Let me do a list of inventions,attraction/compression and repulsion/expanding force related :
Wind and winding
Air gas and Ionic/Electronic gas Power
Melvin Prueitt MECH
Ron Driver heating and cooling pump
Prof. Kanarev Pulse Power explication
Mukherjee Motor/Generator
Richard Fradella electric controlled generator
Prof.Ingo Rechenberg bionic Biot-Savart analogon
Klinsing Biot-Savart formula Winding
Dr.Pavel Imris capacitive em-winding
Dr.Wolfgang Volkrodt magnetic force transformer
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Let me go to R.Fradella generator description:
nominal 1000 RPM gives nominal 1000 W output
then 500 RPM by the same generator will give 1000 W X (0,5)³= 125 W
then 100 RPM by the same generator will give 1000 W x (0,1)³= 1 W
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How you want to controle the ccw and cw force balance/resonance ?
The capacitor windings will work as source but also as load/resistance !
How much power do you think to receive as gain :
surpassing Shkondins Motor(with generator winding) or
www.trinitymotors.net (archive.org)
motor/generator 30% feedback-gains ?
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F=BIL
How to neutralize cw force by ccw force to surpass the 'break even' ?
At first here a description without capacitors !
http://translationportal.epo.org/emtp/translate/?ACTION=description-retrieval&COUNTRY=DE&ENGINE=google&FORMAT=docdb&KIND=A1&LOCALE=en_EP&NUMBER=2733719&OPS=ops.epo.org/3.1&SRCLANG=de&TRGLANG=enThe inventive generator thus comprises a conventional generator for generating electric energy and an electrical device, which counteracts the generated at the conventional generator shaft in the generation of electrical energy retarding force, wherein a part of the electrical energy generated by the generator is consumed.
In a conventional generator the field strength B, the length of its conductor L and the current flowing through is denoted I, the result is the size of the reaction force F exerted on the conductor and thus to the shaft to F = BLI.
If the field strength of the electrical device 2B, the length of its conductor L each, only one current durchfiiesst, corresponds to the strength of the half of the current flowing in the generator current, is the force exerted on the anchor force F '= 2B x L x 1 = LI.
2 This shows that the force exerted on the armature of the electrical device, and thus on the driving wave power is equal to the opposing force which is exerted on the shaft from the conventional generator.
The force is generated to act in a direction such that it compensates the reaction force.
A stronger current flow provides the required torque to the shaft.
Therefore, the shaft and thus the armature moves further and generates electrical energy.
In order to flow current through these half the electrical device, half the voltage generator is required. by half amperageSo with is 1/4 of the power generated is lost to counteract the retarding force.The remaining 3/4 of the energy produced, or slightly less of them are for outdoor use are available.
When the field strength of the electrical device is a multiple of the field strength of the generator, for example,
5-fold,
it is necessary that 1/5 of the electricity generated flowing in the electrical device in order to generate the compensating force. 1/5 of the generated voltage is required for the current flow. 1/5 voltage x 1/5 ampreage = 1/25 powerThus, 1/25 or 4% of the energy produced is consumed in the electrical device, while 96% or less of them are for outdoor use are available.
In this way it is not necessary that any electrical energy from an external source is introduced into the generator according to the invention for generating electrical energy.
Thee gain in magnetic induction in the electrical equipment field compared to the generator field can thus be exploited in two ways, namely one for reducing energy consumption in the electric device and on the other to reduce the length of the conductor in the armature of the electrical device and thus in size and cost.
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This as example about the progressive internal power (F,VA) behaviour.