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Author Topic: The Holographic Universe and Pi = 4 in Kinematics!  (Read 245865 times)

TinselKoala

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Re: The Holographic Universe and Pi = 4 in Kinematics!
« Reply #15 on: May 11, 2014, 09:12:11 PM »
I decided to take the first step.  If you oppose this change, then I will take the thread back and rename it to it's original title of "How to Achieve and Maintain Resonance in the QEG".

Thanks,

Gravock
I don't know why you want to name any thread about me, but if you sincerely want to know how to obtain resonance in a QEG device, it's easy... it must be, if Robitaille and his crew can do it with what they are using. If you want your electrical resonance to occur at a particular frequency you match your inductances and capacitances to give you the correct frequency. The power handling requirement will determine the size and windings of the heavy inductance, and you can then select capacitance to match, remembering to use _the right kind of caps_ not motor-start capacitors. If you then want to use resonant pumping, that is, you want to drive your electrical resonance by a mechanical input of power at the same frequency as the resonance, you design your stator pole pieces and rotor shunt and their clearances and drive system appropriately. I think any competent electromechanical engineer with some experience in extreme high voltage and rapidly rotating assemblies should be able to carry out the necessary calculations, and a competent machinist/model builder could put it together in a week and have it demonstrating full electromechanical resonance at the desired frequency, even in a cave (suitably equipped of course) in Northern Afghanistan.

So yes, I don't think you should use my initials in the title of this thread, unless you want to call attention to the fact that I seem to know what I'm talking about and many of the QEG people.... just don't.

ACG

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Re: The Holographic Universe and Pi = 4 in Kinematics!
« Reply #16 on: May 12, 2014, 08:37:03 AM »
Page 1 of N
Dibs on N passing 100 in 6 months time.

Correction:  Title 1 of N

Currently 3 of N

gravityblock

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Re: The Holographic Universe and Pi = 4 in Kinematics!
« Reply #17 on: May 12, 2014, 07:48:47 PM »
The charge field can be either right-handed or left-handed, or neutral as highlighted in the snapshot below, and as found in the below referenced publication.  What hand will the charge field acquire with a left-handed metamaterial (LHM), such as the Arlon Diclad 880?  In other words, will the LHM emit photons upside-up or upside-down?

Reference:  Three Problems Solved Mechanically: PARTIAL REFLECTION BY GLASS; THE RIGHT-HAND RULE; AND FEYNMAN'S SHRINK-AND-TURN METHOD

Gravock

gravityblock

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Re: The Holographic Universe and Pi = 4 in Kinematics!
« Reply #18 on: May 14, 2014, 05:34:55 PM »

gravityblock

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Re: The Holographic Universe and Pi = 4 in Kinematics!
« Reply #19 on: May 14, 2014, 06:03:05 PM »
Maxwell's Equations are also Unified Field Equations

This one reversal, as described in the snapshot below and as found in the above publication, explains most of the confusion that still exists.

Go to part 2 of Maxwell's lines of force, where it shows how Maxwell's vortices fail, how to correct them, and how to calculate the charge field straight from the Electrical Field.

Gravock

gravityblock

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gravityblock

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Re: The Holographic Universe and Pi = 4 in Kinematics!
« Reply #21 on: May 14, 2014, 07:55:08 PM »
The Extinction of Pi

On a slightly related note, Vi shows how Pi is misused (video).

Summary:  See snapshot below, of the above publication.

Gravock

gravityblock

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Re: The Holographic Universe and Pi = 4 in Kinematics!
« Reply #22 on: May 15, 2014, 04:01:24 AM »

MarkE

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Re: The Holographic Universe and Pi = 4 in Kinematics!
« Reply #23 on: May 15, 2014, 07:32:34 AM »
The Extinction of Pi

On a slightly related note, Vi shows how Pi is misused (video).

Summary:  See snapshot below, of the above publication.

Gravock
Any fourth grader with a compass, a thread, a tack, and a ruler can show that the ratio of circumference to diameter otherwise known as Pi is a lot closer to 22/7 than it is to 28/7.

gravityblock

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Re: The Holographic Universe and Pi = 4 in Kinematics!
« Reply #24 on: May 15, 2014, 05:41:14 PM »
Any fourth grader with a compass, a thread, a tack, and a ruler can show that the ratio of circumference to diameter otherwise known as Pi is a lot closer to 22/7 than it is to 28/7.

Yes, the above quote is true for static or abstract circles, but it is not true for orbits or real circles with motion and includes a time variable.  The arc of a cycloid is 8r, which pi is also replaced by 4, just as in the Manahattan metric.  In orbits and circles drawn out over time, you can't compare a velocity (the diameter) to an acceleration (the circumference) because you need more information.  Oddities such as this, which misses it by 27%,  is one of the many reasons why things don't work out in the real world like they do on paper.  Read and understand the article, then comment.  Condemnation before investigation is folly, which is the mentality of a fourth grader!

Gravock

verpies

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Re: The Holographic Universe and Pi = 4 in Kinematics!
« Reply #25 on: May 17, 2014, 01:35:47 PM »
Any fourth grader with a compass, a thread, a tack, and a ruler can show that the ratio of circumference to diameter otherwise known as Pi is a lot closer to 22/7 than it is to 28/7.
This is going to be fun!

I have analyzed Mathis' papers regarding the issue of π=4 in kinematic situations and could not find an error in it.
π still equals to 3.14... in static geometry done by 4th graders, that does not involve motion

These two situations are clearly different and should not be conflated.

Take a look at the kinematic scenario depicted in the attached AVR1.pdf
Which answer do you think is correct?: Diag.3 or Diag.4 or Diag.5

@Gravityblock
Mathis appears to be a great free thinker.
I think what MarkE is trying to demonstrate is that if Mathis is wrong about such basic issue as Π then he cannot be trusted with his other conclusions (such as his B-Photons of the charge field, evanescent waves, nuclear structure, etc...).

MarkE

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Re: The Holographic Universe and Pi = 4 in Kinematics!
« Reply #26 on: May 17, 2014, 01:54:34 PM »
Yes, the above quote is true for static or abstract circles, but it is not true for orbits or real circles with motion and includes a time variable.  The arc of a cycloid is 8r, which pi is also replaced by 4, just as in the Manahattan metric.  In orbits and circles drawn out over time, you can't compare a velocity (the diameter) to an acceleration (the circumference) because you need more information.  Oddities such as this, which misses it by 27%,  is one of the many reasons why things don't work out in the real world like they do on paper.  Read and understand the article, then comment.  Condemnation before investigation is folly, which is the mentality of a fourth grader!

Gravock
Pi staunchly refuses to change even for very small or very large values of pi.  Using the wrong named constant in a problem and then declaring that the named constant's value has changed because that constant's value does not fit the problem belies a misunderstanding of what the word "constant" means.

verpies

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Re: The Holographic Universe and Pi = 4 in Kinematics!
« Reply #27 on: May 17, 2014, 02:39:47 PM »
Using the wrong named constant in a problem and then declaring that the named constant's value has changed because that constant's value does not fit the problem belies a misunderstanding of what the word "constant" means.
Are you saying that uniform circular motion is a worse measure of a circle than a piece of string?

What is your name for the following ratio?:
tC / tD

Where:
tC = Time period of one revolution in uniform circular motion.
tD = Time period necessary to travel the diameter by a constant velocity equal in magnitude to the tangent velocity of the uniform circular motion.

MarkE

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Re: The Holographic Universe and Pi = 4 in Kinematics!
« Reply #28 on: May 17, 2014, 03:29:19 PM »
Are you saying that uniform circular motion is a worse measure of a circle than a piece of string?

What is the name of the following ratio in your book?:
tC / tD

Where:
tC = Period of one revolution in uniform circular motion.
tD = Period necessary to travel the diameter by a constant velocity equal in magnitude to the tangent velocity of the uniform circular motion.
Pi is a symbol for the ratio of circumference to diameter of a perfect circle.  That ratio is a constant value.  If a ratio between two quantities is a different value then one or both are not proportional to the circumference and diameter of the same perfect circle. 

If one travels at a constant speed then the time taken to follow one path versus another is the ratio of the lengths of the paths. 


verpies

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Re: The Holographic Universe and Pi = 4 in Kinematics!
« Reply #29 on: May 17, 2014, 04:13:11 PM »
Pi is a symbol for the ratio of circumference to diameter of a perfect circle. 
...but what is a perfect circle?  Is it formed non-physically / abstractly on paper, or physically by inertia of a moving mass and some quasi-centripetal force?
These two circles are not equivalent. ...but both have circumferences and diameters that are measured differently and analyzed differently by math since the former does not contain a time variable and the latter does.

If one travels at a constant speed then the time taken to follow one path versus another is the ratio of the lengths of the paths.
Agreed.  But when you measure the circumference of a perfect circle with constant tangential velocity of a moving mass and its diameter with the constant velocity of equal magnitude then you are dealing with a physical circle and the two lengths of these two different physical paths obtained by this method, refer to that physical circle  ...and the ratio of these two lengths is 4.

When you measure a non-physical circle (e.g. abstract circle on paper) then the ratio of its circumference to diameter is 3.1415...
If you limit your definition of Π as the ratio of circumference to diameter in abstract circles only, then you are only correct.