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Author Topic: Starting gravity wheel project, GRAM  (Read 21145 times)

Offline burnit0017

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Re: Starting gravity wheel project, GRAM
« Reply #15 on: November 10, 2014, 11:13:14 AM »
http://youtu.be/lok3KUMT7ZU

Started testing new configuration. Working on connecting the PMA.

Free Energy | searching for free energy and discussing free energy

Re: Starting gravity wheel project, GRAM
« Reply #15 on: November 10, 2014, 11:13:14 AM »

Offline Low-Q

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Re: Starting gravity wheel project, GRAM
« Reply #16 on: November 10, 2014, 10:53:56 PM »
http://youtu.be/lok3KUMT7ZU

Started testing new configuration. Working on connecting the PMA.
Hmmm - it stops! Surprising :-)

Offline Low-Q

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Re: Starting gravity wheel project, GRAM
« Reply #17 on: November 10, 2014, 10:54:25 PM »
Lossless bearings aren't good enough. You need _negative friction_ bearings.

Around here, we call them "motors".
Haha :-)

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Re: Starting gravity wheel project, GRAM
« Reply #17 on: November 10, 2014, 10:54:25 PM »
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Offline burnit0017

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Re: Starting gravity wheel project, GRAM
« Reply #18 on: November 10, 2014, 11:43:19 PM »
http://youtu.be/2ZzfK-mvd2Q

Project update. This is gravity assisted motor project. It will always require power at the input. It is a experiment to determine if it is possible to use mechanical advantage and gravity to generate more at the output than at the input. I see it as two different machines. The first machine will use a small electric motor to use mechanical advantage to tilt the weight plate. As the plate tilts it changes the center of gravity and the weights fall toward the rotating; always changing; center of gravity. More weights, more torque. The longer the center shaft, the more mechanical advantage. 

I still have to connect the PMA, then I can post results.   

Offline Low-Q

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Re: Starting gravity wheel project, GRAM
« Reply #19 on: November 11, 2014, 12:18:07 PM »
http://youtu.be/2ZzfK-mvd2Q

Project update. This is gravity assisted motor project. It will always require power at the input. It is a experiment to determine if it is possible to use mechanical advantage and gravity to generate more at the output than at the input. I see it as two different machines. The first machine will use a small electric motor to use mechanical advantage to tilt the weight plate. As the plate tilts it changes the center of gravity and the weights fall toward the rotating; always changing; center of gravity. More weights, more torque. The longer the center shaft, the more mechanical advantage. 

I still have to connect the PMA, then I can post results.
Have in mind that gravity does not dissapear in the periods you should need that to happen. Gravity will pull the weights towards ground all the time, with equal force at any time. The energy you spend on the machine, and what you get out will allways be accounted for. It will end up in zero total energy, minus loss. Anything that happens in that machine happens for a reason. There are no spooky energy sources that will assist anything.
All that counts is altitude and mass. If it's spinning around in any fashion does not change the different altitudes these weights do have at any given time. As long the headroom you have in altitude doesn't change, you will never be able to "charge" the machine with greater potential energy than available within max and min altitude.


So truely, there is no such as overbalance in this machine - even if it appears to be.


Vidar

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Re: Starting gravity wheel project, GRAM
« Reply #19 on: November 11, 2014, 12:18:07 PM »
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Offline burnit0017

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Re: Starting gravity wheel project, GRAM
« Reply #20 on: November 11, 2014, 01:04:19 PM »
Hi, thanks for the info. Can you explain how a lever works?

Offline kolbacict

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Re: Starting gravity wheel project, GRAM
« Reply #21 on: November 12, 2014, 04:03:18 AM »
Gravity will pull the weights towards ground all the time, with equal force at any time
  ;)And how the gyroscope which has unusual gravitational properties?

Free Energy | searching for free energy and discussing free energy

Re: Starting gravity wheel project, GRAM
« Reply #21 on: November 12, 2014, 04:03:18 AM »
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Offline Low-Q

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Re: Starting gravity wheel project, GRAM
« Reply #22 on: November 12, 2014, 10:12:28 AM »
Hi, thanks for the info. Can you explain how a lever works?
What do you mean? A lever is a lever. A mass that is lifted a given distance in altitude, it does not matter how you do it. The energy you put into the lifting process is the same if you lift it directly or using pulleys, levers or what not. Don't confuse force with energy. Energy is a product of force and distance.


Vidar

Offline burnit0017

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Re: Starting gravity wheel project, GRAM
« Reply #23 on: November 12, 2014, 10:54:11 AM »
http://www.grc.nasa.gov/WWW/k-12/airplane/torque.html

Hi, Direction of the rotation will be in the of direction of higher torque. The weights falling are the real input. As the weights fall toward the rotating center of gravity they will produce a total torque at the output. A DC Buck circuit with a variable duty cycle can be adjusted to limit the load to less than the total output torque.  All motors operate at a loss. I have to fabricate a few more parts than I can test and post results. 

Free Energy | searching for free energy and discussing free energy

Re: Starting gravity wheel project, GRAM
« Reply #23 on: November 12, 2014, 10:54:11 AM »
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Offline Low-Q

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Re: Starting gravity wheel project, GRAM
« Reply #24 on: November 12, 2014, 08:46:13 PM »
http://www.grc.nasa.gov/WWW/k-12/airplane/torque.html

Hi, Direction of the rotation will be in the of direction of higher torque. The weights falling are the real input. As the weights fall toward the rotating center of gravity they will produce a total torque at the output. A DC Buck circuit with a variable duty cycle can be adjusted to limit the load to less than the total output torque.  All motors operate at a loss. I have to fabricate a few more parts than I can test and post results.
When the weights has reached highest torque, what happens next? At some point these weights must repeat the cycle and pass a point with least torque. From where do they get the input to repeat the cycle with even more energy?


Torque isn't all. Examine at what angular velocity the mass has at a given torque.


As long you use gravity to "gain" torque, and the mass is unchanged, the complete cycle will allways end up in loss. There is no way around this - really.


Vidar

Offline burnit0017

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Re: Starting gravity wheel project, GRAM
« Reply #25 on: November 12, 2014, 10:03:58 PM »
Hi, the weights always fall toward the center of gravity but they never reach it because a small motor will always be turning the center shaft. I have to fabricate a few more parts then I can post results. The video will better explain the operation of the device. Good or bad I will post the results.

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Re: Starting gravity wheel project, GRAM
« Reply #25 on: November 12, 2014, 10:03:58 PM »
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Offline burnit0017

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Re: Starting gravity wheel project, GRAM
« Reply #26 on: November 13, 2014, 02:58:51 PM »
Hi, thanks. It seems to balance out the system.  I have been viewing the Skinner black and white movie clip for over a year. Part of what I am looking at looks like a spoof. Other parts I am just starting to understand. Basically what I am fabricating is a simpler version to the Skinner device. It is great to find a few with a greater understanding of physics, I can use all the help I can get. If it works greats, if it does not work then we can all understand why. ;D

Offline burnit0017

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Re: Starting gravity wheel project, GRAM
« Reply #27 on: November 13, 2014, 10:17:02 PM »
http://youtu.be/PHPId8bDrhQ

Hi, a quick video update. I am starting to understand all the parameters better. I have to install a longer center shaft. Add more weights. Make the frame strong. Stop the grinding noise. ;D

Offline burnit0017

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Re: Starting gravity wheel project, GRAM
« Reply #28 on: November 30, 2014, 02:05:01 PM »
Version 3 has limitations, working on version 4.

http://youtu.be/vBnzDB6-brg

Offline AB Hammer

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Re: Starting gravity wheel project, GRAM
« Reply #29 on: November 30, 2014, 11:43:51 PM »
Happy Holiday  8)

 

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