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Solid States Devices => solid state devices => Topic started by: Skysabre on April 29, 2014, 09:20:11 AM
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Hi Friends,
Here's a pdf file on the Don Smith Generator. Please look this over and tell me if this is worth trying or I should move elsewhere. This is more expensive than the Hendershot Generator which unfortunately does not work, despite the circuit variations that we tried. So I'd like to now if I should spend on this or not.
This manual is so poorly organized it gets me confused, or maybe because I have no background in electronics. Maybe along the way, if we decide to do this, the more knowledgeable among you can also teach me a few things.
So first things first: Is this worth a try? If not, I have another project in mind.
Skysabre
(Admin: I had to take the PDF File down due to a copyright claim...)
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Hi Skysabre,
I went through the pdf file you altruistically uploaded. I am strongly "amazed" by seeing the wiring diagram shown in pdf Page 27: they use voltage divider resistors to match the alleged 8kV output voltage (stored in the 2uF capacitor) to the input of an off-the-shelf 12V or 24V DC to 110V AC power inverter. Using resistors for dividing voltages makes sense when reasonably small currents are involved because of the unavoidable heat loss in the resistors.
Let's do some simple calculations backwards, let's choose a power inverter which is able to output just 2kW at 110V AC, ok? Then let's have its own efficiency, say, 90%, so the input DC power to it should be 1.1 x 2kW=2.2kW i.e. 10% higher.
Now if this inverter receives 24V DC input (let's say), then the input DC current demand is about I=2.2kW/24V=91.6A.
Now lets calculate the resistor values for dividing the 8kV DC to 24V. Here is a link I used, it also calculates the power loss in the two resistors: http://www.bowdenshobbycircuits.info/r2.htm
Using the example described in the text for finding the series resistance needed for a LED as a sample, I entered for battery voltage 8000, for current 91.6 and for Vout 24, I got 87 Ohm for R1 (and R2 would be represented by the 24V input of the inverter) but with this value the dissipated power in R1 would amount to 730.6kW.... the idea to use resistors to drop the 8000V to 24V is ABSURD, INSANE to say the least. And there is no any other suggestion to reduce the 8kV (or whatever kV coming from the LC tank via the diodes to the 2uF storage capacitor) to 24V or 12V.
The other thing is that while it may be possible to store a few kW power in a resonant LC tank circuit (it would need a coil and a capacitor with extremely low loss i.e. very high Q) but when directly loading such high Q resonant circuit, the circulating power in it would get reduced just because the external load reduces the high Q (the resonant AC impedance of such a high Q LC tank may range from several ten to several hundred kOhm and shunting it say with the 87 Ohm resistor via the inverter input, the high AC impedance gets killed, so the kV voltage reduces accordingly, there is no 'juice' left in the tank to feed the inverter. AND there is no any high wattage resistor shown in the pictures, which would imply they really used them to reduce the kV output...
Now no wonder why this pdf file contains NO any measurement results done by those 'compiling' it. It is a "pathwork", a "botch", taken text and pictures from some sources, and sorry to say I consider it as a hoax.
At other forums and also here, several members attempted to replicate Don Smith setups but nobody succeeded so far (or did not report, that is) and even Don Smith never showed any working device, only talked about the kW output and showed the assembled boards with those components like in the pictures in the pdf file.
Regardless of Don Smith or from this pdf file, the problem to be solved would be to find a circuit topology which does not reduce an LC tank resonant impedance too much and dissipates only a reasonable amount of power while dividing the kVs to a lower more workable value. This would be challange circuit to design and build for sure, still strongly assuming that the input power to the LC tank could be kept at a lower value than that of the output power received from THE circuit.
Gyula
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Thank you Gyulasun!
You saved me a lot of trouble and expense. So I'm moving on to other possibilities, and maybe i can ask you: do you know of any possibilities I can work on? Name a website or any lead, and I'll look it over.
I just want to help this planet, and I have a bit of time in my hands.
Skysabre
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Hi Skysabre,
I don't know if you saw my comment on your thread, "Has anyone replicated the hendershot generator".
www.free-energy-devices.com is a good site. It also has a good Electronics tutorial - Chapter 12.
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Hi Skysabre,
Well, it is not easy to answer your question... I think if you take a thorough look and reading at this link below, especially member 'erfinder' posts and videos, then possibly you would be on a good track:
http://www.energyscienceforum.com/showthread.php?t=1611 (http://www.energyscienceforum.com/showthread.php?t=1611)
The thread started with a question on Bedini DVD Nr 25 but No need to buy the DVD as you later realize because the topic turns to a pulse motor-like setup as erfinder shows. It does need a hands on building and experience, maybe not the best for the not so experienced but I believe the progress for anyone is given and open. Just read it all over and decide, unfortunately the uploaded pictures can only be seen when you become a member there and log in. (notice that erfinder does not claim anything)
Unfortunately, I am not aware of ANY thread where a real device, capable of giving extra output over the input is shown with real measurements. Speculations, fakes, hoaxes rule... or greedyness to share.
There was the Bedini Ferris Wheel demo at their conference some years ago, see here http://www.energeticforum.com/john-bedini/6786-bedini-ferris-wheel-regauging-motor.html (http://www.energeticforum.com/john-bedini/6786-bedini-ferris-wheel-regauging-motor.html) but I do not know that those who rebuilt it whether got extra output or not.
I would also suggest to study Ben's motor here http://www.overunity.com/14377/the-thomas-motor/msg391150/#msg391150 (http://www.overunity.com/14377/the-thomas-motor/msg391150/#msg391150)
it may give good results (the possibilities are inherent in that setup I think) and Ben is still working on it.
Good luck,
Gyula
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So first things first: Is this worth a try?
Skysabre
Maybe worth, maybe not, that is another model?
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Skysabre,
If you find a system like this Don Smith system that you build and find it is OU
and you are willing to produce the input/output power table for that is a least
1500Watts in excess OU or more maximum. I would be willing to trade a balance
of system design for that design information and link it to a either household
inverter front-end or a portable generator type front end. For example an 8KVDC
at 20amp (measured) continuous output power supply rating linked to an
inverter would be no problem.
You will never find the complete balance of system design for a system that
requires any kind of complex controls. The best you could find in that case
would be to build a start/stop control with constant power production capability
or stop and a large and expensive battery bank capacity.
Keep this offer (by agreement only) in mind and you will see.
:S:MarkSCoffman
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Hi Skysabre,
I went through the pdf file you altruistically uploaded. I am strongly "amazed" by seeing the wiring diagram shown in pdf Page 27: they use voltage divider resistors to match the alleged 8kV output voltage (stored in the 2uF capacitor) to the input of an off-the-shelf 12V or 24V DC to 110V AC power inverter. Using resistors for dividing voltages makes sense when reasonably small currents are involved because of the unavoidable heat loss in the resistors.
Let's do some simple calculations backwards, let's choose a power inverter which is able to output just 2kW at 110V AC, ok? Then let's have its own efficiency, say, 90%, so the input DC power to it should be 1.1 x 2kW=2.2kW i.e. 10% higher.
Now if this inverter receives 24V DC input (let's say), then the input DC current demand is about I=2.2kW/24V=91.6A.
Now lets calculate the resistor values for dividing the 8kV DC to 24V. Here is a link I used, it also calculates the power loss in the two resistors: http://www.bowdenshobbycircuits.info/r2.htm
Using the example described in the text for finding the series resistance needed for a LED as a sample, I entered for battery voltage 8000, for current 91.6 and for Vout 24, I got 87 Ohm for R1 (and R2 would be represented by the 24V input of the inverter) but with this value the dissipated power in R1 would amount to 730.6kW.... the idea to use resistors to drop the 8000V to 24V is ABSURD, INSANE to say the least. And there is no any other suggestion to reduce the 8kV (or whatever kV coming from the LC tank via the diodes to the 2uF storage capacitor) to 24V or 12V.
The other thing is that while it may be possible to store a few kW power in a resonant LC tank circuit (it would need a coil and a capacitor with extremely low loss i.e. very high Q) but when directly loading such high Q resonant circuit, the circulating power in it would get reduced just because the external load reduces the high Q (the resonant AC impedance of such a high Q LC tank may range from several ten to several hundred kOhm and shunting it say with the 87 Ohm resistor via the inverter input, the high AC impedance gets killed, so the kV voltage reduces accordingly, there is no 'juice' left in the tank to feed the inverter. AND there is no any high wattage resistor shown in the pictures, which would imply they really used them to reduce the kV output...
Now no wonder why this pdf file contains NO any measurement results done by those 'compiling' it. It is a "pathwork", a "botch", taken text and pictures from some sources, and sorry to say I consider it as a hoax.
At other forums and also here, several members attempted to replicate Don Smith setups but nobody succeeded so far (or did not report, that is) and even Don Smith never showed any working device, only talked about the kW output and showed the assembled boards with those components like in the pictures in the pdf file.
Regardless of Don Smith or from this pdf file, the problem to be solved would be to find a circuit topology which does not reduce an LC tank resonant impedance too much and dissipates only a reasonable amount of power while dividing the kVs to a lower more workable value. This would be challange circuit to design and build for sure, still strongly assuming that the input power to the LC tank could be kept at a lower value than that of the output power received from THE circuit.
Gyula
Gyula and others
I already made a lot of experiments and i have learn a lot of things around this stuff. But even with the most well designed secondary, i still cant see any OU results. I fooled my self many times as i wanted to believe it, but things are not so good like in the way it presented to be. Perhaps there are other secrets here like NMR as elementsix told us. Or perhaps there is something else which i cant recognize it.
Can someone help to find the NMR freq of copper in combination with the local magnetic field? As i remember gold's nmr frequency under earths magnetic field is very low... 30-36Hz!!! Perhaps element six can define his statement to help us a little more. I dont know how low freqs like that can help.
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Hi Jeg,
I am not an expert on NMR, unfortunately and I recommend to turn to member verpies in a Personal Message if you like, he is an expert on it. of course element six may also help.
Gyula
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Hi Jeg,
I am not an expert on NMR, unfortunately and I recommend to turn to member verpies in a Personal Message if you like, he is an expert on it. of course element six may also help.
Gyula
Thanks a lot Gyula
Even it looks unlikely to me, i should try it.
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Rather than start a new thread, I'm placing a new site and possible project here for looking into.
http://teslasforsustainablesociety.wordpress.com/2012/11/04/canadians-electrical-generator/
I find the last part by Silverhealtheu possible doable by a beginner, but my question is how do we make a drive circuit that can strongly pulse the Drive Coil?
This looks logical from where I sit, but then I'm just a dummy in your ranks.
Please just point me in the right direction and I'll move!
Skysabre
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Hi Skysabre,
This is a pulse generator based on the NE555 timer, with variable frequency and duty cycle control
http://www.free-energy-info.co.uk/Ch10/Fig63.gif (http://www.free-energy-info.co.uk/Ch10/Fig63.gif)
and this is a possible MOSFET switch (driven from the output of the above circuit) to pulse the drive coil (you connect the coil as the load is indicated, the coil will be the load between the Drain pin and the + supply):
http://www.free-energy-info.co.uk/Ch10/Fig65.gif (http://www.free-energy-info.co.uk/Ch10/Fig65.gif)
Use less than 12V supply first to drive the coil and experiment with varying the frequency and duty cycle of the timer while monitoring the output (pickup) coils. Use a full wave bridge and a puffer capacitor at the ouput of the pickups and a load resistor of say any value between 33 - 100 Ohm. A DC voltmeter across it would nicely monitor your efforts with the tuning pots.
(This is where the schematics are: http://www.free-energy-info.co.uk/Chapt10.html (http://www.free-energy-info.co.uk/Chapt10.html) )
Can you now move? 8)
Gyula
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Hi Skysabre,
This is a pulse generator based on the NE555 timer, with variable frequency and duty cycle control
http://www.free-energy-info.co.uk/Ch10/Fig63.gif (http://www.free-energy-info.co.uk/Ch10/Fig63.gif)
and this is a possible MOSFET switch (driven from the output of the above circuit) to pulse the drive coil (you connect the coil as the load is indicated, the coil will be the load between the Drain pin and the + supply):
http://www.free-energy-info.co.uk/Ch10/Fig65.gif (http://www.free-energy-info.co.uk/Ch10/Fig65.gif)
Use less than 12V supply first to drive the coil and experiment with varying the frequency and duty cycle of the timer while monitoring the output (pickup) coils. Use a full wave bridge and a puffer capacitor at the ouput of the pickups and a load resistor of say any value between 33 - 100 Ohm. A DC voltmeter across it would nicely monitor your efforts with the tuning pots.
(This is where the schematics are: http://www.free-energy-info.co.uk/Chapt10.html (http://www.free-energy-info.co.uk/Chapt10.html) )
Can you now move? 8)
Gyula
I've told him about that website a couple of times already and also that it has a good electronics tutorial in Chapter 12, and he just won't listen for some reason!!
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Thanks, friends!
I'll work on this. Buying some of the 555 and condensers, and the steel bar today. I'm ordering the neodymium magnets from Amazon, having a relative bring it here by end-May.
What wire size do I use? I have some 28 ga. here. Will compute length to get 1.2 ohms hopefully to run 10 A to produce 120W on 12 VDC. Are these parameters okay? or do I go smaller? You will know better.
I'll post a new thread when I start. Thankfully, I see nothing in here that will kill me. :D
Skyabre
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Hi Skysabre,
My opinion on the steel bar is that you had better use ferrite rod instead because a 1" OD solid steel bar will surely have strong eddy current losses even at 20-30Hz switching frequency (I do not understand why steel bar was proposed at all). So try to obtain ferrite rods or laminated "I" cores lined up in 1 foot or so length (I do not think the length is so critical). Here is a link to ferrite rods (sold only within USA though) but on ebay you can buy also (but not as big size as this one):
http://www.stormwise.com/page26.htm (http://www.stormwise.com/page26.htm) and choose the permeability, u=2000 type.
On the awg 28 wire size: I find it a bit small OD for 10 Amper, but may be good for a start, once you already have it.
By the way if you start studying some electronics, I offer to look up series RL circuits (i.e. when a coil is connected in series with a resistor) because then you learn that in pulsed (or in AC) circuits the DC resistance, R of a coil is only part of the total impedance, Z, of a coil and the L inductance of the coil you are going to wind will also influence the current in the function of the switching frequency. So the higher you go up in switching frequency, the higher the coil resultant impedance will be, with decreasing current consumption from the same 12V source in the same circuit setup.
By the way, I would not target for 10 Amper, but much less to explore the behaviour and the output power. The 10 A will toast your coil in a very short time if you really let it flow. The starting consideration for such coils is AmperTurns i.e. the number of turns for the coil multiplied by the current. You get the same excitation when you use 10A for say a 40 turns coil or you use 1A for a 400 turns coil. And at what supply voltage would 1A current flow in a 400 turns coil depends mainly on its impedance (R+XL) at a given frequency and you then have to choose the supply voltage too. And the AmperTurns needed will mainly depend of the strength of the magnets.
The switching FET, BUZ350 has a 200V drain source breakdown voltage, perhaps just perhaps just enough not burn from the coil back spikes created at every switch-off event. Here is its data sheet:
http://pdf.datasheetcatalog.com/datasheet/siemens/BUZ350.pdf (http://pdf.datasheetcatalog.com/datasheet/siemens/BUZ350.pdf) the problem with this type is that it has become obsolote.
I suggest using at least 300V (or higher) drain source voltage devices instead, like
http://www.digikey.com/product-detail/en/STP46NF30/497-13442-ND/3770035 (http://www.digikey.com/product-detail/en/STP46NF30/497-13442-ND/3770035)
http://www.digikey.com/product-detail/en/IXTP36N30P/IXTP36N30P-ND/1995085 (http://www.digikey.com/product-detail/en/IXTP36N30P/IXTP36N30P-ND/1995085) or 400V devices like
http://www.digikey.com/product-detail/en/FDP24N40/FDP24N40-ND/1814539 (http://www.digikey.com/product-detail/en/FDP24N40/FDP24N40-ND/1814539) or
http://www.digikey.com/product-detail/en/SIHG25N40D-E3/SIHG25N40D-E3-ND/3458163 (http://www.digikey.com/product-detail/en/SIHG25N40D-E3/SIHG25N40D-E3-ND/3458163)
Of course there are other choices from other sellers too.
Good luck.
Gyula
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Wow, Man!
I'm glad I asked!!!...and I will ask more questions if you don't mind.
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The schematic is somewhat unusual, I really didn't understand what he meant, but then what he is probably doing is
synchronizing with the power supply with the switch and disconnecting the coil right when the maximum peak AC voltage is occuring.
Sometimes when you plug or unplug an appliance if the phase is just right you get a very large arc/spark inside the socket. If he did this
repeatedly and reconnected the battery connection immediately he may have enougth power to do something. That would gibe with
having large amounts of RFI radio frequency interference. Most circuits want to switch at zero crossing - this one wants
to switch at maximum voltage. If you use the zero crossing detector and add a fixed time delay you would constantly
be switching at the peak AC voltage. Both the AC disconnect switch and battery connection switch would need to be FETs
though the AC part could be an SCR.
You have to realize you are only looking for 1500W continious production. This is only one tenth the minimum size of his unit,
which should easily be doable. He should really have two big AH capacity batteries, we'll call them reaction batteries that
energy is produced in then extra energy will be removed and stored in a seperate bank for long term use. There is a maximum
charge and discharge rate for batteries he's probably exceeding that terribly, so for him the picture seems quite unreliable.
:S:MarkSCoffman
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Can someone explain why the spark gap is in series with LC?
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Hi Neo-X,
Strictly technically speaking, the spark gap you ask as shown can fire whenever the (positive) AC peak output voltage from the Neon tube driver exceeds the breakdown voltage of the spark gap. In these events the output current available from the Neon tube driver is limited by its own inner impedance and the parallel L1C tank is pulsed by every second half wave via the spark gap. (I mention the positive peak vs the ground because the output diodes polarity defines that.)
IF you look at the pdf file in Page 27 (what Skysabre uploaded in his first post), there is a second circuit diagram below the one you refer to where a Neon sign transformer, NST drives a 0.2uF 4000V capacitor. The AC output from the NST continuously charges up this capacitor alternately to a positive and to a negative peak value and whenever the voltage (either positive or negative, does not matter) in this capacitor reaches the breakdown of the spark gap, the capacitor discharges to the primary coil labeled as L1. In this case the output current is limited mainly by the ESR (equivalent series resistance) of the 0.2uF capacitor which shunts the output impedance of the NST. Of course an ESR can be much less than the output impedance of the NST so any effect and any output expected by the breakdown of the spark gap can be higher than in the case of the schematic you asked.
Tesla also used charged up capacitors to discharge them via a spark gap because as he explained the amount of the energy taken out from the capacitor could be controlled: the quicker the discharge time is, the more work can be done from the same amount of stored energy. Tesla did not show circuits where he used the output of a HV generator to fire a spark gap, he charged up a capacitor by a HV generator first and then he discharged the capacitor via a spark gap to utilize its stored energy.
One could speculate that kicking an LC tank (like in the schematic you asked) by half wave peak current is not neccessarily a drawback because the kicked LC tank may 'supply' the other half wave, this can only be answered by tests how efficient this can be vs the second circuit where the spark gap fires twice due to the full wave peak current available from the capacitor for exciting the primary coil. (To be compared energy-wise: kicking an LC tank once within a full AC wave or kicking a primary (i.e. a coupling) coil of an LC tank twice within a full AC wave, the conditions for kicking are not identical mainly due to the differing inner impedances of the HV sources in the two cases, impedance matching is lacking in the first case) I think the second method i.e. discharging the HV capacitor can give higher overall efficiency than the method shown with your question.
Of course I do not know what Don Smith or the 'assemblers' of the PDF file thought originally on the different methods of positioning the spark gap... ::)
Gyula
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Can someone explain why the spark gap is in series with LC?
hi,
I am also working on the Don smith device at the same time with the 3volt ou circuit.
My recent findings base on Don smith replication done in China and one of the Don smith video revealed that it is configured for RF and not the typical induction heater coil which many was lead to believe.
Recently i obtained the fast recovery diodes 1200v 26ns 6Amps TO-220 - "HFA06TB120" which is connected 6 in series to form hv diode.For experiment purpose i merely got 12 diodes.
I am able to see spark appear within the spark gap.I am using 12volts to 220volts inverter for safety reasons to power the 10KV 30ma 30khz NST at 18watt battery power drawn.The NST tuned at around 4kv(Variable version on NST)
I would need to get more diodes for the secondary coils.At least 24 diodes is needed in total.I think 10 in series to form the hv diode is the best so total should be 40 diodes.
---------------------------------------------
There is another successful experiment in China based on another variation of Don smith device but without using spark gap instead it is running at around 220khz...230khz.
Details are provided in the pjkbook.pdf 2014 edition Page 260.The link to forum in China is provided in there.Isolated IGBT driver stage is provided in there which i am using for the electronic simulator.
I have recently created the isolated 6 1200volts IGBT in series in multisim before i even proceed to consider to actually create the 12volt to step up around 300volts.Then boosted using MC34063
which is connected to IGBT 1200volts likely 2 connected in series which provides variable voltage from 500volts to 1600volts.
(Video is attached)
At this moment the capacitor is not the suitable one used in multisim since it is hand made base on video for the high Q capacitor 2000....5000 which can handle <10KV using Teflon as separator.
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Hi Neo-X,
Strictly technically speaking, the spark gap you ask as shown can fire whenever the (positive) AC peak output voltage from the Neon tube driver exceeds the breakdown voltage of the spark gap. In these events the output current available from the Neon tube driver is limited by its own inner impedance and the parallel L1C tank is pulsed by every second half wave via the spark gap. (I mention the positive peak vs the ground because the output diodes polarity defines that.)
IF you look at the pdf file in Page 27 (what Skysabre uploaded in his first post), there is a second circuit diagram below the one you refer to where a Neon sign transformer, NST drives a 0.2uF 4000V capacitor. The AC output from the NST continuously charges up this capacitor alternately to a positive and to a negative peak value and whenever the voltage (either positive or negative, does not matter) in this capacitor reaches the breakdown of the spark gap, the capacitor discharges to the primary coil labeled as L1. In this case the output current is limited mainly by the ESR (equivalent series resistance) of the 0.2uF capacitor which shunts the output impedance of the NST. Of course an ESR can be much less than the output impedance of the NST so any effect and any output expected by the breakdown of the spark gap can be higher than in the case of the schematic you asked.
Tesla also used charged up capacitors to discharge them via a spark gap because as he explained the amount of the energy taken out from the capacitor could be controlled: the quicker the discharge time is, the more work can be done from the same amount of stored energy. Tesla did not show circuits where he used the output of a HV generator to fire a spark gap, he charged up a capacitor by a HV generator first and then he discharged the capacitor via a spark gap to utilize its stored energy.
One could speculate that kicking an LC tank (like in the schematic you asked) by half wave peak current is not neccessarily a drawback because the kicked LC tank may 'supply' the other half wave, this can only be answered by tests how efficient this can be vs the second circuit where the spark gap fires twice due to the full wave peak current available from the capacitor for exciting the primary coil. (To be compared energy-wise: kicking an LC tank once within a full AC wave or kicking a primary (i.e. a coupling) coil of an LC tank twice within a full AC wave, the conditions for kicking are not identical mainly due to the differing inner impedances of the HV sources in the two cases, impedance matching is lacking in the first case) I think the second method i.e. discharging the HV capacitor can give higher overall efficiency than the method shown with your question.
Of course I do not know what Don Smith or the 'assemblers' of the PDF file thought originally on the different methods of positioning the spark gap... ::)
Gyula
Thank you for the explanation now i understand why it has spark gap there. ;D
I think the circuit in the picture i post or don smith circuit is more efficient than the classical tesla coil. There is a loss of power when current flows in a spark gap. In classical tesla coil the current oscillate most of the time in spark gap but in don smith circuit the current oscillate in closed circuit and the supply current flow in spark gap is in very short period of time only. Its like a class C amplifier with spark gap in series with LC tank.
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Neo-X and Gyula, the circuit Neo posted in reply #17 was in fact tried by at least one competent experimenter participating in the thread at EF, he found as I did that the arrangement with the spark gap between the tank and the NST did not work very well, the power in the tank and the output was very poor, much less than if the capacitor is charged and the spark gap is placed so as to discharge the capacitor through the L1 coil. Worth anther try though.
Anyway I found a very interesting section of video from the display by Don at the 1996 Tesla Symposium, if you go to 4:30 minutes in the video you can see a guy in a hat asks some questions and ends up getting a thinly veiled threat from Don. The things Don says do not really make much sense, he unplugs the light board saying that the lights burn out quick ::) in the preceding video's he says and does things that make me suspicious. https://www.youtube.com/watch?v=OHsEoFszeEw
Don also said clearly that NST's were Over Unity "off the shelf", but of course they are not, and his coil setup in the device drawing in reply #17 closely resembles an NST but air cored and tuned.
..
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Hi Skysabre,
I went through the pdf file you altruistically uploaded. I am strongly "amazed" by seeing the wiring diagram shown in pdf Page 27: they use voltage divider resistors to match the alleged 8kV output voltage (stored in the 2uF capacitor) to the input of an off-the-shelf 12V or 24V DC to 110V AC power inverter. Using resistors for dividing voltages makes sense when reasonably small currents are involved because of the unavoidable heat loss in the resistors.
Let's do some simple calculations backwards, let's choose a power inverter which is able to output just 2kW at 110V AC, ok? Then let's have its own efficiency, say, 90%, so the input DC power to it should be 1.1 x 2kW=2.2kW i.e. 10% higher.
Now if this inverter receives 24V DC input (let's say), then the input DC current demand is about I=2.2kW/24V=91.6A.
Now lets calculate the resistor values for dividing the 8kV DC to 24V. Here is a link I used, it also calculates the power loss in the two resistors: http://www.bowdenshobbycircuits.info/r2.htm
Using the example described in the text for finding the series resistance needed for a LED as a sample, I entered for battery voltage 8000, for current 91.6 and for Vout 24, I got 87 Ohm for R1 (and R2 would be represented by the 24V input of the inverter) but with this value the dissipated power in R1 would amount to 730.6kW.... the idea to use resistors to drop the 8000V to 24V is ABSURD, INSANE to say the least. And there is no any other suggestion to reduce the 8kV (or whatever kV coming from the LC tank via the diodes to the 2uF storage capacitor) to 24V or 12V.
The other thing is that while it may be possible to store a few kW power in a resonant LC tank circuit (it would need a coil and a capacitor with extremely low loss i.e. very high Q) but when directly loading such high Q resonant circuit, the circulating power in it would get reduced just because the external load reduces the high Q (the resonant AC impedance of such a high Q LC tank may range from several ten to several hundred kOhm and shunting it say with the 87 Ohm resistor via the inverter input, the high AC impedance gets killed, so the kV voltage reduces accordingly, there is no 'juice' left in the tank to feed the inverter. AND there is no any high wattage resistor shown in the pictures, which would imply they really used them to reduce the kV output...
Now no wonder why this pdf file contains NO any measurement results done by those 'compiling' it. It is a "pathwork", a "botch", taken text and pictures from some sources, and sorry to say I consider it as a hoax.
At other forums and also here, several members attempted to replicate Don Smith setups but nobody succeeded so far (or did not report, that is) and even Don Smith never showed any working device, only talked about the kW output and showed the assembled boards with those components like in the pictures in the pdf file.
Regardless of Don Smith or from this pdf file, the problem to be solved would be to find a circuit topology which does not reduce an LC tank resonant impedance too much and dissipates only a reasonable amount of power while dividing the kVs to a lower more workable value. This would be challange circuit to design and build for sure, still strongly assuming that the input power to the LC tank could be kept at a lower value than that of the output power received from THE circuit.
Gyula
the resistors work nothing like you calculate. The voltage presented in this system is cold electricity and if you know anything about cold electricity, the resistance is needed to convert the energy from cold energy to conventional electricity.. The cold electricity, which is basically invisible and non measurable becomes measurable after this conversion,. and, it will do nothing unless it is put through the proper sized resistors. Cold electricity works oppositely with resistances, as Karl palsness has pointed out long ago, the energy out of a high resistance is more power, and it releases no heat as conventional "amperage driven electricity". Since there is no amperage until after this conversion, there is no wattage and no way to burn the resistors. If you use some logic, you will notice that this device is a replica of Tesla's phase conjugate mirror generator, which pumps energy into the ground and returns it as many mirrors of the energy put in, through the ground as a one wire system. If you punched a ground rod into the ground and soldered on an avramenko plug after the energy was continuously pumped into the ground, the ground rod with the two diodes on the other end would read a voltage across each diode to the output side of the resistor. If you connected this before the resistor, youd either get nothing, or smoke your meter. This energy can not be computed or read digitally, it needs analog instrumentation calibrated to it to function and read the energy correctly. Remember, this is the electricity that science did not want use to know about. It has been suppressed for years, and, no matter how many times we rediscover and try to show it to science, it gets hushed and goes away, along with the folks who bring this to the public table. Get a grip and try to learn about it before comparing it to conventional energy. It is much more powerful, exists in much larger amounts, and, is easily able to be converted. If we use a spark coil, it is cold electricity. This consists of a already built one wire system capable of powering up and releasing plasma. If we shot the spark of a coil into a copper plate, it would disturb the ambient and allow us attraction of aether energy to a capacitive coupling. In my example, we could put a sheet of mica between a copper and aluminum plate, then, strike it with the spark coil's output. Then, the other side of the plate, we could place an aluminum sheet, smaller than the mica sheet so it can't arc across. Then, twist two hv diodes together at opposite ends and screw them to the aluminum in a spot that doesn't hinder the distance between the plates (keeping them equally tight together) The other sides of the diodes will now give off energy. One of them can go to ground, and the other can go to a graphene oxide coated aerial copper plate. another plate can be placed near the copper plate, but far enough away so it doesn't arc. connect another avramenko plaug to this plate and test across the diodes installed on all of the plates until you find the energy out. This electricity WILL do work. It can be more powerful than any electrical generator. and, it is cheap enough to buy and make!
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the resistors work nothing like you calculate. The voltage presented in this system is cold electricity and if you know anything about cold electricity, the resistance is needed to convert the energy from cold energy to conventional electricity.. The cold electricity, which is basically invisible and non measurable becomes measurable after this conversion,. and, it will do nothing unless it is put through the proper sized resistors. Cold electricity works oppositely with resistances, as Karl palsness has pointed out long ago, the energy out of a high resistance is more power, and it releases no heat as conventional "amperage driven electricity". Since there is no amperage until after this conversion, there is no wattage and no way to burn the resistors. If you use some logic, you will notice that this device is a replica of Tesla's phase conjugate mirror generator, which pumps energy into the ground and returns it as many mirrors of the energy put in, through the ground as a one wire system. If you punched a ground rod into the ground and soldered on an avramenko plug after the energy was continuously pumped into the ground, the ground rod with the two diodes on the other end would read a voltage across each diode to the output side of the resistor. If you connected this before the resistor, youd either get nothing, or smoke your meter. This energy can not be computed or read digitally, it needs analog instrumentation calibrated to it to function and read the energy correctly. Remember, this is the electricity that science did not want use to know about. It has been suppressed for years, and, no matter how many times we rediscover and try to show it to science, it gets hushed and goes away, along with the folks who bring this to the public table. Get a grip and try to learn about it before comparing it to conventional energy. It is much more powerful, exists in much larger amounts, and, is easily able to be converted. If we use a spark coil, it is cold electricity. This consists of a already built one wire system capable of powering up and releasing plasma. If we shot the spark of a coil into a copper plate, it would disturb the ambient and allow us attraction of aether energy to a capacitive coupling. In my example, we could put a sheet of mica between a copper and aluminum plate, then, strike it with the spark coil's output. Then, the other side of the plate, we could place an aluminum sheet, smaller than the mica sheet so it can't arc across. Then, twist two hv diodes together at opposite ends and screw them to the aluminum in a spot that doesn't hinder the distance between the plates (keeping them equally tight together) The other sides of the diodes will now give off energy. One of them can go to ground, and the other can go to a graphene oxide coated aerial copper plate. another plate can be placed near the copper plate, but far enough away so it doesn't arc. connect another avramenko plaug to this plate and test across the diodes installed on all of the plates until you find the energy out. This electricity WILL do work. It can be more powerful than any electrical generator. and, it is cheap enough to buy and make!
Nicely put. This is a counterintuitive set of phenomena that makes this possible. Resistance strategically placed in the system becomes a kind of gate which allows cold electricity to enter. Again counter-intuitively, generally the higher the resistance the better.
Bob
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Hi Dezeinstein,
It is interesting you returned to this topic which has been dormant for nearly 2 years. I do hope you have achieved something wonderful in practice because most members on the forums do nothing else but talk and talk about the creation of unconventional energy and that is where it all ends and will fall into oblivion.
Looking forward to seeing anything you may have to share, maybe you have a really bulletproof vest... ::)
Gyula
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Talk is cheap! Too cheap.
Those who believe in cold electricity, please post a simple circuit that cools down and does so without heating any other part of the circuit. Oh I forgot, please make it first and prove it to yourself before posting, as you can't expect others to do your research. It must not involve any chemicals as some reactions are endothermic, only electrical circuits please.
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Can someone explain why the spark gap is in series with LC?
Your right It wont work ;) like that!
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Hello,
I know it has been a very long time since you posted this reply to Skysabre,
However, the formulas you are interpreting for the resistors in Don Smith's circuit do not apply for the output power that is generated with his device.
First and foremost, it is confusing to think that it would be possible to run any voltage divider with the kind of voltage and amperage that the system is supposed to create, but I could put it into perspective for you if you give me a chance.
Have you ever played around with the Tesla Hairpin Circuit? Have you noticed the shorted bar across the hairpin and notice how the load still operates with the circuit? This is the reason why the Don Smith generators all would work, like Tesla's hairpin circuit because of the energy output received by it's circuitry. Cold Electricity is an energy in a class of it's own. This IS what the output consists of and the reason why it couldn't be conventional or static electricity is because it doesn't behave like either one.
The power is NOT amperage driven,. it is not reactive energy and it is not based upon the basic watt's or ohm's law because the circuit's conversion through high frequency, a spark gap and it's hv doorknob capacitors creates the energy by conversion, and, if we have a high frequency pulsed energy that is already cold electricity, or radiant energy whatever you will call it, the energy is able to be converted back to conventional energy in a manner similar to how it is created.
The fascinating part of it is that it can be transformed, but only with resonance and a loosley coupled set of coils, then, to get it stepped up, the high frequency energy could be amplified by utilizing a split coil which is rectified and summed/added together. If equally separated and split down the middle, the coils will share equal amounts of voltage and amperage, once converted from HF cold electricity back to conventional energy. These conversions can happen in a couple of ways. First, the easiest method is to ensure you have resonance using the high voltage self healing capacitor to create massive pulses of energy. These pulses allow for the charge pump action that trades off it's low input for the amplification/multiplication of not only voltage, but amperage as well.
Once this energy is pumped up in this method, there are two options to force the output of the step up process to convert it yet again, while stepping it down. The first step up uses the spaark gap in series to utilize as little energy as possible in stepping up and amplifying it's energy. This is done by drawing in the amperage by means of both inductively and capacitively attracting ions while the voltage becomes high enough to be influential "ionically" and can only be done while remaining in resonance. Locking in resonance with a phase lock loop and using a flyback coil to monitor it's output via the other side of the spark gap can be tricky but is none the less the best and most accurate way to control it, which. since Don's publicly posted circuits do not contain the phase lock loop and the flyback monitor circuit, there is no way to control it so it remains active without variations that could easily knock the circuit out of reonance.
Once this happens, we need to step the energy back down, but to remain attractive to the bombarding of the necvessary ions for it's amplification/multiplication, there needs to be a spark gap either in parallel to force amperage to discharge so the L3 coil is fired in a forceful manner so the energy could be stepped back down to a controllable level, and it needs to be in resonance, which can be done simply by creating a 4 to 1 length in windings instead of splitting the coil again, because this time if we cut the coil , the energy will go back to where it came from and not have more energy via multiplication, because it would now divide it due to the coil configuration, if split and center tapped again.
So now we have the stepped down level which could be any voltage we need, however, we need to have enough voltage to charge and dam up the energy into very large capacitors. We could do this by sending it into ac oil filled capacitors at high voltages which converts the energy from cold electricity back to conventional energy , then by building an RF inverter, we could easily create a 60 hz cycle that will easily transform via capacitive pulses that are at such a high power output that the system will drive very large transformers high voltage coils with ease, reducing the voltage and boosting the amperage, giving us all of the massive amounts of power we need, using minimal power to do so, or even having the ability to use minimal battery power that is chargeable with it's output without breaking the dipole, allowing the output to function flawlessly while the input is still operational without any reduction whatsoever.
This could be performed by leaving the power stepped up and dumping it into large caps, but this way is the way shown online with the Barker & Williamson coil that is cut, using the red primary coils of amp king wire, and it is not easily manageable, and difficult to build and get functioning. It is also deadly because of the levels of energy left over in the caps. One discharge of these caps are capable of blasting a 1/4" thick screwdriver in half if the energy is generated and stored correctly. This power is enough to blow a limb off of a body , just like a high voltage power line, provided it is in a sinewave like high voltage power lines are. If the energy is amplified, then converted to conventional energy within a capacitor , the power would remain a powerful dc voltage that is instantaneously replaced as a load is added to it.. This means that the discharge would happen, killing us or hurting us badly, then, once we were disconnected from the circuit, in less than 1/30,000th of a second, the energy would be replaced to a full charge and is able to supply the load without the ability to deplete it's output. If we try to connect loads to the caps, the massive high powered dc voltage stored in them will blow apart any device in their path unless they are oscillated and fed into a transformer coil that could handle the voltage and frequency that the energy is oscillated at.
So, we need to change the output so it is functional and this could be done in a couple of ways, one way was already explained, which is inverted to drive a transformer at 8000 volts of input at 1.25 amps minimum, which would equal an output of 10,000 watts . This could be done with RF transistors to create a 60 cycle inversion at 8000 volts and the power could easily drive a single phase pole top utility transformer (7970v to 240/120) then it would be capable of running a home in it's entirety, but, a solution would need to be made to ensure the spark gap would not degrade, and the NST would remain operational continuously for many years.
The second method is to fire the energy into high voltage rectifiers after the circuit is stepped down a second time, utilizing an arc gap in parallel between the L1 to L2 and the L3 to L4 step down using single coils for both L3 & L4. On the secondary side, we would rectify the output, then split the hf dc voltage with a voltage divider, using some form of resistor, and I did find that normal resistors, or wire wound resistors work just fine for this task. Cold electricity literally is fed into the resistors and with this type of division does not release heat, but, with conventional energy they would release heat and burn to a crisp... With cold electricity, they become colder.
This works in the opposite manner than ohm's law's functions for conventional energy and this is the point I am getting at that show the irrelevance of your formulas from the reply to Skywalker. If we fed a 100 watt light bulb with this energy, we'd get less light than if we used a 40 watt bulb.. In school, all of the teaching of Ohms' law tells us this can't work, they tell us science doesn't accept this, and it is only due to the fact that science has been suppressed from this technology for 135 years. We have been brainwashed into believing this crap,. and it is not right, nor is it fair since the brightest mind in all of the history of electrical energy transmission, distribution & generation was 100% correct and was exactly correct with ALL of his formulas, his circuit explanations, because he has literally replicated all of his visions which were written as notes in many books.
So, Cold electricity can be split with a voltage divider without the worry of burning the resistor whatsoever. Why it does this is because it isn't an amperage forced energy until converted within a capacitor, and it runs along the outside of a conductor like high voltage energy does, but at high frequencies, however it is an inverted type of energy that is coupled in resonance, based upon gathering it's amplified force through inductive and capacitive reactance only if it remains in resonance without jumping in and out or varying itself frequenctly. The output's capabilities are advantageous only if the energy can be controlled because we could set the voltage level rather easily and inexpensively by using cheap resistors of any wattage value , but it seems impossible by looking at how it is wired.. Once this is completed and the voltage is in a way we could use it, we could then take advantage of it because we could feed and very easily charge massive super capacitors with the output of the resistors. The resistors release very high levels of cold electricity at very high frequencies. These frequencies allow this energy to be stored at much faster speeds , then once it is stored into the capacitors, the energy is converted to conventional energy at very quick charge intervals while the energy used is a very small window of frequency, allowing the rest of the output not to be affected or vary since the energy output at 0-59 hz is not used, and 61 to 35,000 hz isn't used. , this will remain in the caps, allowing the system to top off the caps in less time than we could use the energy. The inverter could easily leave so much energy in the system and not limit the output capacity while the capacitors are able to provide approximately 1000 watts per farad of storage.
It is highly recommended to utilize 24 volt or 48 volt super capacitor banks for storage, then the inversion process would follow to draw this conventional DC power from the capacitors with massive 48v pure sinewave inverters capable of 120 or 240v outputs at well over 3000 Farads and only use 1/4 the size of the conductors needed within a 12v dc system. 12 V Dc systems are awful, the wiring needs to be huge, they are inefficient , and the batteries used need to have huge amperage capabilities.
This would equal an output of 3 megawatts. If they make inverters this large, I'd be quite confident they would be extremely expensive, however well worth the cost. The inversion process from the capacitors is way more efficient than battery powered inversion because caps have nearly no loss in comparison with batteries when it comes to high frequency charging , including the speed of the storage needed which is provided by radiant or cold electricity.
The advantageous end of this circuit is that the line side of the inverters at 48v would be much less expensive for amperage handling since the input side could be easily fed with copper bus and is limited in amperage compared to 12 v systems, this is why I highly recommend them to be designed this way.
Hi Skysabre,
I went through the pdf file you altruistically uploaded. I am strongly "amazed" by seeing the wiring diagram shown in pdf Page 27: they use voltage divider resistors to match the alleged 8kV output voltage (stored in the 2uF capacitor) to the input of an off-the-shelf 12V or 24V DC to 110V AC power inverter. Using resistors for dividing voltages makes sense when reasonably small currents are involved because of the unavoidable heat loss in the resistors.
Let's do some simple calculations backwards, let's choose a power inverter which is able to output just 2kW at 110V AC, ok? Then let's have its own efficiency, say, 90%, so the input DC power to it should be 1.1 x 2kW=2.2kW i.e. 10% higher.
Now if this inverter receives 24V DC input (let's say), then the input DC current demand is about I=2.2kW/24V=91.6A.
Now lets calculate the resistor values for dividing the 8kV DC to 24V. Here is a link I used, it also calculates the power loss in the two resistors: http://www.bowdenshobbycircuits.info/r2.htm
Using the example described in the text for finding the series resistance needed for a LED as a sample, I entered for battery voltage 8000, for current 91.6 and for Vout 24, I got 87 Ohm for R1 (and R2 would be represented by the 24V input of the inverter) but with this value the dissipated power in R1 would amount to 730.6kW.... the idea to use resistors to drop the 8000V to 24V is ABSURD, INSANE to say the least. And there is no any other suggestion to reduce the 8kV (or whatever kV coming from the LC tank via the diodes to the 2uF storage capacitor) to 24V or 12V.
The other thing is that while it may be possible to store a few kW power in a resonant LC tank circuit (it would need a coil and a capacitor with extremely low loss i.e. very high Q) but when directly loading such high Q resonant circuit, the circulating power in it would get reduced just because the external load reduces the high Q (the resonant AC impedance of such a high Q LC tank may range from several ten to several hundred kOhm and shunting it say with the 87 Ohm resistor via the inverter input, the high AC impedance gets killed, so the kV voltage reduces accordingly, there is no 'juice' left in the tank to feed the inverter. AND there is no any high wattage resistor shown in the pictures, which would imply they really used them to reduce the kV output...
Now no wonder why this pdf file contains NO any measurement results done by those 'compiling' it. It is a "pathwork", a "botch", taken text and pictures from some sources, and sorry to say I consider it as a hoax.
At other forums and also here, several members attempted to replicate Don Smith setups but nobody succeeded so far (or did not report, that is) and even Don Smith never showed any working device, only talked about the kW output and showed the assembled boards with those components like in the pictures in the pdf file.
Regardless of Don Smith or from this pdf file, the problem to be solved would be to find a circuit topology which does not reduce an LC tank resonant impedance too much and dissipates only a reasonable amount of power while dividing the kVs to a lower more workable value. This would be challange circuit to design and build for sure, still strongly assuming that the input power to the LC tank could be kept at a lower value than that of the output power received from THE circuit.
Gyula
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Hello,
I know it has been a very long time since you posted this reply to Skysabre,
However, the formulas you are interpreting for the resistors in Don Smith's circuit do not apply for the output power that is generated with his device.
First and foremost, it is confusing to think that it would be possible to run any voltage divider with the kind of voltage and amperage that the system is supposed to create, but I could put it into perspective for you if you give me a chance.
Have you ever played around with the Tesla Hairpin Circuit? Have you noticed the shorted bar across the hairpin and notice how the load still operates with the circuit? This is the reason why the Don Smith generators all would work, like Tesla's hairpin circuit because of the energy output received by it's circuitry. Cold Electricity is an energy in a class of it's own. This IS what the output consists of and the reason why it couldn't be conventional or static electricity is because it doesn't behave like either one.
The power is NOT amperage driven,. it is not reactive energy and it is not based upon the basic watt's or ohm's law because the circuit's conversion through high frequency, a spark gap and it's hv doorknob capacitors creates the energy by conversion, and, if we have a high frequency pulsed energy that is already cold electricity, or radiant energy whatever you will call it, the energy is able to be converted back to conventional energy in a manner similar to how it is created.
The fascinating part of it is that it can be transformed, but only with resonance and a loosley coupled set of coils, then, to get it stepped up, the high frequency energy could be amplified by utilizing a split coil which is rectified and summed/added together. If equally separated and split down the middle, the coils will share equal amounts of voltage and amperage, once converted from HF cold electricity back to conventional energy. These conversions can happen in a couple of ways. First, the easiest method is to ensure you have resonance using the high voltage self healing capacitor to create massive pulses of energy. These pulses allow for the charge pump action that trades off it's low input for the amplification/multiplication of not only voltage, but amperage as well.
Once this energy is pumped up in this method, there are two options to force the output of the step up process to convert it yet again, while stepping it down. The first step up uses the spaark gap in series to utilize as little energy as possible in stepping up and amplifying it's energy. This is done by drawing in the amperage by means of both inductively and capacitively attracting ions while the voltage becomes high enough to be influential "ionically" and can only be done while remaining in resonance. Locking in resonance with a phase lock loop and using a flyback coil to monitor it's output via the other side of the spark gap can be tricky but is none the less the best and most accurate way to control it, which. since Don's publicly posted circuits do not contain the phase lock loop and the flyback monitor circuit, there is no way to control it so it remains active without variations that could easily knock the circuit out of reonance.
Once this happens, we need to step the energy back down, but to remain attractive to the bombarding of the necvessary ions for it's amplification/multiplication, there needs to be a spark gap either in parallel to force amperage to discharge so the L3 coil is fired in a forceful manner so the energy could be stepped back down to a controllable level, and it needs to be in resonance, which can be done simply by creating a 4 to 1 length in windings instead of splitting the coil again, because this time if we cut the coil , the energy will go back to where it came from and not have more energy via multiplication, because it would now divide it due to the coil configuration, if split and center tapped again.
So now we have the stepped down level which could be any voltage we need, however, we need to have enough voltage to charge and dam up the energy into very large capacitors. We could do this by sending it into ac oil filled capacitors at high voltages which converts the energy from cold electricity back to conventional energy , then by building an RF inverter, we could easily create a 60 hz cycle that will easily transform via capacitive pulses that are at such a high power output that the system will drive very large transformers high voltage coils with ease, reducing the voltage and boosting the amperage, giving us all of the massive amounts of power we need, using minimal power to do so, or even having the ability to use minimal battery power that is chargeable with it's output without breaking the dipole, allowing the output to function flawlessly while the input is still operational without any reduction whatsoever.
This could be performed by leaving the power stepped up and dumping it into large caps, but this way is the way shown online with the Barker & Williamson coil that is cut, using the red primary coils of amp king wire, and it is not easily manageable, and difficult to build and get functioning. It is also deadly because of the levels of energy left over in the caps. One discharge of these caps are capable of blasting a 1/4" thick screwdriver in half if the energy is generated and stored correctly. This power is enough to blow a limb off of a body , just like a high voltage power line, provided it is in a sinewave like high voltage power lines are. If the energy is amplified, then converted to conventional energy within a capacitor , the power would remain a powerful dc voltage that is instantaneously replaced as a load is added to it.. This means that the discharge would happen, killing us or hurting us badly, then, once we were disconnected from the circuit, in less than 1/30,000th of a second, the energy would be replaced to a full charge and is able to supply the load without the ability to deplete it's output. If we try to connect loads to the caps, the massive high powered dc voltage stored in them will blow apart any device in their path unless they are oscillated and fed into a transformer coil that could handle the voltage and frequency that the energy is oscillated at.
So, we need to change the output so it is functional and this could be done in a couple of ways, one way was already explained, which is inverted to drive a transformer at 8000 volts of input at 1.25 amps minimum, which would equal an output of 10,000 watts . This could be done with RF transistors to create a 60 cycle inversion at 8000 volts and the power could easily drive a single phase pole top utility transformer (7970v to 240/120) then it would be capable of running a home in it's entirety, but, a solution would need to be made to ensure the spark gap would not degrade, and the NST would remain operational continuously for many years.
The second method is to fire the energy into high voltage rectifiers after the circuit is stepped down a second time, utilizing an arc gap in parallel between the L1 to L2 and the L3 to L4 step down using single coils for both L3 & L4. On the secondary side, we would rectify the output, then split the hf dc voltage with a voltage divider, using some form of resistor, and I did find that normal resistors, or wire wound resistors work just fine for this task. Cold electricity literally is fed into the resistors and with this type of division does not release heat, but, with conventional energy they would release heat and burn to a crisp... With cold electricity, they become colder.
This works in the opposite manner than ohm's law's functions for conventional energy and this is the point I am getting at that show the irrelevance of your formulas from the reply to Skywalker. If we fed a 100 watt light bulb with this energy, we'd get less light than if we used a 40 watt bulb.. In school, all of the teaching of Ohms' law tells us this can't work, they tell us science doesn't accept this, and it is only due to the fact that science has been suppressed from this technology for 135 years. We have been brainwashed into believing this crap,. and it is not right, nor is it fair since the brightest mind in all of the history of electrical energy transmission, distribution & generation was 100% correct and was exactly correct with ALL of his formulas, his circuit explanations, because he has literally replicated all of his visions which were written as notes in many books.
So, Cold electricity can be split with a voltage divider without the worry of burning the resistor whatsoever. Why it does this is because it isn't an amperage forced energy until converted within a capacitor, and it runs along the outside of a conductor like high voltage energy does, but at high frequencies, however it is an inverted type of energy that is coupled in resonance, based upon gathering it's amplified force through inductive and capacitive reactance only if it remains in resonance without jumping in and out or varying itself frequenctly. The output's capabilities are advantageous only if the energy can be controlled because we could set the voltage level rather easily and inexpensively by using cheap resistors of any wattage value , but it seems impossible by looking at how it is wired.. Once this is completed and the voltage is in a way we could use it, we could then take advantage of it because we could feed and very easily charge massive super capacitors with the output of the resistors. The resistors release very high levels of cold electricity at very high frequencies. These frequencies allow this energy to be stored at much faster speeds , then once it is stored into the capacitors, the energy is converted to conventional energy at very quick charge intervals while the energy used is a very small window of frequency, allowing the rest of the output not to be affected or vary since the energy output at 0-59 hz is not used, and 61 to 35,000 hz isn't used. , this will remain in the caps, allowing the system to top off the caps in less time than we could use the energy. The inverter could easily leave so much energy in the system and not limit the output capacity while the capacitors are able to provide approximately 1000 watts per farad of storage.
It is highly recommended to utilize 24 volt or 48 volt super capacitor banks for storage, then the inversion process would follow to draw this conventional DC power from the capacitors with massive 48v pure sinewave inverters capable of 120 or 240v outputs at well over 3000 Farads and only use 1/4 the size of the conductors needed within a 12v dc system. 12 V Dc systems are awful, the wiring needs to be huge, they are inefficient , and the batteries used need to have huge amperage capabilities.
This would equal an output of 3 megawatts. If they make inverters this large, I'd be quite confident they would be extremely expensive, however well worth the cost. The inversion process from the capacitors is way more efficient than battery powered inversion because caps have nearly no loss in comparison with batteries when it comes to high frequency charging , including the speed of the storage needed which is provided by radiant or cold electricity.
The advantageous end of this circuit is that the line side of the inverters at 48v would be much less expensive for amperage handling since the input side could be easily fed with copper bus and is limited in amperage compared to 12 v systems, this is why I highly recommend them to be designed this way.
I don't supose you have a short version ?
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Hi Skysabre,
Well, it is not easy to answer your question... I think if you take a thorough look and reading at this link below, especially member 'erfinder' posts and videos, then possibly you would be on a good track:
http://www.energyscienceforum.com/showthread.php?t=1611 (http://www.energyscienceforum.com/showthread.php?t=1611)
The thread started with a question on Bedini DVD Nr 25 but No need to buy the DVD as you later realize because the topic turns to a pulse motor-like setup as erfinder shows. It does need a hands on building and experience, maybe not the best for the not so experienced but I believe the progress for anyone is given and open. Just read it all over and decide, unfortunately the uploaded pictures can only be seen when you become a member there and log in. (notice that erfinder does not claim anything)
Unfortunately, I am not aware of ANY thread where a real device, capable of giving extra output over the input is shown with real measurements. Speculations, fakes, hoaxes rule... or greedyness to share.
There was the Bedini Ferris Wheel demo at their conference some years ago, see here http://www.energeticforum.com/john-bedini/6786-bedini-ferris-wheel-regauging-motor.html (http://www.energeticforum.com/john-bedini/6786-bedini-ferris-wheel-regauging-motor.html) but I do not know that those who rebuilt it whether got extra output or not.
I would also suggest to study Ben's motor here http://www.overunity.com/14377/the-thomas-motor/msg391150/#msg391150 (http://www.overunity.com/14377/the-thomas-motor/msg391150/#msg391150)
it may give good results (the possibilities are inherent in that setup I think) and Ben is still working on it.
Good luck,
Gyula
The Energetic Forum, to be honest it's a waste of time, for a start it refuses to grant access to all publications, even if your a member and if you are it expects you to be a certain grade be for it does, so forget it !!
Re the sparg gap, it's this section I find hard to understand >>>>>> read BELOW !
hi,
I am also working on the Don smith device at the same time with the 3volt ou circuit.
My recent findings base on Don smith replication done in China and one of the Don smith video revealed that it is configured for RF and not the typical induction heater coil which many was lead to believe.
Recently i obtained the fast recovery diodes 1200v 26ns 6Amps TO-220 - "HFA06TB120" which is connected 6 in series to form hv diode.For experiment purpose i merely got 12 diodes.
I am able to see spark appear within the spark gap.I am using 12volts to 220volts inverter for safety reasons to power the 10KV 30ma 30khz NST at 18watt battery power drawn.The NST tuned at around 4kv(Variable version on NST)
I would need to get more diodes for the secondary coils.At least 24 diodes is needed in total.I think 10 in series to form the HV diode is the best so total should be 40 diodes.
NO !
All I have is a home made coil 4 800v UFast diodes BY339, 4 capacitors for timing resonance and 2 fets and some stearing components in the inverter curcuit (manilli) I get a huge fat hot spark acelerant.
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Dezeinstein or anyone who cares to comment, How would you drive the l1 coil of the Don Smith "white board" device? He used a bertonee nst that is out of production and I cant find one no matter how hard I try. And even then I don't think anyone has video of that exact board "in use".
I have 7 different nsts and fried a couple. trying to drive it at radio frequencies, 20khz or more but none of my nsts seems to work right for this arrangement. he has 2 outputs rectified and the spark gap returning through the ground terminal but most modern nsts have gfci on the ground terminal (best I can tell). I think the one I am trying to use now is tripping the gfci.
looking for 1300v so my output is about 4kv. my circuit looks just like his, though I calculate about 150khz resonant frequency with .2uf cap across l1 and .047uf across l2. I could use capacitors to lower it if necessary.
would love to see drawings/details of what you think the most "sure to function" circuit/components would look like to make even a fraction of the power you are describing.
I am having difficulty picturing how you would connect l3 and l4 step down transformer and charge 48v super cap banks while discharging them with an inverter to the load.
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Hi Tesluh,
I cannot answer all your questions but I can tell you a few things.
-- you can buy NSTs at ebay without gfi but they are expensive, plus the shipping cost comes to it
(for instance: http://www.ebay.com/itm/252629542643 (http://www.ebay.com/itm/252629542643) ), or just search ebay with words "neon sign transformer no gfi"
-- a cheaper solution would be to buy this HV transformer and some components and build your own "nst":
http://www.amazing1.com/products/miniature-ferrite-high-frequency-transformer-7kv-10ma-20k-100khz.html (http://www.amazing1.com/products/miniature-ferrite-high-frequency-transformer-7kv-10ma-20k-100khz.html)
There is a downloadable PDF file in the page that includes a schematic circuit for this transformer with the other needed components in Page 10, labeled as 'basic neon 2100'. You can change the operating frequency of the HV output by varying the C5 capacitor across the primary coil (at the transistor collector, the present 1uF gives 36.5 kHz output frequency because the primary coil has 19 uH inductance as per the PDF file, page 9).
-- an even cheaper solution would be to buy a similar HV transformer at ebay and use it in the same schematic of the PDF file. See this offer here: http://www.ebay.com/itm/282215688077 (http://www.ebay.com/itm/282215688077) I think you recognize the HV output is the two lightblue PVC isolated wire pair, the thick enameled wire pair is the primary coil for the collector of the transistor and the thin wire pair is the feedback coil to the base circuit of the transistor as shown in the previous schematic.
You need to experiment with the C5 capacitor to change the frequency, of course, and for this you would need a frequency measuring means like a handheld DMM that includes such feature or a scope, etc. If you have an L meter, that would be great to measure this transformer coils and then you could compare them to the inductance values given in the above PDF file in Page 9. But this latter is not so important, the point is you can tune the frequency by changing C5.
Notice capacitor C8 at the HV output of the schematic, it tunes the HV output coil to approximately to the same frequency the primary coil is tuned by C5 and you need at least a 10kV rated capacitor there. The exact pF value for C8 is not so critical (but the HV rating is important) because the HV output coil has high DC resistance with respect to the primary coil for both the ebay and the amazing1.com transformers, so the resonance curve for the output coil is flat.
It would be wise to run the assembled circuit first from a lower than the 9V indicated in the PDF schematic (say from 5-6V only). If the circuit does not oscillate (i.e. no HV output) then flip the feedback coil ends to get oscillation (oscillation may also depend on the supply voltage, but do not go way higher than 9 - 10V to avoid burning the transformer unless you can measure HV amplitude somehow which is not easy at some ten kHz range).
Hopefully, Mr Dezeinstein returns to this topic and shares his words of wisdom on your other questions.
Gyula
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Thank you Gyula, you beat me to it:) I just got this in the mail today!
http://www.ebay.com/itm/182346077493
12v dc driver and a tv flyback coil.
now the question is, I have a coil with only two output wires, some amount of hv across them (1" streamer), at some kHz frequency (unknown yet). how do I connect those to this primary tank circuit? Dons schematics have a two output nst with both leads having diodes on the ends which supposedly puts out hv hf pulsed dc? The spark gap is connected to the ground terminal which I believe is connected to the center tap on his transformer. either I take both leads and use diodes on the ends and the spark gap has to go somewhere (earth?) or I need to wind a secondary for the flyback that has a center tapped coil so the two outsides can go to diodes and the spark gap can return to center tap of secondary. Either I need three connections from the flyback or I need a different schematic to wire the l1 coil.
this is basically a tesla coil. how would someone drive a tesla coil using a zvs style driver and flyback transformer? I can buy one from ebay but would have to wait weeks for it to arrive to see how they do it.
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Hi Tesluh,
Well, your driver and the flyback trafo are nice but you are limited in the flexible changing of the HV output frequency versus the other oscillator circuit and the HV trafo shown in the PDF file I referred to yesterday.
I do not know the inside circuit of the NST what Don Smith used, my best speculation is his NST had a center tapped secondary coil output i.e three output wires and the two diodes worked exactly like a center tapped full wave rectifier circuit works, you are surely familiar with, see this http://www.electronics-tutorials.ws/diode/diode18.gif and the three wires are A, B and C, C center tap is the common negative (ground symbol). The schema is from this site: http://www.electronics-tutorials.ws/diode/diode_6.html
Now, in your flyback trafo you have only 2 output 'wires', see my attachment 1.
In the second attachment I encircled the positive (red) and the negative (blue) connection points in two Don Smith circuits (they are familiar, aren't they) where I think your flyback trafo outputs should be connected, with the correct polarities. You need to identify the negative HV pin of the flyback trafo, of course but I believe you already did. 8)
The flyback trafo gives a half wave rectified HV output while the NST output (if the center tapped assumption is correct) gives a full wave output; this means the spark gap can fire once from the flyback output during a full T period (T=1/f) and can fire twice from the original NST output during a full period. This means you need to tune L1 (the primary coil) to the spark gap frequency accordingly.
Gyula
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Got it! thank you for your help! Yes, having adjustable frequency would be nice. I have a source for an adjustable hv transformer with outputs similar to this (like the schematic you posted )that would make tuning easier. I'll see if I can find the frequency and tune the l1 and l2 to match.
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Hi Tesluh,
Well, your driver and the flyback trafo are nice but you are limited in the flexible changing of the HV output frequency versus the other oscillator circuit and the HV trafo shown in the PDF file I referred to yesterday.
I do not know the inside circuit of the NST what Don Smith used, my best speculation is his NST had a center tapped secondary coil output i.e three output wires and the two diodes worked exactly like a center tapped full wave rectifier circuit works, you are surely familiar with, see this http://www.electronics-tutorials.ws/diode/diode18.gif (http://www.electronics-tutorials.ws/diode/diode18.gif) and the three wires are A, B and C, C center tap is the common negative (ground symbol). The schema is from this site: http://www.electronics-tutorials.ws/diode/diode_6.html (http://www.electronics-tutorials.ws/diode/diode_6.html)
Now, in your flyback trafo you have only 2 output 'wires', see my attachment 1.
In the second attachment I encircled the positive (red) and the negative (blue) connection points in two Don Smith circuits (they are familiar, aren't they) where I think your flyback trafo outputs should be connected, with the correct polarities. You need to identify the negative HV pin of the flyback trafo, of course but I believe you already did. 8)
The flyback trafo gives a half wave rectified HV output while the NST output (if the center tapped assumption is correct) gives a full wave output; this means the spark gap can fire once from the flyback output during a full T period (T=1/f) and can fire twice from the original NST output during a full period. This means you need to tune L1 (the primary coil) to the spark gap frequency accordingly.
Gyula
Im reposting the 2 circuits.
In the top circuit which seems to depict the circuit just after the nst, its an odd config. The cap is across the first pri coil. Being so, I wonder if the cap is actually being charged by the nst. If the primary and the dual secondary are say lenzless, then maybe the spark gap to the nst gnd is just something that gets the pri lc going into resonance??? ??? Strange setup.
Mags
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l1 capacitor should adjust resonant frequency of primary tank down from MHz to kHz range to match the output of the power supply. capacitor on l2 should make l2 resonant frequency match l1, at least that is how I understand it:) not an easy task but I don't think it will be impossible.
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Hi Mags,
I simply answered member Tesluh's question where he could connect the HV output of his flyback transformer when he omits the nst in DS schematic. And there are some variants of such schematics on the web so I took the ones found in the uploaded paper in the very first post of this thread, after all this thread was started as 'the so called Don Smith generator'. (Using the internet wayback machine the deleted file is there.)
By the way, I also find the first circuit a strange configuration. The same schematic is included in PJK's book, Chapter 3 but I do not mean this justifies the circuit either... :o
Gyula
Im reposting the 2 circuits.
In the top circuit which seems to depict the circuit just after the nst, its an odd config. The cap is across the first pri coil. Being so, I wonder if the cap is actually being charged by the nst. If the primary and the dual secondary are say lenzless, then maybe the spark gap to the nst gnd is just something that gets the pri lc going into resonance??? ??? Strange setup.
Mags
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I have probably looked at over a hundred schematics for just this device alone!
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Hi Mags,
I simply answered member Tesluh's question where he could connect the HV output of his flyback transformer when he omits the nst in DS schematic. And there are some variants of such schematics on the web so I took the ones found in the uploaded paper in the very first post of this thread, after all this thread was started as 'the so called Don Smith generator'. (Using the internet wayback machine the deleted file is there.)
By the way, I also find the first circuit a strange configuration. The same schematic is included in PJK's book, Chapter 3 but I do not mean this justifies the circuit either... :o
Gyula
Hey Gyula
Yes it is strange. But the top diagram is the same as the photos. It would be interesting to just see what happens with that part of the circuit alone done as shown.
Mags
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I have found it depends heavily on the nst. To use a new high frequency model, most have gfci that keep it from functioning. Also found a strange waveform produced by the ones I tested. had to modify one to get to the center tap to even be able to run the circuit. I believe that Bertonee was a very important part of the circuit, not made, impossible for me to find. That's why I am trying the flyback transformer/homemade transformer options.
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Would love to hear more about turning cold electricity output into useful hot electricity, if not for 240v 60 hz mains power, than at least for running something like light bulbs or heaters as a stand alone circuit.
How should the end of Don's white board device look to draw from the "8kv battery that never runs down" and use it practically?
Dezeinstein had some great ideas but I'm having a hard time visualizing what he would propose the circuit would look like after Don's 4 large capacitors.
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Can you produce cold electricity without doorknob capacitors? I see many solid state devices built using doorknob caps.
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Would love to hear more about turning cold electricity output into useful hot electricity, if not for 240v 60 hz mains power, than at least for running something like light bulbs or heaters as a stand alone circuit.
How should the end of Don's white board device look to draw from the "8kv battery that never runs down" and use it practically?
Dezeinstein had some great ideas but I'm having a hard time visualizing what he would propose the circuit would look like after Don's 4 large capacitors.
Put it into a rechargeable battery but watch it don't boil the battery fluid or charge caps with it via a UF high voltage diode and EHT caps.
watch you don't kill your self with them.
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Can anyone convert Dezeinsteins theory into a schematic? I am picturing Dons white board device but with voltage divider resistors/supercap banks and an inverter at the end of it.
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Can anyone convert Dezeinsteins theory into a schematic? I am picturing Dons white board device but with voltage divider resistors/supercap banks and an inverter at the end of it.
why on earth would you want to do that, I could think of better ways to do it.
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What I meant was, that is what I figured he was suggesting the end of the circuit would look like. Open to any suggestions. Still trying to work out the primary side but have no plans of stopping til I figure it out!
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@Tesluh
A cheap way to get the nst's is to go to junk sales
And pick up old signs
Pull the transformers out of them
Also, one suggestion to help you 'tune' this circuit
If you have trouble with coils
Is to use variable capacitors
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You need.not worry yourself with NST. All you need is an High Frequency High Voltage adjustabke inverter.
There are tons of circuit online you can use to make a symple adjustable inverter.
The center tapped transformer in your inverter must be made with AWG#31 copper wire of at least 500g. While it primary should be AWG#19 or #20 of 44ft halved into equal length.
Then get ferrite core be it C-Core (the best) or Straight bar a d couple everything together to make your transformer.
ICSG3524 maximum output frequency is around 600khz so you need POT of 1.8K to use with it to get and vary that high frequency. Your CT must be 2A102 capacitor too.
Search for SG3524 inverter Circuits.
Remember, the higher the frequency the lower the input current needs to kick starts the gen becomes. So if you apply high frequency, you will need no battery at all in your version.
You must connect the spark gap in parallel to our L1 coil.
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Hello,
I know it has been a very long time since you posted this reply to Skysabre,
However, the formulas you are interpreting for the resistors in Don Smith's circuit do not apply for the output power that is generated with his device.
First and foremost, it is confusing to think that it would be possible to run any voltage divider with the kind of voltage and amperage that the system is supposed to create, but I could put it into perspective for you if you give me a chance.
Have you ever played around with the Tesla Hairpin Circuit? Have you noticed the shorted bar across the hairpin and notice how the load still operates with the circuit? This is the reason why the Don Smith generators all would work, like Tesla's hairpin circuit because of the energy output received by it's circuitry. Cold Electricity is an energy in a class of it's own. This IS what the output consists of and the reason why it couldn't be conventional or static electricity is because it doesn't behave like either one.
The power is NOT amperage driven,. it is not reactive energy and it is not based upon the basic watt's or ohm's law because the circuit's conversion through high frequency, a spark gap and it's hv doorknob capacitors creates the energy by conversion, and, if we have a high frequency pulsed energy that is already cold electricity, or radiant energy whatever you will call it, the energy is able to be converted back to conventional energy in a manner similar to how it is created.
The fascinating part of it is that it can be transformed, but only with resonance and a loosley coupled set of coils, then, to get it stepped up, the high frequency energy could be amplified by utilizing a split coil which is rectified and summed/added together. If equally separated and split down the middle, the coils will share equal amounts of voltage and amperage, once converted from HF cold electricity back to conventional energy. These conversions can happen in a couple of ways. First, the easiest method is to ensure you have resonance using the high voltage self healing capacitor to create massive pulses of energy. These pulses allow for the charge pump action that trades off it's low input for the amplification/multiplication of not only voltage, but amperage as well.
Once this energy is pumped up in this method, there are two options to force the output of the step up process to convert it yet again, while stepping it down. The first step up uses the spaark gap in series to utilize as little energy as possible in stepping up and amplifying it's energy. This is done by drawing in the amperage by means of both inductively and capacitively attracting ions while the voltage becomes high enough to be influential "ionically" and can only be done while remaining in resonance. Locking in resonance with a phase lock loop and using a flyback coil to monitor it's output via the other side of the spark gap can be tricky but is none the less the best and most accurate way to control it, which. since Don's publicly posted circuits do not contain the phase lock loop and the flyback monitor circuit, there is no way to control it so it remains active without variations that could easily knock the circuit out of reonance.
Once this happens, we need to step the energy back down, but to remain attractive to the bombarding of the necvessary ions for it's amplification/multiplication, there needs to be a spark gap either in parallel to force amperage to discharge so the L3 coil is fired in a forceful manner so the energy could be stepped back down to a controllable level, and it needs to be in resonance, which can be done simply by creating a 4 to 1 length in windings instead of splitting the coil again, because this time if we cut the coil , the energy will go back to where it came from and not have more energy via multiplication, because it would now divide it due to the coil configuration, if split and center tapped again.
So now we have the stepped down level which could be any voltage we need, however, we need to have enough voltage to charge and dam up the energy into very large capacitors. We could do this by sending it into ac oil filled capacitors at high voltages which converts the energy from cold electricity back to conventional energy , then by building an RF inverter, we could easily create a 60 hz cycle that will easily transform via capacitive pulses that are at such a high power output that the system will drive very large transformers high voltage coils with ease, reducing the voltage and boosting the amperage, giving us all of the massive amounts of power we need, using minimal power to do so, or even having the ability to use minimal battery power that is chargeable with it's output without breaking the dipole, allowing the output to function flawlessly while the input is still operational without any reduction whatsoever.
This could be performed by leaving the power stepped up and dumping it into large caps, but this way is the way shown online with the Barker & Williamson coil that is cut, using the red primary coils of amp king wire, and it is not easily manageable, and difficult to build and get functioning. It is also deadly because of the levels of energy left over in the caps. One discharge of these caps are capable of blasting a 1/4" thick screwdriver in half if the energy is generated and stored correctly. This power is enough to blow a limb off of a body , just like a high voltage power line, provided it is in a sinewave like high voltage power lines are. If the energy is amplified, then converted to conventional energy within a capacitor , the power would remain a powerful dc voltage that is instantaneously replaced as a load is added to it.. This means that the discharge would happen, killing us or hurting us badly, then, once we were disconnected from the circuit, in less than 1/30,000th of a second, the energy would be replaced to a full charge and is able to supply the load without the ability to deplete it's output. If we try to connect loads to the caps, the massive high powered dc voltage stored in them will blow apart any device in their path unless they are oscillated and fed into a transformer coil that could handle the voltage and frequency that the energy is oscillated at.
So, we need to change the output so it is functional and this could be done in a couple of ways, one way was already explained, which is inverted to drive a transformer at 8000 volts of input at 1.25 amps minimum, which would equal an output of 10,000 watts . This could be done with RF transistors to create a 60 cycle inversion at 8000 volts and the power could easily drive a single phase pole top utility transformer (7970v to 240/120) then it would be capable of running a home in it's entirety, but, a solution would need to be made to ensure the spark gap would not degrade, and the NST would remain operational continuously for many years.
The second method is to fire the energy into high voltage rectifiers after the circuit is stepped down a second time, utilizing an arc gap in parallel between the L1 to L2 and the L3 to L4 step down using single coils for both L3 & L4. On the secondary side, we would rectify the output, then split the hf dc voltage with a voltage divider, using some form of resistor, and I did find that normal resistors, or wire wound resistors work just fine for this task. Cold electricity literally is fed into the resistors and with this type of division does not release heat, but, with conventional energy they would release heat and burn to a crisp... With cold electricity, they become colder.
This works in the opposite manner than ohm's law's functions for conventional energy and this is the point I am getting at that show the irrelevance of your formulas from the reply to Skywalker. If we fed a 100 watt light bulb with this energy, we'd get less light than if we used a 40 watt bulb.. In school, all of the teaching of Ohms' law tells us this can't work, they tell us science doesn't accept this, and it is only due to the fact that science has been suppressed from this technology for 135 years. We have been brainwashed into believing this crap,. and it is not right, nor is it fair since the brightest mind in all of the history of electrical energy transmission, distribution & generation was 100% correct and was exactly correct with ALL of his formulas, his circuit explanations, because he has literally replicated all of his visions which were written as notes in many books.
So, Cold electricity can be split with a voltage divider without the worry of burning the resistor whatsoever. Why it does this is because it isn't an amperage forced energy until converted within a capacitor, and it runs along the outside of a conductor like high voltage energy does, but at high frequencies, however it is an inverted type of energy that is coupled in resonance, based upon gathering it's amplified force through inductive and capacitive reactance only if it remains in resonance without jumping in and out or varying itself frequenctly. The output's capabilities are advantageous only if the energy can be controlled because we could set the voltage level rather easily and inexpensively by using cheap resistors of any wattage value , but it seems impossible by looking at how it is wired.. Once this is completed and the voltage is in a way we could use it, we could then take advantage of it because we could feed and very easily charge massive super capacitors with the output of the resistors. The resistors release very high levels of cold electricity at very high frequencies. These frequencies allow this energy to be stored at much faster speeds , then once it is stored into the capacitors, the energy is converted to conventional energy at very quick charge intervals while the energy used is a very small window of frequency, allowing the rest of the output not to be affected or vary since the energy output at 0-59 hz is not used, and 61 to 35,000 hz isn't used. , this will remain in the caps, allowing the system to top off the caps in less time than we could use the energy. The inverter could easily leave so much energy in the system and not limit the output capacity while the capacitors are able to provide approximately 1000 watts per farad of storage.
It is highly recommended to utilize 24 volt or 48 volt super capacitor banks for storage, then the inversion process would follow to draw this conventional DC power from the capacitors with massive 48v pure sinewave inverters capable of 120 or 240v outputs at well over 3000 Farads and only use 1/4 the size of the conductors needed within a 12v dc system. 12 V Dc systems are awful, the wiring needs to be huge, they are inefficient , and the batteries used need to have huge amperage capabilities.
This would equal an output of 3 megawatts. If they make inverters this large, I'd be quite confident they would be extremely expensive, however well worth the cost. The inversion process from the capacitors is way more efficient than battery powered inversion because caps have nearly no loss in comparison with batteries when it comes to high frequency charging , including the speed of the storage needed which is provided by radiant or cold electricity.
The advantageous end of this circuit is that the line side of the inverters at 48v would be much less expensive for amperage handling since the input side could be easily fed with copper bus and is limited in amperage compared to 12 v systems, this is why I highly recommend them to be designed this way.
WOW!!! That is the best explanation I ever have the PLEASURE TO READ... If I understand correctly, The voltage divider with wire resistor could be brought down to 48 or 60 volt to be feed directly in a inverter... The trick is to match the output of the inverter with correspondant caps to maintain the voltage at the input... I`m I wrong in these assomptions????
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Hi sorry to barge in. I don't think you need an NST and they are potted and full of ground protection and what not. You just need high voltage, because the resonance effects are greater in high voltages among various other things.
Cheap HV:
https://www.aliexpress.com/item/XH-M651-For-Tesla-Discharge-Electric-Wire-High-Voltage-Discharger-Generator-Driving-Board-ZVS-DC-12V/32792062146.html
https://www.aliexpress.com/item/Free-Shipping-DC-3V-6V-Bis-400kV-400000V-High-Voltage-Pressure-Igniter-Boost-Step-up-Power/32795150286.html
https://www.aliexpress.com/item/DC-DC-high-voltage-boost-module-ZVS-capacitor-charging-gun-45-390V-780V-adjustable-regulator/32762742856.html?
What I don't get is where the cold energy appears? Do I need my L1 and L2 in resonance and it pulls energy from the center tapped L2? Does it come from the spark gap pulsing the prim coil?
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Hi sorry to barge in. I don't think you need an NST and they are potted and full of ground protection and what not. You just need high voltage, because the resonance effects are greater in high voltages among various other things.
Cheap HV:
https://www.aliexpress.com/item/XH-M651-For-Tesla-Discharge-Electric-Wire-High-Voltage-Discharger-Generator-Driving-Board-ZVS-DC-12V/32792062146.html
https://www.aliexpress.com/item/Free-Shipping-DC-3V-6V-Bis-400kV-400000V-High-Voltage-Pressure-Igniter-Boost-Step-up-Power/32795150286.html
https://www.aliexpress.com/item/DC-DC-high-voltage-boost-module-ZVS-capacitor-charging-gun-45-390V-780V-adjustable-regulator/32762742856.html?
What I don't get is where the cold energy appears? Do I need my L1 and L2 in resonance and it pulls energy from the center tapped L2? Does it come from the spark gap pulsing the prim coil?
Yeah there is a lot more to it than that.
watch this collection of vids watch them all see if the penny drops.
https://www.youtube.com/watch?v=Jqptq7A9cGU
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Well I think cold energy is the back EMF. You need to make it a sharp pulse and get it over the spark gap to the L1
Sharp pulses you get with a cap and a spark gap. What I don't get is that is the magnification in the gap or the coil? Is the gap just a clean break in the circuit or does it provide "all frequencies" to the coil.
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Well I think cold energy is the back EMF. You need to make it a sharp pulse and get it over the spark gap to the L1
Sharp pulses you get with a cap and a spark gap. What I don't get is that is the magnification in the gap or the coil? Is the gap just a clean break in the circuit or does it provide "all frequencies" to the coil.
Watch the video again ! !!!!!!!!!!!!!!!!!!