;).
Because of this,I too have an OU buoyancy device that i designed many years ago -but where to get the money to fund such a device or project.
No broken laws of physics,and the complete math to boot to back up said OU device. The opperation is so simple--.increasing and decreasing mass density/surface area. This is where the !buoyant force! comes into play.If the object’s weight is less than the buoyant force, the object will float.  If the object’s weight is greater than the buoyant force, the object will sink.The buoyant force is the force that pushes against the bottom and top surface areas of the object in the body of water,as the side ways forces cancel each other out.Because the bottom of the object has a greater depth than that of the top of the object(as the object will have hight/thickness),the object will feel slightly lighter under water,as the water pressure under the object will be slightly higher than it is on top of the object-and this depends on many factors in regards to the object. So all you need to do is increase the objects buoyant surface area without increasing it's weight,and the object will float. We then decrease the objects buoyant surface area,and the object will sink.

So here is the kicker. Once the object begins to sink,it will keep sinking with the same downward force until it hits the bottom-ocean floor. And when it begins to float,it will rise with the same force until it reaches the surface. So if it takes say 10000 joules of energy to get the object to sink say 10 feet,it takes the same amount of energy to get the object to sink 1 000 000 feet-->and this is done by decreasing the objects buoyant surface area,while maintaining the object weight.

They say that it takes x amount of energy to lift y amount of weight a set distance. Well using buoyancy as a tool,this is where that law dose not apply.This is one case it takes x amount of energy to lift y amount of weight to any hight,and return it back to it's starting point. 8)
The net downward force on a submerged object is simply the difference between the dry weight of the object and the equivalent weight of fluid displaced by the object's volume.  The energy involved sinking or raising the object is offset by the complementary movement of the displaced fluid.  Altering the object's volume while submerged requires work to increase the volume of displaced fluid, or absorbs work by shrinking.  Rheology aside, there is really no difference in the mechanics of a rock falling through the atmosphere to the land below or a rock sinking in the ocean.  the net energy per unit height is simply reduced in the case of falling through the denser fluid.

Offline telecom

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #6 on: November 27, 2014, 08:48:53 PM »
Hi guys,
there was a French patent where the guy had it with the weight pushing out pistons on one side to
increase the byouncy. And on another side to pull inward to decrease it.
Regards

Free Energy | searching for free energy and discussing free energy

Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #6 on: November 27, 2014, 08:48:53 PM »
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Offline The Eskimo Quinn

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #7 on: November 27, 2014, 10:33:40 PM »
This is a PDF that has the original doc, the validation and notes, and full mechanical design instructions as well now on the end. all in one doc.

if you are building one as a model you can reverse the side drives, so the chain is simply a bicycle chain and the protruding post are on the box. clear perspex is ideal or glass and silicone for models.

Offline tinman

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #8 on: November 27, 2014, 10:50:43 PM »
The net downward force on a submerged object is simply the difference between the dry weight of the object and the equivalent weight of fluid displaced by the object's volume.  The energy involved sinking or raising the object is offset by the complementary movement of the displaced fluid.  Altering the object's volume while submerged requires work to increase the volume of displaced fluid, or absorbs work by shrinking.  Rheology aside, there is really no difference in the mechanics of a rock falling through the atmosphere to the land below or a rock sinking in the ocean.  the net energy per unit height is simply reduced in the case of falling through the denser fluid.
There is a very large difference between the mechanics of air and water. A heavier than air object will not float in the atmosphere,but a heavier than water object will float in water. You can hollow out a rock all you like,and it will not float in air,but it will in water.This means the mechanics are different between fluid displacement and atmospheric displacement. No work is required to alter the objects volume when submerged,as the work is done by way of pressure equilization between the internal and external pressures of the submerged object. Work is only required to reduce surface area of the object at the begining of the cycle,which is while the object is afloat.Once that work is done,the object will sink an infinite depth that is limited only to the deepest water body.If we take a balloon and fill it with a lighter than air gas,the balloon will loose lifting force as it gains altitude,while the same balloon would maintain the same lifting force in water regardless of depth(we are asumeing the balloon is strong enough to withstand crushing forces in this example)

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #8 on: November 27, 2014, 10:50:43 PM »
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Offline TinselKoala

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #9 on: November 28, 2014, 05:27:54 AM »
There is a very large difference between the mechanics of air and water. A heavier than air object will not float in the atmosphere,but a heavier than water object will float in water.
Sorry, you are wrong. An object that is heavier than the water it displaces will not float in water, and an object that is heavier than the air it displaces will not float in air.  An object that is lighter than the air it displaces, like a big blimp, will float in air, and an object that is lighter than the water it it displaces, like a huge container ship, will float in water. Buoyancy is buoyancy, no matter the surrounding material.
Quote
You can hollow out a rock all you like,and it will not float in air,but it will in water.This means the mechanics are different between fluid displacement and atmospheric displacement.
No, you are comparing apples and oranges. If your hollow rock displaces enough air mass, it will float, sure enough. Our air isn't dense enough for any real hollow rock to float, but it will float just fine in a much denser gas environment.
Quote
No work is required to alter the objects volume when submerged,as the work is done by way of pressure equilization between the internal and external pressures of the submerged object. Work is only required to reduce surface area of the object at the begining of the cycle,which is while the object is afloat.Once that work is done,the object will sink an infinite depth that is limited only to the deepest water body.If we take a balloon and fill it with a lighter than air gas,the balloon will loose lifting force as it gains altitude,while the same balloon would maintain the same lifting force in water regardless of depth(we are asumeing the balloon is strong enough to withstand crushing forces in this example)
Again, you are confounding your facts with false comparisons. Take a look at how high-altitude research balloons work. They start at the ground only "partially" inflated, just enough to be buoyant (they displace slightly more airmass than they weigh) and as they rise, the gas inside expands, so they displace more and more volume, of less and less dense air, so they continue to rise until they finally burst from being completely overfull. If you sink a balloon in water by deflating it at the surface, the only way to get it to rise up again is to pump gas into it, and you will have to pump harder the deeper the balloon is. A volume of water must be displaced that has a mass that is greater than the balloon's mass for it to rise up, and the deeper the balloon the more gas must be pumped into it, because the gas is compressible and the pressure inside the balloon must be slightly greater than the pressure of the water, for the balloon to expand and displace the necessary volume of water. When the balloon is expanded enough to displace more mass of water than the balloon weighs, the balloon will begin to rise _and expand even more_ as the gas inside expands to match the water pressure at whatever depth it is at.
When you sink a closed, constant volume thing like your hollow rock, the water level rises. Take a bucket and mark the water level on the side of the bucket, then sink your rock to just below the surface. You will note that the water level is now above your mark; an equal volume of water has been _lifted up_ as your rock has been sunk. This lifting of water takes work. Now let your rock sink more, say one-rock-diameter further. Now you have lifted up another volume of water, but you don't see the water level increase because you aren't changing the overall volume of the system any more, but you still have displaced one rock's worth of water from underneath the rock and moved it to above the rock. This takes work. If you have a rope attached to the rock, the work available by the rock pulling on the rope is _less than_ the work available from dropping the rock/rope in air, less by the amount of work it takes to raise up that water, continuously all the way down. When you pull the rock up, it's easier than in air because the water is flowing back underneath the rock as you lift it. This is buoyancy. There is no free lunch, even underwater.

Offline TinselKoala

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #10 on: November 28, 2014, 05:32:03 AM »
This is a PDF that has the original doc, the validation and notes, and full mechanical design instructions as well now on the end. all in one doc.

if you are building one as a model you can reverse the side drives, so the chain is simply a bicycle chain and the protruding post are on the box. clear perspex is ideal or glass and silicone for models.

Feel free to show us your working model.


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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #10 on: November 28, 2014, 05:32:03 AM »
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Offline TinselKoala

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #11 on: November 28, 2014, 05:41:12 AM »
This is a PDF that has the original doc, the validation and notes, and full mechanical design instructions as well now on the end. all in one doc.

if you are building one as a model you can reverse the side drives, so the chain is simply a bicycle chain and the protruding post are on the box. clear perspex is ideal or glass and silicone for models.

This is just silly, your pdf document is a bunch of nonsense. Are you Archer Quinn, of "sword of god" fame?

"Full mechanical design instructions"... bull hockey. Not even a sketch. Where are the dimensioned blueprints, but more importantly... where is your working model? Why don't you "teach" us how to build it, like you did your "sword of god".

Offline TinselKoala

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #12 on: November 28, 2014, 06:46:36 AM »
Being validated as we speak, no human can "Not" do this at home with a small glass jar in a bucket of water. It is over. and this is the third machine all different physics, number 4 is one its way with another physics application.

NO ONE ON EARTH CANNOT DO THIS AT HOME

as per usual will be no comments read or written by the author except the validation note from the engineers not that this needs it

Yep... my "gandmother" (sic) could make it, but for some reason YOU can't.


Offline tinman

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #13 on: November 28, 2014, 03:20:18 PM »
Sorry, you are wrong. An object that is heavier than the water it displaces will not float in water, and an object that is heavier than the air it displaces will not float in air.  An object that is lighter than the air it displaces, like a big blimp, will float in air, and an object that is lighter than the water it it displaces, like a huge container ship, will float in water. Buoyancy is buoyancy, no matter the surrounding material.  No, you are comparing apples and oranges. If your hollow rock displaces enough air mass, it will float, sure enough. Our air isn't dense enough for any real hollow rock to float, but it will float just fine in a much denser gas environment. Again, you are confounding your facts with false comparisons. Take a look at how high-altitude research balloons work. They start at the ground only "partially" inflated, just enough to be buoyant (they displace slightly more airmass than they weigh) and as they rise, the gas inside expands, so they displace more and more volume, of less and less dense air, so they continue to rise until they finally burst from being completely overfull. If you sink a balloon in water by deflating it at the surface, the only way to get it to rise up again is to pump gas into it, and you will have to pump harder the deeper the balloon is. A volume of water must be displaced that has a mass that is greater than the balloon's mass for it to rise up, and the deeper the balloon the more gas must be pumped into it, because the gas is compressible and the pressure inside the balloon must be slightly greater than the pressure of the water, for the balloon to expand and displace the necessary volume of water. When the balloon is expanded enough to displace more mass of water than the balloon weighs, the balloon will begin to rise _and expand even more_ as the gas inside expands to match the water pressure at whatever depth it is at.
When you sink a closed, constant volume thing like your hollow rock, the water level rises. Take a bucket and mark the water level on the side of the bucket, then sink your rock to just below the surface. You will note that the water level is now above your mark; an equal volume of water has been _lifted up_ as your rock has been sunk. This lifting of water takes work. Now let your rock sink more, say one-rock-diameter further. Now you have lifted up another volume of water, but you don't see the water level increase because you aren't changing the overall volume of the system any more, but you still have displaced one rock's worth of water from underneath the rock and moved it to above the rock. This takes work. If you have a rope attached to the rock, the work available by the rock pulling on the rope is _less than_ the work available from dropping the rock/rope in air, less by the amount of work it takes to raise up that water, continuously all the way down. When you pull the rock up, it's easier than in air because the water is flowing back underneath the rock as you lift it. This is buoyancy. There is no free lunch, even underwater.
I am not wrong TK,you misunderstood what i said-Quote: a heavier than water object will float in water. My statement is correct,and i said nothing about displacement. I was refering to net weight of the bouyant object-EG,steel is heavier than water per net volume,but can be made(shaped) to float in water-made to be bouyant.

Quote TK: No, you are comparing apples and oranges. If your hollow rock displaces enough air mass, it will float, sure enough. Our air isn't dense enough for any real hollow rock to float, but it will float just fine in a much denser gas environment.

No ,im not the one comparing apples to oranges. Im the one saying that the apples and oranges are differnt-Quote: the mechanics between water and air are very different. My statements are also based on the makeup of our planet,not Helion Prime,thus my statement is correct-hollow out a rock all you like,but it will not float in air(planet earths air/atmosphere)

Quote TK: Again, you are confounding your facts with false comparisons. Take a look at how high-altitude research balloons work. They start at the ground only "partially" inflated, just enough to be buoyant (they displace slightly more airmass than they weigh) and as they rise, the gas inside expands, so they displace more and more volume, of less and less dense air, so they continue to rise until they finally burst from being completely overfull. If you sink a balloon in water by deflating it at the surface, the only way to get it to rise up again is to pump gas into it, and you will have to pump harder the deeper the balloon is. A volume of water must be displaced that has a mass that is greater than the balloon's mass for it to rise up, and the deeper the balloon the more gas must be pumped into it, because the gas is compressible and the pressure inside the balloon must be slightly greater than the pressure of the water, for the balloon to expand and displace the necessary volume of water. When the balloon is expanded enough to displace more mass of water than the balloon weighs, the balloon will begin to rise _and expand even more_ as the gas inside expands to match the water pressure at whatever depth it is at

Although i quoted:-->we are asumeing the balloon is strong enough to withstand crushing forces in this example.lets look at this a different way. Let's use a steel sphere insted of our crushless balloon. I will take my steel sphere(lets say with a volume of 1 cubic meter),and pump air into it to a pressure of 100psi-->my sphere will float in water. Now do the same with your sphere of the same size,and see if it floats in air.
Second test. I will now pull an absolute vacume in my sphere,and my sphere will still float just as well as it did with a pressure of 100psi-->now do the same with your sphere,dose it float in air yet?.

Quote TK: When you sink a closed, constant volume thing like your hollow rock, the water level rises. Take a bucket and mark the water level on the side of the bucket, then sink your rock to just below the surface. You will note that the water level is now above your mark; an equal volume of water has been _lifted up_ as your rock has been sunk. This lifting of water takes work. Now let your rock sink more, say one-rock-diameter further. Now you have lifted up another volume of water, but you don't see the water level increase because you aren't changing the overall volume of the system any more, but you still have displaced one rock's worth of water from underneath the rock and moved it to above the rock.

This we know.

Quote TK: If you have a rope attached to the rock, the work available by the rock pulling on the rope is _less than_ the work available from dropping the rock/rope in air, less by the amount of work it takes to raise up that water, continuously all the way down. When you pull the rock up, it's easier than in air because the water is flowing back underneath the rock as you lift it. This is buoyancy. There is no free lunch, even underwater.

This is not correct as far as my device is designed to work,and another reason that the mechanics/dynamics between water and air are very different. A bouyant vessle correctly engineered can be made to sink and then rise again in water without the addition of any air(or gas of any type),as bouyancy in water is not reliant on a gas volume of any kind. As i stated above,the internal area of a sealed bouyant vessle can be under an absolute vacume,and it will have no effect on the bouyancy of the vessle-->not the case with air im afraid. Now you take what ever vessle you want,and make it float in air without the use of a gas,but by simply increasing the size of that vessle. ;)

You must also take into account the weight of the vessle it self when calculating bouyancy,not just the volume of water it displaces.

Offline telecom

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Re: 3rd working machine you gandmother could make _2nd Law crushed
« Reply #14 on: November 28, 2014, 06:06:40 PM »
This is a French patent I was referring too:
http://vitanar.narod.ru/files/02830575A1.pdf
I would like to hear what you, guys, think about its viability.
Regards

 

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