SeaMonkey you are wrong !

You can just use a 120 Volts AC producing 60 Hz sine wave oscillator battery driven or via a supercap, 
that outputs
1 Watts of output power ( and needs maybe only 2 Watts itsself)  into this SERPS Babcock Murray circuit and instead of the
lamps you use a feedback circuit back to the oscillator and get this thing thus to selfrun.

At COP=50 this should be no real problem...

Regards, Stefan.

Hi All,
The issue here really is hard to judge! . . I'm really looking forward to a sufficiently detailed picture of this device or is an exact circuit schematic and it really is!


Regards

In the new Babcock-Murray Serps circuit presented at the Bedini 2014 conference
the actual line input AC voltage is regular 60 Hz sine wave.

They did not publish this in the first left scopeshot, cause that would have given the
timing away...but the comparison of both scopeshots gives it away anyway, so that is why I wrote
it was an eye opener...

I think I know now, how it is working.
I pondered all day long now about it.

Imagine a sine 60 Hz wave input.
One cycle is 0 to 360 degrees.

It seems they just charge 2 caps in parallel via the lamps load from 30 to 90 degrees from the line voltage.
After this they electronically disconnect the 2 caps and put them in series
and at around 100 degrees , they discharge the 2 series caps back to the line voltage  versus the lamps again to about 160 degrees.
This way they have double the sine peak voltage to be able to discharge the 2 series caps and drive negative current back to the grid
through the lamps !

Then the same thing happens for the negative half wave of the sine wave.

At around 210 degrees the 2 caps are again switched in Parallel into the line voltage via the lamps in series and charged
until around 270 degrees up to the peak voltage of the 60 Hz sine wave.
Then at 280 degrees, the 2 caps are put in series and again discharged via the lamps back to the grid until around 340 degrees.
So again energy is returned to grid via the lamps as the load.

It is basically a very easy circuit, but you have to have the right timing and the right load impedance (lamp resistance in Ohm in this case),
so that the areas in the input power MATH trace above and
below the ground line are about equal.

So you minimize the real active input power and try to get the aparent input power
the same as the reactive input power. If you get it right, you will only have reactive input power
and almost no Real active input power. Thus a COP of about 50 as they have shown at the conference can be real !

Great circuit !

Regards, Stefan.

Problem I've never heard that putting cap to series/parallel can give OU, the energy state still the same because capacitance reduce when put in series...

That being said, Hector Perez (the guy with his rotoverter) claimed in special resonant configuration, that you can extract real power from the reactive one, playing with phase (usually three phase power) is the key.
According to him he reversed current in the battery through the inverter ("reverse" power factor correction).
The load and the inductor act "negative" but a lot of impedance matching is necessary.
In the "combine" PDF you can read that is when R is at current node it's powered by "radiant energy" full light with 1/10 of the input voltage...
This theory is worth what it worth...
Anyway I would like to see a schematic of that circuit before making my definitive opinion.

Here is a quick basic circuit diagramm.
The switches must be replaced by MOSFET switches with the right timing and
control circuits.
But this shows how 2 caps can be put in series or in parallel.

I still pondering, why they did use 2 lamps as the load.
Maybe they are also switching the 2 lamps once in series and
then in parallel to have a different load resistor and thus control the charge
and discharge current better to get about equal areas in the input power
MATH trace, so the Real Active input power is minimized and only reactive power
is drawn ( just oscillating power).

Regards, Stefan.

Stefan what do you mean by the circle with the X in it?  That normally symbolizes a multiplier.  Do you mean that to be an AC voltage source?

Anyway, charge shuttling / balancing circuits have been around for a long time for use in DC systems.  For AC the switches and drivers get more complicated.

I already knew the answer MarkE but just so there wouldn't be any argument about it here's top of the Google

In over three decades in the business I have never seen a circle with an X in it used for a light bulb.

In over three decades in the business I have never seen a circle with an X in it used for a light bulb.

Mark,


See:http://www.edrawsoft.com/electrical-symbols.php


This symbol for a lamp was and is still commonly used in the UK.

Hi All,

about half a year ago I saw this idea (shown below),
subjective judgments, I suppose it does not work! . .