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Author Topic: Marosz's Rdial Turbine ( SYMETRY IN PHYSICS NOT EXIST )  (Read 11074 times)


tesla2

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Re: Marosz's Rdial Turbine ( SYMETRY IN PHYSICS NOT EXIST )
« Reply #1 on: November 06, 2014, 08:12:31 AM »
THANK YOU VERY MUCH FOR RESPECT
AND SUPPORT MY DISCOVERY IN LINKEDIN


I PROVED NEWTON's MISTAKE

FUNDAMENTS ARE WRONG ( below very strong and new force inside ATOM )
I explained people how to directly convert Aether's Energy to  work
( if You will read my blog You will understand that electrons inside atom are moving because "Eat" aether )

I showed what is it Aether

We can use atom's energy and directly convert to mechanical energy
 ( antygravitation material )  can become more light or more heavy / we can control this process

http://maroszphysics.blogspot.com/


I'm very good Engineer ( I'm like leonardo DaVince or NIkola below few example My patents and design vision  )
http://tesla4.blogspot.com

I would like to start design for ARMY or Nuclear Industry 
people like me = future for modern physics

I'm 34yo I'm open for cooperation

s3370389

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Re: Marosz's Rdial Turbine ( SYMETRY IN PHYSICS NOT EXIST )
« Reply #2 on: November 06, 2014, 11:07:34 AM »
Hi Marosz,

I'm not really understanding what your diagram is showing when I follow that link. Can you explain please?

tesla2

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Re: Marosz's Rdial Turbine ( SYMETRY IN PHYSICS NOT EXIST )
« Reply #3 on: November 06, 2014, 11:47:34 AM »
Water's mass ( blue)  inside pipe R radius  VS mercury's mass (violet)  inside pipe R radius

green = oil

Oil is pushing water / mercury    ideal symetry left/right


Fr = m*V*V / R  - radial force

Fr mercury > Fr water 

here I testing Radial force for water ( pomp from car - water is making rotation inside pipe )
 http://youtu.be/JRoApSJpEWs

I also make other turbine
http://youtu.be/e5MTpKNf4e4


person inside boat or spaceship
is pushing pistons

<---- F  F ----->

http://4.bp.blogspot.com/-Zak4eXvL-u0/VFprW0iVitI/AAAAAAAACDM/9yki-6k78Ys/s1600/CIMG3381.JPG

water and mercury are giving the same resistance to OIL ( three way pipe )
 

s3370389

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Re: Marosz's Rdial Turbine ( SYMETRY IN PHYSICS NOT EXIST )
« Reply #4 on: November 06, 2014, 12:28:30 PM »
With regard to the diagram at this link:
http://www.spacetimeandtheuniverse.com/space-time-universe/7885-maroszs-turbine-symetry-not-exist-real-world.html#post34907

When the pistons displace the oil, the springs will compress. Once the force is removed from the piston heads (that is, the person stops pushing the pistons) the energy stored in the compressed springs will force the displaced oil back into its original position. Am I understanding this correctly?

What happens now?

tesla2

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Re: Marosz's Rdial Turbine ( SYMETRY IN PHYSICS NOT EXIST )
« Reply #5 on: November 06, 2014, 12:45:53 PM »
OK

mercury is more heavy than water

Water and Mercury are inside pipe diameter d and radius R


Oil ( green)  left / right is going  symetry
but boat will go  there where feel stronger radial  force

Fr mercury = Mmercury * V *V / R
Fr water = Mwater *V*V/R

Fr mercury = 13,59 Fr water

The same oil's capacity will go left/right


tesla2

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Re: Marosz's Rdial Turbine ( SYMETRY IN PHYSICS NOT EXIST )
« Reply #6 on: November 06, 2014, 12:50:15 PM »
MUCH MORE IMPORTANT IS OTHER PROBLEM

RADIAL FORCE ARE ABLE REDIRECT ENERGY
WITHOUT OPPOSITE TO MOTION REACTION

Directly we can redirect atoms inside material and move up material
electrons speed = 2170 km/s

Below link contain
1 explanation -  each mass m = satellite for N objects in universe
2 new force inside atom ( each electron = satellite for N objects in unierse)
3 Marosz's antygravitation Engine
4 Michelson Morley ( force edition how heavy is air Left/right )

5 I PROVED THAT NOT EXIST SYMETRY IN PHYSICS

6 I SHOWING NEW FALL LAW ( better than Gallileo ) 


http://maroszphysics.blogspot.com/

s3370389

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Re: Marosz's Rdial Turbine ( SYMETRY IN PHYSICS NOT EXIST )
« Reply #7 on: November 06, 2014, 01:51:48 PM »
Marosz,

I have attached a diagram. As far as I knew, the radial force (or centripetal force) is directed inward toward the
centrepoint of the circular path that the object is following. But you have your radial force directed outward
(a centrifugal force) why is that?

As far as I remember work is defined as W=Fd, where:
W = Work {Nm}
F = Force {N}
d = Distance {m}
I'm sure that you know this, but I want to make sure that I am speaking the same language as you. The mercury
and water must accelerate. However, the radial component can do no work as it is not in the direction of motion
(the radial force is acting perpendicular to the direction of the water and the mercury).

I don't think that the object at the link will move:
http://www.spacetimeandtheuniverse.com/space-time-universe/7885-maroszs-turbine-symetry-not-exist-real-world.html#post34907

Can you tell me what I am missing here?

s3370389

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Re: Marosz's Rdial Turbine ( SYMETRY IN PHYSICS NOT EXIST )
« Reply #8 on: November 06, 2014, 01:53:25 PM »
<Deleted post>

tesla2

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Re: Marosz's Rdial Turbine ( SYMETRY IN PHYSICS NOT EXIST )
« Reply #9 on: November 06, 2014, 04:05:45 PM »
water = many small mass m

F1+F2 + F3 .....+Fn = F

F1 = mV^2/R * cos@
F2
.......


http://2.bp.blogspot.com/-_SHx3z1xLbk/VFuMky3bIWI/AAAAAAAACDc/wGj2uK1L8XE/s1600/CIMG3383.JPG


1/4 pipe + 1/4 pipe = 1/2 pipe

My turbine = two springs and  1/2 water pipe + 1/2 mercury  pipe

Main idea is very simple
Each small mass m = each small pipe's peace



Please ask Your self
why people who repear water in home are giving foam on pipe in place where water is changing  direction

http://www.fachowyinstalator.pl/images/stories/porady_ogolne/zlaczki-i-ksztaltki-do-rur/zlaczki-i-ksztaltki_1.jpg




s3370389

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Re: Marosz's Rdial Turbine ( SYMETRY IN PHYSICS NOT EXIST )
« Reply #10 on: November 06, 2014, 04:27:46 PM »
Marosz with respect, I asked you a specific question and you have responded with vague generalities.

I will repeat my question.

Quote
But you have your radial force directed outward (a centrifugal force) why is that?

And what do you say to this:

Quote
I'm sure that you know this, but I want to make sure that I am speaking the same language as you. The mercury
and water must accelerate. However, the radial component can do no work as it is not in the direction of motion
(the radial force is acting perpendicular to the direction of the water and the mercury).

s3370389

tesla2

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Re: Marosz's Rdial Turbine ( SYMETRY IN PHYSICS NOT EXIST )
« Reply #11 on: November 06, 2014, 04:46:57 PM »
only people with huge  3D imagination
can prepare so simple drawing 2D and finaly 3D

^
^Fr
^
Moon ---->V1
i
i
R distance
i
i
Earth 

Moon = Earth's  Satellite  / radial force  Fr = M*V1*V1 /R


^
^Fr
^
m -------------------------------->V2
T
O
W  ( R distance)
E
R
Earth

MAROSZ ( me )
  EACH MASS m = Satellite for Earth . Mass m is registering the same force what moon !  Fr = M*V2*V2 /R  high tower we can exchange for short table.

Please speed up Moon = moon will escape to more high obrbite ( R will rise)
ONLY !  on Planet and inside real  gravitation
 mass m can  fly ( chage orbite to more high !) 

table is losting mass
http://1.bp.blogspot.com/-jIKPBonOu-Q/VAgKnhFHZKI/AAAAAAAAB8M/OMrX6H91ULg/s1600/12.gif

8 km/s respect to table m= 1 kg

http://1.bp.blogspot.com/-tw7h9kfZcf0/VBk0W5TEt6I/AAAAAAAAB_k/YKxK437pygQ/s1600/CIMG3331.JPG


You think that 8 km/s it is huge speed ?

please confirm in books electron's speed  Hydrogen  2170 km/ s

radial force are able redirect energy without Newton

please use 30 km/s respect to table Fr force respect to SUN ?

how heavy is mass m ?

http://4.bp.blogspot.com/-z7Ki0fNtLrY/VCqMhjWmV1I/AAAAAAAACA4/W5lTo-22NrI/s1600/CIMG3345.JPG

i
i
i (ROPE)
i
i
m <<< finger

What  feel Your finger  mass m or Q ?

What is Q?

Each V we can exchange for many small v .

V=v1+v2+......vn   (Why vn because  exist N objects in universe )

each small  v  represents each N object in universe 

http://1.bp.blogspot.com/-YrUvn5DtJbs/VBVMugI-61I/AAAAAAAAB_A/QmzLUbz-qoY/s1600/CIMG3325.JPG


Secoundary school Newton

m------DYNAMITE-------m


Marosz
spring = internal force / Where is and where will be midle point mass M1---M2
http://1.bp.blogspot.com/-kVb39PYeYjE/VB2x-lAKGyI/AAAAAAAACAQ/Uwcd1TEJG78/s1600/22.jpg

tesla2

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Re: Marosz's Rdial Turbine ( SYMETRY IN PHYSICS NOT EXIST )
« Reply #12 on: November 06, 2014, 05:08:12 PM »
Marosz with respect, I asked you a specific question and you have responded with vague generalities.

I will repeat my question.

And what do you say to this:

s3370389

I showed You Toy Car   How big force is registering road

A - car is going strait
B - car is changing direction

http://2.bp.blogspot.com/-_SHx3z1xLbk/VFuMky3bIWI/AAAAAAAACDc/wGj2uK1L8XE/s1600/CIMG3383.JPG

car mass m= 1 kg
car speed v=  20 m/s
r = 1 meter

Qcar = m*g = 10 [N]
Fr = m*V*V/r

if Fr > Q car  car can go


please make the same experiment with water ( half pipe )
fast water can chage direction like car ( only one wall will register force and water will not fall down )

s3370389

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Re: Marosz's Rdial Turbine ( SYMETRY IN PHYSICS NOT EXIST )
« Reply #13 on: November 06, 2014, 05:12:11 PM »
Marosz as I said previously, the mercury and water in the piping is experiencing a normal acceleration - that is, an inward radial force (centripetal) not outward. The work done by this force is zero as it is acting perpendicularly. Is my understanding incorrect?

What are you hoping to achieve with this?

tesla2

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