Author Topic: COP 20.00 (2000%) Times, Reactive Power Energy Source Generator, (Read 304788 times)

hartiberlin · « **Reply #150 on:** July 22, 2014, 05:16:38 AM »

Okay, tonight I had time to buy the Serps
lecture:

http://bit.ly/serpslecture

but, well I guess you can spare the 37 US$...

As the slideshows showed interesting devices and
also Paul Babcock showed his toroidal motor turning
and showing needing less power when he enganged his
special switches, there were no real circuit diagrams
shown and also the motor was not shown powering a mechanical load...

Looked more or less like a rotorvertor minimizing the input energy.

Anyway, the only interesting block diagram shown was this one,
which I have modified with further explanation about Tesla´s magnifying
generator.
I added the violet circle and note...

I was wrong, when I assúmed, that they just charge and discharge
the caps over the bulb ( resistive ) loads !

This has too many losses !

You really need to have a switched LC tank circuit with very low ohmic
impedance, where the L is the primary of a transformer
and just have the ohmic load on the secondary of the transformer,
which must have a high impedance ! ( That is why they use 2 bulbs in series
at the secondary of the transformer, there is a higher voltage with lower current = high impedance)

This way you can compensate any ohmical losses from the primary coil of the transformer
with the switched capacitor.

I will draw a block diagram and also post it later.

They did not show any other block diagram, so the video was a bit disapointing...
Having a great technology and sitting on it only waiting for stock investors money
is a waste of time....in my opinion...

Regards, Stefan.

hartiberlin · « **Reply #151 on:** July 22, 2014, 05:49:52 AM »

Okay,here is the block diagram.

The switching timing is the same as already posted before.

Maybe the guys with the simulation software can run this again through ?

Many thanks.

Regards, Stefan.

hartiberlin · « **Reply #152 on:** July 22, 2014, 06:11:50 AM »

By the way, it would be probably good to have the
parallel cap configuration with C1 and C2 resonate with the primary
of the transformer coil L1 at 60 Hz, you you would need to
tune the cap values of the electrolytic caps with some parallel
caps to get the right capactor value to get to 60 Hz resoanance
with the given transformer coil L1.

As there is mutual inductance coupling between L2 and L1
when the 2 bulbs load is applied, this might need to be
taking into account and calculated for this load...to be at optimum
efficiency.
So L1 and (C1+C2) should have a maximum Q, so ohmical losses in this primary
LC tank should be minimal for good efficiency.

Regards, Stefan.

wings · « **Reply #153 on:** July 22, 2014, 09:11:15 AM »

Parameter Variation Machines With focus on EPD FQToEW, JF Murray, Manelstam & Papalex
back to 2012 by garrettm4

http://www.energeticforum.com/renewable-energy/10769-parameter-variation-machines-focus-epd-fqtoew-jf-murray-manelstam-papalex.html#post183458

http://img521.imageshack.us/img521/7771/ractancemachineplot1.png

http://www.energeticforum.com/renewable-energy/6557-charge-conserving-capacitive-spring-9.html#post221075

listener191 · « **Reply #154 on:** July 22, 2014, 09:12:22 AM »

Hi Stefan,

In the earlier video of SERP's you can see fixed links between the two sets of caps, which rules out parallel/series switching.

Regards

Barry

listener191 · « **Reply #155 on:** July 22, 2014, 09:31:01 AM »

Hi Stefan,

Also in the conference presentation video at time:1.06.18 , Babcock says " we use the transformer to duplicate the output of a generator". This indicates the SERP,s switching is after the transformer.

Regards

Barry

listener191 · « **Reply #156 on:** July 22, 2014, 02:44:20 PM »

All,

Re the presentation video time 1.50.08 to 1.50.38. Babcock specifically states 1W out of the transformer for 52W into the load. Just confirming again that the switching is after the secondary of the transformer.

Sorry for belaboring this point in the last few posts, but schemes that are not in alignment with what we know about the SERPS demonstration setup, will not yield the results that Babcock & Murray have obtained.

The SERPS concept by their own admission is not patentable, so the only patent they could apply for, would be a specific circuit configuration and why would they give that away!
I think they have provided enough for replication by experimentation.

Barry

Jdo300 · « **Reply #157 on:** July 22, 2014, 05:00:32 PM »

This is a good point to look into various ways to do AC energy recovery. The following simulation shows an example of how to do this using the series/parallel cap switching version. The load is left out for now for simplicity.

$ 1 4.9999999999999996E-6 9.001713130052181 31 5.0 50
v 288 176 288 48 0 1 60.0 177.0 0.0 0.0 0.5
T 352 80 448 144 0 0.1 1.0 11.68220520430725 -15.210861419364894 0.9999
w 288 48 352 48 0
w 352 48 352 80 0
w 352 144 352 176 0
w 448 80 448 48 0
w 448 48 512 48 0
w 448 144 448 176 0
r 288 176 352 176 0 1.0
R 352 304 288 304 1 2 120.0 2.5 2.5 3.141592653589793 0.13
p 448 144 448 80 0
g 448 176 448 192 0
l 448 176 608 176 0 0.0032335 -15.21086141936489
R 352 224 288 224 1 2 120.0 2.5 2.5 0.0 0.42
x 176 232 255 238 0 24 Charge
x 148 311 256 317 0 24 Discharge
w 640 320 464 320 0
L 352 384 288 384 0 1 false 5.0 0.0
w 464 240 528 240 0
w 352 384 352 336 0
w 352 256 352 336 0
w 464 272 464 384 0
I 480 272 528 272 0 0.5
x 121 394 265 400 0 24 Switching EN
w 464 384 352 384 0
w 624 144 624 256 0
w 624 256 720 256 0
w 688 80 720 80 0
w 640 128 640 320 0
w 720 256 720 80 0
w 608 48 672 48 0
w 608 176 672 176 0
159 608 176 608 112 0 0.1 1.0E10
159 672 112 672 48 0 0.1 1.0E10
159 608 112 672 112 0 0.1 1.0E10
c 672 112 672 176 0 6.8E-5 85.31942656795593
c 608 48 608 112 0 6.8E-5 85.31942656795593
w 608 48 512 48 0
152 528 256 624 256 0 2 5.0
150 352 240 464 240 0 2 5.0
150 352 320 464 320 0 2 0.0
w 464 272 480 272 0
o 5 16 0 35 299.3155353253689 47.89048565205903 0 -1
o 13 16 0 35 5.0 9.765625E-5 0 -1
o 9 16 0 35 5.0 9.765625E-5 0 -1
o 0 16 0 35 299.3155353253689 23.945242826029514 1 -1
o 0 16 1 291 4789.048565205902 9.765625E-55 2 -1

This next example includes a load resistor connected directly in series with the tank circuit. Notice how the current waveforms change. and how the energy recovery is affected.

$ 1 4.9999999999999996E-6 13.097415321081861 31 5.0 50
v 272 192 272 64 0 1 60.0 177.0 0.0 0.0 0.5
T 336 96 432 160 0 0.1 1.0 3.7384976990607903 -5.391754900088215 0.9999
w 272 64 336 64 0
w 336 64 336 96 0
w 336 160 336 192 0
w 432 96 432 64 0
w 432 160 432 192 0
r 272 192 336 192 0 1.0
R 336 320 272 320 1 2 120.0 2.5 2.5 3.141592653589793 0.13
p 432 160 432 96 0
g 432 192 432 208 0
l 432 192 592 192 0 0.0032335 -5.391754900088115
R 336 240 272 240 1 2 120.0 2.5 2.5 0.0 0.42
x 160 248 239 254 0 24 Charge
x 132 327 240 333 0 24 Discharge
w 624 336 448 336 0
L 336 400 272 400 0 1 false 5.0 0.0
w 448 256 512 256 0
w 336 400 336 352 0
w 336 272 336 352 0
w 448 288 448 400 0
I 464 288 512 288 0 0.5
x 105 410 249 416 0 24 Switching EN
w 448 400 336 400 0
w 608 160 608 272 0
w 608 272 704 272 0
w 672 96 704 96 0
w 624 144 624 336 0
w 704 272 704 96 0
w 592 64 656 64 0
w 592 192 656 192 0
159 592 192 592 128 0 0.1 1.0E10
159 656 128 656 64 0 0.1 1.0E10
159 592 128 656 128 0 0.1 1.0E10
c 656 128 656 192 0 6.8E-5 33.30028999979963
c 592 64 592 128 0 6.8E-5 33.30028999979963
152 512 272 608 272 0 2 5.0
150 336 256 448 256 0 2 5.0
150 336 336 448 336 0 2 0.0
w 448 288 464 288 0
r 432 64 592 64 0 24.0
o 5 16 0 35 299.3155353253689 5.986310706507378 0 -1
o 12 16 0 35 5.0 9.765625E-5 0 -1
o 8 16 0 35 5.0 9.765625E-5 0 -1
o 0 16 0 35 299.3155353253689 11.972621413014757 1 -1
o 0 16 1 291 2394.524282602951 9.765625E-55 2 -1
o 40 64 1 35 1280.0 9.765625E-5 3 -1

Now, applyling the same load to the tank circuit through a tuned transformer, see how the currents change again.

$ 1 4.9999999999999996E-6 16.13108636308289 31 5.0 50
v 320 240 320 112 0 1 60.0 177.0 0.0 0.0 0.5
T 384 144 480 208 0 0.1 1.0 -14.75058551194672 15.046711170205125 0.9999
w 320 112 384 112 0
w 384 112 384 144 0
w 384 208 384 240 0
w 480 144 480 112 0
w 480 208 480 240 0
r 320 240 384 240 0 1.0
R 384 368 320 368 1 2 120.0 2.5 2.5 3.141592653589793 0.13
p 480 208 480 144 0
g 480 240 480 256 0
R 384 288 320 288 1 2 120.0 2.5 2.5 0.0 0.42
x 208 296 287 302 0 24 Charge
x 180 375 288 381 0 24 Discharge
w 672 384 496 384 0
L 384 448 320 448 0 1 false 5.0 0.0
w 496 304 560 304 0
w 384 448 384 400 0
w 384 320 384 400 0
w 496 336 496 448 0
I 512 336 560 336 0 0.5
x 153 458 297 464 0 24 Switching EN
w 496 448 384 448 0
w 656 208 656 320 0
w 656 320 752 320 0
w 720 144 752 144 0
w 672 192 672 384 0
w 752 320 752 144 0
w 640 112 704 112 0
w 640 240 704 240 0
159 640 240 640 176 0 0.1 1.0E10
159 704 176 704 112 0 0.1 1.0E10
159 640 176 704 176 0 0.1 1.0E10
c 704 176 704 240 0 6.8E-5 159.3874182125484
c 640 112 640 176 0 6.8E-5 159.38741821253723
152 560 320 656 320 0 2 0.0
150 384 304 496 304 0 2 0.0
150 384 384 496 384 0 2 5.0
w 496 336 512 336 0
r 720 16 720 80 0 24.0
T 640 16 720 80 0 0.0032335 1.0 -15.046711170205052 5.235301061927402 0.999
w 640 80 640 112 0
w 640 16 480 16 0
w 480 16 480 112 0
w 480 240 640 240 0
o 5 16 0 35 299.3155353253689 23.945242826029514 0 -1
o 11 16 0 35 5.0 9.765625E-5 0 -1
o 8 16 0 35 5.0 9.765625E-5 0 -1
o 0 16 0 35 299.3155353253689 47.89048565205903 1 -1
o 0 16 1 291 4789.048565205902 9.765625E-55 2 -1
o 39 64 1 35 2560.0 9.765625E-5 3 -1

Note that although the current waveforms look the same as before when no load was connected, the amplitude of the return spike is now half as tall as it was before.

Just more food for thought.

- Jason O

hartiberlin · « **Reply #158 on:** July 22, 2014, 05:01:19 PM »

Hi Barry , I think Babcock meant the Variac with it...
Maybe they are just not using anymore a Variac but a normal transformer at the input...

Also you can see in the free Serps video that they have 3 x2 wires going to their switching board ,
so they are using 3 Electronic switches to switch the caps.
A different configuration is not possible to get these negative current pulses back to the grid...

Regards , Stefan.
P.S. there is an additional open core transformer probably in Series with L1 or L2 to
Setup and tune to the 60 Hz resonance frequency by changing the inductance
by pulling out the coil a bit out of the core , so it works like a tuneable choke...

Jdo300 · « **Reply #159 on:** July 22, 2014, 05:07:30 PM »

Here's a simulation that combines Simulations 1 and 3 from the previous post to make the waveform comparisons easier. Simple switch the SPDT switch back and forth to compare performance.

$ 1 4.9999999999999996E-6 16.13108636308289 31 5.0 50
v 288 240 288 112 0 1 60.0 177.0 0.0 0.0 0.5
T 352 144 448 208 0 0.1 1.0 -11.027533271887975 13.73770587487674 0.9999
w 288 112 352 112 0
w 352 112 352 144 0
w 352 208 352 240 0
w 448 144 448 112 0
w 448 208 448 240 0
r 288 240 352 240 0 1.0
R 352 368 288 368 1 2 120.0 2.5 2.5 3.141592653589793 0.13
p 448 208 448 144 0
g 448 240 448 256 0
R 352 288 288 288 1 2 120.0 2.5 2.5 0.0 0.42
x 176 296 255 302 0 24 Charge
x 148 375 256 381 0 24 Discharge
w 640 384 464 384 0
L 352 448 288 448 0 1 false 5.0 0.0
w 464 304 528 304 0
w 352 448 352 400 0
w 352 320 352 400 0
w 464 336 464 448 0
I 480 336 528 336 0 0.5
x 121 458 265 464 0 24 Switching EN
w 464 448 352 448 0
w 624 208 624 320 0
w 624 320 720 320 0
w 688 144 720 144 0
w 640 192 640 384 0
w 720 320 720 144 0
w 608 112 672 112 0
w 608 240 672 240 0
159 608 240 608 176 0 0.1 1.0E10
159 672 176 672 112 0 0.1 1.0E10
159 608 176 672 176 0 0.1 1.0E10
c 672 176 672 240 0 6.8E-5 -162.95598681315968
c 608 112 608 176 0 6.8E-5 -162.9559868131597
152 528 320 624 320 0 2 5.0
150 352 304 464 304 0 2 5.0
150 352 384 464 384 0 2 0.0
w 464 336 480 336 0
r 688 16 688 80 0 24.0
T 608 16 688 80 0 0.0032335 1.0 1.7763568394002505E-14 -1.7763568394002505E-14 0.999
w 608 80 608 112 0
w 608 16 432 16 0
w 448 240 608 240 0
S 448 112 448 48 0 1 false 0
w 432 16 432 48 0
w 608 48 608 80 0
l 464 48 608 48 0 0.0032335 -13.737705874876742
o 5 16 0 35 598.6310706507378 47.89048565205903 0 -1
o 11 16 0 35 5.0 9.765625E-5 0 -1
o 8 16 0 35 5.0 9.765625E-5 0 -1
o 0 16 0 35 299.3155353253689 47.89048565205903 1 -1
o 0 16 1 291 4789.048565205902 9.765625E-55 2 -1
o 39 64 1 35 7.62939453125E-5 9.765625E-5 3 -1

Note that the circuit, waveform wise, treats a loaded transformer as an inductor with a voltage source in series. Hence the waveforms look the same as a normal inductor (reactive), but with reduced voltage due to reflected CEMF from the Load on the secondary. This can be reduced by reducing the coupling and allowing the tank circuit to build up more energy, or by changing the winding ratio, which has the same effect.

- Jason O

Jdo300 · « **Reply #160 on:** July 22, 2014, 05:30:21 PM »

Here's yet another method to accomplish AC energy recovery with series tank circuits. In this simulation, rather than doing series-parallel cap switching, you can also take a single capacitor and simply reverse the polarity of the leads every quarter cycle. The following simulation illustrates the idea with an unloaded tank circuit.

$ 1 4.9999999999999996E-6 13.654669808981877 40 5.0 50
v 384 256 384 128 0 1 60.0 177.0 0.0 0.0 0.5
T 448 160 544 224 0 0.1 1.0 -7.524329192899012 3.2365834539612788 0.9999
w 384 128 448 128 0
w 448 128 448 160 0
w 448 224 448 256 0
w 544 160 544 128 0
w 544 128 608 128 0
r 608 128 704 128 0 24.0
w 544 224 544 256 0
r 384 256 448 256 0 0.01
p 544 224 544 160 0
l 544 256 704 256 0 0.1 3.23658345396128
c 816 160 816 224 0 7.036199999999999E-5 95.90704570493776
159 704 256 768 256 0 0.1 1.0E10
159 768 128 704 128 0 0.1 1.0E10
159 704 160 768 160 0 0.1 1.0E10
159 768 224 704 224 0 0.1 1.0E10
w 704 224 704 256 0
w 704 160 704 128 0
w 768 128 816 128 0
w 816 128 816 160 0
w 768 256 816 256 0
w 816 256 816 224 0
w 768 224 800 160 0
w 768 160 800 224 0
w 800 224 816 224 0
w 800 160 816 160 0
w 736 112 736 80 0
w 736 80 864 80 0
w 736 272 736 336 0
w 640 336 736 336 0
w 736 336 864 336 0
w 864 336 864 80 0
w 736 208 736 192 0
w 736 176 736 192 0
w 736 192 672 192 0
w 672 192 672 400 0
w 608 128 608 80 0
w 704 128 704 80 0
s 608 80 704 80 0 0 false
w 480 352 496 352 0
150 368 400 480 400 0 2 0.0
150 368 320 480 320 0 2 5.0
152 544 336 640 336 0 2 5.0
w 480 464 368 464 0
x 137 474 281 480 0 24 Switching EN
I 496 352 544 352 0 0.5
w 480 352 480 464 0
w 368 336 368 416 0
w 368 464 368 416 0
w 480 320 544 320 0
L 368 464 304 464 0 1 false 5.0 0.0
x 164 391 272 397 0 24 Discharge
x 192 312 271 318 0 24 Charge
R 368 304 304 304 1 2 120.0 2.5 2.5 0.0 0.5
R 368 384 304 384 1 2 120.0 2.5 2.5 3.141592653589793 0.5
152 544 400 640 400 0 2 0.0
w 544 416 544 400 0
w 544 400 544 384 0
w 544 400 480 400 0
w 640 400 672 400 0
g 384 256 384 272 0
o 0 32 0 35 299.3155353253689 11.972621413014757 0 -1
o 0 32 1 291 1197.2621413014756 9.765625E-55 1 -1
o 12 32 0 34 149.65776766268445 5.986310706507378 2 -1
o 12 32 0 33 149.65776766268445 5.986310706507378 2 -1
o 7 32 1 35 7.62939453125E-5 9.765625E-5 3 -1

If you set the Enable input to low, this disables the switching network and you will see that the tuned tank circuit will begin to resonate like normal, while the source voltage and current go back in phase. But with the switching network activated, the energy in the circuit is always forced back into the source to keep the phase angle at 90 degrees. This can be accomplished with four bi-directional switches and two control signals.

- Jason

hartiberlin · « **Reply #161 on:** July 22, 2014, 05:37:00 PM »

Hi Jason,
Many thanks for the sims have to go to my PC later and reinstall Java to check these out.
Maybe you can also post screenshots of the scopeshots output for thode who dont get tge simulator to work ? Many thanks.
@Barry, they are using 4 electrolytic caps , so 2 pairs. Each pair is wired -++- so to get an unpolarized cap , so they can use AC with electrolytic caps...

Jdo300 · « **Reply #162 on:** July 22, 2014, 05:51:44 PM »

Hi Stefan,

Sure, I'll go back and add the screenshots for the previous posts.

Here's the previous simulation modified with a transformer. Remember that when using a transformer to couple the load, you can effectively make the look "look" as big or small as you like (impedance matching). The smaller the load looks to the circuit, the more reactive energy will be able to build up. This is a nice trick you can use to get more percent of the active power in reactive form. When you do this, the circuit is less affected by the presence of the load. as in the following situation.

$ 1 4.9999999999999996E-6 35.60246606707791 40 5.0 50
v 336 336 336 208 0 1 60.0 177.0 0.0 0.0 0.5
T 400 240 496 304 0 0.1 1.0 -7.415885983193569 3.6579084260104295 0.9999
w 336 208 400 208 0
w 400 208 400 240 0
w 400 304 400 336 0
w 496 240 496 208 0
w 496 208 560 208 0
r 752 64 752 128 0 24.0
w 496 304 496 336 0
r 336 336 400 336 0 0.01
p 496 304 496 240 0
l 576 128 656 128 0 0.1 -1.3867310077587525E-16
c 768 240 768 304 0 7.036199999999999E-5 89.31556694227751
159 656 336 720 336 0 0.1 1.0E10
159 720 208 656 208 0 0.1 1.0E10
159 656 240 720 240 0 0.1 1.0E10
159 720 304 656 304 0 0.1 1.0E10
w 656 304 656 336 0
w 656 240 656 208 0
w 720 208 768 208 0
w 768 208 768 240 0
w 720 336 768 336 0
w 768 336 768 304 0
w 720 304 752 240 0
w 720 240 752 304 0
w 752 304 768 304 0
w 752 240 768 240 0
w 688 192 688 160 0
w 688 160 816 160 0
w 688 352 688 416 0
w 592 416 688 416 0
w 688 416 816 416 0
w 816 416 816 160 0
w 688 288 688 272 0
w 688 256 688 272 0
w 688 272 624 272 0
w 624 272 624 480 0
w 560 208 560 192 0
w 656 208 656 128 0
w 432 432 448 432 0
150 320 480 432 480 0 2 5.0
150 320 400 432 400 0 2 0.0
152 496 416 592 416 0 2 0.0
w 432 544 320 544 0
x 89 554 233 560 0 24 Switching EN
I 448 432 496 432 0 0.5
w 432 432 432 544 0
w 320 416 320 496 0
w 320 544 320 496 0
w 432 400 496 400 0
L 320 544 256 544 0 1 false 5.0 0.0
x 116 471 224 477 0 24 Discharge
x 144 392 223 398 0 24 Charge
R 320 384 256 384 1 2 120.0 2.5 2.5 0.0 0.5
R 320 464 256 464 1 2 120.0 2.5 2.5 3.141592653589793 0.5
152 496 480 592 480 0 2 5.0
w 496 496 496 480 0
w 496 480 496 464 0
w 496 480 432 480 0
w 592 480 624 480 0
g 336 336 336 352 0
T 656 64 752 128 0 0.1 0.7 -3.657908426010432 1.3241671059262992 0.5
S 560 192 560 128 0 0 false 0
w 544 64 544 128 0
w 544 64 656 64 0
w 496 336 656 336 0
o 0 32 0 35 299.3155353253689 23.945242826029514 0 -1
o 0 32 1 291 2394.524282602951 9.765625E-55 1 -1
o 12 32 0 34 261.87124863169134 2.618712486316914 2 -1
o 12 32 0 33 130.93562431584567 5.237424972633828 2 -1
o 7 32 1 35 149.65776766268445 9.765625E-55 3 -1

Playing with the turns ratio and coupling coefficient are the keys here along with having the circuit properly tuned. Notice that the waveforms across the capacitor almost match identically with what was shown in the original SERPS video.

- Jason O

Jdo300 · « **Reply #163 on:** July 22, 2014, 06:09:24 PM »

One other note. In the presentation video, Jim Murray shows a screenshot of one of his early SERPS prototypes, and you can clearly see that there are only two, electrolytic, capacitors connected in the circuit. If they are connected back to back in order to handle the AC current, it's possible that he could have been switching only a single equivalent capacitor in his early units.

- Jason O

listener191 · « **Reply #164 on:** July 22, 2014, 07:11:49 PM »

Hi Stefan,

The variac is feeding the transformer, which sits behind the caps. The non saturatable inductor is to the right. The transformer provides a power source with a reasonably consistant inductive reactance. The line supply reactance will depend on what other devices are connected and the length of connecting cable to the substation/line transformer etc.

Three switches would give you ability to parallel/series two caps (non polarized made from two electrolytics back to back), which would work if you were charging and discharging in the same half cycle however, that is not what is shown in the presentation material. Slide 42 shows the energy captured in the positive half cycle being returned in the negative half cycle.

By the way I am a practical person, not a theorist.

As you don't know me, I have attached a couple of photos of my Dave Squires motor replication to demonstrate that I am a replicator.
I also know how to switch high voltage/inductive loads without damaging IGBTS, but not using Babcocks complicated switching.

Regards

Barry

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Author Topic: COP 20.00 (2000%) Times, Reactive Power Energy Source Generator, (Read 304788 times)

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